Answer:
r = 12.5p(32 -p)$16 per ticket$3200 maximum revenueStep-by-step explanation:
The number of tickets sold (q) at some price p is apparently ...
q = 150 + 25(20 -p)/2 = 150 +250 -12.5p
q = 12.5(32 -p)
The revenue is the product of the price and the number of tickets sold:
r = pq
r = 12.5p(32 -p) . . . . revenue equation
__
The maximum of revenue will be on the line of symmetry of this quadratic function, which is halfway between the zeros at p=0 and p=32. Revenue will be maximized when ...
p = (0 +32)/2 = 16
The theater should charge $16 per ticket.
__
Maximum revenue will be found by using the above revenue function with p=16.
r = 12.5(16)(32 -16) = $3200 . . . . maximum revenue
_____
Additional comment
The number of tickets sold at $16 will be ...
q = 12.5(32 -16) = 200
It might also be noted that if there are variable costs involved, maximum revenue may not correspond to maximum profit.
Use the given equation to find the missing coordinates of the points and then find the slope of the line for each equation.
y=-2/3x+1/6 ; A(...,6) ; B(9,...)
Answer:
6
Step-by-step explanation:
the least common denominator of 3 and 6 is 6
THATS how I got six
Hopped this helped <3
The slope of the line will be -2/3. And the coordinates will be A(-35/4, 6) and B(9, -34/6).
What is a linear equation?A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
y = -2/3 x + 1/6
The slope of the line is - 2/3.
At y = 6, the value of 'x' is calculated as,
6 = -2/3 x + 1/6
35/6 = -2/3 x
x = -35 / 4
At x = 9, the value of 'y' is calculated as,
y = -2/3 (9) + 1/6
y = -6 + 1/6
y = -35/6
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Absolute minimum and maximum values of [tex]f(x)=2cos (x) +sin (2x)[/tex] on the interval [tex][0,pi/2][/tex]
Step-by-step explanation:
f'(x)=-2sin(x)+2cos(2x)=0
as cos(2x)=2sin(x)cos(x),
-2sin(x)+4cos(x)sin(x)=0
sin(x)-2cos(x)sin(x)=0
(sin(x))(1-2cos(x))=0
-> x = 0, pi/3
testing these values along with the end points of the interval,
f(0)=2
f(pi/3)=1+(0.5sqrt(3))
f(pi/2)=0
so the min is 0 and the max is 2.
A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/4 What is the y-intercept of the function?
Answer:
(0, -3)
Step-by-step explanation:
It will help to graph it out.
Also is the phase shift negative or is it just to the right? Im assuming its just right pi over 4
Answer: 0
Step-by-step explanation:
2pi/4 does not equal pi, it equals half of pi. 2pi/2 equals pi. Regardless here's my answer, since it also checks out for a similar function that was confirmed to have a phase shift of pi/2:
The formula for this is asin(bx - c) + d, where
|a| = amplitude
period = 2pi/b
and phase shift = c/b
The amplitude is 3
3sin(bx - c) + d
Phase shift is c/b, in this case, pi/4
3sin(4x - pi) + d
d is vertical shift
(phase shift, c, is also known as horizontal shift)
We don't see any d here so graph on Desmos as follows....
Graph 3sin(4x - pi)
Looks like the y-intercept is 0
Check by substituting 0 for x:
3sin(4x - pi)
3sin(4(0) - pi)
3sin(-pi) = 0
The answer is 0, checks out.
Christine drives her car 144 miles and has an average of a certain speed. If the average speed has been 5 mph more, she could have traveled 168 miles in the same length of time. What was her average speed?
Let's make a system of equations:
144/x=y
168/(x+5)=y
So,
144/x=168/(x+5)
Solving using cross multiplication,
x=30
So, her average speed for driving 144 miles was 30 miles per hour.
-Hunter
Suppose a normal distribution has a mean of 62 and a standard deviation of 4. What is the probability that a data value is between 56 and 64? Round your answer to the nearest tenth of a percent. OA. 64.5% B. 63.5% O c. 62.5% O D. 61.5%
Answer:Given a normal distribution with μ = 62 and σ = 4., calculate the 68-95-99.7 rule, or three-sigma rule, or empirical rule ranges
Calculate Range 1:
Range 1, or the 68% range, states that 68% of the normal distribution values lie within 1 standard deviation of the mean
68% of values are within μ ± σ
μ ± σ = 62 ± 4.
62 - 4. <= 68% of values <= 62 + 4.
58 <= 68% of values <= 66
Calculate Range 2:
Range 2, or the 95% range, states that 95% of the normal distribution values lie within 2 standard deviations of the mean
95% of values are within μ ± 2σ
μ ± 2σ = 62 ± 2(4.)
62 - 2 x 4. <= 95% of values <= 62 + 2 x 4.
62 - 8 <= 95% of values <= 62 + 8
54 <= 95% of values <= 70
Calculate Range 3:
Range 3, or the 99.7% range, states that 99.7% (virtually ALL) of the normal distribution values lie within 3 standard deviations of the mean
99.7% of values are within μ ± 3σ
μ ± 3σ = 62 ± 3(4.)
62 - 3 x 4. <= 99.7% of values <= 62 + 3 x 4.
62 - 12 <= 99.7% of values <= 62 + 12
50 <= 99.7% of values <= 74
Step-by-step explanation:
The probability that a data value is between 56 and 64 is,
= 64.7%
What is mean by Probability?The term probability refers to the likelihood of an event occurring. Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one.
Given that :
Mean (m) = 62
Standard deviation (s) = 4
Hence, Probability that a data value is between 56 and 64
P(56 < x < 64)
Using the relation :
(x - m) / s
P(x < 56) : (56 - 62) / 4
= - 1.5
P(Z < - 1.5) = 0.10565
( Z probability calculator)
P(x < 64) :
(64 - 62) / 4 = 0.75
P(Z < 0.75) = 0.77337 (Z probability calculator)
Hence, We get;
P(Z < 0.75) - P(Z < - 1.25)
0.77337 - 0.10565
= 0.64772
= 64.7%
Thus, the probability that a data value is between 56 and 64 is,
= 64.7%
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Help! I can't figure this out!
Answer:
57/6 60/6 22/6 26/6
Step-by-step explanation:
So the answers for the blanks are 57, 60, 22, 26.
Let me know if I am incorrect.
Assume your favorite soccer team has 5 games left to finish the season. The outcome of each game can be win, lose or tie. What is the number of possible outcomes
The possible outcomes are the sample space of the game
The number of possible outcomes in the game is 3
How to determine the possible outcomesThe number of games is given as:
n = 5 i.e. 5 games to finish the season
In each game, the soccer team can either win, lose or tie.
So, we have the outcome of each game to be:
Outcome = {Win, Lose, Tie}
Count the outcomes
Count = 3
Hence, the number of possible outcomes in the game is 3
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Diane is saving $2,500 for a new horse. She has saved 3/5 of the amount. How much
more does she need to save to purchase the horse?
Answer:
58
Step-by-step explanation:
the way of the parts of the question
Four-sevenths of the people in a
room are seated in
seven-eighths of the chairs. The
rest of the people are standing.
If there are 8 empty chairs.
How many people are in the room
The number of people in the room is 91.
What is the total number of chairs in the room?The first step is to determine the total number of chairs in the room. In order to determine this value, divide the fraction of the unoccupied chairs by the number of empty chairs.
8 ÷ 1/8
8 x 8 = 64
What is the number of people in the room?Number of people sitting on the chairs = 64 - 8 = 52
Number of people in the room = 52 ÷ 4/7
= 52 x 7/4 = 91
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? x 1/100 = 752 what is the missing number?
Answer:
75200 x 1/100= 752
hope this helps!
Write 22,22 as a fraccion
Answer:
1/1
Step-by-step explanation:
22/22 =1
The area of a trapezoid is 48 square centimeters. The height is 6 centimeters and one base 3 times the length of the other base. What are the lengths of the bases?
The lengths of the bases are: 4cm and 12cm.
Area of a TrapezoidSince the area of a trapezoid is given by the formula;
A = 1/2 (a + b) h.Where a and b are the lengths of the bases and h is the height of the trapezoid.
Hence, in this case scenario; it follows that;
48 = 1/2(x + 3x) 648 = 12xx = 48/12a = x = 4cm
b = 3x = 12cm.
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Help me please please please
Answer:
37.2 cm
Step-by-step explanation:
Perimeter of a rectangle = 2*(length + breadth)
length = 12 cmwidth = 6.6 cm==> perimeter = 2*(12 + 6.6)
= 2*(18.6)
= 37.2 cm
Answer:
[tex] \red{37.2 \: cm}[/tex]
Step-by-step explanation:
The formula to find the perimeter of a rectangle is:
[tex] \text{perimeter} = 2(l + w)[/tex]
Given that,
length = 12cm
width = 6.6cm
Let us find the perimeter of the rectangle now.
[tex] \text{perimeter} = 2(l + w) \\ \text{perimeter} = 2(12 + 6.6) \\ \text{perimeter} = 2 \times 18.6 \\ \text{perimeter} = 37.2 \: cm[/tex]
lcm of 3/11 and 1/4 plis is for something vry importan
Answer:
LCM of 3, 5, and 11 is 165.
Step-by-step explanation:
is 17.8 = 18.8 reasonable explain.
Answer:
No.
Step-by-step explanation:
For there to be a equal sign, it will mean that both sides will have to have the same exact amount. If it is expressions on both sides, then the expressions must, when combined, equal to each other.
In this case, there is not given operation that will allow for both numbers to equal each other, and 17.8 is 10 less than 18.8, therefore it is not reasonable.
17.8 ≠ 18.8
Question
Suppose the length and the width of the sandbox are doubled.
the width is 6ft and the length is 10ft
a. Find the percent of change in the perimeter.
The percent of change in the perimeter is a
( %) increase.
b. Find the percent of change in the area.
The percent of change in the area is a
( %) increase.
Answer:
Rectangle is the closed shaped polygon with 4 sides. Opposite sides of the rectangle are equal. when the length and the width of the sandbox are doubled the percent of change in the perimeter is 100 percent and the percent of change in the area is 300 percent.Given-The length of the sandbox is 10.The width of the sandbox is 6.a) The percent of change in the perimeter.Perimeter of the rectangleThe perimeter of the rectangle is the twice of the sum of its side.The perimeter P of the sandbox is,When the length and the width of the sandbox are doubled the perimeter of the box is,Percentage change in the perimeter,b) The percent of change in the area.Area of the rectangleThe area of the rectangle is the product of its side.The area A of the sandbox is,When the length and the width of the sandbox are doubled the area of the box is,Percentage change in the area,Thus when the length and the width of the sandbox are doubled the percent of change in the perimeter is 100 percent and the percent of change in the area is 300 percent.
find the greatest common factor of 12w^4 and 5y^3
Answer:
1.
Step-by-step explanation:
The greatest common factor is the largest positive integer that divides evenly into all numbers with zero remainder.
So, let's factor each number:
12w⁴: To factor it, factor 12 and w⁴ separately.
12: 1, 2, 3, 4, 12
w⁴: 1, w, w², w³, w⁴
So, the factor of 12w⁴ is all the combinations of the factor of 12 and w⁴.
1, 2, 3, 4, 12, 1w, 2w, 3w, 4w, 12w, 1w², 2w², ..., 12w⁴
5y³: To factor it, factor 5 and y³ separately.
5: 1, 5
y³: 1, y, y², y³
So, the factors of 5y³ are all the combinations of the factor of 5 and y³.
1, 5, 1y, 5y, 1y², ... , 5y³
The only factor that 12w⁴ and 5y³ have in common is 1.
Answer: 1.
Find the probability of each event. Write your answer as a fraction and as a percent. Drawing
a diamond from a standard deck of cards.
b. Rolling a number less than five on a standard number cube.
C. a Drawing a blue marble from a bag of 18 marbles, three of which are blue.
Answer: See below
Step-by-step explanation:
Event 1:
There are 13 diamond cards in total
A standard deck of cards has a total of 52 cards
Probability = 13/52
P = 1/4 or 25%
Event 2:
There are a total of 6 sides on a standard dice
Probability = 4/6
P = 2/3 or 66.67%
Event 3:
There are 3 blue marbles in a bag of 18 marbles
Probability = 3/18
P = 1/6 or 16.67%
Answer: a) 1/4 b) 2/3 c) 1/6
Step-by-step explanation:
All of these are probability problems. They have this trick.
First, the trick. The chance of taking an x amount of blue marbles out of a bag of y marbles is x/y. Now using this…
a) there are 13 diamonds and 52 total. 13 is x, and 52 is y. It is 13/52 = 1/4
b) There are 4 numbers you need to get, and 6 in total. Therefore; there is a 4/6 chance which simplifies to 2/3.
c) There are 3 marbles you need, and 18 of them in total. It is 3/18 which is 1/6.
I once struggled on these problems, for they can be difficult.
Find all the zeros of the polynomial p(x) = x^3 + x^2 + 36x + 36
The zeros are______
Use the zeros to write p(x) in factored form. p(x)=_________
Write down three inequalities which together describe the shaded region. Pls help.
Answer:
y ≤ 6
y ≥ -x + 2
y > x + 4
Step-by-step explanation:
The solid line means ≤ or ≥
The dashed line means < or >
y ≤ 6
y ≥ -x + 2
y > x + 4
The intensity of radiation at a distance x meters from a source is modeled by the function given by R(x)=kx2, where kk is a positive constant. Which of the following gives the average intensity of radiation between 10 meters and 50 meters from the source?
This would be the average value of R(x) between 10 m and 50 m :
[tex]\displaystyle \frac1{50\,\mathrm m - 10\,\mathrm m} \int_{10\,\rm m}^{50\,\rm m} kx^2 \, dx[/tex]
The average intensity of radiation between 10 meters and 50 meters from the source is 1033.33 k.
What is integration?It is the reverse of differentiation.
The intensity of radiation at a distance x meters from a source is modeled by the function given by
R(x)=kx²
where k is a positive constant.
The average intensity of radiation between 10 meters and 50 meters from the source will be
[tex]\rm Average \ intensity = \dfrac{1}{50 - 10} \int_{10}^{50} \ kx^2 \ dx\\\\\\Average \ intensity = \dfrac{k}{50 - 10} [ \dfrac{x^3}{3} ]_{10}^{50}\\\\\\Average \ intensity = \dfrac{k}{40} [ \dfrac{50^3}{3} - \dfrac{10^3}{3} ]\\\\\\Average \ intensity =1033.33k[/tex]
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Find the inverse of the matrix [6, 7] [-6, 7] if it exists
For any square matrix A, if it is invertible, its inverse is given by
[tex]A^{-1} = \dfrac1{\det(A)} \mathrm{adj}(A)[/tex]
where adj(A) is the so-called adjugate matrix, which is the transpose of the cofactor matrix of A. If you don't know what that is, that's not terribly important. What is important is that the inverse does not exist if the determinant, det(A), is zero.
We have
[tex]A=\begin{bmatrix}6&7\\-6&7\end{bmatrix} \implies \det(A) = 6\times7-7\times(-6)=84 \neq 0[/tex]
so the inverse does indeed exist. (And we eliminate D as an answer.)
From the given choices, it's quite clear that C must the correct answer, since we know det(A) = 84, and we can easily confirm that
[tex]\begin{bmatrix}7&-7\\6&6\end{bmatrix} \begin{bmatrix}6&7\\-6&7\end{bmatrix} = \begin{bmatrix}84&0\\0&84\end{bmatrix}[/tex]
so that multiplying by 1/84 recovers the identity matrix.
We are given with a square matrix and we are asked to find it's inverse if it exists . So , let's recall some important points first :-
Inverse can only be found of square matrices.If [tex]{\bf A}[/tex] is a square matrix than , it's inverse is denoted by [tex]{\bf A^{-1}}[/tex] , and is given by [tex]{\bf{A^{-1}=\dfrac{1}{adj(A)}det(A)}}[/tex] , where adj(A) is the adjoint of the matrix A and det(A) is the determinant of the matrix AInverse of a matrix exist if A is non-singular Non-Singular means that det(A) ≠ 0 Adjoint of a matrix is the matrix of transpose of cofactors Transpose of a matrix is founded by exchanging it's rows by columns and columns by rows and is denoted by [tex]{\bf{A^{T}}}[/tex]Now , in this question let's assume that [tex]{\sf A=\begin{bmatrix}6 & 7 \\ -6 & 7\end{bmatrix}}[/tex]
Now , Calculating det(A) :-
[tex]{:\implies \quad \sf det(A)=\begin{vmatrix}6 & 7 \\ -6 & 7 \end{vmatrix}}[/tex]
[tex]{:\implies \quad \sf det(A)=42-(-42)}[/tex]
[tex]{:\implies \quad \sf det(A)=42+42}[/tex]
[tex]{:\implies \quad \sf det(A)=84}[/tex]
As , det(A) ≠ 0 . So , [tex]{\bf A^{-1}}[/tex] exists . Now , we need to find the matrix of cofactors first , but let's find cofactors first , so here ;
[tex]{\blacktriangleright \sf C_{11}=7,\: C_{12}=6,\: C_{21}=-7,\: C_{22}=6}[/tex]
Now , let's assume that matrix of cofactors is C , so putting the cofactors as elements of the matrix , C will be ;
[tex]{:\implies \quad \sf C=\begin{bmatrix}7 & 6 \\ -7 & 6\end{bmatrix}}[/tex]
Now , adj(A) will be found by interchanging it's rows by columns and vice versa.
[tex]{:\implies \quad \sf adj(A)=\begin{bmatrix}7 & -7 \\ 6 & 6\end{bmatrix}}[/tex]
Now as [tex]{\sf A^{-1}}[/tex] is given by [tex]{\bf{A^{-1}=\dfrac{1}{adj(A)}det(A)}}[/tex]
[tex]{:\implies \quad \bf \therefore \quad \underline{\underline{A^{-1}=\dfrac{1}{84}\begin{bmatrix}7 & -7 \\ 6 & 6\end{bmatrix}}}}[/tex]
Hence , Option C) [tex]{\sf \dfrac{1}{84}\begin{bmatrix}7 & -7 \\ 6 & 6\end{bmatrix}}[/tex] is correct :D
What is 11/12 - 2/3
Subtracting Proper Fractions
Answer:
0.25
Step-by-step explanation:
11/12 = 0.917
2/3 = 0.667
0.917 - 0.667 = 0.25
A book sold 33,100 copies in its first month of release. Suppose this represents 8.7% of the number of coples sold to date. How many coples have been sold to
date?
Round your answer to the nearest whole number,
Answer:
380,460
Step-by-step explanation:
x copies have been sold to date
so 8.7% * x = 33,100
x = 33,100/0.087 = 380,460
help me i'll give brainlist
Answer:
[tex]x=\frac{1}{2}[/tex]
Step-by-step explanation:
equation of a circle: [tex](x - h)^2+(y-k)^2=r^2[/tex]
where (h, k) = center and r = radius
From inspection, we can see that the center of the circle = (0, 0)
and the radius = 1
[tex]\implies (x - 0)^2+(y-0)^2=1^2[/tex]
[tex]\implies x^2+y^2=1[/tex]
Substitute [tex]y=\frac{\sqrt{3}}{2}[/tex] into [tex]x^2+y^2=1[/tex] and solve for [tex]x[/tex]:
[tex]\implies x^2+(\frac{\sqrt{3}}{2})^2=1[/tex]
[tex]\implies x^2+\frac{3}{4}=1[/tex]
[tex]\implies x^2=\frac{1}{4}[/tex]
[tex]\implies x=\pm \sqrt{\frac{1}{4}}[/tex]
[tex]\implies x=\pm\frac{1}{2}[/tex]
As point P is in quadrant 1, [tex]x[/tex] is positive, so [tex]x=\frac{1}{2}[/tex]
What is 5x + 80 Will?
HELPP MEEE WITH MY HOMEWORK PLEASEEEE
Answer:
Letter a is 6:38 and letter b is 2:17
Hope this helps!
Write down Mrs chaukes balance on the 25 march 2021 in words
Answer:
March 25, 2021, Mrs. Chaues balance is _____
Step-by-step explanation:
Mrs. Chauke balance in words is Eighteen thousand five hundred eighty-two and seven hundredths
From the complete question, we have the following highlights:
She bought an airtime worth R110.0 on 23rd of MarchShe bought another airtime worth R55.0 on 24th of MarchThe balance on 25 March 2021 is R18,582,07When 18,582,07 is expressed In words, it is:
Eighteen thousand five hundred eighty-two and seven hundredths
Hence, Mrs. Chauke balance on the 25 March 2021 in words is Eighteen thousand five hundred eighty-two and seven hundredths
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To ethically advertise a school lottery scheme to try to raise money for the athletic department, the organizer of the lottery needs to explicitly specify the probability of each of the prize in the lottery.
a. True
b. False
f(x) = 4x2 + 7x – 3
g(x) = 6x3 – 7x – 5
-
Find (f + g)(2).
Answer:
[tex]6x-7x^{2}[/tex]
Step-by-step explanation:
o= 4x [tex]x[/tex] 2 +7x -3
0= 8x +7x -3
0= 15x -3
- 15x =-3
x= [tex]\frac{1}{5}[/tex]
x= 0.2 , x =[tex]x^{-1}[/tex]
[tex](f+g)(2)[/tex]
[tex]18 - 7x -5-7 \\6-7x\\[/tex]