Q1: A cyclist brakes to a stop. His thinking distance was 1m and his braking distance was 3m. What was his overall stopping distance?

Q2: A car driver notices that there is a red light coming up. He brakes and stops in a total distance of 52 metres. If his thinking distance was 15 metres, what was his braking distance?

Q3: A car takes 76 metres to stop once a driver has noticed a hazard. If the thinking distance of the driver was 14m and the speed of the car was 8m/s how long did it take the brakes to slow the car down to a stop?

Q4: A lorry travels 28m when stopping from a speed of 4m/s. If its braking distance was 18m, what was the driver’s reaction time?

Q5: Car 1 brakes to a stop on a dry road. Car 2 does the same thing, at the same speed, on a road where it has been raining.

Answer:

The total distance moved by the car is 80 metres

Explanation:

Given

North = 30 meters

South = 50 meters

Required

Determine the distance

Distance is a scalar quantity and hence, the total distance is the summation of distance moved in both directions

i.e.

[tex]Total\ Distance = North + South[/tex]

[tex]Total\ Distance = 30\ metres + 50\ metres[/tex]

[tex]Total\ Distance = 80\ metres[/tex]

Hence;

The total distance moved by the car is 80 metres

Answer:

Water

Explanation:

How do we have water at our disposal, like that's crazy.

Answer:

B. A metal image of gas molecules as tiny balls

Answer:

B. A mental image of gas molecules as tiny balls

Answer:

When we run a piece of paper with the oil in our head with the help of a comb produces electrostatic force.

Balloons get attracted to another balloon when one of them are rubbed with hair.

Explanation:

Those are 2 examples of electrostatic force.

Answer:

[tex]\frac{729\frac{m^{2} }{s^{2} } }{83m}[/tex]≈8.8[tex]\frac{m}{s^{2} }[/tex]

Explanation:

Answer:

Yes the correct answer is B

Explanation:

Answer:

 v_A = 6 m/s , v_B = 0 m/s ,  v_C = - 4 m/s , v_D = -4 m/s ,     v_E = 2.66 m / s

Explanation:

For this exercise we use the definition of average velocity in each segment

         v_average = (x₂-x₁) / Δt

segment A of the graph you take the value of distance and time

x₁ = 0 m     t₁ = 0 s

x₂ = 60 m   t₂ = 10 s

using the average velocity equation and calculate

         v_A = (60-0) / (10-0)

         v_A = 6 m / s

Segment B

x₁ = 60m

x₂ = 60 m

since the displacement variation is zero (particle stopped) the velocity is zero

         v_B = 0 m / s

Segment C and D

x₁ = 60 m    t1 = 15 s

x₂ = -40 m  t2 = 40 s

        v_C = (-40 -60) / (40 -15)

        v_C = - 4 m / s

Segment D

how is the same line

         v_D = -4 m / s

Segment E

x₁ = -40 m  t₁ = 40 s

x₂ = 0 m    t₂ = 55 s

         v_E = (0- (-40)) / (55 -40)

         v_E = 2.66 m / s

Answer:

The work done is 2.94 Nm.

Explanation:

First, you have to find the force of a brick layer using the formula, Force = mass×gravity :

[tex]f = m \times g[/tex]

[tex]let \: m = 10,g = 9.8[/tex]

[tex]f = 10 \times 9.8[/tex]

[tex]f = 98N[/tex]

Given that the force of a brick layer is 98N. Next, you have to apply work done formula, Work done = force×distance :

[tex]w.d = f \times d[/tex]

[tex]let \: f = 98,d = 0.03m[/tex]

[tex]w.d = 98 \times 0.03[/tex]

[tex]w.d = 2.94Nm[/tex]

Answer:

Option (D) is correct.

Explanation:

The balloon lands horizontally at a distance of 420 m from a point where it as released.

Velocity of air balloon along +X axis =10 m/s

velocity of ball=4 m/s along + X axis

the velocity of balloon gets added to the velocity of ball. So the resultant velocity of the balloon=10+4 = 14 m/s

time taken= 30 s

The distance traveled is given by d= v t

d= 14 (30)

d= 420 m

Thus the balloon lands horizontally at a distance of 420 m from a point where it as released.

Answer:

Positive

Ghhhhhhbn

Ggvbbn

To minimize damage during a broadside collision decrease the speed to put the point of impact behind the passenger section.

A broadside collision happens when the front of one vehicle bangs into the side of another, usually at a high rate of speed. Although catastrophic injuries can occur in any automobile accident on the road, broadside crashes are especially dangerous.

This is due to the fact that there is not much room or protection between the person inside the hit automobile and the moment of contact. The injury happens to the vehicles depends on their speed.

As the speed is reduced, many such collisions can stopped in time and we can prevent broadside collision as well and giving enough time to pass other vehicles through the intersection.

Find more on broadside collision:

https://brainly.com/question/28271581

#SPJ2

Answer:

accuracy refers to the deviation of a measurement from a standard or true value of the quantity being measured

Answer:

8 seconds = 72cm

3 seconds = 36cm

6 seconds = 96cm

Explanation:

lab assignment i just took.

Speed is the rate of distance over time. The speed of the cart is as follows:

Let:

[tex]s \to[/tex] speed

[tex]d \to[/tex] distance

[tex]t \to[/tex] time

After 8 seconds

For low fan speed; the distance (d) at 8 seconds is:

[tex]d =576cm[/tex]

Speed (s) is calculated using:

[tex]s = \frac dt[/tex]

[tex]s = \frac{576cm}{8s}[/tex]

[tex]s = 72cms^{-1}[/tex]

Hence, the speed after 8 seconds is [tex]72cms^{-1}[/tex]

After 3 seconds

For medium fan speed; the distance (d) at 3 seconds is:

[tex]d = 108cm[/tex]

The speed (s) is :

[tex]s = \frac dt[/tex]

[tex]s = \frac{108cm}{3s}[/tex]

[tex]s = 36cms^{-1}[/tex]

Hence, the speed after 3 seconds is [tex]36cms^{-1}[/tex]

After 6 seconds

For high fan speed; the distance (d) at 6 seconds is:

[tex]d = 108cm[/tex]

The speed (s) is :

[tex]s = \frac dt[/tex]

[tex]s = \frac{576cm}{6s}[/tex]

[tex]s = 96cms^{-1}[/tex]

Hence, the speed at 6 seconds is [tex]96cms^{-1}[/tex]

Read more about speed at:

https://brainly.com/question/7359669

Answer:

because they both have large area to capture air

Answer:

Because they have a large surface area to capture moving air when going at a certain speed.

Explanation:

When your trying to fly a kite and the wind isn't that much, you have to run so that the kite can come in contact with the fast moving air which pushes the kite to go up. Just like a eagle because when a eagle is trying to fly, it has to first flap its wings to push air downwards so that it can create lift and at a certain altitude, the eagle doesn't have to flap it's wings though it tilts its body downwards a little so that gravity can do the work, so the eagle is basically gliding downward.

Answer:

the light travels at a velocity of [tex]2\,\,10^8 \frac{m}{s}[/tex] in the glass

Explanation:

Recall that the refractive index of a material (n) is defined as the quotient between the speed of light in vacuum (c), and the speed of light in the medium (v). Therefore we can solve for the speed of light in the medium if we know the index of refraction it has:

[tex]n=\frac{c}{v} \\v=\frac{c}{n} \\v=\frac{3\,\,10^8}{1.5} \frac{m}{s} \\v=2\,\,10^8 \frac{m}{s}[/tex]

Answer:

D) The contraction of objects in space

Explanation:

A) Expansion of the universe as originated from the Big Bang is an important evidence, as B) the Cosmic microwave background which is thought to be left over from the Big Bang. The right proportion of hydrogen and helium as unprocessed material that has been detected as the basic elements from where the universe started.

The only out of context option is option D

Answer:

The true statement about the maximum speed of each car will be that the power of each car directly proportional to the speed of each car.

Explanation:

Given that,

Power of first car = 100 watt

Power of second car = 150 watt

Power of third car = 200 watt

We know that,

Power :

The power is directly proportional to the cube of speed.

In mathematically,

[tex]P\propto v^3[/tex]

Where, P = power

v = speed

If the power is increased then the speed will be increase.

We need to find the maximum speed of car

According to question,

The power of car is maximum so the speed of car will be maximum.

For first car,

The power of first car is 100 watt.

So, the speed of first car will be 1000000 m/s.

For second car,

The power of second car is 150 watt.

So, the speed of second car will be 3375000 m/s.

For third car,

The power of third car is 200 watt.

So, the speed of first car will be 8000000 m/s.

Hence, The true statement about the maximum speed of each car will be that the power of each car directly proportional to the cube of speed of each car.

Explanation:

1 L = 1000 cm³

m = ρV

m = (13.6 g/cm³) (1000 cm³)

m = 13,600 g

Answer: 12 mph

Explanation: 36 miles divided by 3 hours would be 12 mph

Answer:

nngh have

bjruh hjrhhj be rnrnnrnrnnnrnjrjnnnnnnnnrnrn n n and I was nrn

Explanation:

jbbbbbhhhjjnnnnnnnnnnjhvcc

Explanation:

Explanation:

Given data

velocity v= 25m/s

The time it takes to put on brake t= 0.3s

the distance covered when the  brake was put on is

v=s/t

s= v*t

s= 25*0.3s

s= 7.5m

hence the distance covered is 7.5m

Also the rate of decrease in aceleration is 5m/s^2

we can also calculate the distance covered at this rate

v^2=u^2+2as

25^2= 0+2*5*s

625=10s

divide both sides by 10

s=625/10

s= 62.5m

The total  distance covered between putting on the brakes and decelareation is  7.5+62.5= 70m

Given that the tree is 75m ahead, the car would not hit the tree

Answer:

it must move back and forth during sex

Answer:

   x_total = 23250 m

Explanation:

This is a uniform motion exercise, the equation that describes the motion is

         v = x / t

the position is

        x = v t

let's reduce the magnitude to the SI system

        v = 85 km / h (1000 m / 1km) (1h / 3600 s) = 23.61 m / s

         t = 0.25 h (3600 s / 1h) = 900 s

let's calculate

         x₁ = v t₁

         x₁ = 23.61   900

         x₁ = 21250 m

The distance from the origin is

         x_total = x_station + x₁

         x_total = 2000 + 21250

         x_total = 23250 m

Answer:

60008.4 J

Explanation:

The mass of each kid = 30 kg

mass of the cart = 20 kg

The speed of the cart down the hill = 30 km/hr = 30 x 1000/3600 = 8.33 m/s

The height of the hill = 80 m

The potential energy of the boys at the top of the hill = mgh

where

m is the total mass of the kids and the cart = (30 x 2) + 20 = 80 kg

g is the acceleration due to gravity = 9.81 m/s^2

h is their height above the ground = 80 m (on the top of the hill)

substituting, we have

potential energy PE = 80 x 9.81 x 80 = 62784 J

At an instance at the bottom of the hill

their kinetic energy = [tex]\frac{1}{2} mv^2[/tex]

where

v is their velocity = 8.33 m/s

m is their total mass = 80 kg

substituting, we have

kinetic energy KE = [tex]\frac{1}{2}*80*8.33^2[/tex] = 2775.6 J

Total work done on the cart is equal to the energy lost by the cart when it reached the bottom of the hill

work done by friction = PE - KE = 62784 - 2775.6 = 60008.4 J

Answer:

A System

Explanation:

There are many systems including the circulatory and nervous system where multiple organs work together to perform a job.

Answer:

Option D - 0.2 s

Explanation:

We are given;

Initial velocity; u = 7 m/s

Height of table; h = 1.8m

Now,since we want to find the time the car spent in the air, we will simply use one of Newton's equation of motion.

Thus;

h = ut + ½gt²

Plugging in the relevant values, we have;

1.8 = 7t + ½(9.8)t²

4.9t² + 7t - 1.8 = 0

Using quadratic formula to find the roots of the equation gives us;

t = -1.65 or 0.22

We can't have negative t value, thus we will pick the positive one.

So, t = 0.22 s

This is approximately 0.2 s

Answer:

1. 50 m/s 2. 10 ft/min 3. 50 miles/hour 4. 10 m/s

Explanation:

We are required to calculate the speed in each instant

Since speed = distance/time,

1. For the doctor, speed = distance/time = 100 m/20 s = 50 m/s

2. For the duck, speed = distance/time = 20 feet/ 2 min = 10 ft/min

3. For the dude who flew, speed = distance/time = 100 miles/ 2 hours = 50 miles/hour = 50 mi/h

4. For Dave who rolled down the hill, speed  = distance/time = 300 metres/ 30 s = 10 metres/ second = 10 m/s