ASAP 1. what is the mass, in Kilograms, of a star that is 1.5×10^2 times thw mass of the sun? The sun's mass is 2.0×10^30 kg. Express the answer in Scientific notation. 2. Solve Apply the concepts to this problem. Set up the problem. (2.0 X 10^30) X (1.5 X 10^2) Multiply the coefficients. (2.0 X 10^30) X (1.5 X 10^2), (2.0 X 1.5) = 3.0 Then add the exponents. (2.0 X 10^30) X (1.5 X 10^2) = (10^30 X 10^2) = 10^30 + ^2 = 10^32, Combine the results of the two operations. (2.0 X 10^30) X (1.5 X 10^2) = 3.0 X 10^32 The star's mass is 3.0 x 10^32 kg.

* Muliply numbers written in Scientific notation by multiplying the coefficients and then adding the exponents. you will get Free huge point and a Crown!​

Answer:

first answer

Step-by-step explanation:

Hi, this is correct because repeating decimals are rational numbers.

Rational numbers can be written by a fraction of integers.

If there is a pattern, it means that this is the division of two integers.

hope this helps

Answer:

yes

Step-by-step explanation:

Answer:

2 and 4.

Step-by-step explanation:

(x+2)^2 - x^2 = 12

x^2 + 4x + 4 - x^2 = 12

4x + 4 = 12

4x = 8

x = 2.

Hence the integers are 2 and 4.

Answer:

Option C

Step-by-step explanation:

[tex]f(x) = 40( \frac{1}{4} )^{x} [/tex]

Answer: its a

Step-by-step explanation:

[tex]-5*(-7)=35[/tex]

[tex]|35|=35[/tex]

[tex]-1*35=-35[/tex]

Hope this helps.

頑張って!

Answer:

It has 1 solution

[tex]x=5[/tex]

Step-by-step explanation:

Given

[tex]x - 5 = 5 - x[/tex]

Required

Determine the number of solution

[tex]x - 5 = 5 - x[/tex]

Collect Like Terms

[tex]x + x = 5 + 5[/tex]

[tex]2x = 10[/tex]

Divide both sides by 2

[tex]\frac{2x}{2} = \frac{10}{2}[/tex]

[tex]x = \frac{10}{2}[/tex]

[tex]x = 5[/tex]

Since the value of x is 5, then the equation has 1 solution

[tex]x = 5[/tex] is its only value

Answer:

x = 36 degrees, the smaller angle.

4(36) = 144 degrees, The larger angle.

36 + 144 = 180 degrees.

Cleomenius.

Answer:

x = 36 degrees, the smaller angle.4(36) = 144 degrees, The larger angle.36 + 144 = 180 degrees.

Step-by-step explanation:

(1)adjacent- two non-overlapping angles that share a common vertex and a common side

(2)the non-common sides are opposite rays.

(3)adds up to 180

Answer:

5

Step-by-step explanation:

g(x) = 3 - 2x

Let x= -1

g(-1) = 3 - 2*-1

      = 3 - -2

     = 3+2

     = 5

Answer:

5

Step-by-step explanation:

g(-1)=3-(2(-1))

g(-1)=3+2

g(-1)=5

Answer:

Option (B)

Step-by-step explanation:

There are two lines PS and QT intersecting each other at a point M.

It's given that m∠PMT = 128° and m∠QMR = 90°

Since ∠PMT and ∠QMS are the vertical angles so these angles will be equal in measure.

∠PMT = ∠QMS

128° = m∠QMR + m∠RMS

128° = 90° + m∠RMS

m∠RMS = 128° - 90°

m∠RMS = 38°

Therefore, Option (B) will be the answer.

Answer:

BC, BD

Step-by-step explanation

If right please brainly

Answer:

1) 3

2) 7

3) 4

4) 13

5) 5

6) 6

7) 11

8) 8

9) 7

10)80*

11)45*

12) Can't really see sorry

13) Is that the whole question? If not just comment the whole thing and Il'l try answer it ☺ Hope that helped!

Answer:

1. RS = - 2-(-5) = 3

2. R5 = 2 -(-5) = 7

3. ST = 2- (-2) = 4

4. RU = 8-(-5) = 13

5. PQ is a straight line with the length of 5 units.

6. QR is a straight line with the length of 6 units.

7. PR is a straight line with the length of 11 units.

8. AC = 24

4x=24

x=6

AB=6

9. BC = 15

3x=15

BD = 3x + 4x - 13

= 22

I might be wrong

Answer:

B. 3

Step-by-step explanation:

Start with the inside brackets where we have g(3). As seen, g(3) is given to be =2 so g(3) inside the bracket is now replaced with 2, giving us f(2). F(2) is given as 3, therefore the answer is B. 3

Hope this helped!

Answer: March to April shows the least increase of average temperature.

Answer:

It’s d

Step-by-step explanation:

Answer:

[tex] 3^2 \times 3^5 = 3^7 [/tex]

3^2 * 3^5 = 3^7

Step-by-step explanation:

I assume you mean this:

[tex] 3^2 \times 3^5 [/tex]

If so, then the rule is that when you multiply two numbers with the same base, you give the same base and add the exponents.

[tex] 3^2 \times 3^5 = 3^{2 + 5} = 3^7 [/tex]

Answer:

  6 minutes

Step-by-step explanation:

'a' in the formula represents altitude in feet. You are told the altitude is 21000 feet, so put that into the formula:

   21000 = 3400t +600

You can solve this for t:

  20400 = 3400t . . . . . subtract 600 from both sides

  6 = t . . . . . . . . . . . . . . . divide both sides by 3400

The problem statement tells you that t represents minutes after lift off, so this solution means the altitude is 21000 feet 6 minutes after lift off.

The question is asking for the number of minutes after lift off that the plane reaches an altitude of 21000 feet, so this answers the question directly:

  The plane is at an altitude of 21000 feet 6 minutes after lift off.

Answer:

3

Step-by-step explanation:

18/6 = 3

Answer:

2+2=4

Step-by-step explanation:

Answer:

g = 14

Step-by-step explanation:

g + 3 = 17

minus 3 from both sides

g = 14

Answer:

1.618

Step-by-step explanation:

Also known as the golden ratio.Golden ratio, also known as the golden section, golden mean, or divine proportion, in mathematics, the irrational number (1 + Square root of√5)/2, often denoted by the Greek letter ϕ or τ, which is approximately equal to 1.618.

HOPE THIS HELPED!

Answer:

Well, in this case all the students selected live in the dorms, so it is actually likely that they eat in the cafeteria regularly.

For example, a student that lives in a house (with family, friends, etc) may have access to eat in his own place or may have larger economic freedom, so maybe they go and eat out. In this group, you may find that the probability for a randomly selected student eats in the cafeteria regularly may be smaller than in the group of the students that live in the dorms.

So the sample will be biassed towards eating regularly in the cafeteria.

Answer:

4:18, 6:27, etc

Step-by-step explanation:

Basically, anything x 2 and x 9 would be equivalent as a ratio

Answer:

4:18

Step-by-step explanation:

times them both by two

Answer:  see proof below

Step-by-step explanation:

Use the following Sum to Product Identities:

[tex]\sin x+\sin y=2\sin \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\sin x-\sin y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=2\cos \bigg(\dfrac{x+y}{2}\bigg)\cos \bigg(\dfrac{x-y}{2}\bigg)\\\\\\\cos x+\cos y=-2\sin \bigg(\dfrac{x+y}{2}\bigg)\sin \bigg(\dfrac{x-y}{2}\bigg)[/tex]

Proof LHS → RHS

[tex]\text{LHS:}\qquad \qquad \qquad \dfrac{\sin 5-\sin 15+\sin 25 - \sin 35}{\cos 5-\cos 15- \cos 25 + \cos 35}[/tex]

[tex]\text{Reqroup:}\qquad \qquad \qquad \dfrac{(\sin 25+\sin 5)-(\sin 35 + \sin 15)}{(\cos 35+\cos 5)-(\cos 25 + \cos 15)}[/tex]

[tex]\text{Sum to Product:}\quad \dfrac{2\sin \bigg(\dfrac{25+5}{2}\bigg)\cos \bigg(\dfrac{25-5}{2}\bigg)-2\sin \bigg(\dfrac{35+15}{2}\bigg)\cos \bigg(\dfrac{35-15}{2}\bigg)}{2\cos \bigg(\dfrac{25+15}{2}\bigg)\cos \bigg(\dfrac{25-15}{2}\bigg)-2\cos \bigg(\dfrac{35+5}{2}\bigg)\cos \bigg(\dfrac{35-5}{2}\bigg)}[/tex][tex]\text{Simplify:}\qquad \qquad \dfrac{2\sin 15\cos 10-2\sin 25\cos 10}{2\cos 20\cos 15-2\cos 20\cos 5}[/tex]

[tex]\text{Factor:}\qquad \qquad \dfrac{2\cos 10(\sin 15-\sin 25)}{2\cos 20(\cos 15-\cos 5)}[/tex]

[tex]\text{Sum to Product:}\qquad \dfrac{\cos 10\bigg[2\cos \bigg(\dfrac{15+25}{2}\bigg)\sin \bigg(\dfrac{15-25}{2}\bigg)\bigg]}{\cos 20\bigg[-2\sin \bigg(\dfrac{15+5}{2}\bigg)\sin \bigg(\dfrac{15-5}{2}\bigg)\bigg]}[/tex]

[tex]\text{Simplify:}\qquad \qquad \dfrac{\cos 10[2\cos 20\sin (-5)]}{\cos 20[-2\sin 10\sin 5]}\\\\\\.\qquad \qquad \qquad =\dfrac{-2\cos10 \cos 20 \sin 5}{-2\sin 10 \cos 20 \sin 5}\\\\\\.\qquad \qquad \qquad =\dfrac{\cos 10}{\sin 10}\\\\\\.\qquad \qquad \qquad =\cot 10[/tex]

LHS = RHS:  cot 10 = cot 10   [tex]\checkmark[/tex]

Answer:

Im not sure but hiiiiiiiiii.

Step-by-step explanation:

Answer:

14300

Step-by-step explanation:

12500-26800

Answer:

a). Cards (1) and (4)

b). Cards (3) and (5)

Step-by-step explanation:

(a). From the cards attached,

  If card (1) is rotated by an angle of 180° counterclockwise, we get the image given in card (4).

  Therefore, card (4) will be the image of card (1) after a rotation.

(b). If we reflect card (3) across a horizontal line (or x- axis) image card (4) is obtained.

   Therefore, card (3) and card (5) is the pair of cards.