At a temperature of 408K, which gad will have the highest velocity?

Answers

Answer 1

Answer:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Explanation:

Kinetic Energy is directly related to temperature; the higher the temperature the higher the kinetic energy. Kinetic energy is also equal to 12m⋅v2, so if we want a high velocity we want high temp and low mass. So let's list out approximate masses:

m(H2)≈2

m(NO2)≈46

m(Ne)≈20

So we have NO2 at 339 K, the lowest temperature out of the mix, and the highest mass out of the mix, so this is moving the slowest.

In contrast, we have H2 at 425 K, the highest temperature out of the mix, and the lowest mass out of the mix, so this is moving the fastest.

Now we have Ne and H2 at 371 K, since they are at the same temperature they have the same kinetic energy. But H2 is lighter than Ne so it must be faster. To quantify this mathematically, let's assume (this is wrong but just as an assumption for an example) KE at 371 K is 100:

100=12⋅m⋅v2

200=m⋅v2

√200m=v

So H2 is about v=10 and Ne is about v=√10≈3

So the order to recap is:

1 - NO2 at 339 K

2 - Ne at 371 K

3 - H2 at 371 K

4 - H2 at 425 K

Hope that makes it clearer!


Related Questions

write a story of your life when you were hurted by someone whom you trusted blindly...​

Answers

Answer:

Sis I think it happened with me but I am not able to remember if u want u can share if it happened with u

Students are asked to design an experiment with cookies to demonstrate their understanding of the scientific method. One group has decided to determine the amount of time it will take for a cookie to "dissolve" in a glass of milk.

Which variable would most likely NOT affect the time it takes for the cookie to dissolve?

a) the size of the cup of milk
b) the type of cookie
c) the number of students in the group
d) the temperature of the milk
e) the type of milk​​

Answers

I'm gonna guess E on this one, but I think you should choose either E or A

Somebody please answer

60 L of a 180 mol MgCl2 solution is created. What is the molarity of MgCl2 are in this solution?

Answers

Explanation:

Molarity = (# of moles)/(# of liters)

= 180 mol MgCl2/60 L

= 3.0M MgCl2

A or B or C or D plzz answer fasttt

Answers

Answer:

B

Explanation:

Hope this helps! sorry if incorrect

ACTIVITY NO.3
DIRECTIONS: Read each item carefully. Choose the letter of your answer.
1. Light travels in a
line when is passes through a single medium.
a. curve
b. straight
C. crooked
d. dotted
2. When the sound travels through solids, the vibration of the particles occurs
?
a. fast
b. slowly
c. moderately
irregularly
3. What affects the speed of sound as it travels?
a. Person receiving it
b. The origin of the sound
c. The nature of materials
d. Loudness of the sound
4. How is heart transferred in solid materials?
a. Through convection
b. Through conduction
c. Through radiation
d. Through vacuum
5. What is the direction of heat transfer?
a. From hot to cold
b. From Cold to hot
c. From bottom to top
d. From side to side​

Answers

Be more specific I just need points

Which
gas is exchanged in the air sac of
longs? -
oxygen and nitrogen
oxygen and carbondioxide
O nitrogen and coarbondioxide
oxygen and hydrogen
O
Other:​

Answers

Answer:

oxygen and carbon dioxide.

hope this helps you

Which hand is negatively changed?

A.
B.
C.
D.

Answers

Answer:

I think B

Explanation:

There are more negative ions than positive ions

pls help i need asap will mark brainlest

Answers

Answer:

B. 50%

Explanation:

2H₂ + CO → CH₃OH

First we convert the given masses of the reactants into moles, using their respective molar masses:

4 g H₂ ÷ 2 g/mol = 2 mol H₂25 g CO ÷ 28 g/mol = 0.893 mol CO

0.893 moles of CO would react completely with (0.893 * 2) 1.786 moles of H₂. As there are more H₂ moles than that, H₂ is the reactant in excess and CO is the limiting reactant.

Now we calculate how many CH₃OH moles would have been formed if all CO would have been consumed:

0.893 mol CO * [tex]\frac{1molCH_3OH}{1molCO}[/tex] = 0.893 mol CH₃OH

Then we convert 0.893 moles of CH₃OH into grams, using its molar mass:

0.893 mol CH₃OH * 32 g/mol = 28.57 g

Finally we calculate the percent yield:

14 g / 28.57 g * 100% = 49%

Metal plating is done by passing current through a metal solution. For example, an item can become gold plated by attaching the item to a power source and submerging it into a Au3 solution. The item itself serves as the cathode, at which the Au3 ions are reduced to Au(s). A piece of solid gold is used as the a node and is also connected to the power source, thus completing the circuit.

Required:
What mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min ?

Answers

Answer:

9.18g

Explanation:

Step 1: Write the reduction half-reaction

Au³⁺(aq) + 3 e⁻ ⇒ Au(s)

Step 2: Calculate the mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min

We will use the following relationships:

1 min = 60 s1 A = 1 C/s1 mole of electrons has a charge of 96486 C (Faraday's constant).1 mole of Au is produced when 3 moles of electrons circulate.The molar mass of Au is 196.97 g/mol.

The mass of gold produced is:

[tex]15.0 min \times \frac{60s}{1 min} \times \frac{15.0C}{1s} \times \frac{1 mol e^{-} }{96486C} \times \frac{1molAu}{3 mol e^{-} } \times \frac{196.97gAu}{1molAu} = 9.18gAu[/tex]

How many different chlorinated products
are based in the following reaction.
CH3CH2CH2CH3 + Cl2 heat

Answers

Answer: if I’m not mistaken it would be 8

Explanation:

Answer:

2

Explanation:

:)

One of the governing laws of the universe is the thermodynamic law of entropy. Which choice best describes entropy?

A. Particles and energy in a system become more and more disordered.

B. Energy is consumed in a chemical reaction.

C. Heat is evenly distributed throughout the universe.

D. More bonds are broken in a chemical reaction than bonds are formed.

Answers

A.

Particles and energy in a system become more and more disordered.

What is (aq),(I), and (g) mean in H2O2(aq) -> H2O(l) + O2(g) and why is it nesesary to have (aq),(I), and (g)

Answers

Explanation:

A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.

This is because it tells in what state the reactants were present and in what state the products are then formed.

For example, [tex]H_{2}O_{2}(aq) \rightarrow H_{2}O(l) + O_{2}(g)[/tex]

Now here, (aq) means aqueous, (l) means liquid and (g) means gas.

So, these states denoted are necessary as it tells that [tex]H_{2}O_{2}[/tex] in aqueous state dissociates to give [tex]H_{2}O[/tex] in liquid state and [tex]O_{2}[/tex] in gaseous state.

Choose the molecule or compound that exhibits dipole-dipole forces as its strongest intermolecular force.
BCl3CBr4SO2H2H2O

Answers

Answer:

SO2

Explanation:

Dipole-Dipole exist between parmanent dipoles in a molecule. THis means that molecule must have a parmanent dipole moment in it.

Example - HCl

Hydrogen bonding is an attraction between lone pair of an electronegative element and H atom of same or different molecule. H must be covalantly attached to either F, N or O.

Example - H2O

Among the molecules given in the list only SO2 and H2O exihibits parmanent moment. As BCl3 , CBr4 and H2 are symmetric compounds.

Since, SO2 cannot exihibit H- bonding only dipole-dipole forces as its strongest intermolecular force.


In the lab, you are asked to plan an investigation that shows how the structure of substances can explain the strength of the electrical forces between
particles. To show this, you decide to determine how much tinfoil will melt when the heat of different objects touches it. One of the objects you test
releases 5.7 kJ of heat. How much of the tinfoil will melt?
AHjus=7.029 kJ/mol
O
A. 16.99
B. 20.89
C. 84.39
D. 96.39

Answers

So the lab kk 14 klmo is 3737

If you have 600g of nitroglycerin, how many moles do you have?

help please

Answers

Answer:

600

Explanation:

there's 1 mole in every nitroglycerin

I think

156 grams of calcium fluoride, CaF2, is dissolved in 2000 mL of solution. Determine the molarity (M).

Answers

Answer:

1 M

Explanation:

We'll begin by calculating the number of mole of in 156 g of CaF₂. This can be obtained as follow:

Mass of CaF₂ = 156 g

Molar mass of CaF₂ = 40 + (19×2)

= 40 + 38

= 78 g/mol

Mole of CaF₂ =?

Mole = mass /molar mass

Mole of CaF₂ = 156 / 78

Mole of CaF₂ = 2 moles

Next, we shall convert 2000 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

2000 mL = 2000 mL × 1 L / 1000 mL

2000 mL = 2 L

Finally, we shall determine the molarity of the solution. This can be obtained as follow:

Mole of CaF₂ = 2 moles

Volume = 2 L

Molarity =?

Molarity = mole / Volume

Molarity = 2 / 2

Molarity = 1 M

Thus, the molarity of the solution is 1 M

[H] = 1.00 x 10^-7 M

a. Acidic
b. Basic
c. Neutral

Answers

the answer would be A

How do we measure the rate of this reaction A + B —> C

Answers

⟰ ANSWER ⟰

U R ANS IS IN THE PIC

HOPE IT HELPS U !!!!! (:

Which laws protect citizens against human trafficking​

Answers

Answer:

It depends on the country you are coming from. For example, the human trafficking laws in the US are different from UK. If you need an essay on this contact me on (irenedavid at g mail dot com)

Explanation:

Why is it dangerous to stand under tall trees and building during thunder?​

Answers

Because the tree might get struck by lightning and the tree will catch on fire leaving you to get burned

What're the differences between oxidation and reduction​

Answers

Answer:

Oxidation:Oxidation is the loss of electron or Hydrogen atoms or gain of Oxygen atomsRemoval or loss of electrons

A ⟶ A⁺ + e⁻

Removal of Hydrogen

AH + B ⟶ A + BH

Addition of Oxygen

A + BO ⟶ AO + B

All the above reactions release energy

Reduction:Reduction is the gain of electron or Hydrogen atoms or loss of Oxygen atomsAddition or gain of electrons

A + e⁻ ⟶ A⁻

Addition of Hydrogen

A + BH ⟶ AH + B

Removal of Oxygen

AO + B ⟶ A + BO

All the above reactions stores energy

-TheUnknownScientist

A chemistry student weighs out 0.021 kg of an unknown solid compound X and adds it to 650. mL of distilled water at 30. 0C. After 10 minutes of stirring, all of the X has dissolved. Just to be sure, the student adds a further 11. mg of X to the solution, and it, too, dissolves. Using only the information above, can you calculate the solubility of X in water at 30. 0C?

Answers

Answer:

"No" I can't calculate the solubility of X.

Explanation:

Beyond certain temperatures or heat levels, a solvent's soluble has been determined by many as the proportion of something like the solution necessary for saturating the solvents' measured amount at around that atmospheric pressure.This same solution isn't absorbed throughout this situation. It is not saturated however since the addition of 11 g of something like the mixture towards the solution completely dissolved without separating a solution.

This is why the preceding solution would be the proper one.

Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at
STP.

Answers

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}[/tex]

[tex]0.008389261745 \times 273 = 4.5P_2[/tex]

[tex]P_2 =\dfrac{0.008389261745 \times 273 }{4.5}[/tex]

[tex]P_2 =0.51 \ atm[/tex]

Can someone give me an example of balancing equations with a solution that is simple?​

Answers

Explanation:

[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]

Here is an example
The equation:
K + HOH -> KOH + H2 (an example of a single replacement reaction)
Balanced equation:
2 K + 2 HOH -> 2 KOH + 1 H2

cómo se puede comprobar el efecto universo​

Answers

Answer:

???! huhhhjhhh no I speak English

Explanation:

?

Answer:

vifucivud UKvi uiiijhhh

A mixture of fuel and is injected into a cylinder fitted with a piston. The initial volume is 0.37 L. After the mixture is ignited, gaseous products are formed and 1885 J of energy is released by the reaction. 311 J of the released energy is lost as heat to the surroundings. To what volume would the gases expand against a constant pressure of 1.036 atm, if the remainig energy is converted to work to push the

Answers

Answer:

The gases will expand to a volume of 2.37 L

Explanation:

Gases are able to do work when they expand or compress against an external constant pressure.

This work done by gases when they expand or compress against a constant external pressure is known as pressure-volume work or PV work.

The formula for calculating the work done by gases when they compress or expand against a constant pressure is given as W = PΔV

Where ΔV is change in volume given as V2 - V1

Where V2 is final volume, V1 is initial volume

By convention, W can either be negative or positive. When work is done by the system (ΔV > 0), W is negative and when work is done on the system (ΔV < 0), W is positive.

In the gas mixture above, W = PΔV

Remaining energy, W = (1885 - 311) J = 1574 J

P = 1.036 atm = 1.036 × 760 mmHg = 787.36 mmHg

ΔV = V2 - V1

ΔV = V2 - 0.37

1574 = 1.036 (V2 - 0.37)

V2 - 0.37 = 1574/787.36

V2 - 0.37 = 1.999 L

V2 = 1.999 + 0.37

V2 = 2.369 L

Therefore, the gases will expand to a volume of 2.37 L

Consider the energy diagram below.
AY
B
Free Energy
Reaction Progression
Which line indicates a higher reaction rate?
A because it has a lower activation energy.
B because it has a lower activation energy.

Answers

It is A because it has a lower activation emery than like B

Answer:

B because it has a lower activation energy.

Explanation:

Just took the test

Place the following in order of increasing entropy at 298 K.
Ne Xe He Ar Kr
A) He < Kr < Ne < Ar < Xe.
B) Xe < Kr < Ar < Ne < He.
C) Ar < He < Ar < Ne < Kr.
D) Ar < Ne < Xe < Kr < He.
E) He < Ne < Ar < Kr < Xe.

Answers

Answer:

E

Explanation:

The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.

The atomic mass of various elements is as follows

Ne = 20 g/mol

Xe = 131 g/mol

He = 4 g/mol

Ar = 40 g/mol

Kr = 84 g/mol

Therefore, the order of increasing entropy must be

He<Ne<Ar<Kr<Xe.

Hence, option E is the correct answer.

Which statement would indicate the presence of an acid?
It tastes bitter..
It does not react with active metals.
It reacts with active metals to form a gas.
It does not change the color of litmus paper

Answers

Hey, it would not chnage the color and it wouldn’t react with metals so it’s between those two options. Sorry, I don’t want to say something and it’s my wrong. That’s my best guest .

Answer:

hey the answer is that it reacts with active metals to form a gas.

Explanation:

sorry i know this is late

How much ammonia would it take to neutralize 5ml of apple cider and 5ml of white vinegar if the ammonia had a molarity of 0.25?

Answers

Answer:

[tex]m_{NH_3}=0.0213gNH_3[/tex]

Explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

[tex]CH_3COOH+NH_3\rightarrow CH_3COONH_4[/tex]

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

[tex]M_{acid}V_{acid}=M_{base}V_{base}\\\\[/tex]

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

[tex]m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3[/tex]

Regards!

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Written journal entry / BlogNewsletterVideo journal / VlogAudio journal / podcastDigital InfographicIf you have something else in mind, send me an email for approval.Requirements:_Complete sentences_ Use specific examples from the readings, assignments, or live sessions _ 1 paragraph for each of the 3 sections (total of 3 paragraph all together) _ Put in a good faith effort and _ Reach out if you need helpCheck FuelEd/Course Page for rubric you will be graded on. An outline is provided on page 2 . I recommend using this to spark your thinking and organize your thoughts. Once you have figured out what you want to say, pick a format to present this information. I encourage you to use this opportunity to be creative. After you have self-assessed yourself on the rubric and are happy with your work, turn this in! OutlineUse this outline to help you get started. 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