a group of students is collecting books to add to their library. the table shows the number of books in the library after 1, 3, and 5 days. if the relationship between days and books continues to be linear, which ordered pairs could appear in the table? check all that apply.

Answer:

1233cm^2

Step-by-step explanation:

a of triangle = 1/2 bh

1/2 x 12 x 9 = 54

108 x 2 = 108

a of regtangle = l x w

25 x 15 = 375

375 x 3 = 1125

total surface area = 1125 + 108 = 1233cm^2

Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided.  The expression that was provided is [tex]15c^2 - 5c[/tex].

The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common.  We can see that both [tex]15c^2[/tex] and [tex]-5c[/tex] have the number 5 and the variable c associated with them so we can factor out those two.

Factor out 5c

Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of [tex]5c(3c - 1)[/tex].

Answer:

5c(3c - 1)

Step-by-step explanation:

Take out the 5c to factor out completely

Answer:

4

Step-by-step explanation:

Given :

f(x) = x² - 6x + 8

=============================================================

Solving :

Splitting the middle term :

⇒ f(x) = x² - 6x + 8

⇒ f(x) = x² - 2x - 4x + 8

⇒ f(x) = x (x - 2) - 4 (x - 2)

⇒ f(x) = (x - 4)(x - 2)

============================================================

Solutions :

⇒ x - 4 = 0 ⇒ x = 4

⇒ x - 2 = 0 ⇒ x = 2

The length of DE in the triangles is 5.9

The given parameters are:

DB = 6.3

AC = 9.4

AD : DB = 3 : 5

Substitute DB = 6.3 in AD : DB = 3 : 5

AD : 6.3 = 3 : 5

Express as fraction

AD / 6.3 = 3 / 5

Multiply both sides by 6.3

AD = 3.78

The length DE is then calculated using the following ratio:

BD : DE = BA : AC

Where:

BA = BD + AD

This gives

BD : DE = BD + AD : AC

Substitute known values

6.3 : DE = 6.3 + 3.78 : 9.4

Simplify

6.3 : DE = 10.08 : 9.4

Express as fraction

DE/6.3 = 9.4/10.08

Multiply both sides by 6.3

DE = 5.9

Hence, the length of DE is 5.9

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Simple interest is a method of calculating interest on an amount for n period of time with a rate of interest of r. The principal at the end of 3 years is $248.

Simple interest is a method of calculating interest on an amount for n period of time with a rate of interest of r. It is calculated with the help of the formula,

SI = (P × R × T)/100

where SI is the simple interest, P is the principal amount, R is the rate of interest, and T is the time period.

The principal at the end of 3 years is,

Principal after 3 years = P + (P × R × T)

= $200 + ($200 × 0.08 × 3)

= $200 + $48

= $248

Hence, the principal at the end of 3 years is $248.

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Answer:

D) None of the choices are correct.

Explanation:

Given triangles AHL and NKG

Sides which are congruent:

So, AHL ≅ NKG. There are no such options.

The price per share of the stock of the high-tech firm that was purchased by Jake is  $50.

Percentage is a measure of frequency that calculates the fraction of an amount out of hundred.

What is the price per share of the stock purchased by Jake = current value / ( 1 + percentage increase)

61 / 1.22 = $50

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Answer:

3/2 + 3/2 + 3/2 = 3/1

so 3 over 1 times 1 over 2

Answer:

B

Step-by-step explanation:

if

x=3

y=2

-2xy²

3

2³=8

-2×3×8

= -48

Answer:

$42 would be the correct answer.

the answer is 40 minute's 250-210 is 40

Step-by-step explanation:

please Mark me brainlist!!

Answer:

See below

Step-by-step explanation:

Basically, the associative property states that when an expression has three terms, they can be grouped in any way to solve that expression.

For example, [tex](8*4)*5=8*(4*5)[/tex] if you're doing multiplication, or [tex](8+4)+5=8+(4+5)[/tex], if you're doing addition.

The equation that describes the which gives the area of the pen, A, as a function of x, the length of fence parallel to the barn is A = 130x - x²

The pen is rectangular. Therefore,

area of a rectangle = lw

where

Therefore,

perimeter = 2w + l

perimeter = 2w + x

130 = 2w + x

130 - x = 2w

w = 65 - 1/ 2 x

A = xw

A = x(65 - 1/ 2 x)

A = 65x - 1 / 2 x²

Therefore, the function that represents A, the area of the pen is as follows:

A = 130x - x²

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Answer:

D) y = 1x + 2

Step-by-step explanation:

The general structure of an equation in slope-intercept form is:

y = mx + b

In this equation, "m" stands for the slope and "b" stands for the y-intercept. You can substitute the given value of the slope into the equation. Since you are not given "b", you can plug the value of the points into the half-completed equation (with the slope) and isolate "b".

slope = m = 1

y = (1)x + b

(3,5) ------> y = 5 and x = 3

5 = 1(3) + b

5 = 3 + b

2 = b

Final Equation:

y = 1x + 2

The attached graph represents the graph of the function f(x) = |x - 3| + 2

The equation of the function is given as:

f(x) = |x - 3| + 2

The above equation is an absolute value function, and it has the following parameter:

Vertex = (3,2)

Next, we plot the graph of the function (see attachment)

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[tex]\\ \rm\Rrightarrow 77x+93=360[/tex]

[tex]\\ \rm\Rrightarrow 77x=360-93[/tex]

[tex]\\ \rm\Rrightarrow 77x=367[/tex]

[tex]\\ \rm\Rrightarrow x=4.77[/tex]

[tex]\\ \rm\Rrightarrow x=4.8[/tex]

Aswer with Nina ^-^

Don't report my answer ✅

Answer:

See below

Step-by-step explanation:

y = -3 x^7   is NOT a parabola....   y = -3x^2  IS a parabola that opens downward due to the negative coefficient (-3)

Answer:

[tex]x = 2~\text{and} ~x = -3[/tex]

Step-by-step explanation:

[tex]~~~~~~f(x) = g(x)\\\\\implies -x +4 =x^2 -2\\\\\implies x^2 -2+x -4=0\\\\\implies x^2 +x -6 = 0\\\\\implies x^2 +3x -2x -6 =0\\\\\implies x(x+3) - 2(x+3) = 0\\\\\implies (x-2)(x+3) = 0\\\\\implies x = 2,~ x = -3[/tex]

Answer:

x = -3 and x = 2

Step-by-step explanation:

Plotting the graphs :

f(x)

⇒ Find two points (preferably the x and y intercepts)

⇒ 0 = -x + 4

⇒ x = 4

⇒ Point 1 : (4, 0)

⇒ f(x) = 0 + 4

⇒ f(x) = 4

⇒ Point 2 : (0, 4)

g(x)

⇒ g(x) = 0 - 2

⇒ g(x) = -2

⇒ Point 1 : (0, -2)

⇒ g(x) = 2² - 2

⇒ g(x) = 2

⇒ Point 2 : (2, 2)

* Graph with both functions is attached below *

=============================================================

Finding the solutions :

⇒ Equate f(x) and g(x)

⇒ -x + 4 = x² - 2

⇒ x² + x - 6 = 0

⇒ x² + 3x - 2x - 6 = 0

⇒ (x + 3)(x - 2) = 0

⇒ x = -3 and x = 2

Answer:

-1.5

Step-by-step explanation:

h(-1/2)=2 [tex](\frac{-1}{2})^{2}[/tex] -2

h(-1/2)= [tex]\frac{1}{2} -2\\[/tex]

h(-1/2)=-1.5

Answer:

[tex]\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}[/tex]

[tex]\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10[/tex]

[tex]\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10[/tex]

[tex]\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}[/tex]

[tex]\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}[/tex]

[tex]\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}[/tex]

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The mean scores are the same.

Nilo's standard deviation is higher than Lisa's.  Therefore, Nilo's test scores are more spread out that Lisa's, which means Lisa's test scores are more consistent.

The figure (i) have a distance of 15.996 meters and a displacement of 13.892 meters and (ii) a distance of 480 centimeters and a displacement of 339.411 centimeters

The distance is the sum of the lengths that form a trajectory and the displacement is the distance between the initial and final point of a trajectory. Then, we have the following results for each case:

Case I

Distance

d = 5 m + 0.5π · (7 m)

d ≈ 15.996 m

Displacement

[tex]D = \sqrt{(12\,m)^{2}+(7 m)^{2}}[/tex]

D ≈ 13.892 m

Case II

Distance

d = 8 · (60 cm)

d = 480 cm

Displacement

[tex]D =\sqrt{(240\,cm)^{2}+(240\,cm)^{2}}[/tex]

D ≈ 339.411 cm

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Answer:

A its becuase im rewlly smart

Answer:

[tex]\sf 2 x-5y +25=0[/tex]

Explanation:

Equation:

[tex]\dashrightarrow \sf y - y_1 =m(x - x_1)[/tex]

[tex]\dashrightarrow \sf y - 1 = \dfrac{2}{5} (x - (-10))[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +4 + 1[/tex]

[tex]\dashrightarrow \sf y = \dfrac{2}{5} x +5[/tex]

[tex]\dashrightarrow \sf 5y = 2 x +25[/tex]

Answer:

3.6%

Step-by-step explanation:

Because the two events are independent, their probabilities are multiplied, so the probability of a student being born in March and having a blood type of O+ is 9% * 40% = 0.09 * 0.40 = 0.036 = 3.6%

Polynomial is an expression that consists of indeterminate(variable) and coefficients. The roots of the given polynomial are -2, -1, 0, and 2.

Polynomial is an expression that consists of indeterminate(variable) and coefficient, it involves mathematical operations such as addition, subtraction, multiplication, etc, and non-negative integer exponential.

The roots of the given polynomial when plotted on graph are the point at which the graph intersect the x-axis. Therefore, the roots of the given polynomial is,

x = -2, -1, 0, 2

Hence, the roots of the given polynomial are -2, -1, 0, and 2.

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Answer:

It's A. -2, -1, 0, 2

Step-by-step explanation:

8x+72.8=5x+84.5

8x-5x = 84.5-72.8

3x = 11.7

x = 3.9

x = {3.9}

[tex]\\ \rm\Rrightarrow g(x)=6(\dfrac{3}{2})^x[/tex]

[tex]\\ \rm\Rrightarrow g(-1)=6(\dfrac{3}{2})^{-1}=6(\dfrac{2}{3})=2(2)=4[/tex]

[tex]\\ \rm\Rrightarrow g(0)=6[/tex]

[tex]\\ \rm\Rrightarrow g(1)=6(\dfrac{3}{2})=3(3)=9[/tex]

[tex]\\ \rm\Rrightarrow g(2)=6\times\dfrac{9}{4}=13.2[/tex]

Attached the graph

Answer:

Given function:

[tex]g(x)=6\left(\dfrac{3}{2}\right)^x[/tex]

To find each of the points, substitute the given values of x into the function:

[tex]x=-1 \implies g(-1)=6\left(\dfrac{3}{2}\right)^{-1}=4[/tex]

[tex]x=0 \implies g(0)=6\left(\dfrac{3}{2}\right)^{0}=6[/tex]

[tex]x=1 \implies g(1)=6\left(\dfrac{3}{2}\right)^{1}=9[/tex]

[tex]x=2 \implies g(2)=6\left(\dfrac{3}{2}\right)^{2}=13.5[/tex]

Therefore:

[tex]\large \begin{array}{| c | c | c | c | c |}\cline{1-5} x & -1 & 0 & 1 & 2 \\\cline{1-5} g(x) & 4 & 6 & 9 & 13.5 \\\cline{1-5} \end{array}[/tex]

As the function is exponential, there is a horizontal asymptote at [tex]y=0[/tex].

Therefore, as [tex]x[/tex] approaches -∞ the curve approaches [tex]y=0[/tex] but never crosses it.

So the end behaviors of the graph are:

Plot the points on the graph and draw a curve through them.