Based on the triangle given, determine the trig ratio of the cos 0

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

[tex]M = \frac{50463-38737}{2} = 5863[/tex]

Relating the margin of error with the sample size:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.9}{2} = 0.05[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.05 = 0.95[/tex], so Z = 1.64.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

For this problem, we have that [tex]\sigma = 14300, M = 5863[/tex]. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]5863 = 1.645\frac{14300}{\sqrt{n}}[/tex]

[tex]5863\sqrt{n} = 1.645*14300[/tex]

[tex]\sqrt{n} = \frac{1.645*14300}{5863}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2[/tex]

[tex]n = 16[/tex]

The sample size was of 16.

Answer:

check the picture

Step-by-step explanation:

I hope this helps

Answer:

Hey your question is in incomplete

Step-by-step explanation:

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9514 1404 393

Answer:

  see attached

Step-by-step explanation:

You know that f(0) = 2^0 = 1, so g(0) = -11 has been shifted down 12 units from f(x). A shift of half as much will be a shift down 6 units from f(x), or up 6 units from g(x).

In the attached, we have named the new function h(x). It is equivalent to g(x)+6. That is, you can add 6 to each of the g(x) table values to get the corresponding values for h(x).

Answer:

B

Step-by-step explanation:

Answer:

it's B. pa brainliest nalang po thanks

Step-by-step explanation:

B.

Answer and Step-by-step explanation:

First, multiply the parentheses, then add everything together.

-- (5x + 24)(9x +  12)

-- 45[tex]x^2\\[/tex] + 60x + 216x + 288 (Simplify)

-- 45[tex]x^2\\[/tex] + 276x + 288

--- (3x + 9)(8x + 6)

--- 24[tex]x^2\\[/tex] + 18x + 72x + 54 (Simplify)

--- 24[tex]x^2\\[/tex] + 90x + 54

---- (2x + 7)(24[tex]x^2\\[/tex] + 90x + 54)

---- 48[tex]x^{3}[/tex] + 180[tex]x^2\\[/tex] + 108x + 168[tex]x^2\\[/tex] + 630x + 378 (Simplify)

---- 48[tex]x^{3}[/tex] + 348[tex]x^2\\[/tex] + 738x + 378

----- 45[tex]x^2\\[/tex] + 276x + 288 + 48[tex]x^{3}[/tex] + 348[tex]x^2\\[/tex] + 738x + 378

----- 48[tex]x^{3}[/tex] + 393[tex]x^2\\[/tex] + 1014x + 666

48[tex]x^{3}[/tex] + 393[tex]x^2\\[/tex] + 1014x + 666 is the final answer.

#teamtrees #PAW (Plant And Water)

Answer:

[tex] \rm \displaystyle {48x}^{3} + 393 {x}^{2} +1014x + 660[/tex]

Step-by-step explanation:

we would like to simplify the following:

[tex] \rm \displaystyle (5x + 24)(9x + 12) + (3x + 9)(8x + 6)(2x + 7)[/tex]

there're two parts the multiplication the whole part to solve the multiplication part we can consider FOIL and for the whole, PEMDAS which can be represented as

[tex] \rm\displaystyle \rm \displaystyle \underbrace{\underbrace{(5x + 24)(9x + 12) } _{ \text{FOIL - 1}}+ \underbrace{ (3x + 9)(8x + 6)(2x + 7)} _{ \text{FOIL - 2}}} _{ \text{PEMDAS}}[/tex]

let's figure out FOIL-1 part

By FOIL we obtain:

[tex] \displaystyle {45x}^{2} + 60x + 216x + 288[/tex]

simplify addition:

[tex] \displaystyle {45x}^{2} + 276x+ 288[/tex]

let's figure out FOIL-2:

By FOIL and PEMDAS we acquire:

[tex] \rm \displaystyle {48x}^{3 } + {348x}^{2} + 738x + 378[/tex]

finally the whole part

[tex] \rm \displaystyle {45x}^{2} + 60x + 216x + 288+ {48x}^{3 } + {348x}^{2} + 738x + 378[/tex]

combine like terms:

[tex] \rm \displaystyle {48x}^{3} + 393 {x}^{2} +1014x + 660[/tex]

and we are done!

Answer:

(1-4)^0-3y^0

( -3)^0 -3^0

1 -1

0

Answer:

-2

Step-by-step explanation:

(y -4)^0 - 3y^0

substitute the value of y

(3-4)^0 - 3*1^0

(-1)^0 - 3*1

1 - 3

-2

Answer:

A.) m = 1.5 | B.) p = -1 | C.) t = 2

Step-by-step explanation:

A.)

[tex]4(m+3)=18\\4m+12=18\\4m=6\\m=3/2=1.5[/tex]

B.)

[tex]-2(p+5)+8=0\\-2p-10+8=0\\-2p-2=0\\-2p=2\\p=-1[/tex]

C.)

[tex]3+5(t-1)=8\\3+5t-5=8\\5t-2=8\\5t=10\\t=2[/tex]

Answer:

(a)=

4(m+3)=18

4m+12=18

4m=18-12

4m=6

m=

[tex] \frac{6}{4} [/tex]

(b)=

-2(p+5)+8=0

-2p-10+8=0

-2p=0+10-8

-2p=2

p=

[tex] \frac{2}{ - 2} = - 1[/tex]

(c)=

3+5(t-1)=8

3+5t-5=8

5t=8-3+5

5t=10

t=

[tex] \frac{10}{5} = 2[/tex]

[tex]please \: mark \: as \: brainliest \: because \: i \: spent \: much \: time \: on \: this \: question[/tex]

Answer:

The player made one two-point shot and 13 free throws.

Step-by-step explanation:

We can write a system of equations to model the situation.

Let t represent the number of two-point shots and let f represent the number of free throws made.

Since she scored a total of 14 times, the sum of two-pointers and free throws must equal 14. Hence:

[tex]t+f=14[/tex]

And since she scored a total of 15 points and each two-pointers is worth two points and every free throw is worth one:

[tex]2t+f=15[/tex]

Solve the system. We can use elimination. From the first equation, multiply both sides by negative one:

[tex]-t-f=-14[/tex]

We can add this to the second equation:

[tex](2t+f)+(-t-f)=(15)+(-14)[/tex]

Simplify:

[tex]t=1[/tex]

So, the player made only one two-point shot.

Using the first equation again, substitute one for t and solve for f:

[tex](1)+f=14\Rightarrow f=13[/tex]

Therefore, the player made one two-point shot and 13 free throws.

Answer:

Dependent and independent variables are variables in mathematical modeling, statistical modeling and experimental sciences. Dependent variables are studied under the supposition or demand that they depend, by some law or rule, on the values of other variables.

Step-by-step explanation:

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is [tex]Q(x,y)[/tex] is predicate that [tex]x<y[/tex] then [tex]x^{2} <y^{2}[/tex]. where [tex]x,y[/tex] are rational numbers.

a)

when [tex]x=-2, y=1[/tex]

Here [tex]-2<1[/tex] that is [tex]x<y[/tex]  satisfied. Then

[tex](-2)^{2}<1^{2}[/tex]

[tex]4<1[/tex] this is wrong. since [tex]4>1[/tex]

That is [tex]x^{2}[/tex][tex]>y^{2}[/tex] Thus [tex]Q(x,y)[/tex] [tex]=Q(-2,1)[/tex]is false.

b)

Assume [tex]Q(x,y)=Q(-5,2)[/tex].

That is [tex]x=-5, y=2[/tex]

Here [tex]-5<2[/tex] that is [tex]x<y[/tex] this condition is satisfied.

Then

[tex](-5)^{2}<2^{2}[/tex]

[tex]25<4[/tex] this is not true. since [tex]25>4[/tex].

This is similar to the truth value of part (a).

Since in both [tex]x<y[/tex] satisfied and [tex]x^{2} >y^{2}[/tex] for both the points.

c)

if [tex]Q(x,y)=Q(3,8)[/tex] that is [tex]x=3[/tex] and [tex]y=8[/tex]

Here [tex]3<8[/tex] this satisfies the condition [tex]x<y[/tex].

Then [tex]3^{2} <8^{2}[/tex]

[tex]9<64[/tex] This also satisfies the condition [tex]x^{2} <y^{2}[/tex].

Hence [tex]Q(3,8)[/tex] exists and it is true.

d)

Assume [tex]Q(x,y)=Q(9,10)[/tex]

Here [tex]9<10[/tex] satisfies the condition [tex]x<y[/tex]

Then [tex]9^{2}<10^{2}[/tex]

[tex]81<100[/tex] satisfies the condition [tex]x^{2} <y^{2}[/tex].

Thus, [tex]Q(9,10)[/tex] point exists and it is true. This satisfies the same values as in part (c)

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{13 - 4.5 + (-8)}\\\\\large\textsf{= 13 - 4.5 - 8}\\\\\large\textsf{13 - 4.5 = \boxed{\bf 8.5}}\large\checkmark\\\\\large\textsf{8.5 - 8}\\\\\boxed{\large\textsf{= \bf 0.5}}\large\checkmark\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 0.5}}}\huge\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

150°

Step-by-step explanation:

360° - 210° = 150° .......

Answer:

1  2/3 ( d is the answer)

Step-by-step explanation:

See image below:) I know it says 5/3 but where it says alternative form it says 1  2/3

Answer:

x = 57°

Step-by-step explanation:

Cos(x) = 0.5505

x = Cos⁻¹(0.5505)

x = 56.59

Rounding to the nearest degree;

x = 57°

Hope this helps!

Answer:

0,0

Step-by-step explanation:

Answer:

260.

because 263 is below 265 so it wont change to 270.

Answer:

1553.6mm

Step-by-step explanation:

Given data

Diameter = 622mm

Radius= 622/2= 311mm

Circumference= 2πr

Circumference= 2*3.142*311

Circumference= 1954.32

Each revolution the wheels will turn 1954.32mm

Now let us convert radian to turns

1 radian= 0.159155 turns

5 radians=  x turns

cross multiply

x= 5*0.159155

x=0.795 turns

If 1 turn will give 1954.32mm

0.795 turn will give  x

cross multiply

x= 0.795*1954.32

x=1553.6mm

Answer: 26.4

Step-by-step explanation: 1.2x22=

Answer: An expression [tex]3 \times (8 \times 8 \times 3)[/tex] will give her the total volume of the pans.

Step-by-step explanation:

Given: Length = 8 inch

Width = 8 inch

Height = 8 inch

Formula to calculate the volume of rectangular pans is as follows.

[tex]Volume = length \times width \times height\\[/tex]

Substitute the values into above formula as follows.

[tex]Volume = length \times width \times height\\= 8 \times 8 \times 3 in^{3}\\= 192 in^{3}[/tex]

Therefore, volume of each pan is 192 cubic inch. As there are three baking pans so total volume of the pans is as follows.

[tex]3 \times 192 in^{3}\\= 576 in^{3}[/tex]

Thus, we can conclude that an expression [tex]3 \times (8 \times 8 \times 3)[/tex] will give her the total volume of the pans.

Answer:

y = ½x -3

Step-by-step explanation:

_____________________

Answer:

Step-by-step explanation:

A circle centered in [tex]P(x_o,y_o)[/tex] an radius [tex]r[/tex] has a equation:

[tex](x-x_o)^2+(y-y_o)^2=r^2[/tex]

So, your equation wold be:

[tex](x-0)^2+(y-0)^2=8^2\Rightarrow x^2+y^2=64[/tex]

The correct circle's equation with radius 8 is,

⇒ x² + y² = 64

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

This circle is centered at the origin, and the length of its radius is 8.

Since, The general equation of circle with center (h, k) and radius r is,

⇒ (x - h)² + (y - k)² = r²

Here, Center = (0, 0)

Radius = 8

Hence, The correct circle's equation with radius 8 is,

⇒ (x - h)² + (y - k)² = r²

⇒ (x - 0)² + (y - 0)² = 8²

⇒ x² + y² = 64

Thus, The correct circle's equation with radius 8 is,

⇒ x² + y² = 64

Learn more about the circle visit:

https://brainly.com/question/24810873

#SPJ7

Question:

c=3x+80  

R=12x- 0.02x^2

R= revenue  

C=cost  

X=items sold  

A) 9x-(0.2x^2+80)

B) x(9-0.2x)-80  

C) x(9-0.02x)

D) 9x-0.02x^2+80

Answer:

c) x(9-0.2x)

is the correct answer

PLZ MARK BRAINLIEST

Answer:

The center (-3, 0)

9514 1404 393

Answer:

Step-by-step explanation:

The desired parameters can be found by putting the equation into the standard form for the equation of a circle:

  (x -h)^2 +(y -k)^2 = r^2 . . . . . circle centered at (h, k) with radius r

The values of h and k will be half the coefficients of the linear x- and y-terms, respectively.

  x^2 +6x +9 +y^2 -7 = 9 . . . . . add 9 to complete the square

  (x +3)^2 +y^2 = 16 . . . . . . . . . add 7 to get the desired form

This equation shows us (h, k) = (-3, 0) and r = 4.

The center is (-3, 0), and the radius is 4.

answer: each slide would be one sixth of the entire area; the entire area is (pi)(72).  

Do not use pi = 22/7 because that's untrue. It's approximately 3.1416; round off later!

hope this helps

Answer:

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Step-by-step explanation:

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Answer:

[tex]Area = 1357.344m^2[/tex]

Step-by-step explanation:

Given

Shape: dome

[tex]r = 12[/tex]

Required

The surface area

This is calculated as:

[tex]Area = 3\pi r^2[/tex]

So, we have:

[tex]Area = 3*3.142* 12^2[/tex]

[tex]Area = 1357.344m^2[/tex]