As the object moves from point A to B, the kinetic energy of the object decreases and the mechanical energy of the object increases.
In this problem, the law of energy conservation is applied. It is given that the work done by conservative force is -70J and the work done by non-conservative force is 50J.
The resulting forces between these two forces is -70J + 50J = -20 J.
The conservative force is linked with the movement caused by the sum of two energies, therefore there is a decrease in kinetic energy. The increase in mechanical energy is due to the positive non-conservative force.
Thus, the correct answer is kinetic energy of the object decreases and the mechanical energy increases.
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c) A physicist while calculating the charge over on an object found that 6× 10-¹⁹ ℃ cannot be the magnitude of the charge on an object. Justify.
An electron has a charge that is equal to the size of the elementary charge, e, with a negative sign. The value of the elementary charge is 1.602 x 10-19 C.
Positive and negative electric charges are two distinct types that are known to exist. Electrons have a negative charge, whereas protons have a positive charge. The item has a positive net charge if there are more protons than electrons. The net charge of an object is considered to be negative if there are more electrons than protons. If there are an equal number of protons and electrons, the object is considered to be electrically neutral.For more information on electric charge kindly visit to
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Part E Explain how you obtain your answer. Drag the terms on the left to the appropriate blanks on the right to complete the sentences. Terms:
- decreasing
- oppose
- increasing - support
Sentences:
- When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is ___
- Induced currents in the loops and the forces exerted on them are directed so they ____ this change
When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is decreasing.
Induced currents in the loops and the forces exerted on them are directed so they oppose this change
Magnetic flux is a size of the entire magnetic subject which passes thru a given region. it's far a useful device for helping describe the outcomes of the magnetic pressure on some thing occupying a given location.
Magnetic flux through a surface is the surface integral of the ordinary element of the magnetic subject B over that floor. it is also denoted Φ or ΦB. The SI unit of magnetic flux is the weber, and the CGS unit is the maxwell.
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A 2.5 kg sledge hammer hit a cement block with a force of 6.0 Newtons.
How does the force the sledge hammer exerted on the cement block compare with the force the cement block exerted on the sledge hammer?
Responses
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is less in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledge hammer.
HURRY HURRY HURRY !!!The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
The force the sledge hammer exerted on the cement block is equal in magnitude and in the same direction as the force the cement block exerted on the sledge hammer.
When a 2.5 kg sledgehammer hit a cement block with a force of 6.0 Newtons. The force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
What are opposite forces?This refers to forces that act on an object in opposite directions. The net force is gotten by solving for the difference between the two forces.
When the opposing forces are equal or balanced, the net force is zero. The sledgehammer hits with a force and the cement block is receiving the impart as a stationary object.
Obviously, the force the sledgehammer exerted on the cement block is greater in magnitude and opposite in direction to the force the cement block exerted on the sledgehammer.
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a 16 kg box sitting at the top of an icy hill begins to slide down the essentially frictionless surface. at the bottom of the hill it collides with a spring loaded guardrail with a spring constant of 384 N/m. if the hill is 7.1 m high, how much did the box compress the spring?
The compression of the spring of spring constant 384 N/m is 2.41 m.
What is compression spring?Compression springs work by resisting and pushing back against any downward or inward force that tries to squash and hold them in a compressed state.
To calculate the compression of the spring, we use the formula below.
Formula:
e = √(2mgh/k)........... Equation 1Where:
e = Compression of the springm = Mass of the boxh = Heightg = Acceleration due to gravityk = Spring constantFrom the question,
Given:
m = 16 kgh = 7.1 mg = 9.8 m/s²k = 384 N/mSubstitute these values into equation 1
e = √(2×16×7.1×9.8/384)e = 2.41 mHence, the compression of the spring is 2.41 m.
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Which of the following is a natural resource for humans?
O Cars
O Electricity
O Houses
O Wood
Which of the following is a natural resource for humans?
O Cars
O Electricity
O Houses
O Wood
Wood
Answer:
wood is a natural resources to man because it is not created by man
Which statements describe acceleration? Check all that apply. Negative acceleration occurs when an object slows down in the positive direction. Negative acceleration occurs when an object slows down in the negative direction. Negative acceleration occurs when an object speeds up in the negative direction. Positive acceleration occurs when an object speeds up in the positive direction. Positive acceleration occurs when an object speeds up in the negative direction. Positive acceleration occurs when an object slows down in the negative direction.
All of the true statements that describe acceleration include the following:
A. Negative acceleration occurs when an object slows down in the positive direction.
C. Negative acceleration occurs when an object speeds up in the negative direction.
D. Positive acceleration occurs when an object speeds up in the positive direction.
F. Positive acceleration occurs when an object slows down in the negative direction.
What is an acceleration?In Science, an acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.
How to calculate the acceleration of an object?Mathematically, the acceleration of a physical object or body can be calculated by using this formula:
a = (V - U)/t
Where:
a represents the acceleration.V represents the final velocity.U represents the initial velocity.t represents the time measured in seconds.Generally speaking, a physical object would experience positive acceleration when it either speeds up in the positive direction or slows down in the negative direction.
On the other hand (conversely), a physical object would experience negative acceleration when it either speeds up in the negative direction or slows down in the positive direction.
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The speed of light depends on the medium. Refractive index of the water is 1.33 and for glycerin is 1.473.
The medium determines the speed of light in which light is travelling.
The refractive index is the ratio of the speed of light in the vacuum to the speed of light in that particular medium. The speed of light in a vacuum is 3 x 10⁸ m/s
n = c/v
c = speed of light in the vacuum
v = speed of light in the medium
n = refractive index of the medium
The Refractive index of the water is 1.33 and for glycerin is 1.473. It means the speed of light is more in water than in glycerin. This occurs because of more density in glycerin as compared to water. The material with greater density hampers the speed of light.
Hence, more the refractive index of water slower light travel through it.
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A spring is compressed 0.48 m inside a dart gun. What is the potential
energy of the spring? (k = 800 N/m)
Answer:
92.16J
Explanation:
E = ½ke²
E = ½(800)(0.48)²
E = 400 x 0.48²
E = 92.16
A person is pushing a couch that has a mass of 20 kg. The couch initially accelerates at a rate of 1.5 m/s2. According to Newton’s second law of motion, what is the magnitude of the net force on the couch?
The magnitude of the net force on the couch will be equal to 30 N.
What is force?Force acting on an object can be defined as the effect that changes the state of the body of motion or rest. The force's SI unit is Newton and force is a vector parameter.
The force can be determined from the product of the mass (m) and acceleration (a).
F = ma
Given, the mass of the couch, m = 20 Kg
The couch is accelerating, a = 1.5 m/s²
According to Newton’s second law of motion, the magnitude of the net force on the couch can be calculated as:
F = ma = 20 ×1.5
F = 30 N
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I have found a small piece of rock that I believed is actually gold. The density of gold is 19.3 g/cc. Is there a way that I could find the density of the piece of rock I found? How would I find the density?
You can measure its mass and volume and use the equation density=mass/volume
If you know how to do physics i would appreciate if you help me. i am extremely confused
Answer: position E
Explanation:
After the ball is thrown it has a negative acceleration (it's slowing down) at a rate of 9.8 m/s2 (round that to 10 m/s2), which is g, the rate of acceleration due to gravity. The position of the ball is shown every 1 second. At position B, the ball has a speed of 40 m/s, at C = 30 m/s, at D = 20 m/s, and at E = 10 m/s. Every 1 second, the ball slows down by 10 m/s. At F, the top, the instantaneous speed = 0 m/s. Then the ball will then speed up by 10 m/s every second, until it reaches K, where the speed is back at 50 m/s.
Questions
Answer questions in complete sentences.
1. Compare the accelerations for the three trials. Explain how Newton's second law was demonstrated in the simulation?
2. Describe how Newton's first and third laws would apply to this situation if this simulation was done in the real world.
3. Compare the masses that you calculated for the three trials. If the actual mass of the cart did not change (same cart for all trials), what measurement do you believe contributed the largest amount of error to that calculation? Explain your answer.
Data Collection—Table 1:
Trial Force used (N) Time (s) Distance (m) (fixed) Acceleration (m/s2) Mass (kg)
1 200 4.77 5.0 0.21 952.38
2 300 3.82 5.0 0.34 882.35
3 50 9.39 5.0 0.05 1000
Furthermore, according to Newton's Second Law, the force required to accelerate an object increases with its mass.
What evidence is there for Newton's second law?When a ball is struck, it accelerates to a certain degree. The force exerted on the ball immediately correlates to the acceleration with which it moves. Consequently, Newton's second rule of motion is demonstrated in real life by the fact that the ball moves quicker the harder you strike it.
What is the connection between acceleration and Newton's second law?A force exerted on an object causes it to accelerate in accordance with Newton's Second Law of Motion, commonly referred to as the Law of Force and Acceleration or the Law of Force and Mass.
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a person travels 5 meter east in 20 second and 12 meter north in 45 second. Find its speed and velocity
Answer:
The car goes 100 metres in the east direction,in 4 seconds.
The car goes 50 metres in the west direction,in 1 second.
to find :
The average velocity and average speed of the car.
Explanation:
Speed is a scalar unit which means, direction is not necessary in this case. We can simply divide the total covered distance by the total taken time,in order to calculate the average speed.
So, average speed = (100 m + 50 m)/(4sec + 1sec) = (150m/5sec) = 30m/s
Now, velocity is a vector unit,which means direction is necessary in this case. We need to find the displacement (distance between starting point and ending point of the journey) and we need to divide the displacement with total taken time.
Here,east and west are opposite directions.
So, displacement = 100 m - 50 m = 50 m in east direction
Average velocity = 50m/5sec = 10m/sec
Hence,the average speed is 30m/s and the average velocity is 10m/sec.
Welcome.
A kid is standing on a merry-go-round 1.14 m from the center rotating at 2.38 rad/s. What is his linear velocity?
Answer:
[tex]\huge\boxed{\sf v = 2.7\ m/s}[/tex]
Explanation:
Given data:Radius = r = 1.14 m
Angular velocity = ω = 2.38 rad/s
Required:Linear velocity = v = ?
Formula:v = rω
Solution:v = (1.14)(2.38)
v = 2.7 m/s[tex]\rule[225]{225}{2}[/tex]
The odometer of a car indicates the total distance travelled by the vehicle. A driver looks at his odometer at two instances while he is driving (as shown below). Given that the diameter of the wheels of the vehicle is 75 cm, what is the average number of revolutions completed by each wheel in 1 minute?
A. 71
B. 283
C. 1200
D. 12700
The average number of revolutions completed by each wheel in 1 minute is 283 rounds.
What is distance?
Distance is the amount of space between two points or objects. It is a measure of length and can be measured in a variety of units such as kilometers, miles, or even light-years. Distance is an important concept in mathematics, used to calculate the length of a line segment, the circumference of a circle, the area of a triangle, and the volume of a sphere. It is also used in everyday life, such as calculating the distance between two cities, or the distance a car has traveled. Distance can also be used to compare the size of things, such as the relative distance between planets.
It is symbolized as km /sec.
as per the given question-distance= 20650.5-20950.5=60km
Time = 14:04-12:34=1 hour 30 minutes
1 hour 30 minutes = 90 minutes
wheel radius = 75÷2 = 37.5 cm
wheel circumterence =235.62cm
we know,
Average speed= distance/circumentace /time
60km/235.62cm/90 = 283 rounds.
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The half-life of chromium-51 is 28 days. If the sample contained 510 grams, how much chromium (in grams) would remain after 1 year?
Answer: 0.061gm
Explanation:
The Sun radiates energy at a rate of about 4×1026W. Earth is about 150×106km from the Sun.
Estimate the energy coming to Earth from the Sun each second. The radius of Earth is about 6400 km .
The average intensity received on the Earth's surface is [tex]12.6*10^{10} W/m^{2}[/tex]
[tex]Intensity = Rate of energy radiated/4\pi R^{2}[/tex]
where R is the distance of the earth from the sun.
[tex]I=4*10^{26}/4\pi *[150*106*10^{3}]^{2}[/tex]
[tex]I=0.12597*10^{12}[/tex]
[tex]I=12.6*10^{10} W/m^{2}[/tex]
What is the meaning of the intensity of sunlight?
Sun intensity refers to the amount of incoming solar energy, or radiation, that reaches the Earth's surface. The angle at which the rays from the sun hit the Earth determines this intensity.
What is the average intensity received on the Earth's surface?
The average intensity received on the Earth's surface is given by:
[tex]I=rate of energy radiated/4\pi R^{2}[/tex]
Thus, the average intensity received on the Earth's surface is [tex]12.6*10^{10} W/m^{2}[/tex]
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Need to fill in the blank
Neglecting drag, the cannonball's initial height, and its horizontal motion, the maximum height rise is 110.45 metres, the time it takes for the ball to rise is 4.7 seconds, and the overall flight duration is 9.4 seconds.
Equation:
A pupil propels a cannonball 47.0 metres per second vertically upward.
assuming that the acceleration brought on by gravity is 10 m/s2.
Using the equation U2 = 2gH, the cannonball's highest point will be determined.
where H is the height the cannonball reaches.
When all the figures are put together, 47*47 = 2*10*H
H = 110.45 metres.
The cannonball's ascent time would be given by t=(2H/g).
When all the values are put together, t = (2*110.45/10)t = 4.7 seconds.
The cannonball's total flight time, T, is equal to the sum of its rise and descent times.
The ratio of ascent to descent is time.
Time of ascension = 4.7 Seconds since there is no other acceleration present and it is motion under gravity.
T = 2×(time of ascent) (time of ascent)
9.4 seconds are equal to T = 2*4.7.
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A Composite wall is shown with surface temperatures T0 and TL. Layer 1 has a conductivity k1, Thickness L1 and layer 2 has conductivity k2, thickness L2. The cross sectional area of both layers is A.
L1/k1A + L2/k2A is the total thermal resistance between the surfaces at temperatures T0 and TL.
What does heat resistance actually mean?A measurement of the temperature differential at which a material or item resists the transfer of heat is known as thermal resistance. Thermal resistance is the inverse of thermal conductivity. Since the bulk of electrical components generate heat and need cooling, thermal resistance of materials is of special interest to electronic engineers. Electronic components might malfunction or fail due to overheating, hence special care must regularly be taken while designing those components.
What relationship does thermal conductance have with resistance?Engineering regularly uses another important concept. Since there is a resemblance between the dispersion of heat and electrical charge, engineers typically use the thermal resistance (i.e., thermal resistance vs heat conduction) to compute heat transport through materials. Thermal resistance is the reverse of thermal conductivity.
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The complete question is,
A composite wall is shown with surface temperatures T0 and TL. Layer L1 has conductivity K1, thickness L1 and layer 2 has conductivity k2, thickness L2. The cross-sectional area of both layers is A. The total thermal resistance between the surfaces at temperatures T0 and TL is.
A 50 g ball of clay traveling at speed Vo hits and sticks to a 1.0 kg block sitting at rest on a frictionless surface. What is the speed of the block after the collision? What percentage of the ball's initial energy is "lost"?
0.048 v₀ is the speed of the block after the collision and 95.2 percentage of the ball's initial energy is "lost".
How does collision happen?Particles, groups of particles, or solid objects that are moving in the same direction collide when they are sufficiently close to one another.
Briefing:Ball mass, m1 = 50 g = 0.05 kilogram
ball's velocity, = v₀
brick's mass, m2 Equals 1 kilogram
Let v be the brick's speed following the collision.
Utilize the idea of linear momentum conservation;
m1v0 + m2u2 = v(m1 + m2)
0.05v₀ + 0 = v(1 + 0.05)
0.05v₀ = 1.05 v
v = 0.05v0 / 1.05
v = 0.048 v₀
Consequently, the brick's speed following the contact is 0.048v0.
The entire kinetic energy at rest;
K.E. = 1 / 2 * 1.05 * (0.048 v₀)²
K.E. = 0.012v₀²
How much mechanical energy was lost during the impact;
= 0.025v₀² - 0.012 v₀² / 0.025v₀² * 100%
= 95.2 %
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A copper cable is 1.2 km long and has a cross-sectional area of 5 mm^2. Find its resistance at 80°C if at 20°C the resistivity of copper is 0.02*10^-6ohm m and its temperature coefficient of resistance is 0.004/°C
Explanation:
Equation for resistity
[tex]p(t)= p(0) \times (1 + a \times (change \: in \: temp))[/tex]
[tex] = 0.02 \times {10}^{ - 6} \times (1 + 0.004 \times 60)[/tex]
[tex] = 2.48 \times {10}^{ - 8} ohm \: m[/tex]
[tex]r = (p \times l) \div a[/tex]
[tex] = (2.48 \times {10}^{ - 8} \times 1200) \div \: 5 \times {10}^{ - 6} [/tex]
[tex] = 5.952 \: ohms[/tex]
1. What type of plate boundary is at the point labeled "A"?
2. When an ocean plate converges with another plate, what is created on the seafloor at the line of convergence?
3. What type of plate boundary is being formed at the point labeled "B"?
4. What process is occurring at the points labeled "C "and "D"?
5. How do some rocks store information about Earth's magnetic field?
A specific spot on a tectonic plate border is represented by Point A.
what is tectonic plate border ?
An enormous slab of solid rock with an uneven form known as a tectonic plate is often made up of both continental and oceanic lithosphere rocks. Tectonic plates can be anything from a few hundred and a few thousand kilometres across in size. Among the biggest plates on the earth are the Pacific and Antarctic Plates.
Numerous smaller or less significant tectonic plates are also present. Despite being smaller, the minor plates play a smaller role in forming the earth's surface characteristics. The tectonic plates move like a conveyor belt due to currents in the molten rocks underneath the plates. The interaction where the plates meet or split is where the majority of geologic activity occurs. The plates barely shift a few millimetres annually, though.
A specific spot on a tectonic plate border is represented by Point A. Major tectonic plates are represented by plates X and Y. Labeling has been done for the Hellenic Trench, the minor tectonic plate Anatolian Plate, and the island of Crete. The relative directions of plate motion are shown by arrows.
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Why are S-H bonds longer than O-H bonds?
Answer: S-H bonds are typically longer than O-H bonds because sulfur is larger than oxygen. The size difference between the two atoms means that the electrons in the bond are farther apart in an S-H bond, resulting in a longer bond length. Additionally, sulfur is less electronegative than oxygen, which means that the electrons in the bond are less strongly attracted to the sulfur atom and are therefore more likely to be found in the region between the two atoms, further increasing the bond length.
Explanation:
Answer:
Describe the differences between the O-H and S-H bond lengths. Due to its stronger shielding, which lessens the nuclear pull for the bonding electrons and causes a longer bond length, sulfur is a bigger atom than oxygen.
Explanation:
Review what you learned in the unit about attribution theory. Explain in your own words what it is. Describe how attributions affect the way we explain behavior. In what way can attribution theory be harmful? In what way can it be helpful?
Attribution theory describes how an individual says or thinks that something is a as a result of a person's deed or an action of an external factor.
The cause of behavior is attributed to some internal characteristic of a person rather than external forces.
It can be harmful because attributing a person's character to a mistake can lead to underestimation of an individual.
Attribution helps an individual to understand the reason behind another person's behavior and thinking.
What is Attribution theory?Attribution theory is related to how ordinary people explain the causes of behavior and events that follow it. This helps them understand how they receive, interpret action, and how they give form an opinion of them.
When an person displays certain behaviors, they are usually attributed to certain internal characteristics. This theory can be harmful to explaining behavior because mistakes are attributed to character instead of external factors leading to underestimating people. On the other hand, it is beneficial to understanding people.
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A solar panel receives energy from the Sun at a rate of 5.0 kW.
Thermal energy is transferred from the solar panel to water with an efficiency of 20%.
Cold water of mass 15 kg enters the solar panel every hour.
The specific heat capacity of water is 4200 J/(kg °C).
Calculate the temperature increase of the water.
The temperature increase of the water is 57.1⁰C.
What is the change in temperature of the water?
The temperature increase of the water is determined by calculating the change in temperature of the water.
Q = mcΔθ
where;
Q is the quantity of heat transferred to the waterm is the mass of the waterΔθ is the change in temperature1 hour = 3600 seconds
The quantity of heat water transferred to the water = e x P x t
where;
e is the efficiency of the solar panelP is powert is the time duration( 0.2 x 5,000 x 3600 ) = 15 x 4200 x Δθ
3,600,000 = 63,000Δθ
Δθ = 3,600,000 / 63,000
Δθ = 57.1 ⁰C
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Choose the one which is False.
1. If the speed changes, the velocity also changes.
2. If the speed changes, there is acceleration.
3. If the speed does not change, but the direction changes, there will be acceleration.
4. Motion with constant velocity is accelerated motion.
5.
Motion along a straight line is Linear motion.
Answer:
4
Explanation:
1 is true. Speed is the magnitude of velocity so if the magnitude of velocity(speed) changes, then velocity changes itself.
2 is true.
[tex]a _{avg} = \frac{v _{f} - v _{i} }{t} [/tex]
Since speed changes, the inital and final speeds are different, therefore we will have some nonzero acceleration because the numerator does not equal zero.
3 is correct, acceleration is a vector so it has direction, meaning if the direction of speed changes then we will have acceleration.
4. is false, a constant velocity has a acceleration of 0.
5 is correct, motion along a straight line is linear.
A skateboarder with a mass of 120 kilograms (including the skateboard) is traveling at a speed of 5.00 meters per second upon reaching the bottom of a ramp. Between the top of the ramp and the bottom, the skateboarder lost 150 joules of thermal energy due to friction. What was the potential energy of the skateboarder at the top of the ramp?
6,150 J.
5,850 J.
1,650 J.
1,350 J.
The potential energy of the skateboarder at the top of the ramp was 1650 joule.
What is laws of conservation of energy?The law of conservation of energy asserts, in essence, that: The total energy of the system is preserved in a closed system, or a system that is separated from its surroundings.
Given that: A skateboarder with a mass of 120 kilograms (including the skateboard) is traveling at a speed of 5.00 meters per second upon reaching the bottom of a ramp.
So, his kinetic energy = 1/2×mass×speed² = 1/2 × 120 × 5² = 1500 Joule.
Loss of energy due to friction = 150 joule.
So, the potential energy of the skateboarder at the top of the ramp be = 1500 Joule + 150 joule = 1650 joule.
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The picture below shows a prominence in the sun's atmosphere.
The picture shows the surface of the sun with a curved layer of flame representing prominence rising from the surface of the sun.
Which of these events is most likely to occur as a result of the prominence?
the corona would become visible
the auroras would become visible
the sun's photosphere would be blocked
the sun's magnetic effect would decrease
Since the surface of the Sun has a curved layer of flame that represent prominence rising from the surface of the Sun, an event which is most likely to occur as a result of the prominence is: B. the auroras would become visible.
What is the Sun?In Science, the Sun can be defined as an astronomical or celestial body that is typically found within the solar system around which planetary (astronomical) bodies orbit, and whose light shines on planet Earth to differentiate day and night.
What is a solar prominence?A solar prominence is also known as filament and it can be defined as a large, bright, dense cloud of luminous ionized gas such as hydrogen, sodium calcium, etc., that erupts and extends from the surface of the Sun.
Based on astronomical records, a solar prominence can linger in the corona for a very long time, reaching hundreds of thousands of kilometers into the Sun's atmosphere (space). Consequently, this solar prominence would make the auroras (polar lights) to become visible.
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the beam has a rectangular cross section and is subjected to the loadings shown. determine the principal stresses at point a and point b, which are located just to the left of the 20-kn load. show the results on elements located at these points.
To determine the principal stresses at points A and B, we need to consider how these forces are distributed over the surface of the volume element. The principal stresses are the stresses that act along the directions of maximum and minimum stress on the element.
To determine the principal stresses at points A and B, we need to consider the forces acting on a small volume element located at these points.
The stress on a volume element is defined as the force acting on the element per unit area. The stress components at a point can be represented by a stress tensor, which is a 3x3 matrix with nine elements. The diagonal elements of the stress tensor represent the normal stress components, while the off-diagonal elements represent the shear stress components.
In this case, we are given that the beam has a rectangular cross-section and is subjected to the loadings shown. There is a vertical force F acting on the beam at point A, as well as a horizontal force P. The beam is also subjected to a moment M about the z-axis.
To find the principal stresses, we can first calculate the normal stress components and shear stress components at the points of interest. Then, we can use the equations of mechanics to determine the principal stresses by finding the eigenvalues of the stress tensor.
To do this, we need to know the dimensions of the volume element, as well as the magnitudes of the forces and moments acting on the beam. With this information, we can use the equations of statics to solve for the stress components at points A and B, and then use the equations of mechanics to determine the principal stresses at these points.
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On a hot summer day, you decide to make some iced tea. First, you brew 1.50 L of hot tea and leave it to steep until it has reached a temperature of tea = 75.0 ∘C. You then add 0.975 kg of ice taken from the freezer at a temperature of ice = 0 ∘C. By the time the mix reaches equilibrium, all of the ice has melted. What is the final temperature T of the mixture? Find the equilibrium final temperature T of the system.
The final temperature of the mixture is 17.9 °C.
How find the final temperature?The final temperature of the mixture can be found using the formula for heat exchange between two bodies at different temperatures: Q = mcΔT, where Q is the heat exchanged, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
For the tea, Q = mcΔT = (4.18 J/g·°C)(1.50 L)(1000 g/L)(75.0 - T)
For the ice, Q = mcΔT = (2.09 J/g·°C)(0.975 kg)(0 - T)
Since the total heat in the system is conserved, the heat gained by the tea is equal to the heat lost by the ice. So, we can set the two equations equal to each other and solve for T.
(4.18 J/g·°C)(1.50 L)(1000 g/L)(75.0 - T) = (2.09 J/g·°C)(0.975 kg)(0 - T)
T = (75.0 - (2.09 J/g·°C)(0.975 kg)/(4.18 J/g·°C)(1.50 L)(1000 g/L)) = 17.9 °C
So, the final temperature of the mixture is 17.9 °C.
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