A 1167 kg car is driving along a highway with 458,350 J of kinetic energy.
What is its speed?

1) The control group are the people that are in group B

2) The independent  variable is the administration of the breath mint

3) The dependent variable is the breath of the participants

4) The conclusion of Mr Krab should be that the breath mint is effective in treating bad breath.

5)  10 people in group B reported fresher breath because they thought that they got the breath mint.

The term experiment is used to describe the way tat we could be able to spot the relationship between the dependent and the independent variable. Let us note that the independent variable is the variable that we have to manipulate in the course of an experiment while the dependent variable is the variable that would change as we change the independent variable.

We can see that there was a sort of improvement of the breath of the customers which according to the hypothesis of the experiment would be attributable to the new formula of the  breath mint.

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A 90 kg astronaut, initially at rest, throws a 5 kg oxygen tank at 1 m/s away from himself.  The new speed for astronauts is 0.055 meters per second, and they will go in the opposite direction of the thing they are chasing.

This is further explained below.

Generally, For this, use the law of conservation of momentum

Total final momentum = Total final momentum

P_{a i}+P_{0 i}=P_{a f}+P_{o f}

m_{a v_{a i}}+m_0 v_{o i}=m_{a v_{a f}}+m_0 v_af

0+0=90 v_{a f}+5 *1

90 v_{a f}=-5 a

[tex]v_{a f}=-\frac{5}{90} \mathrm{~m} / \mathrm{sec} \\\\v_{a f}=-0.055 \mathrm{~m} / \mathrm{sec}[/tex]

In conclusion, The new speed of astronauts is  0.055m/second and astronauts will move in the opposite direction of the object.

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The force of gravity will become one fourth of the original force when the masses of the objects remain the same but their distance of separation doubles.

Force of gravity is an attraction force which holds the object towards the ground surface.

The gravitational force depends directly on the masses of two objects and indirectly on the square of the distance between them.

Let

m₁ and m₂ be the two different masses

r₁ be the initial distance between the the two masses

r₂ be the distance when their separation doubles.

i.e. r₂ = 2r₁

So, according to the formula,

F₁ =   [tex]\frac{Gm1m2}{r1^{2} }[/tex]

F₂ =   [tex]\frac{Gm1m2}{r2^{2} }[/tex]

since masses are same:

[tex]\frac{F1}{F2} = \frac{r2^{2} }{r1^{2} }[/tex]

[tex]\frac{F1}{F2} = \frac{4r1}{r1}[/tex]

F₁ = 4F₂

F₂ = [tex]\frac{1}{4}[/tex]F₁

The resultant force is one fourth of the original force.

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The average speed for the remainder of the journey of the car which covers a distance of 120 km in 2.5 h is 15 km / h

v = d / t

v = Average velocity

d = Distance

t = Time

During the first 1.5 h,

v = 70 km / h

d = v * t

d = 70 * 1.5

d = 105 km

During the remainder of the journey,

d = 120 - 105

d = 15 km

t = 2.5 - 1.5

t = 1 hr

v = 15 / 1

v = 15 km / h

Therefore, the average speed for the remainder of the journey is 15 km / h

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The total distance covered is 100m and displacement is 60m

The area under curve(a1)=1/2×b×h

=1/2×6×20

=60m

The area under curve(a2)=1/2×b×h

=1/2×2×10

=20m

The area under curve(a3)=l×b

=2×10

20m

∴The total distance covered=a1+a2+a3

=(60+20+20)m

=100m

∴The displacement=a1-a2+a3

=(60-20+20)m

=60m

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Error might the student have made was in angle 147 as acute angle means angle less than 57°.

An acute angle is any angle that is more than 0° and less than 90°.

1st angle = 33 °

That sum of acute angles of a triangle should be less than 90°.

Let's assume other angle be x.

So ;

x + 33° < 90°

x <90° - 33°

x < 57°

The student had measured ∠2 wrongly because sum of acute angles of a triangle should be less than 90°.

The correct measure of other angle should be less than 57°.

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Answer:

work = force x displacement

force = 250N

displacement = 15m

work = 250 x 15

work = 3750J

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Answer:

the tendency of an object to resists a change in motion depends on its mass. if the net force acting on an above zero, its inertia is also zero.

when you are moving at a high rate of speed, inertia makes it hard to stop . newton's first law of motion applies only to objects that are already moving.

Explanation:

the answer would be TRUE

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Answer:

True

Explanation:

An object thats in motion will stay in motion with the same direction and speed unless an unbalanced force acts upon it. This means that when moving at a high rate of speed, its hard to stop unless you come in contact with an unbalanced force.

Answer:

a sleep doesnt get to depict whether you get a good grade or not its what you know.

Option (b) mgh/t will be the power supplied by the lifting force.

What does Newton's first law of motion state?

According to Newton's first law of motion, if a body is at rest or moving in a straight line at a constant speed, it will continue to move at that speed or remain at rest until acted on by a force.

How are formulas of power and force interlinked?

F = mg is the formula for force where,

F = force required

m = mass of the object

g = gravitational constant

and P=Fd/t is the formula for power where,

P= power

F=force

d= distance

and t= time

Substituting the value F=mg, in P=Fd/t we get,

P=mgd/t or P=mgh/t

Hence, we can conclude,

F = mg is the equation that expresses the force required to raise an item at a constant speed. P = Fd/t = mgh/t is then used to calculate the power.

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The minimum amplitude of the wave is equal to  [tex]\frac{g \mu}{T_{\mathrm{s}}}\left(\frac{\lambda}{2 \pi}\right)^2[/tex]

A type of radio propagation known as a surface wave is known as ground wave propagation. Low and medium frequency versions of these waves travel across the surface of the earth. Mostly, these are employed for transmission between the earth's surface and the ionosphere. The quantity of individual waves makes up these.

The expression for the velocity of the wave is as follows:

[tex]v=\sqrt{\frac{T_s}{\mu}}[/tex]

Here,

Ts is the tension and

μ is the mass per unit length.

The expression for the wave vector is as follows:

[tex]k=\frac{2 \pi}{\lambda}[/tex]

λ is the wavelength of the wave.

The expression for the angular frequency is as follows:

ω = v k

Here, v is the velocity of the wave.

The expression for the minimum amplitude is as follows:

[tex]A=\frac{g}{\omega^2}[/tex]

Here, g is the acceleration due to gravity.

putting the values of v and k in w

[tex]\begin{aligned}&\omega=v k \\&\omega=\left(\sqrt{\frac{T_s}{\mu}}\right)\left(\frac{2 \pi}{\lambda}\right)\end{aligned}[/tex]

[tex]\begin{aligned}A=& \frac{g}{\omega^2} \\A=& \frac{g}{\left(\left(\sqrt{\frac{T_s}{\mu}}\right)\left(\frac{2 \pi}{\lambda}\right)\right)^2} \\&=\frac{g}{\frac{T_s}{\mu}\left(\frac{2 \pi}{\lambda}\right)^2} \\&=\frac{g \mu}{T_s}\left(\frac{\lambda}{2 \pi}\right)^2\end{aligned}[/tex]

The minimum amplitude of the wave is equal to [tex]\frac{g \mu}{T_{\mathrm{s}}}\left(\frac{\lambda}{2 \pi}\right)^2[/tex]

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Option B The thickness of the central portion of a thin conveying lens can be determined very accurately by using a micrometer screw gauge.

One micrometer of thickness can be measured with a micron micrometre screw gauge. A Use of Micrometer Screw Gauge as like example Upon turning the screw of the micrometer screw gauge four times, a 2 mm space is covered.

A tool known as a micrometer is used to measure solid objects’ lengths, thicknesses, and other dimensions precisely and linearly.

The SI symbol m is also known as a micron, which is an SI-derived unit of length equaling 1106 meters, where 106 is the SI standard prefix for the prefix “micro-.” A micrometer is one-millionth of a meter.

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The area of the ball that weighs 95 N and exerting a pressure of 43 Pa is 1.51 m².

Area can be defined as the region bounded by a plane shape.

To calculate the area of the ball, we use the formula below.

Formula:

Where

Make A the subject of the equation

Froim the question,

Given:

Substitute these values  into equation 2

Hence, the area of the ball that weighs 95 N and exerting a pressure of 43 Pa is 1.51 m².

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Increasing human population have advanced the problem of the impact of humans on the environment as shown above.

We know that the environment has to do with our natural surroundings. The environment has to do  with that space that is around us from which we obtain the materials and energy that are necessary to support life.

We know that the greatest pressure that is placed on the environment and the resources that is in it comes from anthropogenic activities. These are the activities of the people that live within the environment. The extraction of resources for the provision of energy as well as construction pts great pressure on the environment

As we look at the image, we call to mind that the the explosions in the population of human beings have put more pressure on the environment and thus made it unable to support the human population.

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The time taken for the car to accelerate to the given speed is 10 seconds.

The acceleration of the car is the change in the velocity of the car with time.

a = Δv/Δt

where;

The initial velocity of the car = 0 mi/hr = 0 m/s

The final velocity of the car = 60 mi/hr = 26.82 m/s

The acceleration of the electric car = (26.82 m/s - 0 m/s) / 30 s = 0.89 m/s²

When the final velocity of the car = 80 mi/hr = 35.76 m/s, the time taken to reach the speed is calculated as follows;

v = u + at

where;

t = (v - u)/a

t = (35.76 - 26.82) / 0.89

t = 10 s

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Answer:

can be used to generate a magnetic effect ( magnetic field ) or magnetism can be generated by electricity , There is a relation between magnetism and electricity , where electric current has a magnetic effect , while  magnet generates an electric current .The electromagnet is used in factories to move ( lift ) the heavy iron blocks as it is used for making big-sized winch ( crane ) .The electromagnet is used in making many appliances ( devices ) as the electric bell , the electric mixer , the disc drive and the television .The electromagnet is used in factories to move ( lift ) the heavy iron blocks as it is used for making big-sized winch ( crane ) .The electromagnet is used in making many appliances ( devices ) as the electric bell , the electric mixer , the disc drive and the television .

Explanation:

According to the given statement the resultant displacement of the car is 5 m.

Displacement is the act of removing something from its customary location or position and replacing it with something else in that location or position.

A vector called displacement points from an object's initial position to its ultimate position. Meters are the accepted units of displacement. A vector called velocity depicts the direction and speed of motion. Meters per second are the accepted units for measuring velocity.

East and north are perpendicular to one another.

Displacement is the distance between a car's starting position and its ending position.

Displacement is √(3² + 4²) = √(25) = 5m

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The gravitational force between them will change by a factor 1/9.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

R2 = 3R1

By substituting the following parameters, we get

F2/F1 = G.m1.m2 / R2² / G.m1.m2 / R1²

F2/F1 = G.m1.m2 / (3R1)² / G.m1.m2 / R1²

F2/F1 = 1/9

Hence, the gravitational force between them will change by a factor 1/9.

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The magnitude of the net force that acts on the charge is 1.1 x 10^(-2).

What are magnetic and electric forces and how are they calculated?
The Lorentz Force Law, and specifically the magnetic force on a moving charge, is used to define the magnetic field B: F = q (v * B).
The magnetic field B and the charge q's velocity v are both perpendicular to the force.
F = q(v*BsinФ), where Ф is the angle less than 180° between the velocity and the magnetic field, gives the force's magnitude. This suggests that there is no magnetic force acting on a charge that is stationary or travelling perpendicular to the magnetic field.
The right hand rule specifies the force's direction. The aforementioned force relationship takes the shape of a vector product.
Even when they are not in contact, charged particles can nevertheless attract or repel one another. Electric fields are said to be created by charged particles. Additionally, the probes that find an electric field are charged particles. Charged particles experience force from an electric field. The strength of the electric field E that a charged particle at a place P creates is the amount of positive electric force that particle applies to another charged particle at that same position. The force acting on a positive charge is exerted in the direction of the electric field. F = q*E gives the real force acting on a particle with charge q. In the case of a negative charge, it points away from the electric field E.

Let F₁ denote the magnetic field and F₂ denote the electric field.
Since F₁ is perpendicular to F₂, we can use Pythagorian theorem to find the magnitude of the net force(F) by using F = √(F₁² + F₂²)
Therefore, F₁ = qvBsin(90°) = qvB = (1.8 * 3.1 * 1.2)/10³ = 6.70/10³ N
Again, F₂ = q*E = (1.8 * 4.6)/10³ = 8.28/10³ N
Thus, magnitude of the net force = F = √(F₁² + F₂²) = √[(6.70/10³)² + (8.28/10³)²] = 1.1 x 10^(-2) N (approx).

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In the given electric dipole, the charge q = 0.2 C and the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C is E = 138.37 10⁹ N/C.

What is electric dipole?

Any electromagnetic system has an electric dipole separating the positive and negative charges. A simple illustration of this system is a pair of opposite-sign, equal-sized electric charges that are separated from one another by a relatively short distance. (A permanent electric dipole is known as an electret.)

a) Let's calculate the field for each of the both charge at the point y = 10 cm, x=0 or in the dipole line, for that we calculate the field that creates each charge and add them vectorially  

For the Charge 1  

y₁ = (0.1 - 0.035) = 0.065 m  

(Electric field) E1 = k q / y₁²  

E1 = 8.99 10 9 q / 0.065²  

E1 = 2127.8 q  

For the Charge 2  

y₂ = (0.1 - (-0.035) = 0.135 m  

(Electric field) E2 = k (-q) / y₂²  

E2 = 8.99 109 q / 0.135²  

E2 = - 493.3 q  

In an electric dipole the value of the two charges is of equal magnitude, but otherwise, suppose the positive charge is the highest  

Et = E1 -E2  

Et = 2127.8q -493.3q  

330 = q (2127.8 -493.3)  

q = 330 / 1634.5  

q = 0.2 C

Now let the negative charge is higher  

Et = (-2127.8 +493.3) q  

330 = -1634.5 q  

q = -0.2 C  

b) calculate the field for the point x = 0.1 m y = 0 m  

This is a point perpendicular to the midpoint of the dipole, so that we can use the dipole equation  

E = k 2qa / √(x² + a²)³  

E = 8.99 10⁹ 2 0.2 0.07 / √(0.1² + 0.07²)³  

E = 0.2517 10⁹ / (0.001819)  

E = 138.37 10⁹ N/C

Therefore, the charge q is 0.2 C  and electric field E is 138.37 10⁹ N/C.

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Complete Question

An electric dipole is formed from two charges, ±q, spaced 0.700 cm apart. The dipole is at the origin, oriented along the y-axis. The electric field strength at the point (x,y)=(0cm,10cm) is 330 N/C . What is the charge q? Give your answer in nC what is the electric field strength at the point (x,y) = (10 cm, 0 cm) N/C = ?

tempreture

√12 is  degrees Celsius per meter.

What is tempreture?

tempreture is the degree of hotness or coldness of any kind of objects.

Sol-

The highest rate of tempreture increase is given as 6degrees as per the question

Imagine this high rate as a diagonal vector pointing in the northeast direction.

This vector has an x component (horizontal, or east) and a y component (vertical, or north).

The highest rate (maximum) is found as the magnitude of these two components.

It is the square root of (x^2)+(y^2).

6= √((x^2)+(y^2))

-> Take the square of both sides to remove the square root on the right side of the equation.

36 = (x^2)+(y^2)

-->The x^2 and y^2 values each must equal 8 in order to get:  12

(x^2) = 12

x = √12

(y^2) = 12

y = √12

If the object moves directly north, it is therefore moving only in the y-direction.

Thus, it is increasing tempreture at a rate of √12 degrees Celsius per meter.

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The force required if a pressure of 5Pa is exerted on an area of 15m² is 75N.

Pressure is a force applied to a surface. It is measured in Pascals denotes by Pa. It can also be defined as the physical force exerted on an object.

The force applied is perpendicular to the surface of objects per unit area. The formula for calculating pressure is as follows:

Pressure = Force ÷ Area

According to this question, the pressure of 5Pa is exerted on an area of 15m². The force required is as follows:

Force = 5Pa × 15m²

Force = 75N

Therefore, the force required is 75N

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The gravitational potential energy of the pot plant before it begins to fall is 392 J.

The total mechanical energy of the pot plant after it has fallen two meters is 78.39 J.

The speed with which the pot plant hits the ground is 19.8 m/s.

The gravitational potential energy of the pot plant before it begins to fall is calculated as follows;

P.E = mgh

where;

P.E = (2 kg) (9.8 m/s²) (20)

P.E = 392 J

The total mechanical energy of the pot plant after it has fallen two meters is calculated as follows.

M.E = K.E + P.E

where;

M.E = ¹/₂mv² + mgh

M.E = ¹/₂(2 kg)(6.26 m/s)²  +  (2 kg)(9.8 m/s²)(2 m)

M.E = 78.39 J

The speed with which the pot plant hits the ground is calculated by applying the principle of conservation of energy as follows;

K.E(bottom) = P.E(up)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 20)

v = 19.8 m/s

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just substitute whatever number is in the x column for x in the equation, then whatever you get from that equation is the y value

Answer:

melting point (a)

Explanation:

The launch velocity of the marble launcher is 34.65 m/s

Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).

The time for landing can be calculated by the second equation of motion formula:

h = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

Let u = 0

0.2 = 0×t + [tex]\frac{1}{2}[/tex] × 9.8 × [tex]t^{2}[/tex]

[tex]t^{2}[/tex] = [tex]\frac{0.2}{4.9}[/tex]

[tex]t^{2}[/tex] = 0.04

t = 0.2s

Now, the launch velocity of the marble launcher can be calculated by:

Speed = Distance / Time

Speed = [tex]\frac{0.73 + 6.3}{0.2}[/tex]

Speed = [tex]\frac{6.93}{0.2}[/tex]

Speed = 34.65 m/s

Therefore, the launch velocity of the marble launcher is 34.65 m/s

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The rock did not knock the spy satellite out of the sky. Detail below

To determine whether the rock will knock out the spy satellite, we shall determine the maximum height reached by the rock. This is obatined as follow:

v² = u² - 2gh (since the ball is going against gravity)

0² = 367² - (2 × 9.8 × h)

0 = 134689 - 19.6h

Collect like terms

0 - 134689 = -19.6h

-134689 = -19.6h

Divide both side by -19.6

h = -134689 / -19.6

h = 6871.89 m

DIvide by 1000 to express in km

h = 6871.89 / 1000

h = 6.87 Km

From the calculation made, we can see that the maximum height reached by the rock is 6.87 Km

Thus, we can conclude that the rock did not knock out the spy satellite becaue the satellite is 400 Km above the ground.

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Following are the differences between substance and mixture

A material is said to be pure if it just contains that substance and cannot be broken down into any other components. It is possible to separate a mixture into two or more pure substances. Pure substances have distinct physical and chemical properties, whereas mixtures have various qualities depending on the pure substance amounts and placement within each mixture.

Pure substances might be molecules made up of two or more different elements, or they can be elements composed solely of one type of atom. Depending on how thoroughly the components are combined, mixtures can either be homogeneous or heterogeneous.

Following are the differences between element and compound

Compounds are chemical unions of two or more elements and can potentially be pure substances, whereas elements are invariably pure things. Real-world substances, such as elements and compounds, are rarely pure because they are frequently tainted during manufacturing, storage, or by their environment. In theory, pure denotes the absence of any discernible imperfections. The majority of the time, it is achievable to purify substances to that standard, albeit it frequently necessitates a lot of work.

Following are the differences between heterogeneous and homogeneous mixtures.

Mixtures can be physically separated since they contain multiple types of atoms and molecules. When a combination is homogenous, the particles are so small that the entire mixture appears to be formed of the same substance. When a mixture is heterogeneous, the qualities of the mixture vary depending on which section of the mixture is being analyzed. Typical homogeneous mixtures include solutions. For instance, a salt-water solution is a homogenous combination since it is possible to separate the water and salt using distillation to create pure water and crystalline salt.

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The magnitude of the gravitational field strength is  2.76 * 10^-18 N/Kg.

The gravitational force is the force that acts on an object that is found in the earth's gravitational field. Let us recall that if an object is thrown up, the object must surely and definitely come down. This is because, there is a force of gravity that is acting on the object on the earth gravitational filed and that the direction of this force as it were is always towards the center of the earth.

In this case we are asked by the question that we ought to be able to obtain the gravitational field strength of the Hubble telescope as we have in the question and this we want to do.

Hence;

g = Gm/r^2

G = gravitational constant

m = mass of the object

r = distance covered

g = 6.67 * 10^-11 * 1.3 * 10^4/(5.6 * 10^5)^2

g = 2.76 * 10^-18 N/Kg

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