Using the part-whole meaning of a fraction, find the larger of each. Write down your explanation. 12 10 d. and and f. and 101 19

Answers

Answer 1

we can conclude that 12/17 is the larger fraction between 12/17 and 12/19 using the part-whole meaning of a fraction.

To determine which fraction is larger between 12/17 and 12/19 using the part-whole meaning of a fraction, we need to compare the sizes of the parts (numerators) relative to the wholes (denominators) for both fractions.

Let's consider the fractions 12/17 and 12/19:

For 12/17:

- The numerator, 12, represents a part of the whole.

- The denominator, 17, represents the total number of equal parts into which the whole is divided.

For 12/19:

- The numerator, 12, also represents a part of the whole.

- The denominator, 19, represents the total number of equal parts into which the whole is divided.

Since the numerators are the same (both 12) and we are comparing the fractions with the same numerator, the fraction with the smaller denominator represents larger parts or more significant portions of the whole.

Comparing the denominators, we can see that 17 is smaller than 19. This means that the whole in 12/19 is divided into fewer parts compared to the whole in 12/17. Therefore, each part of the whole in 12/17 is larger than each part in 12/19.

As a result, we can conclude that 12/17 is the larger fraction between 12/17 and 12/19 using the part-whole meaning of a fraction.

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Related Questions

A rectangular prism has a length of 18 meters, a height of 10 meters, and a width of 5
meters. What is its volume, in cubic meters?

Answers

Answer:

900

Step-by-step explanation:

The figure is the net for a rectangular prism.
What is the surface area of the rectangular prism represented by the net?

PLS HELP!! I WILL GIVE BRAINLYIEST!!

Answers

Answer:

surface area = 544 cm²

Step-by-step explanation:

surface area = (16)(8 + 6 + 8 + 6) + (2)(8)(6) = 448 + 96 = 544 cm²

Help me guys. plz no Decimal please. Thank you!

Answers

Answer: 1,145,375cm^3

Step-by-step explanation:

The area of the base is 7 cm. What is the surface area of the pyramid?

Answers

Answer: 34.5

Step-by-step explanation:

(Base · Height) ÷ 2 → (2 · 4.5) ÷ 2 = 5.5

5.5 · 5 = 27.5

27.5 + 7 = 34.5

Astudent was asked to find a 99% confidence interval for the proportion of students who take notes using data from a random sample of size n - 83. Which of the following is a correct interpretation of the interval 0.14 « p<0.342?

Answers

The given confidence interval is 0.14 < p < 0.342, where p represents the proportion of students who take notes. To interpret this interval correctly, we can say:  We are 99% confident that the true proportion of students who take notes lies between 0.14 and 0.342.

In other words, based on the data from the random sample of size 83, we estimate that the proportion of students who take notes falls within this range with a 99% level of confidence. This means that if we were to take multiple random samples of the same size and calculate confidence intervals, approximately 99% of those intervals would contain the true proportion of students who take notes.

Furthermore, the interval does not include the value of 0.5, which represents no preference or a 50% proportion. Since both 0.14 and 0.342 are less than 0.5, we can infer that the data suggests that a substantial proportion of students take notes, but we cannot conclude with certainty whether the majority or minority take notes without further information.

It's important to note that the interpretation assumes the random sampling method was appropriate and the sample is representative of the population of interest.

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fill in the missing justifications to the proof given: lm = np, lp = mn prove: lmn = npl

Answers

The justification for the proof based on the information will be:

lm = np (Given)

lp = mn (Given)

(1) lmn = lm * n

Justification: Associative property of multiplication

(2) lmn = np * n

Justification: Substitute lm = np

(3) lmn = n * np

Justification: Commutative property of multiplication

(4) lmn = npl

Justification: Substitute lp = mn

Therefore, lmn = npl.

How to explain the information

The associative property of multiplication is one of the fundamental properties of arithmetic. It states that the grouping of factors does not affect the result of multiplication.

In other words, when you multiply three or more numbers, you can change the grouping of the factors without changing the product.

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Write a polynomial of least degree with roots 2 and – 7

Answers

Answer: x^2+5x-14

Step-by-step explanation:

2 and -7 are the roots of the polynomial then we have to write them as

 x=2 ,x=-7

To convert these as factors, we have to write them as

(  x-2) (x+7)

The product of those factors will give the polynomial. Because we have two factors, we will get a quadratic polynomial.

x^2+7x-2x-14

x^2+5x-14

Number of factors  =  Highest exponent of the polynomial

Answer:

y = x² + 5x - 14

Step-by-step explanation:

Given roots x = a, x = b, then the corresponding factors are

(x - a) and (x - b) and the polynomial is the product of the factors

y = (x - a)(x - b)

Here the roots are x = 2 and x = - 7, then the factors are

(x - 2) and (x - (- 7)) = (x + 7), so

y = (x - 2)(x + 7) ← expand using FOIL

y = x² + 5x - 14

can someone help me with this please

Answers

Answer:

x=4

Step-by-step explanation:

so there are two triangles in that shape and they are similar to each other because their angles are equal and the ratio of their sides it 1:2

so the ratio of the side 5x & 40 is 1:2

5x/40=1/2

10x=40

x=4

 
A debt of $25,000 is to be amortized over 17 years at a 7% annual interest rate under monthly compounding. What value of monthly payments will achieve this? Please round your numerical answer to the nearest integer dollar.

Answers

After considering the given data we conclude that value of monthly payments will achieve this is $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203.

To evaluate the monthly payments that will amortize a debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding, we could apply the following steps:
Alter the annual interest rate to a monthly interest rate by applying division of 12. The monthly interest rate is 7% / 12 = 0.5833%.
Alter the number of years to the number of months by multiplying by 12. The number of months is 17 × 12 = 204.
Apply the formula for the monthly payment on an amortized loan:
[tex]P = (r * PV) / (1 - (1 + r)^{(-n))}[/tex]
Here,
P = monthly payment,
r = monthly interest rate,
PV = present value of the loan (which is $25,000),
n = total number of payments (which is 204).
Placing in the values, we get:
[tex]P = (0.005833 * 25000) / (1 - (1 + 0.005833)^{(-204))} = $202.91[/tex]
Hence, the monthly payments that will amortize the debt of $25,000 over 17 years at a 7% annual interest rate under monthly compounding is $203 (rounded to the nearest dollar).
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Find the absolute maximum and minimum values of the given function on the indicated inter- val. (a) f(x) = 31/3 - 3:2/3, on 11-,3).

Answers

The absolute maximum value of the function on the interval [-3, 1] is approximately 28.97, and the absolute minimum value is approximately 3.84.

To find the absolute maximum and minimum values of the function f(x) = 31/3 - 3x2/3 on the interval [-3, 1], we need to evaluate the function at its critical points and endpoints.

First, let's find the critical points by taking the derivative of the function:

f'(x) = (2/3)(31/3)(-3x^(-1/3)) = -2(31/3)(1/x^(1/3)) = -62/x^(1/3)

To find the critical points, we set f'(x) equal to zero and solve for x:

-62/x^(1/3) = 0

This equation has no solutions since the numerator is always non-zero.

Next, we evaluate the function at the endpoints of the interval:

f(-3) = 31/3 - 3(-3)^(2/3) ≈ 3.84

f(1) = 31/3 - 3(1)^(2/3) ≈ 28.97

Finally, we compare the values of the function at the critical points and endpoints to determine the absolute maximum and minimum:

Absolute maximum: f(1) ≈ 28.97

Absolute minimum: f(-3) ≈ 3.84

Therefore, the absolute maximum value of the function on the interval [-3, 1] is approximately 28.97, and the absolute minimum value is approximately 3.84.

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Which describes the difference between the two sequences?
First Sequence: 3, 6, 9, 12, ...
Second Sequence: 3, 12, 48, 192, ...
The first sequence is geometric because there is a common difference of 3. The second sequence is arithmetic
because there is a common ratio of 4.
O The first sequence is arithmetic because there is a common difference of 3. The second sequence is geometric
because there is a common ratio of 4.
The first sequence is arithmetic because there is a common ratio of 3.
The second sequence is geometric because there is a common difference of 4.
O The first sequence is arithmetic because there is a common difference of 4. The second sequence is geometric
because there is a common ratio of 3.

Answers

Answer:

the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

Step-by-step explanation:

In this question table is given as

n          1          2         3           4            5

f(n)     48       -96      192      -385       768

We have to find out if the sequence is arithmetic or geometric.

For Arithmetic sequence :

Difference should be common in each term of fees.

common difference  = f(2) - f(1)

= -96 -48 = -144

similarly  = f(3) - f (2) = 192 + 96 = 288

Here,  ≠  so the sequence is not an arithmetic sequence.

For Geometric sequence :

Ratio  should be common in each term of f(n)

Common ratio  =

Therefore, the sequence is geometric sequence with common ratio (-2).

Option : D is correct.

A bus route takes about 45 minutes. One driver's times for 9 runs of the route are shown.
Times to Complete Bus Router (min)
44.6 44.8 45.0 44.7 44.6 44.9 44.8 44.8 45.0
Calculate the mean of the bus times.
The mean time for this driver to complete the route was
minutes.

Answers

You need to add all the numbers(358.4) and then divide by the total amount of numbers not counting 45 twice(8) and the answer is 44.8

w
Which value of x would make ASUV 2 ATUN by HI?
S
(4X-1
O 2
03
O 4
05
2x + 9

Answers

Answer:

fourth answer choice) 5

Step-by-step explanation:

2x + 9 = 4x - 1

9 = 2x - 1

10 = 2x

5 = x

x = 5

I would appreciate Brainliest, but no worries.

The value of x that would make ASUV = ATUN by HL is 4, the correct option is C.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that;

SUV congruent to TUV

Now,

To solve for x in the equation 2x+9=4x+1, we need to isolate x on one side of the equation.

First, we can simplify both sides by subtracting 2x from each side:

2x+9-2x=4x+1-2x

Simplifying this gives us:

9=2x+1

Next, we can subtract 1 from each side:

9-1=2x+1-1

Simplifying this gives us:

8=2x

Finally, we can divide both sides by 2:

8/2=2x/2

Simplifying this gives us:

4=x

Therefore, by the algebra the answer will be x=4.

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A set H in R² is displayed on the right. Assume the set includes the bounding lines. Determine whether H is a subspace of R² and justify.

Answers

To determine whether set H is a subspace of R², we need to check if H satisfies the three requirements for a subspace: closure under addition, closure under scalar multiplication, and contains the zero vector.

To determine if set H is a subspace of R², we need to check if it satisfies the three properties of a subspace.

Closure under addition: For any two vectors u and v in H, their sum u + v should also be in H. If the lines forming the boundary of H extend infinitely, then any two vectors u and v in H can be added to form a vector that lies within H. Thus, H is closed under addition.

Closure under scalar multiplication: For any vector u in H and any scalar c, the scalar multiple cu should also be in H. Similarly to the closure under addition, if the lines forming the boundary of H extend infinitely, then any vector u in H can be multiplied by a scalar to obtain a vector that lies within H. Hence, H is closed under scalar multiplication.

Contains the zero vector: The zero vector (0, 0) is part of R² and is also part of H since it lies within the boundary of H.

Since H satisfies all three requirements, it is a subspace of R².

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water from a tap flows into a bath at rate of a 750 ml/s. how long does it take to fill the bath with 180 L of water​

Answers

Answer:

750 equals to 1081 after that divide 1081 by 750 then you will get an answer.

1/3 points Previous Answers TanApMath7 10.5.004. My Notes + Ask Your Teacher The owner of the Rancho Los Feliz has 3180 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it by means of a fence running parallel to the sides. No fencing is required along the river. (See the figure below.) What are the dimensions of the largest area that can be enclosed? x = X yd y = 1590 yd What is this area? x yd2 Need Help?

Answers

The dimensions of the largest area that can be enclosed is 1590 × 795= 1264050 yd² when no fencing is required along the river.

Given the owner of the Rancho Los Feliz has 3180 yd of fencing to enclose a rectangular piece of grazing land along the straight portion of a river and then subdivide it by means of a fence running parallel to the sides. No fencing is required along the river.

We need to find the dimensions of the largest area that can be enclosed.

Therefore, the length of the land is the perimeter of the rectangle minus the river front.

We have; 2x + 3y = 3180 yd

Also, we can rewrite this equation in terms of x;

2x = 3180 - 3yy = (3180 - 2x) / 3

Substituting y in terms of x in the area equation;

Area A = x y= x(3180 - 2x) / 3

Taking the derivative of the area equation to find the maximum value of A;

A' = 1060 - 2x / 3 When A' = 0, x = 1590 / 2 = 795 yd.

Substitute x = 795 into the equation for y;

2(795) + 3y = 3180y = (3180 - 1590) / 3 = 530 yd

Therefore, the dimensions of the largest area that can be enclosed are; Length = 1590 yd Width = 795 yd

Hence, the area is given by; Area = Length × Width= 1590 × 795= 1264050 yd².

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Please Answer This, the question is on the picture. it needs to be a fraction
will mark brainllest if its right, no links!

Answers

Given adjacent = 14.7
Given degree = 41
Find hypothenuse
Sohcahtoa (use cah to find hypothenuse)

Cosine = adjacent/hypothenuse
Cos(41) = 14.7/h
0.7547095802 = 14.7/h
14.7/0.7547095802 = 19.477691

Round to nearest tenth:

Solution: 19.5

Answer:

x = 19.48 or 19 12/25

Step-by-step explanation:

cos 41° = 14.7/x

x = 19.48 or 19 12/25

Please answer^^ I will give you brainlist!
Yes 5th grade math :clown face:

Answers

Answer:

Rhombuses

Step-by-step explanation:

It has four vertical lines, then draw a Venn Diagram, opposite to opposite.

Order from Venn Diagrams:

Quadrilaterals

Rectangles

Squares

Rhombuses.

what is the total lateral area of the square pyramid in square inches, 8 inches base and 9 inches height​

Answers

Area of lateral= (1/2)(8)(9)*4
Lateral area=144 in^2

I need the answers 1-4

Answers

Answer:

hope this helps you out question 4 and 3 are the same

Manny invested $8,000 in an account that pays 6.5% simple
interest. Manny will not make any additional deposits or
withdrawals. How many years must the money stay invested for
before the investment has a balance of $13,200?​

Answers

Answer:

10 years

Step-by-step explanation:

Simple interest formula:

AV=PV(1+it)

13200=8000(1+.065t)

1.65=1+.065x

.65=.065x

10=x

Simplify the ratio 7:21.
(OLD HW!!)
(TIPS FOR ALGEBRA TO PLS ^^)

Answers

Answer:

Simplified : 1:3

Step-by-step explanation:

7:21 is equal to 1:3

Also, for algebra tips. Algebra is literally practice. There aren't too many complicated equations or anything until you get into a higher math class so practicing problems is best.

Answer:

7:21 = 1:3

Tips for algebra...

just know the basics and related rules or theorams and practice as much as u can

good day mate

The lengths of three line segments are shown above. Which of the following statements is true?

Answers

Where is the three lines segments

Determine the number of ways 7 books can be arranged on a shelf if a) there are no restrictions?

Answers

The number of ways seven books can be arranged on a shelf if there are no restrictions is 7! = 5040.Why? As there are no restrictions, any of the seven books can occupy any of the seven places on the shelf. Therefore, there are 7 ways to place the first book. After the first book has been placed, there are 6 ways to place the second book (as one place is now occupied).Then, after the first and second books have been placed, there are 5 ways to place the third book (since two places are now occupied). Similarly, there are 4 ways to place the fourth book after the first four have been placed. There are 3 ways to place the fifth book after the first five have been placed.

There are 2 ways to place the sixth book after the first six have been placed. There is only one way to place the last book after the first six have been placed.

So, using the Multiplication Principle, the number of ways 7 books can be arranged on a shelf is:7 × 6 × 5 × 4 × 3 × 2 × 1 = 5040.

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Ms. Padilla is ordering art supplies for 90 students. She
orders 8 jars of paint for every 5 students and 10 sketch
pads for every 3 students.
Determine whether each statement about Ms. Padilla's order is true or false.
Select True or False for each statement.
Ms. Padilla orders 40 sketch pads.
O True
O False
оо
Ms. Padilla orders 144 jars of paint.
O True
O False
The ratio of sketch pads to jars of paint in Ms. Padilla's order can be written as
25 : 12
O True
O False
The ratio of jars of paint to sketch pads in Ms. Padilla's order can be written as
4:5.
o
O True
O False

Answers

1. True
2. False
3. False
4. True

Answer:

1. False

Sketch pads ordered: 10(90/3) = 10×30 = 300

2. True

Painting jars ordered: 8(90/5) = 8×18 = 144

3. True

(25×12)/(12×12) = 300/144

or

25/12 = 300/144 = 2.083..

4. False

Since the previous statement isn't 5:4 and it's true, then this statement is false.

let f be a continuous function on the interval [a,b]. select the answer that correctly completes each sentence. the area between the graph of y=f(x) and the x-axis on the interval [a,b]

Answers

A continuous function the graph of y = f(x) and the x-axis on the interval [a, b] evaluating the definite integral of f(x) over that interval, the changes of f(x) if applicable.

The area between the graph of y = f(x) and the x-axis on the interval [a, b]  by evaluating the definite integral of f(x) over that interval.

The definite integral of f(x) from a to b represents the signed area between the graph of f(x) and the x-axis. The sign of the area depends on the behavior of f(x) above and below the x-axis.

If f(x) is non-negative (greater than or equal to 0) on the interval [a, b], then the area between the graph of f(x) and the x-axis will be positive or zero.

If f(x) is non-positive (less than or equal to 0) on the interval [a, b], then the area between the graph of f(x) and the x-axis will be negative or zero.

If f(x) changes sign on the interval [a, b] (i.e., it is positive in some regions and negative in others), then the area between the graph of f(x) and the x-axis will be the sum of the positive areas minus the sum of the negative areas.

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i just want to make sure i’m correct so is this correct?

A standard coffee mug has a capacity of 16 fluid ounces. If Annie needs to fill 26 mugs with coffee, how many total quarts of coffee does she need?

so what i did is i multiplied 16 x 26 = 416 then i divided 32 and 416 and got 13 so Annie filled 13 quarts of coffee.

please tell me i’m correct or not.

Answers

Answer:

I think you are I'm not 100%

Answer:

13qt

Step-by-step explanation:

your totally correct.

Please solve these for me will give you brainiest please!!

Answers

2- y= -5

3-  y= 2x

4- y= -4

5- y= 6x,,, 60

6-   -4,,,,,,,,,   36

whats 3x+2 x 12.
.
.
.
.
.
music recommendations pls (unknown artist pls not like billie e. or lil nas x/ariana g and megan/cardi b/Justin b) Artist like ALI, Kikou/ mafumafu/set it off/K.flay/twice/ASTRO/taemin. artist like them? like name the artist and some of their songs.

Answers

Answer:

sheck wes, sam hunt, mainiac, petty level , lakeyah , doja cat, sawatiee

Step-by-step explanation:

Answer:

NF: Songs are kinda depressing sometimes but he is a really good rapper. Hear clouds

Kid Laroi: Listen to without you.

iann dior: rapper and really good

Mumford and sons: more of slow music but upbeat at the same time

Tracy chapman: She has really good music. Recommend listening to fast car

those are some of my favs

Step-by-step explanation:

Do there exist subspaces S,T, and U of R3 such that SIT, SIU, and T 1 U? If so, provide an example of such an S, T, and U, and prove that SIT, SIU, and T 10. If not, prove why they do not exist.

Answers

There exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

In order to answer the given question, we first need to understand the definition of subspaces of a vector space.A subspace of a vector space is a subset that meets three requirements:

i) It includes the zero element of the vector space.

ii) It is closed under addition (if u and v belong to the subspace, then u + v is also in the subspace).

iii) It is closed under scalar multiplication (if u is in the subspace and k is a scalar, then ku is also in the subspace).

there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

The reason is simple because if T∩U = Ø, then either SIT or SIU will be the trivial subspace {0}.

However, this contradicts the fact that both SIT and SIU have to contain a non-zero vector as they are subspaces that are generated by S, T, and U.

Therefore, it is proven that there exist no subspaces S, T, and U of R³ such that SIT, SIU, and T∩U.

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If you double the diameter of a telescope, you double its light-collecting area. True False Clarissa wants to create more shade in her yard to block the hot sun, so she buys a sapling of an oak tree and plants it in the yard. To make sure the tree is growing at a healthy rate, she makes the following table to track its height over a period of weeks. What is the average rate of change in the tree's height from week 3 to week 9? Enter your solution into the box below. Determine whether the given credit card numbers are valid. 1. 4417-5486-1785-641 2. 5591-4912-7644-1105. 3. 6011-0408-9477-3158 4. 3715-5487-3184-4663 5. 4274-3156-0372-5492 6. 5164-8295-1229-3674 7. 6011-4988-1002-6487 8. 4896-4198-8760-1970 9. 3401-7143-3912-04 10. 5229-4203, 5061-5465 Consider the function y = 8x + 3 between the limits of x = 2 and x = 8. a) Find the arclength L of this curve: L: ___________ Round your answer to 3 significant figures.b) Find the area of the surface of revolution, A, that is obtained when the curve isrotated by 2 radians about the x-axis.Do not include the surface areas of the disks that are formed at x = 2 and x = 8. A = ___________ Round your answer to 3 significant figures. CAN YOU EXPLAIN? What is chemical weathering, how does it occur? After Cuba lost economic aid from the Soviet Union, Fidel Castroturned to other communist countries for help.changed the countrys system of government.encouraged the United States to invest in the country.allowed some economic reforms to occur. Kena, Limo and Mara had been orphaned when both their parents died in a bus accident inApril 1992. Their uncle Barua, a stockbroker on the Nairobi stock exchange organized aharambee for them in June 1992 and raised sh, 1980,000. He invested this amount as follows:Shs.9,600 sh. 10 Ordinary Shares in KAB Ltd 432,00012,600 sh. 10 Ordinary Shares in BBB Ltd 756,00013,200 sh. Ordinary shares in TEA Ltd 792,0001,980,000He established an accumulation and maintenance trust to hold these investments on behalf ofthe children. The trust had a wide investment clause. He ruled that accounts be made up to 31stmay each year. When each child reached the age of 21, the trustees were to transfer to him hisshare of the fund at that date. Kena turned 21 years on 31st may 1996.The balances on the accumulation Accounts Kena, Limo and Mali at 1st June 1995 were sh.207,900, sh. 103,950 and sh. 34,650. To this date, the trustees had used accumulated income topurchase 5,775 sh. 10 Ordinary shares in TEA Ltd. on 1st June 1995, thee was no cash in theincome account in the bank.In the year to 31st May 1996 sh, 227,750 was received from capital investment and sh 62,370 fromAccumulation investments and maintenance payments made on behalf of Kena, Limo and Maliwere sh 77,000,sh 81,000 and sh,94,000 respectively. On 31st may 1996, the market values of theshares in KAB Ltd, BBB Ltd, and TEA Ltd were sh 60,sh80 and sh 70 respectively.Kena was to receive 10,000 sh. Ordinary shares in BBB Ltd and the balance due to him oncapital would be made up of shares in KAB Ltd. Out of the accumulation assets, Kena was toreceive sh.32, 222 in cash and the balance in shares in TEA Ltd.Required:The beneficiaries accumulation accounts for the year ended 31st may 1996 and distributionstatements for the capital and accumulation assets as at 31st May 1996