Assuming the compound is dissolved in water, what is the formula for phosphorous acid?
Symbol
Name
phosphate
PO
phosphite
phosphorus
0 H3P
0 H3PO4
O HP
0 Hзроз
PO3
P

The volume of the oxygen into a balloon is, V = 1.70 ml.

To calculate the volume of the oxygen using the formula

PV = nRT

where,

P is pressure

V is volume

n is number of moles

R is gas constant

T is temperature

So, the known values are :

P = 1183 mmHg

R = 8.314 J/mol

T = 151.4°F = 66.33°C

mass = 58.41g

n = ?

V = ?

While we don't know the value of n but we know mass so we can calculate number of mole by using formula,

n = m / M

That is,

n is number of mole

m is mass

M is molecular mass

Now, putting values in this

n = 58.41 / 15.99

n = 3.65 mol

Thus, now we know the value of n

Put the value in formula

PV =nRT

1183 mmHg x V = 3.65 mol x 8.314 J/mol x 66.33°C

V = 2012.86 / 1183

V = 1.70 ml

Hence, the volume of the oxygen into a balloon is 1.70 ml.

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Answer:

why alkali metal are called as most reactive elements?

Hydrochloric acid reacts with zinc, giving Hydrogen gas and zinc chloride.

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The statement 'It may include pieces of asphalt' is TRUE about soil used as evidence in forensic science (Option B).

Forensic science is a sub-discipline aimed at solving police cases based on evidence found at the crime scene, thereby being a key part of a police investigation. in this sense, pavement structural evaluation may result very useful in forensic science.

Therefore, we can conclude that forensic science is based on evidence found in the crime scene, which may include evidence in the asphalt ([pavement) that is collected by investigators in order to analyze it.

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Answer: B

Explanation:

Answer:

Circumference of carbon = 483.56 pm

Circumference of sulphur = 1111.56 pm

Explanation:

The circumference is the length of any great circle, the intersection of the sphere with any plane passing through its centre.

For carbon atom:

Atomic radius = 77 pm

Circumference = 2πr

=2 X 3.14 X 77

=154 X 3.14

Circumference of C = 483.56 pm

For sulphur:

Atomic radius = 177 pm

Circumference = 2πr

=2 X 3.14 X 177 pm

=1111.56 pm

Circumference of sulphur = 1111.56 pm

Hence,

The circumference of Carbon is 483.56 and the circumference of sulphur is 1111.56 pm.

[tex]c \: = 2\pi\:r[/tex]

C = 2(3.14)(77)

C = 6.28 × 77

C = 2(3.14)(103)

C = 6.28 × 103

According to Charle's law, a balloon at 600 K has a volume of 3.83 L.

Charles' law states that, under constant pressure, the volume a given amount of gas fills is directly proportional to its absolute temperature. For instance, when the temperature drops during the winter, a basketball placed outside in the ground would contract.

Mathematically, Charles' law can be written as V1/T1 = V2/T2, where V1 denotes the volume at the beginning, T1 the temperature at that point, and V2 the volume at the end with T2 the temperature at that point.

The following examples of how Charles' law is applied in real life:

Helium balloons shrink when it's cold outside.

From Charles' law, V/T = constant

V₁/T₁ = V₂/T₂

or, 2/313 = V₂/600

or, V₂ = (2x600)/313

          = 3.83

Hence, form Charles' law we conclude the volume of balloon at 600 K is 3.83 L.

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Answer:

40.04g

Explanation:

the water has one molecule of hydrogen and two molecules of oxygen(H20)

(4.02)(2)(32)

A bigger atom  fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.

By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.

Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.

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The right answer is (KP)-1/2. Option A.

An expression of the equilibrium constant in terms of partial pressure is denoted as Kp. The equilibrium constant Kp is equal to the partial pressure of the product divided by the partial pressure of the reactant, and the partial pressure increases with a force equal to the coefficient of the substance in the equilibrium equation.

Kp is the equilibrium constant used to express equilibrium concentrations at atmospheric pressure and Kc is the equilibrium constant used to express equilibrium concentrations in molar terms. The relationship between Kp and Kc depends on the change in the number of moles of gaseous reactants and products. Kp has exactly the same form as Kc but partial pressure is used instead of concentration. Gases to the right of the formula are at the top of the print, and gases to the left are at the bottom.

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Out of gold and copper, gold metal would have larger mass.

What is molar mass?

The mass of any chemical substance divided by the volume of the material is known as the molar mass of that compound.

Given:  The value of volume is same for both the metals = 45

The value of the volume is the same for both the metals = 45 cm3

By using formula of density i.e = mass/volume

Since the volume is the same

The density is directly proportional to the mass.

From the periodic table,

The mass of gold = 196.9 u

The mass of copper = 63.5 u

Since the volume is the same, we consider only the absolute masses value

Hence, gold is heavier than copper metal

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Sulfuric acid is a strong acid, which means it can dissociate completely when dissolve in water. In other words, the reactant H2SO4 is completely soluble in water, otherwise, it wouldn't be a strong acid.

On other hand, the second reactant Ba(OH)2 is soluble in water because it's a strong base, which are bases that completely dissociate when dissolve in water.

Therefore, sulfuric acid (H2SO4) is soluble in water and the barium hydroxide (Ba(OH)2) is also soluble in water.

Ideal gas equation PV =nRT

The parameters are given in problem : moles (n)  = 2.55 Volume (V) = 205L:Temperature(T) = 273K Pressure = ?kPa

Universal Gas constant  R = 8.31kPa.L/mol.K   substitue all these values in ideal gas equation in PV = nRT

PV = nRT  

Px205 = (2.55)x(8.31)x(273)

P = (3.05)x(8.31)x(273) /205 kPa

P = 33.75 kPa.

The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. An ideal gas is one that obeys the law pv=RT at all pressures and temperatures. At high temperatures and low pressure, the potential energy due to intermolecular forces becomes almost insignificant compared to the kinetic energy of the particles, and the size of the molecules increases compared to the intermolecular voids.

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Answer:

86400

Explanation:

24*24*69seconds

The distribution of positive and negative particles was not uniform. This hypothesis of Thomson’s atomic model was later found to be not true by Rutherford.

Because positive charge particle is in center and the negative charge particle is surround to it.

J.J. Thomson proposed that an atom is a definitely charged sphere wherein negatively charged electrons are embedded in it. Neils Bohr proved it to be false as the mass of any atom is localized inside the middle of an atom which is positively charged even as negatively charged electrons revolve across the effective center.

Thomson was incorrect due to the fact he assumed that the positive charge of an atom become all one uniform blob of count number with the electrons transferring in orbits inside the nucleus. If Thomson's model had been accurate, the alpha particles could skip thru the atomic shape of the foil unimpeded.

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The classification of Rupatadine is H-1 receptor antagonists or H-1 blockers.

As a platelet-activating factor antagonist and second-generation antihistamine, rupatadine is used to treat allergies. It was found and developed by Uriach [es][2], and it is sold under the trade names Rupafin and a few other names as well. For the treatment of chronic urticaria and allergic rhinitis in adults and children older than 12 years, rutadine fumarate has been approved. It is offered as round, light salmon-colored tablets to be taken orally once day that contain 10 mg of rupatadine (as fumarate).

Rupatadine's effectiveness as a treatment for allergic rhinitis (AR) and chronic idiopathic urticaria (CIU) has been examined in adults and adolescents (aged over 12 years) in several controlled studies, demonstrating a rapid action onset and a great safety characteristics even in long treatment durations of a year.

The drug rupatadine, a dual antagonist of the histamine H1 and platelet activating factor receptors, is used to treat the symptoms of chronic spontaneous urticaria and seasonal and perennial rhinitis. It is available in tablet and liquid formulations for adult and pediatric usage in Canada and has received marketing approval under the trade name Rupel.

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20 Grams of Water.

Grams : mL

2 : 1

4 : 2

6 : 3

8 : 4

10 : 5

12 : 6

14 : 7

16 : 8

18 : 9

20 : 10

Answer:

20 grams

Explanation:

mass = Density × Volume

= M = 2g/ml × 10ml

= 20g

Answer:

electron(negative)

neutron(neutral)

proton(positive)

When the pH of a solution decreases, hydrogen ion concentration increases

The overall concentration of hydrogen ion is inversely related to its pH and can be measured on the pH on the pH scale which is from 1 to 14 and therefore the more hydrogen ions present, the lower the pH conversely the fewer hydrogen ions the higher the pH as the concentration of hydrogen ion is logarithmically inversely proportional to pH and pH of solution is decreased then hydrogen ion concentration will increase by the power of 10

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The new temperature of certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm will be 300 K if its volume is doubled at the same time that its pressure is decreased to one-half its original value.

We will use combined gas law equation to find the new temperature.

We know that

Initial temperature T₁ = 27°c +273 K = 300 K

Initial pressure P₁ = 1.00 ATM

Initial volume V₁ = V

Final volume V₂ = 2 V

Final pressure P₂ = P/2 = 1/2 = 0.5 atm

Now, using the combined gas law equation, which is given as -

P₁V₁ = P₂V₂

 T₁       T₂

where,

P₁ = Initial pressure

P₂ = Final pressure

V₁ = Initial volume

V₂ = Final volume

T₁ = Initial temperature

T₂= Final temperature

Avogadro's law states that equal volumes of gases contains equal number of molecules at same temperature and pressure.

P₁V₁T₂ = P₂V₂T₁

Dividing P₁V₁ on both the sides

P₁V₁T₂  =  P₂V₂T₁

P₁V₁           P₁V₁

We get,

T₂ = P₂V₂T₁

        P₁V₁

Substituting values,

T₂ = 0.5 × 2V × 300 × V

                           1

T₂ = 300K

Hence, the new temperature is 300 K.

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Answer

the correct answer would be A

Explanation:

They were unable to find class nor individual characteristics.

The mole fraction of the water solution is 0.77.

The mole fraction or molar fraction is defined as a unit of the quantity of a constituent, nᵢ, divided by the total quantity of all parts in a combination.

Moles of water = given mass/ molar mass

Moles of water = 84/18

Moles of water = 4.6

Moles of hexane =  given mass/ molar mass

Moles of hexane = 100/76

Moles of hexane = 1.3

Total moles = Moles of water + Moles of hexane

Total moles = 4.6 + 1.3 = 5.9

Mole fraction of water = Moles of water / Total moles

Mole fraction of water = 4.6/5.9

Mole fraction of water = 0.77

Hence, the Mole fraction of water is 0.77.

The mole fraction is the same as the mole percent however in a specific shape in chemistry. Inside the given combination, the range of moles of one constituent is divided by the total number of moles is referred to as the mole fraction. Multiplying the mole fraction of the thing by then we gain the mole percentage of the aspect.

Mole fraction is a unit of awareness, described to be equal to the range of moles of an aspect divided through the whole wide variety of moles of a solution. Because it's miles a ratio, the mole fraction is a unitless expression.

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Since hydroiodic acid is a strong acid and completely dissociates, we can use this formula:

pH = -log[H+]

pH = -log[0.0520]

pH = 1.284

Answer:

D

Explanation:

Carbon has atomic number of 6 so it has 6 protons.

The fact that 21 g of A and 21 g of B produce 17 g of C does not obey the law of conservation of mass.

The law of conservation of mass states that the mass of a substance can neither be created nor destroyed.

This law further explains that in a chemical reaction, the amount of reactants must be equal to the amount of products in the reaction.

For example, if a substance A of mass 21g reacts with another substance B of mass 21g, the mass of the product C should be 21g + 21g = 42g in order to align with the law of conservation of mass.

However, according to this question, the product C has a mass of 17g, which shows that the law of conservation of mass is not obeyed.

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The percent yield of carbon dioxide is 87%.

The balanced chemical equation for reaction of octane with oxygen,

CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O

We can use the mole concept here,

Mole = Given mass/molar mass.

From the reaction,

1 mole of Octane = 8 moles of carbon dioxide.

Now, moles of octane N,

N = 31.98/114.23

N = 0.2799

Moles of Carbon dioxide = 8 x 0.2799

Moles of Carbon dioxide = 2.239

Mass of CO₂ formed,

2.239 = Mass of CO₂/44

Mass of CO₂ = 98.54 grams/mole.

Percentage yield = theoretical mass/experimental mass x 100

Theoretical mass = 98.54 grams/mole.

Experimental mass = 85.8 grams/mole.

Percentage yield of CO₂ = 85.8/98.54 x 100

Percentage yield of CO₂ = 87%

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Anhydrides are binary substances or compounds that are the result of a nonmetal with oxygen.

I leave you 2 steps to make the anhydrides:

1: To make anhydrides, write your nonmetal symbol followed by oxygen.

2: The oxidation numbers must be the same and for this the exchange of oxidation numbers or valence between its non-metallic element and Oxygen is used.

Examples of anhydrides:

1: Chlorous anhydride

[tex]\bold{ \: Cl + O₂ \rightarrow \: Cl₂ O₃}[/tex]

Keep in mind that when it ends in OSO we look for its valence, which in this case would be +3.

2: Iodic anhydride

[tex]\bold{ \: I + O₂ \rightarrow \: I₂ \: O₅}[/tex]

We take into account its symbol that in this would be me and to solve it we must look for its valence that in this case ends in ICO which is already known that its ICO valence is +5.

3: Per bromic anhydride

[tex]\bold{\:Br + O₂ \rightarrow \:Br₂ \:O₇}[/tex]

We take into account its symbol, which in this case would be Br, and to solve it we must find its valence, which in this case ends in ICO, which is already known to have an ICO valence of +7.

The Table of metals and non-metals is attached.

Step 1 - Understanding the relation of potential energy, kinectic energy and the conservation of energy

The potential energy is the energy related to a body that can start moving under the influence of a force anytime soon.

The kinf of potential energy depends on the force that could act on the body. When a body is lifted, because gravity can pull it back, we say that this body has gravitational potential energy

Kinetic energy, on the other hand, is related to actual movement. It depends on the mass as well as on the velocity of the body. When we lift an object and drop it next, all the potential energy will be converted to kinetic energy, i.e., the velocity of the object we dropped will be also proportional to the height. It cannot gain more energy.

Step 2 - Interpreting the problem

Now that we know how potential and kinetic energy work, we can start working on the problem. Since potential energy is directly proportional to height, the highest potential energy would be attained at F.

The lowest potential energy, on the other hand, woud be attained at D, i.e., the smaller height.

The highest kinetic energy would be attained when all the potential energy is converted to kinetic energy, i.e., when the bicyclist, starting at A, loses its potential energy reaching D

The speed is directly proportional to the kinetic energy: the higher the speed, the higher the kinetic energy. Since the kinetic energy, as we saw, is the greatest at D, the velocity will also be the greatest at this point.

If a population consist of large portion of reproductive Indvidual's,  then the future population size is also increase .

As previously said, populations with early reproduction have the ability to increase far more quickly than populations with later reproduction. The life tables for a certain species show how the age of first reproduction affects population growth.

Preoperative people make up a large amount of the triangular age pyramid, whereas reproductive people make up a more moderate number and post-reproductive people make up less of it. It signifies a young or populace that is expanding quickly.

In an age pyramid with an urn shape, there are more reproductive people than pre-reproductive people. It symbolises population loss or reduction and negative growth.

The proportion of pre-reproductive and reproductive people in the age pyramid has a bell shape. Comparatively fewer people are post-reproductive. It indicates a population that is steady or stationary and is neither increasing nor decreasing.

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Taking into account the reaction stoichiometry, the maximum amount of SF₆ that can be produced from the reaction of 32.1 g of sulfur with 114 g of fluorine is 146.46 grams.

In first place, the balanced reaction is:

S + 3 F₂  → SF₆

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 57 grams of F₂ reacts with 32 grams of S, 114 grams of F₂ reacts with how much mass of S?

mass of F₂= (114 grams of F₂× 32 grams of S)÷ 57 grams of F₂

mass of F₂= 64 grams

But 64 grams of F₂ are not available, 32.1 grams are available. Since you have less mass than you need to react with 114 grams of F₂, S will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of S form 146 grams of SF₆, 32.1 grams of S form how much mass of SF₆?

mass of SF₆= (32.1 grams of S× 146 grams of SF₆)÷ 32 grams of S

mass of SF₆= 146.46 grams

Finally, 146.46 grams of SF₆ can be produced from the reaction of 32.1 g of S with 114 g of F₂.

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