Before mr.wonsavage was a superhero in "wontropolis" he made wedding favors fof wedding receptions using peanuts and m&ms. pesnuts cost $3.50 per pound and m&ms cost $8 per pound. mr won wants to make 60 pounds of the peanut/m&ms mixture costings $6.00 per pound. how many pounds of peanuts and m&ms shoukd be mixed?

Answers

Answer 1

Answer:

10 pounds of copounds must be mixed

Step-by-step explanation:

Because if Mr wom wants 60 pounds if 1 cost &$6.00 he must take the prime number that can be multiplied by 6 to give us 60. The number is 10.


Related Questions

1. You and your friends receive a lunch bill for $22.50 before tax is included. The sales tax in your state
is 8%. What is the total cost when the tax is included?

Answers

Answer:

$24.30

Step-by-step explanation:

8% of 22.50 = $1.8

$22.50 + $1.8 = $24.30

Give brainliest, please!

Hope this helps :)

help geometry ………ignore this i need 20 words

Answers

Answer:

The answer is 1

Step-by-step explanation:

What is the volume of a rectangular sandbox that is 3 feet by 4 feet by 1 foot?

13 ft 3
8 ft 3
12 ft 3
7 ft 3

Answers

Answer:

Volume = 12 ft^3

Step-by-step explanation:

Vol = length×width×height

= 3×4×1

= 12

The volume is 12 cubic feet.

it would be 12ft3 because 3x4x1= 12!

evaluate the following expression. you should do this problem without a calculator e^In3

Answers

The relation between the exponential and the logarithm is used. Then the expression [tex]e^{\ln3}[/tex] is given as 3.

What is a logarithm?

Exponents can also be written as logarithms. A number base logarithm is similar to some other number. It is the exact inverse of the exponent expression.

The expression is given below.

[tex]\rightarrow e^{\ln3}[/tex]

We know the formula

[tex]\rm e^{\ln x} = x[/tex]

Then the expression can be written as

[tex]e^{\ln3} = 3[/tex]

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Find the distance between y=7 and y=-1

Answers

Answer:

Er I think it’s 8 but not sure

Step-by-step explanation:

Solve the following:
4x3 = 2x + 7

Answers

Answer:

If you meant 4x to the third power, than x = 1.34

Bob bikes to work 8 miles each day. The trip takes him 0.5 hours. If Bob bikes at a constant rate, what is his biking speed? A. 5 mph B. 8 mph C. 16 mph D. 40 mph

Answers

Given the distance covered and the time elapsed, if the bike is at a constant rate, the speed of Bob's bikes is 16 mph.

Option C) is the correct answer.

What is Speed?

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

Distance covered d = 8milesTime elapsed t = 0.5hrsSpeed of the bike S = ?

Speed = Distance ÷ time

Speed = 8miles / 0.5hrs

Speed = 16 mph

Therefore, Given the distance covered and the time elapsed, if the bike is at a constant rate, the speed of Bob's bikes is 16 mph.

Option C) is the correct answer.

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John is weighing his jars of coins. his jar of pennies weighs 84.96 ounces, and his jar of nickels weighs 3.11 kilograms. there are 0.0283495 kilograms per ounce. which jar weighs more, and how many more pounds does it weigh? a. the jar of pennies weighs 8.41 pounds more than the jar of nickels. b. the jar of pennies weighs 0.089 pounds more than the jar of nickels. c. the jar of nickels weighs 2.06 pounds more than the jar of pennies. d. the jar of nickels weighs 1.55 pounds more than the jar of pennies.

Answers

The jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d

Calculating weight

From the question, we are to determine the jar that weighs more

From the given information

His jar of pennies weighs 84.96 ounces

and his jar of nickels weighs 3.11 kilograms

First, we will 84.96 ounces to kilogram

From the given conversion,

There are 0.0283495 kilograms per ounce

That is, 0.0283495 kg = 1 ounce

If 1 ounce = 0.0283495 kg

Then,

84.96 ounces = 84.96 × 0.0283495 kg

∴ 84.96 ounces = 2.4086 kg

His jar of pennies weighs 2.4086 kg

Since the John's jar of nickels weighs 3.11 kg, his jar of nickels weigh more.

3.11 kg - 2.4086 kg = 0.7014 kg

Convert 0.7014 kg to pounds

1kg =  2.20462 pounds

∴ 0.7014 kg = 0.7014 × 2.20462 pounds

0.7014kg ≅ 1.55 pounds

Hence, the jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d.

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− 4 + 1 2 x = 8 is it true

Answers

Answer:

12 -4x = 8

So "Yes" it is true

Can someone solve this please

Answers

Answer:

4x + 5x = 180

9x = 180

x = 180/9

x = 180 ÷ 9

x = 20

Help me i am on iready math

Answers

Answer:

14

Step-by-step explanation:

Because your total is 182 desserts and you want to arrange them into 13 rows you will divide the two numbers. So, 182/13 is 14. so 14 is your answer.

Hope that helped

Answer:

14 Tropical cupcakes per row

Hope this helped :)

Step-by-step explanation:

182 ÷ 13 = 14

Check:

14 × 13 = 182 ✓

Calculate the value of p in the diagram below


Answers

Answer:

40.5

Step-by-step explanation:

(n-2)*180

(7-2)*180=5*180=900

10p+135+149+121+90=900

10p=-495+900=405

p=40.5

How do you add these two consecutive triangular numbers?
TR(4)+TR(3)

Answers

The n-th trianglar number is given by

[tex]T_n = \dfrac{n(n+1)}2[/tex]

Then

[tex]T_4 + T_3 = \dfrac{4\times5}2 + \dfrac{3\times4}2 = \boxed{16}[/tex]

Alternatively, the triangular numbers are defined recursively by

[tex]\begin{cases}T_1 = 1 \\ T_n = T_{n-1} + n & \text{for } n>1\end{cases}[/tex]

This means

[tex]T_1=1[/tex]

[tex]T_2 = T_1 + 2 = 3[/tex]

[tex]T_3 = T_2 + 3 = 6[/tex]

[tex]T_4 = T_3 + 4 = 10[/tex]

so that

[tex]T_3+T_4=\boxed{16}[/tex]

The paddock in judy's ranch is 60 feet long and 20 feet wide. he also built a square corral adjacent to the paddock. if the side of the corral measures 16 feet, determine the total area of the paddock and corral.

Answers

Answer:

1456ft²

Step-by-step explanation:

A = lw

A = 60(20)

A = 1200ft²

A = 16(16)

A = 256ft²

1200 + 256 =

1456ft²


John bought 4 pounds of hot dogs for his party.
How many ounces of hot dogs did John buy?

Answers

Answer:

64 Ounces

Step-by-step explanation:

64 Ounces of hot dogs

Answer:

64 oz

Step-by-step explanation:

1 lb = 16 oz

4 × 1 lb = 4 × 16 oz = 64 oz

Simplify this question

Answers

Step-by-step explanation:

9x²/3x + 12x/3x + 1

= 3x/1 + 4/1 + 1

= 3x + 5

I hope this is true..

9x^2 +6x+6x+1
3x(3x+2) +6x +1

Answer = 3x +2+6x+1
=9x +3 or 3(3x+1)

#8 HELP IM STUCK ON THIS

Answers

Answer:

12 ft

Step-by-step explanation:

for the model is 1 and the actual is 5

conversion yards to feet

3 feet = 1 yard

20 * 3 = 60

60/5 = 12

your answers 12 ft

hope this helps:)

its wrong someone help me with it

Answers

Answer:

the answer is π^8

Step-by-step explanation:

the math program has got some bugs in it. See your teacher and tell him or her about it

Stephanie earns $50 a week from babysitting. She spends
$25, saves $15, and uses the rest to repay a loan of $100 from
her brother. After six weeks, how much has Stephanie spent,
how much has she saved, and how much does she still owe her
brother?

Answers

Step-by-step explanation:

Stephanie has spent $150

she has saved $90

and owes her brother$40

Spent:
$25 X 6 = $150

Saved:
$15 X 6 = $90

Owed:
$50 - $25 - $15 = $10
$10 X 6 = $60
$100 - $60 = $40

I need help what is (4÷5×x) what I x​

Answers

Answer:

0.8x

Step-by-step explanation:

According to BODMAS,

Step 1 :

4 ÷ 5

= 4 / 5

= 0.8

Step 2 : Multiply x.

0.8 * x = 0.8x

Answer:

Step one

4 ÷ 5

= 4/5

= 0.8

Step two = 0.8 * x

= 0.8x

i need some help with this

Answers

Answer:

x + y = 4

substitute (-A, 2B) in the equation.

-A + 2B = 4

substitute (3A-2, 3-B) in the equation

3A-2 + 3-B = 4

Use elimination method and hence multiply the first substituted equation by 3

-3A + 6B = 12

3A-2 + 3-B = 4

-2 + 3 + 5B = 16

5B = 15

B = 3

Substitute value of B in any of the equations

and hence A = 2

sin(-17pi/6)

How do I solve this

Answers

Answer:

if you have a graphing calculator you can just plug the whole equasion in. the anser I got was -0.1547307191

Step-by-step explanation:

to get pie you have to hit second and then ^

the points at which a quadratic equation intersects the x-axis

Answers

The points at which a quadratic equation intersects the x-axis are referred to as   x intercepts or zeros or roots of quadratic equation

Given :

The points at which a quadratic equation intersects the x-axis

The points at which the any quadratic equation crosses or touches the x axis are called as x intercepts.

At x intercepts the value of y is 0.

So , the points at which a quadratic equation intersects the x-axis is also called as zeros or roots of the quadratic equation .

The points at which a quadratic equation intersects the x-axis are referred to as   x intercepts or zeros or roots of quadratic equation

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What is the quotient? startfraction 2 y squared minus 6 y minus 20 over 4 y 12 endfraction divided by startfraction y squared 5 y 6 over 3 y squared 18 y 27 endfraction startfraction 2 over 3 (y minus 5) endfraction startfraction 3 (y minus 5) over 2 endfraction startfraction (y minus 5) (y 2) squared over 6 (y 3) squared endfraction startfraction 3 (y 5) (y minus 2) over 2 (y 2) endfraction

Answers

The quotient of two fractions, (2y² - 6y - 20)/(4y + 12) and (y² + 5y + 6)/(3y² + 18y + 27), is: 3(y - 5)/2

What is a Quotient?

Quotient can be described as the result you get from dividing a term by another term.

Let's find the quotient of (2y² - 6y - 20)/(4y + 12) and (y² + 5y + 6)/(3y² + 18y + 27)

Quotient = (2y² - 6y - 20)/(4y + 12) ÷ (y² + 5y + 6)/(3y² + 18y + 27)

Change the division sign to multiplication sign and turn the second fraction upside down

(2y² - 6y - 20)/(4y + 12) × (3y² + 18y + 27)/(y² + 5y + 6)

Bringing out the common terms, we would have:

2(y² - 3y - 10)/4(y + 3) × 3(y² + 6y + 9)/(y² + 5y + 6)

Factorize

2(y - 5)(y + 2)/4(y + 3) × 3(y + 3)(y + 3)/(y + 3)(y + 2)

Cancel out common factors

= 3(y - 5)/2

Quotient = 3(y - 5)/2

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Answer:b

Step-by-step explanation:

lol

Construct a 90% confidence interval for the population mean, . assume the population has a normal distribution. a sample of 15 randomly selected students has a grade point average of 2.86 with a standard deviation of 0.78

Answers

Answer:

[tex]CI=\{2.5053,3.2147\}[/tex]

Step-by-step explanation:

Assuming the conditions for constructing a t-confidence interval are true, we use the formula [tex]\displaystyle CI=\bar{x}\pm t^*\biggr(\frac{s}{\sqrt{n}}\biggr)[/tex] where our sample mean is [tex]\bar{x}=2.86[/tex], our sample standard deviation is [tex]s=0.78[/tex], our sample size is [tex]n=15[/tex], and a 90% confidence level is equivalent to a critical value of [tex]t^*=1.7613[/tex],

[tex]\displaystyle CI=\bar{x}\pm z^*\biggr(\frac{s}{\sqrt{n}}\biggr)\\\\CI=2.86\pm 1.761\biggr(\frac{0.78}{\sqrt{15}}\biggr)\\\\CI=2.86\pm0.3547\\\\CI=\{2.5053,3.2147\}[/tex]

Hence, we are 90% confident that the true population mean of a student's grade point average is between 2.5053 and 3.2147

If the dimensions of a rectangular prism are 10 cm x 5 cm x 7 cm, what is
the surface area?

Answers

Answer:

310

Step-by-step explanation:

Multiply the l/w/h x 2

A teacher randomly chooses a two-person leadership team from a group of four qualified students. Three of the
students, Sandra, Marta, and Jane, are girls. The fourth student, Franklin, is a boy.
Using the sample space of possible outcomes listed below, where each student is represented by the first letter
of his or her name, answer each of the following questions.
What is P(A), the probability that the first student is a girl?
What is P(B), the probability that the second student is a girl?
What is P(A and B), the probability that the first student is a girl and the second student is a girl?

Answers

Answer:

what is P(A), the probability that the first student is a boy? 3/5


what is P(B), the probability that the second student is a girl? 3/4


what is P(A and B), the probability that the first student is a boy and the second student is a girl? 1/2


No, évents A and B are not independent events

Step-by-step explanation:

The probability that the first student is a girl P(A)= 3/4.

The probability that the second student is a girl P(B)= 3/4.

The probability that the first student is a girl and the second student is a girl P(A and B)=9/16.

Given that there are three girls (Sandra, Marta, Jane) and one boy (Franklin), and the sample space of possible outcomes is:

{SA, SM, SJ, SF, MA, MS, MJ, MF, JA, JS, JM, JF, FA, FS, FM, FJ}

P(A): Probability that the first student is a girl (Sandra, Marta, or Jane).

Number of favorable outcomes where the first student is a girl: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(A) = Number of favorable outcomes / Total outcomes = 3 / 4

P(B):

Probability that the second student is a girl (Sandra, Marta, or Jane).

Number of favorable outcomes where the second student is a girl: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(B) = Number of favorable outcomes / Total outcomes = 3 / 4

P(A and B):

Probability that the first student is a girl and the second student is a girl.

Number of favorable outcomes where both students are girls: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(A and B) = P(A).P(B)

= 3/4 × 3/4

=9/16

Hence, P(A)=3/4

P(B)=3/4

P(A and B)=9/16

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The volume of this cylinder is 1,481,276.16 cubic inches. What is the radius? (will mark brainliest)

Answers

Answer:

radius = 72.00 in (nearest hundredth)

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Volume = 1,481,276.16 in³Height = 91 inπ ≈ 3.14

Substituting the given values into the formula and solving for r:

[tex]\implies \sf 1481276.16=3.14 \cdot r^2 \cdot 91[/tex]

[tex]\implies \sf 1481276.16=285.74r^2[/tex]

[tex]\implies \sf r^2=\dfrac{1481276.16}{285.74}[/tex]

[tex]\implies \sf r^2=5184[/tex]

[tex]\implies \sf r=\sqrt{5184}[/tex]

[tex]\implies \sf r=72\:in[/tex]

Answer: radius : 72.00 inch

The following is a cylinder.

Volume of Cylinder: πr²h

Given following:

volume: 1,481,276.16height: 91 inchπ ≈ 3.14radius: r

Solve for radius:

[tex]\rightarrow \sf \pi r^2h =V[/tex]

[tex]\rightarrow \sf (3.14) r^2(91) =1,481,276.16[/tex]

[tex]\rightarrow \sf r^2 =\dfrac{1,481,276.16 }{91(3.14)}[/tex]

[tex]\rightarrow \sf r^2 =5184[/tex]

[tex]\rightarrow \sf r=\sqrt{5184}[/tex]

[tex]\rightarrow \sf r=72[/tex]

whats the 8th term of 12,18,27

Answers

THIS QUESTION IS SOLVED BY DOUBLE DIFFERENCE

8,12,18,27

DIFFERENCE NO. 1

12–8=4

18–12=6

27–18=9

DIFFERENCE NO. 2

6–4=2

9–6=3

FINALLY

4+9=13

13+27=40

ANSWER= 40

Answer:

205.03125.

Step-by-step explanation:

18/12 = 1.5

27/18 = 1.5

This is geometric with nth term = ar^(n-1)

Here first term a = 12 and common ratio r = 1.5, so

The 8th term = 12(1.5)^(8-1)

= 205.03125

Identify the terms, coefficients, and constants in the expression 20x+13.

Answers

Answer: coeficient is 20 and the constant which is 13

Step-by-step explanation:

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Anna and her husband had two small children, and Reverend Burwell's salary was small. Anna decided to use her lifelong love of education to help her family and other young women. As a supplement to her husband's income, Anna began teaching the daughter of James Webb, the owner of the town's general store. Two years later, Anna opened one of the first all-female academies in North Carolina, the Burwell Female School. In addition to being the founder of the Burwell Female School, Anna was also the full-time administrator. She created the curriculum for the school's classes, which included Latin, botany, astronomy, and physical education. Many students traveled from out of state to attend the school, and these students shared the Burwell home with Anna, her husband, and their growing family (which eventually included twelve children). Over the course of twelve years, two hundred students were educated at the Burwell's school. Anna shared her love for education with her students. In fact, many of Anna's students went on to create schools of their own.What does the author's emphasis on education convey to the reader? A. By emphasizing education, the author conveys Annas difficulty in creating the curriculum. B. By emphasizing education, the author highlights the challenges that educators faced in the nineteenth century. C. By emphasizing education, the author conveys the significance of education in achieving success. D. 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