Assume that when adults with smartphones are randomly selected, 49% use them in meetings or classes. If 15 adult smartphone users are randomly selected find the probability that fewer than 3 of them use their smartphones in meetings or classes.

Answers

Answer 1
We can calculate the probability of having less than 3 smartphone users among 15 users by using the binomial distribution formula, which is given by:

P(k;n,p) = C(n,k) * p^k * (1-p)^(n-k)

Where:

k is the number of successful outcomes, in this case the number of smartphone users who use their devices in meetings or classes
n is the total number of trials, in this case the total number of smartphone users we are selecting
p is the probability of success, in this case the probability that a smartphone user uses their device in meetings or classes
First, we need to calculate the probability that exactly 0 smartphone users use their devices in meetings or classes. This is given by:

P(0;15,0.49) = C(15,0) * 0.49^0 * (1-0.49)^15 = 0.26

Next, we need to calculate the probability that exactly 1 smartphone user uses their device in meetings or classes. This is given by:

P(1;15,0.49) = C(15,1) * 0.49^1 * (1-0.49)^14 = 0.33

Finally, we need to calculate the probability that exactly 2 smartphone users use their devices in meetings or classes. This is given by:

P(2;15,0.49) = C(15,2) * 0.49^2 * (1-0.49)^13 = 0.15

The probability of having fewer than 3 smartphone users among 15 users is given by the sum of the probabilities of having 0, 1, or 2 smartphone users, which is 0.26 + 0.33 + 0.15 = 0.74. This means that there is a 74% probability that fewer than 3 of the 15 selected smartphone users use their devices in meetings or classes.
Answer 2

The probability that fewer than 3 of the 15 smartphone users use their phones in meetings or classes is 7.46%.

What is the binomial probability theorem?

The binomial probability formula.

P(X = k) = [tex]^nC_r[/tex] [tex]P^k[/tex] [tex](1 - P)^{n - k}[/tex]

where n is the sample size, k is the number of successes, P is the probability of success, (P - 1) is the failure.

We have,

The required probability.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

Where X is the number of smartphone users out of 15 who use their phones in meetings or classes.

Now,

Using the binomial probability.

P(X = k) = [tex]^nC_r[/tex] [tex]P^k[/tex] [tex](1 - P)^{n - k}[/tex]

where n is the sample size, k is the number of successes (using their smartphones in meetings or classes), p is the probability of success (49%), and (n choose k) is the number of ways to choose k successes out of n trials.

We get,

P(X = 0) = [tex]^{15}C_0[/tex] x [tex]0.49^0[/tex] x [tex]0.51^{15}[/tex] = 0.0018

P(X = 1) = [tex]^{15}C_1[/tex] x [tex]0.49^1[/tex] x [tex]0.15^{14}[/tex] = 0.0149

P(X = 2) = [tex]^{15}C_2 \times 0.49^2 \times 0.49^{13}[/tex] = 0.0579

The probability of fewer than 3 smartphone users using their phones in meetings or classes.

P(X < 3)

= P(X = 0) + P(X = 1) + P(X = 2)

= 0.0018 + 0.0149 + 0.0579

= 0.0746

= 0.0746 x 100

= 7.46%

Thus,

The probability that fewer than 3 of the 15 smartphone users use their phones in meetings or classes is 7.46%.

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In-person communication is precisely what it sounds like, and it is one of the most successful methods of forming parent connections. In-person communication is used whenever you interact with a parent in person.

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Explanation:

Classify the following data. Indicate whether the data is qualitative or quantitative, indicate whether the data is discrete, continuous, or neither, and indicate the level of measurement for the data.

Survey responses to the question "In which of the following regions of the country do you live?"

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Answers

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Number of College Faculty The number of
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