Answer:
2.5m/s
Explanation:
m1=55kg
m2=25kg
Ben's velocity before collision=0m/s
Junior's velocity before collision= 8m/s
P1=m1v1+m2v2
P1=55kg(0m/s)+25kg(8m/s)
P1=200kg(m/s)
Know that the momentum before the collision = momentum after the collision
P2=(55kg+25kg)V
200kg(m/s)=(75kg)V
200kg(m/s)/75kg=V
V=2.5m/s.
It makes sense bc after they collide, their speed would slow down, and it wouldn't make sense if the momentum would be greater or less after they collide.
What is the significance of Isaac's name?
Answer:
ghgivjgifigo ra together aigig disgust u hoodie
A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a third ball with a mass of 0.2 kg. If the system is closed, what is the velocity of the third ball?
4 m/s
36 m/s
30 m/s
1.44 m/s
A crane is lifting a 500 lb piano with a velocity of 2fts''. Express the power of the crane in hp. (1 hp = 550ft-lbs)
Answer:
goalindia
goalindiaGiven:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kg
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 W
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s- So, the velocity of the car will be 0.61❤
while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to gravity on the earth. what is the centripetal force acting on her
Answer:
Explanation:
70.0(5.00)(9.81) = 3,433.5 = 3430 N
To solve this we must be knowing each and every concept related to centripetal force and its calculations. Therefore, the centripetal force acting on her is 3430 N.
What is centripetal force?The term centripetal relates to a propensity to gravitate toward the center. Centripetal refers to moving in the direction of the center. The force that maintains an item moving in a circular direction and helps it stay on the path is referred to as centripetal force.
Furthermore, centrifugal force is indeed the tendency of things to deviate from a circular route and fly in a straight line. People frequently confuse centripetal force with centrifugal force.
Mathematically,
F = m a
= 70 acceleration
= 70 × 5 × 9.81
= 3430 N
Therefore, the centripetal force acting on her is 3430 N.
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Who did the ram caught in the thicket (Genesis 22:13) represent?
Answer:
I'm no Bible person, but I think it stands for i-dont-give-a-donkey-poop.
and suck-dog-nuts.
a
A person throws a ball up into the air, and the ball falls back towar
would the kinetic energy be the lowest? (1 point)
at a point before the ball hits the ground
when the ball leaves the person's hand
o when the ball is at its highest point
at a point when the ball is still rising
Answer:
when the ball is at its highest point
Explanation:
Provided the ball returns to where it was thrown. The velocity, and therefore kinetic energy, will be momentarily zero at the highest point of the throw.
5. Which statement about the acceleration of an object is corr
a. The acceleration of an object is directly proportional to t
external force acting on the object and inversely propo
mass of the object.
b. The acceleration of an object is directly proportional to
external force acting on the object and directly propor
mass of the object.
c. The acceleration of an object is inversely proportional
external force acting on the object and inversely prop
mass of the object.
d. The acceleration of an object is inversely proportiona
external force acting on the object and directly propo
mass of the object.
Answer:
a
Explanation:
you will find out that an object that has more weight requires more energy to move than the one with less weight
It takes about 4.4 Newtons to lift 1 pound.
How many Newtons would it take to lift 2 pounds?
If it takes 4.4 Newton to lift 1 pound, then to lift 2 pounds the force required will be equal to 8.8 Newton.
What is Force?A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.
Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.
According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.
As per the given data in the question,
It takes 4.4 N to lift 1 pound,
Let the total force required to lift 2 pounds is x.
x = (4.4 × 2)/1
x = 8.8 N
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In your own words, describe how metter is identified
Answer: It is identified with color, texture, boiling point, melting point and freezing point
Explanation:
18. Why is the sun included in this model of the water cycle?
A. The water cycle takes place in the atmosphere and and since the sun can be
seen through the atmosphere it make the model more detailed
B. The sun is the driving force that provides the energy that keeps the water cycle
going
C. The water cycle takes place in the hydrosphere and since the sun makes it
possible for us to see everything it is included in the picture.
D. The sun is part of condensation and run-off
Answer:
b
Explanation:
1st grade common sense
Write down the condition required for the thermonuclear fusion.
Answer:
The main condition necessary for a controlled thermonuclear fusion:
The ions must be held together in close proximity at high temperature with a confinement time long enough to avoid cooling.
when the tides are especially weak it is called a _____ tide
Answer:
When the tides are especially weak, it is called a NEAP tide.
Explanation:
Hope this helps :)
Answer:
Neap
Explanation:
Answered!
A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total energy.
Answer:
a = ω^2 A formula for max acceleration (ignoring sign)
V = ω A formula for max velocity
V^2 = ω^2 A^2 = a A from first equation
E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J
(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule
You are given two vectors A⃗ =−3.00i^+5.00j^ and B⃗ =7.00i^+2.00j^. Let counterclockwise angles be positive.
a)What angle θA, where 0∘≤θA<360∘, does A⃗ make with the +x-axis?
Express your answer in degrees.
b)What angle θB, where 0∘≤θB<360∘, does B⃗ make with the +x-axis?
Express your answer in degrees.
c)Vector C⃗ is the sum of A⃗ and B⃗ , so C⃗ =A⃗ +B⃗ . What angle θC, where 0∘≤θC<360∘, does C⃗ make with the +x-axis?
Express your answer in degrees.
Answer:
Explanation:
We can subtract directly the corresponding components and check using the parallelogram rule.
Explanation:
Have a look:
enter image source here
Where, graphically, I used the fact that:
→
A
−
→
B
=
→
A
+
(
−
→
B
)
For the magnitude we use Pythagoras (with the components) to get:
∣
∣
∣
→
A
−
→
B
∣
∣
∣
=
√
(
−
1
)
2
+
(
5
)
2
=
√
1
+
25
=
√
26
≈
5.1
For the direction I can see that will be
90
∘
from the
x
axis up to the
y
axis, plus the little bit passed the
y
axis given as:
θ
=
arctan
(
1
5
)
=
11.3
∘
giving in total: angle
=
90
∘
+
11.3
∘
=
101.3
∘
C. Answer the following questions.
1. Define Earthquake. Write any 3 precautions during earthquake
Answer:
1. An earthquake is a sudden violent shaking of the ground, typically causing great destruction, as a result of movements within the earth's crust or volcanic action. 2. (3 precautions during an earthquake are)... If you are indoors take cover under a desk, Stay away for glass doors, windows or outside doors and finally drop down or hold on to something until the shaking stops.
Hope that helped?
Explanation:
A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s. (a) what is the mass of the block office? (b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s?
Answer:
(a) 91 kg (2 s.f.) (b) 22 m
Explanation:
Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.
(a)
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}[/tex]
Subsequently,
[tex]F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})[/tex]
*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.
(b) To find the final velocity of the ice block at the end of the first 5 seconds,
[tex]v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}[/tex]
According to Newton's First Law which states objects will remain at rest
or in uniform motion (moving at constant velocity) unless acted upon by
an external force. Hence, the block of ice by the end of the first 5
seconds, experiences no acceleration (a = 0) but travels with a constant
velocity of 4.4 [tex]m \ s^{-1}[/tex].
[tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}[/tex]
Therefore, the ice block traveled 22 m in the next 5 seconds after the
worker stops pushing it.
1. What is the frequency of light waves with wavelength of 5 x 10-⁷ m?
Answer:
Speed of light =m/s
wavelength = m
frequency = ?
we have
Speed = frequency × wavelength
[tex]3* 10^8[/tex] = frequency × [tex]5 * 10^{-7}[/tex]
Frequency = [tex]\frac{3*10^8}{5*10^{-7}}=6*10^{14}[/tex]hz
Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.
Definition of wavelengthFirst of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
Definition of frequencyOn the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Definition of propagation speedFinally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f× λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.
Frequency of light waves with wavelength of 5×10⁻⁷ mIn this case, you know:
v= 3×10⁸ m/sf= ?λ= 5×10⁻⁷ mReplacing in the definition of propagation speed:
3×10⁸ m/s = f× 5×10⁻⁷ m
Solving:
3×10⁸ m/s ÷ 5×10⁻⁷ m= f
f= 6×10¹⁴ Hz
In summary, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.
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The earth has a mass of 5.972 x 1024 Kg. You decide to
put the satellite in an orbit 400 Km above the surface of the earth which has a radius of 6,371 Km, so the total
distance from the center of the earth to the satellite is 6,771,000 m. What will you need the velocity of the
satellite to be to stay in orbit? Show your work
Answer:
Explanation:
You want the required centripetal force to equal gravity force
if m is the mass of the satellite
ma = mv²/R
a = v²/R
F = ma = GMm/R²
a = GM/R²
v²/R = GM/R²
v² = GM/R
v = √(GM/R)
v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)
v = 7.672 x 10³ m/s
The block in the figure below has a mass of 5.1 kg and it rests on an incline of angle . You pull on the rope with a force F = 34 N. Assume the incline is smooth and determine the angle of the incline if the block moves with constant speed.
42.9°
Explanation:
Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:
[tex]x:\;\;\;\;F - mg\sin{\theta} = 0\;\;\;\;[/tex]
[tex]\Rightarrow mg\sin{\theta} = F[/tex]
Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at [tex]\theta.[/tex] Solving for the angle, we get
[tex]\sin{\theta} = \dfrac{F}{mg}[/tex]
or
[tex]\theta = \sin^{-1}\left(\dfrac{F}{mg}\right)[/tex]
[tex]\;\;\;= \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right][/tex]
[tex]\;\;\;=42.9°[/tex]
The spring constant of Spring A is twice as great as the spring constant of Spring B. Both springs are stretched the same amount. How does the
force the Spring A applies compare to the force Spring B applies?
Answer:
FA = 2FB
Force on spring A is twice the Force on spring B
Explanation:
F = kx
FB = (kB)x
FA = (kA)x
FA= (2kB)x
FA = 2(kB)x
FA = 2FB
The force [tex]F_A[/tex] needed to stretch spring A is going to be twice as much as the force [tex]F_B[/tex] needed to stretch spring B.
Explanation:
We know that the spring constants are related as
[tex]k_A = 2k_B[/tex]
The force [tex]F_A[/tex] needed to stretch spring A is given by
[tex]F_A = -k_Ax[/tex]
Also, the force [tex]F_B[/tex] needed to stretch spring is
[tex]F_B = -k_Bx[/tex]
Taking the ratio of the forces, we get
[tex]\dfrac{F_A}{F_B} = \dfrac{-k_Ax}{-k_Bx} = \dfrac{k_A}{k_B}[/tex]
Since [tex]k_A = 2k_B,[/tex] the equation above becomes
[tex]\dfrac{F_A}{F_B} = \dfrac{2k_B}{k_B} = 2[/tex]
or
[tex]F_A = 2F_B[/tex]
This shows that since the spring constant of spring A is twice as large as that of spring B, the force needed is going to be twice as large.
What is the unit of frequency
Answer:
hertz (Hz)
The number of periods or cycles per second is called frequency. The SI unit for frequency is the hertz (Hz).
Answer: the answer is hertz! if you’re on plato it’s option C. have a nice day! :)
Explanation:
please help me rn rn
Answer:
merry Christmas ⛄
A 2.00 kg rock is dropped from the top of a 30.0 m high building. Calculate the ball’s momentum at the time that it strikes the ground.
Explanation:
We use the Theorem of conservation of mechanical energy for finding the velocity when it strikes the ground:
Ei = Ef
Ki + Ui = Kf + Uf
Ui = Kf
m g h = 1/2 m v^2
v = sqrt(2gh)
So the momentum will be:
p = mv = m * sqrt(2gh)
What are the characteristics of high energy wave?
A. Low frequencies and short wavelengths.
B. High frequencies and long wavelengths.
C. Low frequencies and long wavelengths.
D. High frequencies and short wavelengths
Answer:
D. High frequency and short wavelengths.
Explanation:
If a wave is high in energy it will have a higher frequency.
High frequency = short wavelengths
What is force? And tell it's unit
Answer:
force is simply a push or a pull in a particular direction. The unit is N (newton)
Explanation:
hope this helped
Answer:
In physics force is an influence which changes the motion of an object which has mass
Its unit is N or kgms/2
A change
1. Ricardo has purchased a forklift for his business. The forklift can put out 4950 W of power. If the forklift is operating at full capacity, how much work can it do in 2.40 seconds?
O 2060)
O 4950)
O 6490)
O 11,900
The work done if the forklift is operating at full capacity is 11,900 J.
We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;
Power = Work done/time taken
When;
Power = 4950 W
Time taken = 2.40 s
Work done = Power × time taken
Work done = 4950 W × 2.40 s
Work done = 11,900 J
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How much energy is needed to change the temperature of 50g of water 15°c
Explanation:
This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature
A garden hose shoots water horizontally from the top of a tall building toward the wall of a second building 20 meters away. If the speed with which the water leaves the hose is 5 m/sec, how long does it take the water to reach the second building, and what distance does the water fall in this time?
Answer:
Explanation:
If air resistance is ignored, the water travels for a time of
t = d/v = 20 m / 5 m/s = 4 s
falling from vertical rest, the water strikes the wall a distance below the hose
d = ½gt² = ½(10)4² = 80 m
Yeah, I think ignoring air resistance is wishful thinking considering the time and distances involved.
8.
When minerals seep into and replace the organic cells of a dead organism, creating a
mineral replica of the organism is called ...
Petrification
b. Tar Seeps
C. Amber
d. Mummification
Answer:
a. petrification
Explanation:
tar seeps = natural trade that, because of its close proximity to the ground surface, seeps from the cracks in the Earth or between rocks forming pits or pools (tar pits)
amber = fossilized resin produced by extinct coniferous trees, typically yellow in color
mummification = a process in which the skin and flesh of a corpse can be preserved by embalming and drying
How is the A He related to the A Hof a reaction?
Answer:
by giving a person to person