A student in lab needs to make a solution that is 8.00% by mass NaCl. If 145 g of NaCl is available, what mass of solution can
be prepared?

Answers

Answer 1

According to the given statement 1812.5 g mass of solution can be prepared.

How is solution formed?

When one substance dissolves, or separates into the other, a solution is created. A solute is the name for the material that dissolves to create a solution. A solvents is the material that a solution will dissolve in. Sugar is the solute while water is the solvent in a sugar syrup.

Briefing:

8.0% by mass NaCl means 8 g NaCl in a total of 145 g solution. (note it is g of total solution)

Use dimensional analysis:

145 g NaCl x 100 g solution/8 g NaCl

= 1812.5 g solution

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Related Questions

For the reaction of calcium chloride and sodium oxalate, write: a chemical equation that represents the reaction including all appropriate phase labels (e.g. (s), (l), (aq)).​

Answers

The chemical equation that represents the reaction is NaCl(s) ⇒Na+(aq) + Cl-(aq).

A mixture of sodium sulfate and calcium chloride produces four crystals sodium sulfate calcium chloride sodium chloride and calcium sulfate. Calcium chloride dissolved in water dissociates into ions according to the formula This is an example of a precipitation reaction. This occurs when two aqueous solutions combine to form a precipitate and by-products. It is also usually water-based.

A balanced equation is an equation of a chemical reaction in which the number of atoms and the total charge of each element in the reaction is the same for both reactants and products. In other words, mass and charge are balanced on both sides of the reaction. Widely used as an acid laundry detergent, oxalic acid effectively removes rust and ink stains because it converts most insoluble iron compounds to soluble complex ions.

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The charge on an electrically neutral atom of hydrogen is __.


A +1


B 0


C -1

Answers

Answer:

B. 0

Explanation:

The charge on any electrically neutral atom is alway zero.

an example of a element would be A. Chlorine gas B. salt C. tap water D. vegetable soup

Answers

An example of a element would be chlorine gas

An element is a substance whose atoms all have the same number of protons another way of saying this is that all atoms of a given element have the same number of protons and elements are the simplest chemical forms and thus can not be broken down through chemical reactions and chlorine is a yellow-green gas at room temperature and chlorine has a pungent, irritating odor similar to bleach that is detectable at low concentrations and the density of chlorine gas is approximately 2.5 times greater than air and in the given option only chlorine gas is the element

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How many grams of Br are in 115 g CaBr₂?

Answers

Answer: 95.7 g Br

Explanation: Molecular weight of Ca = 40.78

Molecular weight of Br is 79.9.

Molecular weight of CaBr2 is 192g/mol

115g CaBr2 x 1 mol CaBr/192g  = 0.6  x 2 mol Br/1mol CaBr2 = 1.2 mol Br

1.2 mol Br x  79.9g Br/mol Br =  95.7g Br

A chemistry student needs 65.0 g of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is 1.10 g-cm^- 3. Calculate the volume of pentane the student should pour out. Be sure your answer has the correct number of significant digits.

Answers

The volume of the pentane the student should pour out, given that he needed 65.0 g of it is 59 cm³

How to determine the volume

From the definition of density, we can obtain an expression to calculate volume. This is illustrated below:

Density = mass / volume

Cross multiply

Density × volume = mass

Divide both sides by density

Volume = mass / density

With the above formula, we can obtain the volume of the pentane as follow:

Mass of pentane = 65 gramsDensity of pentane = 1.10 g/cm³ Volume of pentane = ?

Volume = mass / density

Volume = 65 / 1.10

Volume = 59 cm³

Thus, the volume of the pentane is 59 cm³

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Calculate the number of grams that would be needed to make 2.50 x 10? mL of 0.754 M KOH. Enter your answer in the provided box.

Answers

Concentration
=
Moles of solute
Volume of solution
, and get approx.
2.5

g

K
O
H
.
Explanation:
And so (i) we calculate the molar quantity.....
Moles of KOH
=
concentration
×
volume
=
0.179

m
o
l

L

1
×
250.0

m
L
×
10

3

L

m
L

1
=
4.475
×
10

2

m
o
l
.
And then (ii) we multiply this molar quantity by the formula mass of
K
O
H
, .....
4.475
×
10

2

m
o
l
×
56.11

g

m
o
l

1
=
?
?

g
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