Three polarizing filters are shown in the figure below. The alignment of each filterâs transmission axis is shown, as measured from the vertical. Show calculations to justify all of your answers.Angles: 0, 70, and 90a. Unpolarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?b. Vertically polarized light, with an intensity I0 passes through the three filters. What is the intensity of the transmitted light?c. Is it possible to remove a polarizer from this collection of filters so that unpolarized light transmitted from the left is not transmitted at all? If so, which filter?
Answer: B.
Explanation:
Hope help :p
A) The intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
B) The intensity of the transmitted light will be equal to the initial intensity, I0.
C) The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Polarizing filters are optical devices that allow light waves vibrating in a specific direction to pass through while blocking or attenuating light waves vibrating in other directions. The alignment of a polarizing filter's transmission axis refers to the direction in which it allows light to pass through with maximum intensity.
a. Unpolarized light passing through a polarizing filter will have its intensity reduced by a factor called the transmittance, which depends on the angle between the polarization direction of the incident light and the transmission axis of the filter. If the incident light is unpolarized, it contains an equal distribution of light waves vibrating in all possible directions.
As a result, when unpolarized light passes through a polarizing filter, only the component of light vibrating parallel to the transmission axis will be transmitted, while the perpendicular components will be blocked. Therefore, the intensity of the transmitted light will depend on the angle between the polarization direction of the incident light and the transmission axis of each filter.
b. Vertically polarized light has its electric field oscillating only in the vertical direction. When vertically polarized light passes through a polarizing filter whose transmission axis is aligned with the vertical direction, it will pass through with maximum intensity. Therefore, the intensity of the transmitted light will be equal to the initial intensity, I0.
c. In general, if you have a collection of polarizing filters with different transmission axes, it is possible to remove a polarizer so that unpolarized light transmitted from the left is not transmitted at all. This can be achieved by removing the filter whose transmission axis is perpendicular to the direction of polarization of the incident light. The filter that blocks light vibrating perpendicular to its transmission axis is typically called a "crossed" polarizer.
Specific calculations and analysis of the figure you provided would require more detailed information, such as the transmittance characteristics of each filter at different angles. Without the figure or additional data, it is not possible to provide precise calculations or identify the exact filter that should be removed to block unpolarized light.
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What's centrifugal force
GOOGLE: Centripetal force is defined as, "the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation," while centrifugal force is defined as "the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of
I don't actually know what that is but I hope this helps! Good luck!
What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?
Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
[tex]a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2[/tex]
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
Find the magnitude of the buoyant force on the block. The acceleration of gravity is 9.8 m/s 2 . Answer in units of N.
Which of the following substances is a compound?
O A. hydrogen gas
B. nitrogen gas
O c. table sugar
O D. oxygen gas
Table sugar is a compound, it consists of carbon, hydrogen, and oxygen.
Hence, C is the correct answer.
What is the chemical state of matter?The chemical state of matter consists :
ElementCompound andMixturesElement-The substance which contains only one atom and cannot be broken down. Example-Hydrogen.Compound-It is defined as a substance formed when two or more chemical elements are chemically bonded together. The substance can be pure or impure.Mixture-It contains two or more elements or compounds, but they are not chemically combined. Mixtures are of two types :Homogeneous mixture and,Heterogeneous mixtureHence, table sugar is a compound because it is formed by more than 2 chemical elements, and they are chemically bonded together.
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HELP!!
You are traveling at a speed of 70 miles per hour. How long did it take you to travel 2400 miles?
Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3
100 Points !!!!!!!! I WILL GIVE BRAINLIEST
Answer: 1. 0.25 m/s squared
2. A = 0.4 m/s^2
3.=20kg. I did this before.
Explanation:
Answer:
Answer: 1. 0.25 m/s squared
2. A = 0.4 m/s^2
3.=20kg.
Explanation:
brainliest? ill answer more of your recent questions!!
A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the end of the spring of _____ m.
Answer:k=1175
Explanation:thank you for asking
A 20.0 cm wrench is used to generate a torque at a bolt. A force of 50 N is applied at the end of the wrench at an angle of 60.0 degrees to the wrench. The torque generated at the bolt is A. 4.9 N•m. B. 5.7 N•m. C. 6.0 N•m. D. 7.5 N•m. E. 8.7 N•m.
Answer:
The correct option is E
Explanation:
From the question we are told that
The length of the wrench which is also the radius of the circle made by the wrench is [tex]l =r = 20.0 \ cm = 0.2 \ m[/tex]
The force is [tex]F = 50 \ N[/tex]
The angle is [tex]\theta = 60^o[/tex]
Generally the torque generated by the bolt is mathematically represented as
[tex]\tau = F * sin (\theta ) * r[/tex]
=> [tex]\tau = 50 * sin (60 ) * 0.2[/tex]
=> [tex]\tau = 8.7 \ N \cdot m[/tex]
A tennis ball is thrown against a vertical concrete wall that is fixed to the ground. The ball bounces off the wall. How does the force exerted by the ball on the wall compare with the force exerted by the wall on the ball
А The force exerted by the ball is greater
B The forces exerted by the ball and the wall have the same magnitude.
C. The force exerted by the ball is smaller
D The relative magnitudes of the forces cannot be determined without knowing how long the ball and the wall are in contact
Answer:
The forces exerted by the ball and the wall have the same magnitude
Explanation:
Newton's Third Law Dictates Such
When a tennis ball is thrown against a vertical concrete wall that is fixed to the ground. The ball bounces off the wall because the forces exerted by the ball and the wall have the same magnitude but are opposite in direction, therefore the correct answer is option B.
What is Newton's third law of motion?Newton's third law of motion explains that forces exist in pairs. It states that for every action force there exists equal and opposite reaction forces, these pairs of forces are equal in magnitude but opposite in direction.
As given in the problem when a tennis ball is launched up against a fixed-to-the-ground vertical concrete wall.
Because the forces being applied by the ball and the wall are equal in magnitude but directed differently, the ball bounces off the wall.
Thus, the correct answer is option B.
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Calculate the wavelengths of a 1530 kHz AM radio signal, a 105.1 MHz FM radio signal, and a 1.90 GHz cell phone signal.
Answer:
196.07 m, 2.85 m and 0.15 m
Explanation:
Frequency of AM radio signal, f₁ = 1530 kHz
Its wavelength can be given by :
[tex]\lambda_1=\dfrac{c}{f_1}\\\\=\dfrac{3\times 10^8}{1530\times 10^3}\\\\=196.07\ m[/tex]
Frequency of FM radio signal, f₂ = 105.1 MHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{105.1\times 10^6}\\\\=2.85\ m[/tex]
Frequency of cell phone signal, f₃ = 1.9 GHz
Its wavelength can be given by :
[tex]\lambda_2=\dfrac{c}{f_2}\\\\=\dfrac{3\times 10^8}{1.9\times 10^9}\\\\=0.15\ m[/tex]
Hence, the required wavelengths are 196.07 m, 2.85 m and 0.15 m respectively.
How are all paths that have a displacement of zero similar?
Answer:
Any situation that has a path that stops at the same position that it started from has a displacement of zero
Explanation:
hope it helps
Juan is making ice tea. When he adds ice to the tea, why does the tea cool down?
Answer: because the ice was cold, and it melted in the tea. So the tea is now cooler.
Explanation:
If 3 cups are sitting outside on a hot summer day, which cup will gain the most heat? Cup A starts a little above freezing, Cup B is initially room temperature, and Cup C is just below boiling.
A-Hot
B- Room
C- Cold
D- None, the heat doesn't change
Answer:
c- cold
Explanation:
1. What outdoor activities do you prefer? Why? 2. What outdoor activities are you interested in, but have never tried?
The outdoor activities u prefers most is swimming because I feel relaxed after that.
The outdoor activities I am more interested in but I have not tried is mountain climbing.
What is outdoor activities?Outdoor activities refers to exercises or activities that is carried out outside an enclosed areas. These include swimming, mountain climbing, running and the rest.
Therefore, The outdoor activities u prefers most is swimming because I feel relaxed after that.
The outdoor activities I am more interested in but I have not tried is mountain climbing.
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To exercise, a man attaches a 4.0 kg weight to the heel of his foot. When his leg is stretched out before him, what is the torque exerted by the weight about his knee, 40 cm away from the weight? Use g = 10 m/s2. A. 160 Nâm B. 16 Nâm C. 1600 Nâm D. 1.6 Nâm
Answer:
B. τ = 16 Nm
Explanation:
In order to find the torque exerted by the weight attached to the heel of man's foot, when his leg is stretched out. We use following formula:
τ = Fd
here,
τ = Torque = ?
F = Force exerted by the weight = Weight = mg
F = mg = (4 kg)(10 m/s²) = 40 N
d = distance from knee to weight = 40 cm = 0.4 m
Therefore,
τ = (40 N)(0.4 m)
B. τ = 16 Nm
The torque exerted by the weight about his knee, 40 cm away from the weight is: D. 1.6 Nm
Given the following data:
Mass = 4.0 kgDistance = 40 cm to m = 0.04 metersAcceleration due to gravity (g) = 10 [tex]m/s^2[/tex].To determine the torque exerted by the weight about his knee, 40 cm away from the weight:
First of all, we would calculate the force being exerted by the weight on his heel.
[tex]Force = mg\\\\Force = 4 \times 10[/tex]
Force = 40 Newton
Mathematically, torque is given by the formula:
[tex]Torque = force \times distance[/tex]
Substituting the given parameters into the formula, we have;
[tex]Torque = 40 \times 0.04[/tex]
Torque = 1.6 Nm
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A 4 kilogram box is at rest on a frictionless floor. A net force of 12 newtons acts on it. What is the acceleration of the box?
Answer:
3 m/s^2Explanation:
Step one:
given
Mass m= 4kg
Force F= 12N
Required
Acceleration the relation between force, acceleration, and mass is Newton's first equation of motion, which says a body will continue to be at rest or uniform motion unless acted upon by an external force
F=ma
a=F/m
a=12/4
a=3 m/s^2
What changes occurred when you heated sugar ?
Please help
Test
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
250 BC by Aristarchus is the answer ot the question
Data supporting the theory of a round earth was collected as early as _____.
1570 AD by Galileo
1500 AD by Copernicus
250 BC by Aristarchus
1640 AD by Kepler
A 200 W light bulb connected across a 110 V dc power supply. (A) What current will flow through this bulb? (B) What is the resistance of the light bulb?
Answer:
I=1.8amps
R=60.5ohms
Explanation:
Step one:
given data
power = 200W
voltage = 110v
. (A) What current will flow through this bulb
we know that the formula relating power, current and voltage is
P=IV
I=P/V
I=200/110
I=1.8amps
(B) What is the resistance of the light bulb?
we know that the formula relating resistance power and voltage is
[tex]P=\frac{V^2}{R}[/tex]
substituting our data we have
[tex]200=\frac{110^2}{R}\\\\[/tex]
cross multiply we have
[tex]200*R=110^2\\\\200*R=12100\\[/tex]
divide both sides by 200
we have
R=12100/200
R=60.5ohms
(A) The current will flow through this bulb will be 1.8amps
(B) The resistance of the light bulb will be 60.5ohms.
What is resistance?Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The given data in the problem is;
P is the power= 200 W
V is the voltage= 110 V
I is the current
R is the resistance
(A) The current will flow through this bulb will be 1.8amps
The relationship between the power and the voltage is given by;
[tex]\rm P=IV\\\\\ I=\frac{P}{V} \\\\ I=\frac{200}{110} \\\\\ I=1.8amps[/tex]
Hence the current will flow through this bulb will be 1.8amps
(B) The resistance of the light bulb will be 60.5ohms.
The relationship between the power and the resistance is given by;
[tex]\rm P= \frac{V^2}{R} \\\\ \rm R= \frac{V^2}{P} \\\\ \rm R= \frac{(110)^2}{200} \\\\ \rm R=60.5 \ ohm[/tex]
Hence he resistance of the light bulb will be 60.5ohms.
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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 G to 1.60 M in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20 Ω?
Complete Question
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of [tex]1.20 \ \Omega[/tex]
Answer:
The current is [tex]I = 0.0007 41 \ A[/tex]
Explanation:
From the question we are told that
The area is [tex]A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2[/tex]
The initial magnetic field at [tex]t_o = 0 \ seconds[/tex] is [tex]B_i = 0.500 \ T[/tex]
The magnetic field at [tex]t_1 = 0.99 \ seconds[/tex] is [tex]B_f = 1.60 \ T[/tex]
The resistance is [tex]R = 1.20 \ \Omega[/tex]
Generally the induced emf is mathematically represented as
[tex]\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }[/tex]
=> [tex]\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }[/tex]
=> [tex]\epsilon = 0.000889 \ V[/tex]
Generally the current induced is mathematically represented as
[tex]I = \frac{\epsilon}{R }[/tex]
=> [tex]I = \frac{0.000889}{ 1.20 }[/tex]
=> [tex]I = 0.0007 41 \ A[/tex]
You have learned how to create an effective study space in this learning path.
What has been the biggest change you have made in your study space?
Give at least one specific example.
How has the information you have learned (and the possible changes you have made) already been a benefit to you?
Your answer should be at least two complete sentences.
Answer:
Getting comfy but not too comfy
Explaination : Some people work the majority of their lives in sweat pants and a grungy t-shirt; others dress in full business attire before sitting down at the desk in their study. Because I want to enjoy the place where I study, I say be comfortable—but not too comfortable. I change out of my pajamas before I crack open my books to give my mind another signal that this isn’t lounge time, but study time.
A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 150 rad/s^2. Determine the mass of the disk.
Answer:
m = 4.0 Kg
Explanation:
Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:[tex]\tau_{ext} = I* \alpha (1)[/tex]
Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:[tex]\tau = F*r*sin 90 = F*r (2)[/tex]
For a solid disk, the rotational inertia regarding an axis through its center, and perpendicular to its face is as follows:[tex]I = \frac{m*r^{2}}{2} (3)[/tex]
Replacing (3) in (1), and (2) in the left side of (1) also, we can solve for m, as follows:[tex]m = \frac{2*30.0N}{0.1m*150(1/s2)} = 4.0 Kg (4)[/tex]
So, the mass of the disk is 4.0 Kg.Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?
Fp, Ff, and Fg
Fp and FN
Fp, Fg, and Ff
Fp and Fg
Answer:
Answer is D: D.Fp and Fg
Explanation:
I did the quiz some time ago and rember it hope it helps.
Answer:
i just finish its d
Explanation:
A metal wire of resistance R is cut into six equal pieces that are then placed together side by side to form a new cable with a length equal to one-sixth the original length. What is the resistance of this new cable?
Answer:
d ko alam wag puro asa sa app
In a pig caller can produce a sound intensity level of 107 dB. How many pig callers would be needed to generate an intensity level of 120 dB, assuming each caller can individually produce a sound intensity level of 107 dB
Answer:
20 pig callers
Explanation:
Given that:
A pig caller produced intensity level of a sound = 107 dB
To find how many pig callers required to generate an intensity level of 120 dB;
we have:
120 dB - 107 dB = 13 dB
Taking the logarithm function;
[tex]10 \ log \bigg(\dfrac{I}{I_o} \bigg) = 13 \ dB[/tex]
where;
[tex]I_o[/tex] = initial intensity
[tex]log \bigg(\dfrac{I}{I_o} \bigg) = 1.3[/tex]
[tex]\dfrac{I}{I_o}= 10^{1.3 }[/tex]
I = 19.95[tex]I_o[/tex]
I ≅ 20 pig callers
Jeff was riding in a car with a textbook sitting on the seat beside him. When would the textbook demonstrate the GREATEST effect of inertia?
А
When the car makes a sudden stop,
B
When the car changes into another lane.
С
When the car slows down gradually.
D
When the car runs out of gas and rolls to a stop
A stone is dropped from the top of a cliff which is 10-m high. What is its velocity when it hits the ground? Sketch the stones position vs time and velocity vs time graphs.
S = displacement
V = final velocity
U = initial velocity
What 4 types of atoms/molecules can you choose from? Which is currently selected?
Answer:
Different Kinds of Atoms
Description. Atoms are made of tiny particles called protons, neutrons and electrons. ...
Stable. Most atoms are stable. ...
Isotopes. Every atom is a chemical element, like hydrogen, iron or chlorine. ...
Radioactive. Some atoms have too many neutrons in the nucleus, which makes them unstable. ...
Ions. ...
Antimatter.
Explanation:
All of the following are categories used to classify problems except problems of
A. arrangement
B. inducing structure
C. transformation
D. schematic completion
Answer:D. schematic completion
Explanation:The rest are actual categoroes
Answer:
schematic completion
Explanation:
got it right on edge