Bab needs help with complex numbers

Answer:

51200

Step-by-step explanation:

64000×80%=51200

[tex]\huge\mathfrak{question}[/tex]

they are sixty four thousand people at a football game 80% of the people were supporting the home team how many people were supporting the home team

[tex] \huge \mathfrak step \: by \: step[/tex]

First we will look for how much 80% of 64,000 is.

Lets put our equation

[tex]64000 \times 80 \div 100[/tex]

solve it and we get

[tex]{{\boxed{{51200}}}}}[/tex]

as our answer

1. 5

2.2

3.2,5

4.2,5

5.2

HOPE IT HELPS:)

PLS FOLLOW:)

#BRAINLIEST:)

Answer:

Merry xmas bro

Step-by-step explanation:

fav nintendo game is the first mario

Answer:

50%

Step-by-step explanation:

The diagonal line divides the square in half

I hope this help you

Answer: 6

Step-by-step explanation:

Ok lemme actually format this set

[tex]$C = \left\{\frac 1x : x \in \mathbb{Z}\ \text{and}\ 4 \leq x \leq 9\right\}$[/tex]

Well the only integers from 4 to 9 are 4, 5, 6, 7, 8, 9. So this set is just

[tex]$C = \left\{\frac 14, \frac 15, \frac 16, \frac 17, \frac 18, \frac 19\right\}$[/tex]

which has cardinality [tex]\boxed{6}[/tex] .

Answer:

Step-by-step explanation:

y - 4 = 7(x - 1)

y - 4 = 7x - 7

y = 7x - 3

True

One from of the linear function is Y =  mx + b where b is the y intercept.

The y intercept is where x is 0 so it would be at (0,6)

Answer:

13=6 and no

Step-by-step explanation:

Answer:

The distance is 19 miles

Step-by-step explanation:

I know that because you have to add how many he drove to his parents and the amount of miles driven to the cafe and then it will give the total amount driven.

Answer:

- 162, 486, - 1458

Step-by-step explanation:

To find the next term in a geometric sequence , multiply the previous term by the common ratio r

r = [tex]\frac{T_{2} }{T_{1} }[/tex] = [tex]\frac{-18}{6}[/tex] = - 3 , then

T₄ = T₃ × - 3 = 54 × - 3 = - 162

T₅ = T₄ × - 3 = 486

T₆ = T₅ × - 3 = - 1458

Answer:

Natalie pays $9 every week.

d = 9w + 72

Step-by-step explanation:

Answer:

I DON'T KNOW WHERE YOu belong because im in philippines

Answer:

Using a calcuator, [tex]7.6^{2} =57.76[/tex]

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer....

Hope it helps!

Brainliest pls!

Follow me! ♧

Answer:

I don't know

Step-by-step explanation:

Answer:

all correct except A.

Step-by-step explanation:

pls mark me brainly if u can

16%

Step-by-step explanation:

Percent can by calculated by part divided by whole multiplied by one hundred so (448/2800)*100=16

Answer:

1875

Step-by-step explanation:

Answer:

Hello!

After reviewing the problem you have provided I have come up with the correct solution:

x= 9

Step-by-step explanation:

To come up with this solution you have to first realize that the smaller triangle is a proportionally scaled down version of the entire larger triangle! (I will show what I mean in a linked picture)

So after we have realized that the smaller triangle is a scaled down version of the larger one, we can then create a formula or ratio to calculate the value of the missing side of the larger triangle (being x+6=??).

To create the formula/ratio I divided 10inches by 4inches. Thus the larger triangle is 2.5 times larger than the smaller one.

I then use this ratio to figure out the missing length of the larger triangle by doing:

6inches x 2.5 = 15inches.

I then inputed the 15inches into the formula of the missing side:

x+6=15

Subtracted 6 from both sides to simplify, and came up with the solution!

x=9

Let me know if this helps!

[tex] \: \: \: \: [/tex]

[tex]6x - 30 - 3x = - 12[/tex]

[tex]6x - 30 = - 12[/tex]

[tex] 3x = - 18[/tex]

[tex]x = 3[/tex]

[tex] \: \: \: \: \: [/tex]

[tex]\sf \longmapsto6(x−5)=3x−12[/tex]

[tex]\sf \longmapsto(6)(x)+(6)(−5)=3x+−12[/tex]

[tex]\sf \longmapsto6x+−30=3x+−12[/tex]

[tex]\sf \longmapsto \: 6x - 30 = 3x - 12[/tex]

[tex]\sf \longmapsto \: 6x−30−3x=3x−12−3x[/tex]

[tex]\sf \longmapsto3x−30=−12[/tex]

[tex]\sf \longmapsto3x−30+30=−12+30[/tex]

[tex]\sf \longmapsto3x=18[/tex]

[tex]\sf \longmapsto \: \dfrac{3x}{3} = \dfrac{18}{3} [/tex]

[tex]\sf \longmapsto \: x = 6[/tex]

[tex] \boxed{\sf \: x = 6 }[/tex]

Answer:

10.446

Step-by-step explanation:

1.

[tex]y=\frac{5}{3} x-2[/tex]

2.

[tex]y=-2x+2[/tex]

3.

[tex]y=x+5[/tex]

4.

[tex]y=\frac{1}{4}x[/tex]

Answer:

20

Step-by-step explanation:

4r - 3r = 20

r = 20

There you go.

Answer:

r = 20

Step-by-step explanation:

Let's solve your equation step-by-step.

4r − 3r = 20

Step 1: Simplify both sides of the equation.

4r − 3r =20

4r + −3r =20

(4r + −3r) =20 (Combine Like Terms)

r = 20

Hope this helps

Answer:

Neither.

Step-by-step explanation:

Manipulate the formulas into slope-intercept form which is [tex]y=mx+b[/tex].

In order for them to be parallel, m needs to be the same. Perpendicular, m for one needs to be the negative reciprocal of the other [tex]m=-\frac{1}{m}[/tex].

Let's see what we get.

(1)

[tex]3x+4y=2\\4y=-3x+2\\y=-\frac{3}{4}x+1/2[/tex]

(2)

[tex]4x+3y=2\\3y=-4x+2\\y=-\frac{4}{3}x+2/3[/tex]

They are reciprocals, but they are both negative. So, they are not the same line, perpendicular, nor parallel.

Also, you can graph these equations on desmos and see easily that they have none of these relationships.

Answer:

2,4,6,

6,12,18

10,20,30

Answer:

75,388

Step-by-step explanation:

Long Multiplication form

[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]

[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]

[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]

[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]

[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]

[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]

[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]

[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex]     [tex]=75,388[/tex]

See Image for the addition:

Answer:

Length = 90 feet

Width = 70 feet

Step-by-step explanation:

    The area of a rectangle is found by finding the product of the length. Therefore, the following formula equation can be made:

[tex]A=lw[/tex]

    The problem tells us that the area of the garden is 6,300 square feet and that the length is 20 feet longer than the width. Therefore, our equation can be rewritten as such:

[tex]6300=(w+20)(w)~or~6300=w(w+20)[/tex]

Now that there are no longer two different variables, we can solve for w.

[tex]6300=w(w+20)\\\\6300=w^2+20w\\\\0=w^2+20w-6300[/tex]

    We are left with a trinomial so we'll use the quadratic formula to further solve for w.

[tex]w=\frac{-20\pm\sqrt{20^2-4(1)(-6300)} }{2(1)}\\\\w=\frac{-20\pm\sqrt{400+25200} }{2}\\\\w=\frac{-20\pm\sqrt{25600} }{2}\\\\w=\frac{-20\pm160}{2}\\\\\\w=70\\or\\w=-90[/tex]

    Since distance cannot be negative, w = -90 cannot be a solution for this problem. Therefore, the width of the rectangular garden is 70 feet.

    Now that the width has been found, we know the length is 20 feet longer than it. Therefore, the length is 90 feet.

Answer:

Your equation option is possibly in here somewhere.

Step-by-step explanation:

A = C - 2

B = A + 6  → A = B - 6

C - 2 = A = B - 6 → B = C + 4

44 = C + B + A

44 = C + (C + 4) + (C - 2)

44 = 3C + 2

42 = 3C

C = 7

Answer360

Step-by-step explanation: