Answer:
Explanation:
KHAN ACADEMY
The free body diagram of the cheese block is attached with the answer.
What is free body diagram?A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.
Given is a block of cheese is pulled on by a string and slides to the right along a rough surface.
The free body diagram of the cheese block is given with the image attached. The force applied for the forward motion of the block is greater in magnitude than the frictional force. The weight of the block is balanced by the normal reaction force. The following mathematical relations can be written -
F - F(f) = ma
and
mg = N
m = N/g
So -
F - F(f) = (N/g)a
Therefore, the free body diagram of the cheese block is attached with the answer.
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A 0.1 kg tennis ball is brought from a speed of 15 m/s to a speed of 45 m/s when hit by a tennis racket. If this done over 0.05 seconds, what is the power generated by the tennis racket
A ball of clay is moving at a speed of 12 m/s collides and sticks to a stationary ball of clay. If each ball has a mass of 13 kg, what's the combined velocity of the two balls of clay after the collision
Answer:
p_{f} = 6 m / s
Explanation:
We can solve this exercise using conservation of momentum. For this we define a system formed by the two balls, so that the forces during the collision have been intense and the moment is preserved
Initial instant. Before the crash
p₀ = m v +0
Final moment. Right after the crash
[tex]p_{f}[/tex] = (m + m) v_{f}
how the moment is preserved
p₀ = p_{f}
m v = 2 m v_{f}
v_{f} = v / 2
we calculate
v_{f} = 12/2
p_{f} = 6 m / s
A golf ball starts with a speed of 2 m/s and slows at a constant rate of 0.5 m/s2, what is its velocity after 2 s?
Answer:
3m/s
Explanation:
Given parameters:
Initial speed = 2m/s
Acceleration = 0.5m/s²
Time = 2s
Unknown:
Final speed = ?
Solution:
To solve this problem, we apply the right motion equation;
V = U + at
V is the final speed
U is the initial speed
a is the acceleration
t is the time
V = 2 + (2 x 0.5)
V = 2 + 1
V = 3m/s
Is a bike being pedaled potential or kinetic?
Answer:
Since there is no motion yet, there is no kinetic energy. This means that the work needed to get up the hill is the potential energy at the top. Once you have coasted down the hill and are at the bottom, all of the energy is kinetic.
Explanation:
.
What were the two classifications of motion according to Aristotle?
Answer:
natural motion and violent motion
Explanation:
The mass of a material is a/an ___________.
Answer:
Extensive property
Explanation:
Answer:
Extensive property
Explanation:
Density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.
what are two ways to advance basketball down the Court
having a plan and listening to your coach
derivation of traingle law of vector adddition
Answer:
Triangle law of vector addition is one of the vector addition laws. Vector addition is defined as the geometrical sum of two or more vectors as they do not follow regular laws of algebra. The resultant vector is known as the composition of a vector
Explanation:
if it helps great if that still doesn't help thats the best i can do
A rock falls from a vertical cliff that is 4.0 m tall and experiences no significant air resistance as it falls. At what speed will it's gravitational potential energy (relative to the base of the cliff) be equal to its kinetic energy in m/s?
Answer:
v = 6.3 m/s
Explanation:
Since no significant air resistance exists, total mechanical energy must be kept constant at any time.At the top of the cliff, all the energy is gravitational potential energy, as follows:[tex]E_{i} = K_{i} + U_{i} = 0 + U_{i} (1)[/tex]
If we choose the ground level as our zero reference level for the gravitational potential energy, Ui is simply:Ui = m*g*h (1)At any height, the sum of the kinetic and the gravitational potential energy must be equal to (1).We know from the question, that at the point of interest, both types of energies must be equal each other, so we can write the following expression from (1):[tex]m*g* h = 2*\frac{1}{2}*m*v^{2} (2)[/tex]
Dividing both sides by m, simplifying, and solving for v, we get:[tex]v = \sqrt{g*h} =\sqrt{9.8m/s2*4.0m} = 6.26 m/s (3)[/tex]
v = 6.3 m/s (with two significative figures)Kinetic energy is the energy of _____.
Speed, Mass, Work, Motion
Answer: Motion
Explanation:
In a jigsaw classroom: A. students choose their own groups. B. students have to depend on one another to learn the required information. C. students learn the material on their own. D. students change groups every day
Answer:
B. students have to depend on one another to learn the required information.
Explanation:
It's kinda like puzzles having pieces and you use them to put together. So they can use this information to figure out what they're trying to solve with the information. -I hope this helped!
How might you determine experimentally the moment of inertia of an irregularly shaped body about a given axis?
Answer:
Using the parallel axis theorem
Explanation:
We note the angular speed and also the systems energy. Using these information we calculate the moment of inertia of irregular shaped body.
Io = 2E/w²
When we have moment of inertia of irregular shaped body, we can then use parallel axis theorem to solve for the moment of inertia of the body about the given axis.
I = Io + md²
About how much greater is the gravitational force exerted by the moon on the near side of the earth than on the far side? Choose one of the Following:
(a) About 2% greater
(b) About 7% greater
(c) About 11% greater
(d) About 15% greater
Solution :
Distance between the Earth and the moon, D = [tex]$3.84 \times 10^8 \ m$[/tex]
Radius of the earth, r = [tex]$6.37 \times 10^6 \ m$[/tex]
Gravitational force on the near side of the moon, [tex]$F_N = \frac{GM_m m}{(D-r)^2}$[/tex] ......(1)
Gravitational force on the far side of the moon, [tex]$F_F = \frac{GM_m m}{(D+r)^2}$[/tex] ..............(2)
where, [tex]$M_m$[/tex] = mass of moon
m = mass of the near side and far side respectively (both are taken as equal)
Therefore,
[tex]$\frac{F_N-F_F}{F_N}\times 100 = \frac{\frac{GM_m m}{D-r}^2-\frac{GM_m m}{D+r}^2}{\frac{GM_m m}{D-r}^2} \times 100 $[/tex]
[tex]$=1 - \frac{(D-r)^2}{(D+r)^2} \times 100$[/tex]
[tex]$=1- \left(\frac{1-\frac{r}{D}}{1+\frac{r}{D}}\right)^2 \times 100$[/tex]
[tex]$= 1- \left(\frac{0.98}{1.02}\right)^2 \times 100$[/tex]
= 7%
Hence, correct option is (b) About 7% greater
As tall as a tree, as small as a bug, As fast as an eagle, as slow as a slug. Many times in front or behind but never on top, always aligned. What am i
A white dwarf star has a density of about 1.0 x 10^9 kg/m3. If the earth were to suddenly become as dense as a white dwarf star, what would its radius be?
Answer:
R = 98304.75 m = 98.3 km
Explanation:
The density of an object is given as the ratio between the mass of that object and the volume occupied by that object.
Density = Mass/Volume
Now, it is given that the density of Earth has become:
Density = 1 x 10⁹ kg/m³
Mass = Mass of Earth (Constant) = 5.97 x 10²⁴ kg
Volume = 4/3πR³ (Volume of Sphere)
R = Radius of Earth = ?
Therefore,
1 x 10⁹ kg/m³ = (5.97 x 10²⁴ kg)/[4/3πR³]
4/3πR³ = (5.97 x 10²⁴ kg)/(1 x 10⁹ kg/m³)
R³ = (3/4)(5.97 x 10¹⁵ m³)/π
R = ∛[0.95 x 10¹⁵ m³]
R = 98304.75 m = 98.3 km
A pan of water is sitting on an electie over the stove is then turned on to high What will happen to the movement of the particles in the pan?
The particles that make up the pan will move closer together
The parties that make up the pan will not be affected
The particles that make up the pan will speed up
The partides that make up the pan will slow down
Answer:
The particles that make up the pan will speed up
Explanation:
PLZZ ANSWER THE QUESTION
Answer:
D. ? Its the only one talking about color
The density of ice is 917 kg/m^3, and the density of sea water is 1025 kg/m^3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 6.78 m^3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?
Answer:
w_bear = 7175.95 N , m = 732.24 kg
Explanation:
Let's analyze the situation a bit, the ice block is in equilibrium with the thrust given by Archimedes' law that is directed towards the bottom, the weight of the ice and the weight of the bear.
B -W_ice - w_bear = 0
w_bear = B - W_ice
The thrust is given by
B = ρ g V
B = 1025 9.8 6.78
B = 68 105.1 N
Note that we use the total volume of the block since the problem indicates that it is submerged.
The weight of the ice is
W_ice = m g
the density is
ρ_ice = m_ice / V
m_ice = rho_ice V
we substitute
W_ice = ρ_ice g V
W_ice = 917 9.8 6.78
W_ice = 60929.15 N
we substitute in the first equation
w_bear = 68105.1 - 60929.15
w_bear = 7175.95 N
the mass of this bear is
w_bear = m g
m = w_bear / g
m = 7175.95 / 9.8
m = 732.24 kg
Determine the magnitude of the force between two 42 m-long parallel wires separated by 0.03 m, both carrying 6.3 A in the same direction.
Answer:
The magnitude of the force between the two parallel wires is 0.0111 N.
Explanation:
Given;
length of the two parallel wires, L = 42 m
distance between the two wires, r = 0.03 m
current in both wires, I₁, I₂ = 6.3 A
Therefore, the magnitude of the repulsive force between the two parallel wires is given by;
[tex]F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F = 0.0111 \ N[/tex]
Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.
I need guidance pls
Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of the dive, the speed of the airplane is 150 m/s. What is the apparent weight of the 70-kg pilot at that point?
Answer:
3311N
Explanation:
r = radius = 600m
V = speed = 150m/s
Mass = weight = 70kg
The weight of pilot when calculated due to circular motion
W = tv
Fv = mv²/r
Fv = 70x150²/600
Fv = 79x22500/600
= 15750000/600
= 2625N
Real Weight of the pilot = m x g
= 70 x 9.8
= 686N
The apparent Weight is calculated by
Mv²/r + mg
= 2625N + 686N
= 3311 N
Therefore the apparent Weight is 3311N
How high will a cannonball reach if fired straight up out of a cannon at an initial upward velocity of
120m/s?
Answer:
720 m
Explanation:
Taking the upward direction as positive
We are given:
Initial vertical velocity of the cannonball = 120 m/s
Vertical acceleration of the cannonball = -10 m/s²
Final velocity of the Cannonball = 0 m/s [at the maximum height, the velocity of the ball will be 0 m/s for a moment]
Maximum height of the ball:
v² - u² = 2as [Third equation of motion]
replacing the variables (s is the maximum height)
(0)² - (120)² = 2(-10)(s)
-14400 = -20s
s = -14400 / -20 [Dividing both sides by -20]
s = 720 m
Hence, the maximum height of the Cannonball fired vertically at a velocity of 120 m/s is 720 m
The timeline below shows some major discoveries in biology.
Which of the following theories did these discoveries lead to?
A.
the theory of evolution
B.
the cell theory
C.
the germ theory
D.
the atomic theory
Each piece has 15 of 4 meters of fabric.
Answer:
The cell theory
Explanation:
Answer:
The cell theory
Explanation:
Which best explains why an MRI is useful for diagnosing cancer but ineffective in treating it?
The frequency of the radio waves used is so high that the waves cannot be used to target specific cells.
The wavelength of the radio waves used is so short that the waves cannot be used to target specific cells.
The amount of energy carried by radio waves is enough to provide images but not enough to kill cells.
The amount of energy carried by radio waves is so high that it provides images but can also damage cells.
Answer:The amount of energy carried by radio waves is enough to provide images but not enough to kill cells.
Explanation:
The reason of MRI should be useful is that the energy amount that should be carried out via the radio waves.
What is Magnetic resonance imaging (MRI) ?It refers to the medical imaging technique that should be applied in the radiology to create the pictures with respect to the anatomy and the process of physiological with related to the body.
Also, it is applied for strong the magnetic field, gradient related to the magnetic field, also the radios waves for produce image in the body organs.
Learn more about wave here: https://brainly.com/question/12734041
Select the correct responses to the questions from the drop-down menus. Which type of wave vibrates both side to side and up and down? P waveS wavesurface wave Which type of wave is the first to arrive during an earthquake? P waveS wavesurface wave Which type of wave may make the ground roll? P waveS wavesurface wave
The S wave vibrates both side to side and up and down whereas P wave is the first to arrive during an earthquake
Seismic waves during earthquake:During the eathquake, two types of seismic waves are generated , P wave and S wave.
The S waves produces vibrations to the ground in a shearing force perpendicular to the direction of propagation of the wave, moving the ground up and down or from side to side. S waves are called secondary waves because arrive after P waves.
The P waves is analogous to longitudinal vibrations, producing vibrations to the ground to compress and expand in the direction of propagation f the wave. They are called primary waves because they are the first type of wave to arrive at seismic recording stations.
Learn more about seismic waves:
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Answer:
i got it right so chillllll :)
Explanation:
Select the correct responses to the questions from the drop-down menus.
Which type of wave vibrates both side to side and up and down?
✔ S wave
Which type of wave is the first to arrive during an earthquake?
✔ P wave
Which type of wave may make the ground roll?
✔ surface wave
Little Billie has a mass of 25 kg. The acceleration of gravity on the moon is one-sixth of the value on Earth. What is Little Billie's weight on the moon? _____________ What is little Billie's mass on the moon? _____________
Answer:
Mass is constant everywhere,
But weight is different,
If earth g = 10 then moon's is 1.6666667
Now billie's weight in moon is 41.6667
PLZ HELP I BEG YOU :(
I DON'T KNOW WHAT THE ANSWERS ARE
Answer:
9. qulitative(spell check)
10. false
11. true
Explanation:
Which two options describe physical properties of matter?
A: weather a substance forms from a patina
B: whether a substance is acidic or basic
C: The color of the light that is reflected of a substance’s surface
D: The amount of mass per unit volume
F: how easily a substance reacts with other substances
Answer:
C: The color of the light that is reflected off a substance's surface
D: The amount of mass per unit volume
Explanation:
just took this!
Options C and D are correct.
C: The color of the light that is reflected on a substance’s surface
D: The amount of mass per unit volume.
What is the matter?Physical and chemical features can be used to classify matter. The matter is defined as something that occupies space and has mass. Solid, liquid, and gaseous are the three states of matter.
C: The color of the light that is reflected on a substance’s surface
If the light is completely absorbed, the thing appears black; if the light is completely reflected, the object appears white. The wavelengths of light that a material absorbs determine its color.
Hence it is an important property of matter.
D: The amount of mass per unit volume.
Density is defined as the mass per unit volume.it is denoted by ρ. It is the most important parameter to define the property of a matter.
Density shows the compactness of matter. it is calculated per unit volume. The density is used to find the space for the material that has to be filled.
Due to the above reasons options, C and D are correct.
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At time t = 0.00 s, a car is traveling along a straight line at a speed of 10 m/s with constant acceleration. The car travels 46.0 m during the time interval between t = 2.00 s and t = 4.00 s. What is the acceleration of the car?At time t = 0.00 s, a car is traveling along a straight line at a speed of 10 m/s with constant acceleration. The car travels 46.0 m during the time interval between t = 2.00 s and t = 4.00 s. What is the acceleration of the car?
Answer:
0.00
Explanation:
A basketball is shot with an initial velocity of 16 m/s at an angle of 55° to the
horizontal. What is the approximate horizontal distance that the ball travels in
1.5 s?
Answer:
approximately 13.77 m
Explanation:
We use the kinematic equations for the horizontal motion which is a uniform non-accelerated motion, and with initial velocity equal to 16 * cos(55). This is described by the equation:
[tex]x=16 * cos(55^o) * t = 9.177 * t[/tex]
then at t = 1.5 seconds, the covered distance becomes:
x = 9.177 * (1.5) = 13.7655 m
Round the answer to the number of decimals that the problem asks.