Answer: Aspirin is recommended as initial treatment to prevent recurrent ischemic stroke. Clopidogrel is recommended as an alternative monotherapy and in patients allergic to aspirin. The combination of clopidogrel and aspirin is not recommended for long-term use (more than two to three years) because of increased bleeding risk. Aspirin has been shown to lower the risk of heart attack and stroke in patients who have cardiovascular disease.
Explanation:
What is the sun 70% made of?
Answer:
hydrogen
Explanation:
The Sun is a huge, glowing sphere of hot gas. Most of this gas is hydrogen (about 70%) and helium (about 28%). Carbon, nitrogen and oxygen make up 1.5% and the other 0.5% is made up of small amounts of many other elements such as neon, iron, silicon, magnesium and sulfur.
The sun is 70% made of Hydrogen.
What is hydrogen?
The element hydrogen has the sign H and the atomic number 1. The lightest element is hydrogen. Under normal conditions, hydrogen is a gas composed of diatomic molecules with the formula H2. It has no colour, no odour, no taste, is non-toxic, and is extremely flammable. Hydrogen is the most prevalent chemical element in the universe, accounting for approximately 75% of all normal matter. The Sun and other stars are mostly made up of hydrogen in the plasma state. The majority of hydrogen on Earth resides in molecule forms like water and organic substances. Each atom of hydrogen's most common isotope (symbol 1H) has one proton, one electron, and no neutrons.
The sun is around 70% made of Hydrogen and 28% Helium
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I am not sure how to approach this question.
Answer:
35.2 AU
Explanation:
Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.
[tex]\boxed{T^2 \propto a^3 \implies T^2=ka^3}[/tex]
Kepler's Third Law
[tex]T^2=\dfrac{4 \pi^2}{GM}a^3[/tex]
where a is the semi-major axis of the ellipse.
If expressed in the following units:
T = Earth years.a = Astronomical units AU (a=1 AU for Earth).M = Solar masses.then:
[tex]\implies\dfrac{4 \pi^2}{GM}=1[/tex]
Therefore Kepler's Third Law can be expressed as:
[tex]\boxed{T^2=a^3}[/tex]
Given:
T = 75.6 yearsFrom inspection of the given diagram:
[tex]\implies 2a=x+0.57[/tex]
[tex]\implies a=\dfrac{x+0.57}{2}[/tex]
Substitute these values into the equation and solve for x:
[tex]\implies (75.6)^2=\left(\dfrac{x+0.57}{2}\right)^3[/tex]
[tex]\implies (75.6)^\frac{2}{3}=\dfrac{x+0.57}{2}[/tex]
[tex]\implies 2(75.6)^\frac{2}{3}=x+0.57[/tex]
[tex]\implies x=2(75.6)^\frac{2}{3}-0.57[/tex]
[tex]\implies x=35.1883819...[/tex]
[tex]\implies x=35.2\; \text{AU}[/tex]
given an angle of incidence of ice as 40 degree and angle of refraction of 25.9 degree what is the refractive index of the ice
Answer:sin40∘=0.643) Hint: The relationship of angle of incidence and angle of refraction at interface of two media is given by Snell's law.
Explanation:
Magnets are used in an electric door bell as well as in a magnetic compass. State three differences between the two magnets
Answer:hope this helpsss
Explanation:
A permanent magnet that is always aligned with the magnetic field of the earth makes up the magnetic needle of a magnetic compass, which is used for navigation.
The magnetic field is produced by an electric current in an electromagnet. Because they are transient magnets, electromagnets lose their magnetic properties as soon as the current is interrupted.
Question 15 of 34
Which of the following would increase the mechanical advantage of a lever?
A. Moving the fulcrum closer to the output force
O B. Moving the fulcrum farther from the output force
C. Decreasing the input force without moving the fulcrum
D. Increasing the input force without moving the fulcrum
The option that would increase the mechanical advantage of a lever is option A. Moving the fulcrum closer to the output force.
What influences a lever's mechanical advantage?Mechanical advantage quantifies a lever's effectiveness (how easy it is to lift the load). - When compared to the distance between the load (resistance) and the fulcrum, the advantage relies on the distance between the effort and the latter (effort arm) (resistance arm).
Note that in Levers of Class 1:
The mechanical advantage will increase when the fulcrum is brought closer to the load.The mechanical advantage will increase when the effort is moved further from the fulcrum. You might need a longer lever for this.Learn more about mechanical advantage from
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When an earthquake occurs, potential energy in the Earth's crust is released and waves of energy move across the Earth. What are
these waves called?
OA. seismic waves
OB. crust waves
OC. rock waves
OD. solid waves
Answer:
seismic waves
Explanation:
A star loses 6.022×10²³ mass per second. The total mass of the star is 12.044×10⁴⁶ in how much time will the star lose all its mass.
please helpp!!!!
It would take the star 2 seconds to lose all it's mass.
I got this by dividing 12.044×10⁴⁶ by 6.022×10²³
Two 10¢ coins (dimes) carrying identical charges are lying 2.5 m apart on a table. If each of these coins experiences an electrostatic force of magnitude 2.0 N due to the other coin, how large is the charge on each coin?
I know the answer is 52 micro coulombs, but I keep getting 37.26...
Answer:
Charge q = 37.27 micro coulombs
Explanation:
Given:
q₁ = q₂ = q
r = 2.5 m
F = 2.0 N
________
q - ?
Coulomb's law:
F =k·q₁·q₂ / r² = k·q·q / r² = k·q² / r²
Charge:
q = √ (F·r² / k)
q = √ (2·2.5² / (9·10⁹) ≈ 37.27·10⁻⁹ C
or q = 37.27 micro coulombs
The correct answer is not 52, but !!! :))
Katie pulls her wagon by the handle. She exerts a force of 60 N 30 degrees above the
horizontal. The force of friction from the sidewalk on the wagon is 30 N. The wagon has
a mass of 20 kg. What is the normal force on the wagon?
a. 226 N
b. 196 N
c. 166 N
d. 136 N
Answer: D: 136 N
..
..
Pls help :)
An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion, as shown in this graph.
Answer the following questions:
What is the period and frequency of the pendulum’s motion?
How many seconds out of phase with the displacements shown would graphs of the velocity and acceleration be?
What is the acceleration due to gravity on the surface of the planet in ? Determine the number of g-forces.
Show any necessary calculations.
a. ) The period is 1/frequency = 5sec / 9 cycles = 0.555 seconds
b.) the seconds out of phase with the displacements shown would graphs of the velocity and acceleration be 5/18 (0.2777...) sec delayed with respect to displacement
c.) Gravity = (324 π²) (0.2) / 25 = 25.582 m/sec²
What is gravity?
Gravity is defined as a fundamental interaction which causes mutual attraction between all things with mass or energy.
Solving for the acceleration due to gravity on the surface of the planet, we have the following:
For small swing angles, the period of an ideal pendulum anywhere is
T = 2pi √(length / local gravity) .
The astronaut has already done the pendulum and transmitted the data to us, so
we can use his data and this formula to calculate the local gravity where he is located
P = 2pi √(length / local gravity)
5/9 sec = 2π √(0.2m / gravity)
√(0.2m / gravity) = 5/9sec / 2π
Take the reciprocal of each side: √(gravity) / √(0.2) = 18π / 5
Multiply each side by √(0.2): √(gravity) = 18π √(0.2) / 5
Square both sides: Gravity = (324 π²) (0.2) / 25 = 25.582 m/sec²
The value gotten is about 2.608 times the Earth's gravity.
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URGENT!! ILL GIVE
BRAINLIEST!!!! AND 100 POINTS!!!!!
Answer:
The force of friction and air resistance slow down the movement of the bus.
c) A forse is changing the motion of the bus
950 kg
3.
If the car has 30.400 J of kinetic
energy, how fast is it moving?
Kate was doing some resistance training where she would push against a brick wall
for 30 seconds. Which of the following statements best explains this situation in
terms of Work and Energy.
Kate did not do any work on the wall, because the wall did not move.
Kate used stored energy in her body which was likely converted to heat energy-
Kate did not change the Kinetic Energy of the wall; she did not change the
gravitational potential energy of the wall; and she did not change the elastic
potential energy of the wall.
All of the above statements are true.
Answer:
Kate did not do any work on the wall , because the wall did not move
A weightlifter curls a 25 kg bar, raising it each time a distance of 0.50 m. How many times must he repeat this exercise to burn off the energy in one slice of pizza? Assume 25% efficiency. Energy content of one slice of pizza is 1260 kJ .
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
What is energy?
Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Energy burn by the weightlifter = potential energy
Potential energy = mgh
Potential energy = 25.(9.8)(0.50)
Potential energy = 122.5 Joule.
Assume 25% of efficiency so energy burn = 122.5*25/100
energy burn = 30.625 joule
Number of times = 1260/30.625
Number of times = 42 times.
42 times must he repeat this exercise to burn off the energy in one slice of pizza.
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Two balls of the same radius but densities p1 = 2 p and p2 = 4 pare placed in a
liquid of density p. What is the ratio (the weight of ball 1 in the liquid / the weight of
ball 2 in the liquid)?
Answer:
W1 = d1 V
W2 = d2 V weight of balls in air (both have same volume0
w2 = (d2 - p) V apparent weight of ball 2 (p * V = buoyant force
w2 / w1 = (d2 - p) / (d1 - p) the liquid exerts the same buoyant force on each ball
Let p be in units of kg / m^3 * g say 1 N / m^3
Suppose d1 = 2 and d2 = 3 N/m^3 and p = .5 N/m^3
The ratio of apparent weights would be
w2 / w1 = (3 - .5) / (2 - .5) = 1.67 to 1
A 70kg student, happy to see snow in early
November, rushes out to sled on a hill with a 10kg
sled. They start h=12m above a horizontal plane.
How fast are they moving by the time they reach
the bottom of the hill? (assume the coefficient of
friction is zero here) After a short distance the
reach a point where there are some dry leaves are
scattered producing an effective coefficient of
friction uk=0.4. How far do they travel through the leaves before they
come to rest?
Use the fundamental principle
(a) The speed of the student at the bottom of the hill is 15.34 m/s.
(b) The speed of the student at the presence of friction force is 11.88 m/s.
What is the speed of the student at the bottom of the hill?
The speed of the student at the bottom of the hill is calculated by applying the principle of conservation of energy as shown below.
Kinetic energy at the bottom hill = potential energy at maximum height
¹/₂mv² = mgh
where;
m is mass of the studentv is the speed of the speed of the student at bottom hillh is the height of the hillv² = 2gh
v = √2gh
v = √(2 x 9.8 x 12)
v = 15.34 m/s
The speed of the student at the presence of friction force is calculated as;
Kinetic energy at the bottom hill + work done against friction = potential energy at maximum height
¹/₂mv² + μmgh = mgh
¹/₂v² + μgh = gh
v² + 2μgh = 2gh
v² = 2gh - 2μgh
v² = (2 x 9.8 x 12) - (2 x 0.4 x 9.8 x 12)
v² = 141.12
v = √141.12
v = 11.88 m/s
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Compare the momenta of a 6300-kg elephant walking 0.11 m/s and a 50-kg dolphin swimming 10.4 m/s.
Answer:
Explanation:
p₁ = m₁·V₁ = 6300·0.11 = 693 kg·m/s
p₂ = m₂·V₂ = 50·10.4 = 520 kg·m/s
693 kg·m/s > 520 kg·m/s
a cat is moving at 2 m/s when it accelerates at 4 m/s for 2 seconds. his new velocity is
vf = vi + at = 2 m/s + (4 m/s²) (2 s) = 10 m/s
A model of a helicopter rotor has four blades, each of length 3.4 m from the central shaft to the blade tip. The model is rotated in a wind tunnel at a rotational speed of 600 rev/min.
What is the radial acceleration of the blade tip expressed as a multiple of the acceleration due to gravity, g ?
Express your answer as a multiple of g .
The radial acceleration of the blade tip is 1370 g rad/s².
What is radial acceleration?Radial acceleration is defined as "the acceleration of the object is along the radius, directed towards the center" in uniform circular motion.
Given parameters:
Rotational speed of the helicopter rotor: ω = 600 rev/min
= 600 × 2π/60 rad/min.
= 20π rad/min.
Length of the blade: r = 3.4 m.
Then, the radial acceleration = ω²r = (20π)²× 3.4 rad/s².
= {(20π)²× 3.4}/9.8 g rad/s².
= 1370 g rad/s².
Hence, the radial acceleration of the blade tip is 1370 g rad/s².
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15. A hybrid automobile traveling at 5.0 km/h, steadily increases its speed to 20.0 km/h in 10.0 s
a. Calculate its average acceleration, b. Calculate the distance the automobile travels during this
period of acceleration.
6. A race car traveling:
The average acceleration of the hybrid automobile is 0.42 m/s².
The distance travelled by the hybrid automobile during the period of acceleration is 34.5 m.
What is the average acceleration of the hybrid automobile?
The average acceleration of the hybrid automobile is the rate of change of velocity of the hybrid automobile with time.
Mathematically, the formula for average acceleration is given as;
a = Δv/Δt
where;
Δv is change in velocity of the automobileΔt is change in time of motion of the automobilea = (v - u)/t
where;
v is the final velocity of the hybrid automobile = 20 km/h = 5.56 m/su is the initial velocity of the hybrid automobile = 5 km/h = 1.389 m/sa = (5.56 - 1.389)/10
a = 0.42 m/s²
The distance travelled by the automobile during the period of acceleration is calculated as follows;
v² = u² + 2as
2as = v² - u²
s = (v² - u²)/(2a)
s = (5.56² - 1.389²) / (2 x 0.42)
s = 34.5 m
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a boy throws a ball of mass of 0.25kg straight upward with initial velocity of 20 m/s when the ball returns its speed it 17m/s. how much work does air resistance do on the ball
1.125 joule work done does air resistance do on the ball
work done= kinetic energy= mΔv²/2
m=0.25kg
Δv=3 m/s
work done= mΔv²/2
work done=-0.25×9÷2
work done=-1.125 joule
When an item is moved across a distance by an external force, at least a portion of that force must be applied in the direction of the displacement. This is known as work done in physics. By multiplying the length of the path by the component of the force operating along the path, work may be calculated if the force is constant. The work W is equal to the force f times the distance h, or W = mgh, to mathematically describe this idea. The work is W = mas if the force is applied at an angle of to the displacement.
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A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. 1. (a) When the lights are switched on and working correctly, the current through each lamp is 0.25 A. (i) What is the total current drawn from the mains supply?
The total current that is drawn from the mains supply is 5 A.
What is current?The term current has to do with the flow of charges in a circuit. Now we have been told that A set of lights consists of 20 lamps connected in series to the 230 V mains electricity supply. It was also said in the question that when the lights are switched on and working correctly, the current through each lamp is 0.25 A.
Now we have the following information;
Current passing through each lamp = 0.25 A
Number of lamps = 20 lamps
Hence;
Total current = 0.25 A * 20
= 5 A
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Starting from rest, a car accelerates at 2.2 m/s2 up a hill that is inclined 5.2 ∘ above the horizontal. How far horizontally has the car traveled in 13 s ?
The horizontal distance travelled by the car in the given time period of 13 seconds is determined as 168.3 m.
What is the horizontal distance travelled by the car?The horizontal distance travelled by the car is calculated as follows;
s = ut + ¹/₂acosθ(t²)
where;
v is the final horizontal speed of the caru is the initial horizontal speed of the cara is the acceleration of the cart is the time of motion of the carθ is the angle of inclination of the planes = 0 + ¹/₂(2) x cos(5.2) x (13)²
s = 168.3 m
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Excluding air pressure, there is how many force or force(s) acting on a book lying at rest on a tabletop?
Answer: 2 Forces
Explanation:
1. Normal force- object is on a surface
2. Weight
State the name given to reflected sound waves
Echo
Explanation:
It is termed as Echo. Echo is a reflection of sound that arrives at the listener with a delay after the direct sound.
Calculate weight if an object, given its mass
Answer:
Weight is a measure of the force of gravity pulling down on an object. It depends on the object's mass and the acceleration due to gravity
Explanation:
A 5 kg block is moved up a 30 degree incline by a force of 50 N, parallel to the incline. The coefficient of kinetic friction between the block and the incline is 0.25. What is the net work done on the block over this distance?
The net work done on the block over the given distance is 39.4d (joules)
What is the net work done on the block over this distance?The net work done on the block over the given distance is calculated by applying the following equation as shown below:
W(net) = F(net) x d where;
F(net) is the net force on the blockd is the distance moved by the blockF(net) = F - μmgcosθ where;
μ is the coefficient of kinetic frictionm is the mass of the blockg is acceleration due to gravityθ is the angle of inclination of the planeF(net) = 50 N - (0.25 x 5 x 9.8 x cos30)
NF(net) = 50 N - 10.6 NF(net) = 39.4 N
The net work done on the block over the given distance is calculated as: W = 39.4 N x dwhere;
d is the distance moved by the block = length of the incline
W = 39.4d (joules)
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An ordinary workshop grindstone has a radius of 8.50 cm and rotates at 5500 rev/min.
(a)
Calculate the magnitude of the centripetal acceleration at its edge in meters per second squared and convert it to multiples of g.
magnitude m/s2
magnitude g
(b)
What is the linear speed in m/s of a point on its edge?
m/s
(a.i) The magnitude of the centripetal acceleration at its edge is 28,197.04 m/s².
(a. ii) In terms of multiple of g, the centripetal acceleration is 2,874.3 g.
(b) The linear speed is determined as 48.96 m/s.
What is the magnitude of the centripetal acceleration?The magnitude of the centripetal acceleration of the workshop grindstone is calculated by applying the following kinematic equation.
a = v²/r = ω²r
where;
v is the linear speed of the grindstoneω is the angular speed of the grindstoner is the radius of the grindstoneThe given parameters include;
ω = 5500 rev/min
ω = 5500 rev/min x 2π rad/rev x 1 min / 60 s
ω = 575.96 rad/s
a = (575.96²) x (0.085)
a = 28,197.04 m/s²
In terms of acceleration due to gravity (g);
a = 28,197.04 m/s² / 9.81 = 2,874.3 g
The linear speed of the grindstone is calculated as follows;
v = ωr
v = 575.96 rad/s x 0.085 m
v = 48.96 m/s
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10. If an evaporator has a pressure drop of 10 psig and the low side pressure is 15 psig, what is the pressure at the
inlet of the evaporator?
a.5 psig
b.10 psig
c.15 psig
d.25 psig
If an evaporator has a vapour pressure drop of 10 psig and the low side pressure is 15 psig, pressure at the inlet of the evaporator will be 25 psig
change pressure= low side pressure-pressure drop
change pressure=15-(-10)
change pressure=25 psig
The vapor pressure of a liquid, sometimes referred to as the equilibrium pressure of a vapor above its liquid, is the pressure of the vapor produced by the evaporation of a fluid (or solid) over a sample of the liquid (or solid) in such a closed container (or solid).
Vapor pressure is the term for the force that is produced as liquids evaporate. Three factors commonly have an effect on a vapor press: surface area, intermolecular forces, and temperature. The vapor pressures of molecules change with temperature.
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Turner’s treadmill runs with a velocity of −1.2 m/s and speeds up at regular intervals during a half-hour workout. After 25 min, the treadmill has
a velocity of −6.5 m/s. What is the average acceleration of the treadmill
during this period?
0.212 m/s² is the average acceleration of the treadmill.
during this period
initial velocity, u = -1.2 m/s
time= 25 min
final velocity, v= −6.5 m/s
acceleration = (v-u)÷ t
acceleration =5.3/25
acceleration =0.212 m/s²
The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating. A moving object can occasionally alter its velocity by the same amount every second. a moving object that changes its speed by 10 m/s per second. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration. It is important to distinguish between an item with a constant acceleration and one with a constant velocity. Be not deceived! An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, a moving item with a constant speed is not accelerating.
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