If ammonium phosphate reacts with sodium chloride in aqueous solution, what are the products?

Answer:

1. Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵

2. Kc = [I₂]²

3. Kc = 1/[NH₃] [HCl]

Explanation:

The equilibrium constant (Kc) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactant raised to their stoichiometric coefficients. It only includes gases and aqueous species.

1. 4 NH₃(g) + 5 O₂(g) ↔ 4 NO(g) + 6 H₂O(g)

Kc = [NO]⁴ [H₂O]⁶ / [NH₃]⁴ [O₂]⁵

2. ZrI₄(s) ↔ Zr(s) + 2 I₂(g)

Kc = [I₂]²

3. NH₃(g) + HCl(g) ↔ NH₄Cl(s)

Kc = 1/[NH₃] [HCl]

Answer:A

Explanation:

1. [tex]^{222}Rn_{86}[/tex] → [tex]^{218}Po_{84} + ^{4}He_{2}[/tex]

What is a spontaneous decay?

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Answer:

It's 23.14 percent

Explanation:

First, the mass of all the elements are:

N = 14

O = 16

Fe = 56

In this molecule you have 3 atoms of N, and 9 atoms of O, so:

3•14 = 42

16•9 = 144

The whole mass of the molecule is:

56 + 42 + 144 = 242

242/100 = 2.42, so 1% is 2.42

56/2.42 = 23.14%

Answer:

7 is the mass number of li and 3 is the atomic number

a 3

b 7

c 3

d 4

Answer:

Place a glass rod in the solution, if the crystallisation point has been reached, you should notice small crystals formed on it.

Answer: 63.96%.

Explanation:

In 111g of Calcium chloride, there is 40g of Calcium and 71g of Chlorine. Percentage Composition of Chlorine is 63.96%.

Hope This Helps!

Answer:

They are compounds.

Explanation:

..........

Answer:

compounds!!

Explanation:

...........

Answer:

[tex]m_{Al}=9.42gAl[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

[tex]m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2} *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl[/tex]

Regards!

Answer:

The correct solution is "[tex]0.480 \ J/g^{\circ}C[/tex]".

Explanation:

Given:

q = 103 J

Mass,

m = 12.6 grams

Temperature,

[tex]T_1=22.4[/tex]

[tex]T_2=39.4[/tex]

[tex]\Delta T=T_2-T_1[/tex]

      [tex]=39.4-22.4[/tex]

      [tex]=17^{\circ}C[/tex]

Now,

⇒  [tex]C=\frac{q}{m\times \Delta T}[/tex]

⇒      [tex]=\frac{103}{12.6\times 17}[/tex]

⇒      [tex]=\frac{103}{214.2}[/tex]

⇒      [tex]=0.480 \ J/g^{\circ}C[/tex]

Answer:

Five general properties of organic  compounds:

Answer:

I think the answer would be A.

The question is incomplete. The complete question is :

C. Balance these fossil-fuel combustion reactions. (1 point)

C8H18(g) + 12.5O2(g) →    ____CO2(g) + 9H2O(g) + heat

CH4(g) + ____O2(g) →     ____CO2(g) + ____H2O(g) + heat

C3H8(g) + ____O2(g) →    ____CO2(g) + ____H2O(g) + heat

C6H6(g) + ____O2(g)  →   ____CO2(g) + ____H2O(g) + heat

Solution :

C8H18(g) + 12.5O2(g) →    __8__CO2(g) + 9H2O(g) + heat

When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.

CH4(g) + __2__O2(g) →     __1__CO2(g) + __2__H2O(g) + heat

When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.

C3H8(g) + __5__O2(g) →    __3__CO2(g) + __4__H2O(g) + heat

When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.

C6H6(g) + __1/2__O2(g)  →   __6__CO2(g) + __3__H2O(g) + heat

When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.

Answer. First things first... Balance the Chemical Equation

2FeCl3 + 3(NH4)2CO3 ---------> 6NH4Cl + Fe2(CO3)3

Its balanced Now.

200g of FeCl3 ---Given this... We can get jts reacting Moles

Mole = Mass/Molar Mass

Molar Mass of FeCl3 = 56 + (35.5)x3=162.5gmol-¹

Mole=200/162.5 =1.231moles of FeCl3

From the equation of Reaction

When 2mole of FeCl3 reacts.... It produces 1mole of Iron III carbonate [Fe2(CO3)3]

Since Mole ratio of reaction between both is 2:1

Therefore When 1.231moles of FeCl3 react....

1.231/2 moles of Fe2(CO3)3 will be produced.

= 1.231/2 = 0.616moles.

0.616Moles of Fe2(CO3)3 will be produced

Recall MASS =MOLE X MOLAR MASS

MOLAR MASS OF FE2(CO3)3= 56(2) + (60)(3)=292gmol-¹

MASS = 0.616 x 292 =179.872g ~ 180g of Fe2(CO3)3 Will Be Produced.

OPTION A SEEMS TO BE THE CLOSEST. THAT SHOULD BE OUR ANSWER. I MAY HAVE MISSED IT A BIT BECAUSE OF SOME APPROXIMATIONS.

BYE!

Answer:

[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]

first balance the chemical equation

first balance the chemical equation[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]

2FeCl₃=2*162=324g

6NH₄Cl=6*53.5=321g

324 g of FeCl₃ gives 321 g of NH₄Cl

200g of FeCl₃ gives 321/324*200=198.14 g of NH₄Cl

in nearest value it is 198g/mole

The number of grams of ammonium chloride (NH4Cl) that will be produced is C.198___ grams.

Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Explanation:

Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L

Molarity = 0.750 M

It is known that molarity is the number of moles of solute present in liter of a solution.

Therefore, moles present in given solution are calculated as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\0.750 M = \frac{moles}{0.085 L}\\moles = 0.0637 mol[/tex]

Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.

Answer:

The particles begin to move faster as the gas is heated. Since the gas remains at a constant pressure and volume, the particles are not able to spread out, so they move around the container even faster.

Explanation:

its just what happens

When a. certain volume of gas is heated at constant pressure, the speed of motion of the gas increases with temperature increase.

Anontons law states that If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. If the volume is held constant, the increased speed of the gas molecules results in more frequent and more forceful collisions with the walls of the container, therefore increasing the pressure.

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A solution is prepared by mixing 50.00 mL of 0.100 M HNO3 and 100.00 ml of 0.200 M Ca(NO3)2. The molarity of the nitrate ion in the final solution is 0.1667 M.

The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per liter of a solution is known as molarity. The molar concentration of a solution is another name for molarity.

Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the solution in liters, is the most widely used unit to express solution concentration: liters of solution/moles of solute equals M. One liter of a solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.

50.0 mL x 0.100 M

= 5.00 millimoles of HNO3

=0.00500 moles

100.0 mL x 0.200 M

= 20.0 millimoles of HNO3

=0.0200 moles

The whole solution has a volume of 150.0 mL

= 50.0+100.0

= 150

The whole solution contains 25.0 millimoles of HNO3

= 5.00+20.0

= 25

millimoles / mL = Molarity

25.0 / 150.0

= 0.1667 M

moles / Liters = Molarity

0.0250 / 0.1500

= 0.1667 M

Thus, The molarity of the nitrate ion in the final solution is 0.1667 M.

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Answer:

Volume = 4614 m³

Explanation:

The volume of a pyramide is given by the following formula:

We are already given all the required information to calculate the volume by inputting the data:

The pyramid's volume is 4614 cubic meters.

Answer:

[tex]\boxed {\boxed {\sf 0.255 \ mol \ C }}[/tex]

Explanation:

If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

Look up the molar mass of carbon.

Set up a ratio using the molar mass.

[tex]\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]

Since we are converting 3.06 grams to moles, we multiply by that value.

[tex]3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]

Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.

[tex]3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}[/tex]                      

[tex]3.06 * \frac{1 \ mol \ C}{12.011 }[/tex]    

[tex]\frac {3.06}{12.011 } \ mol \ C[/tex]                                

[tex]0.25476646 \ mol \ C[/tex]

The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.

The 7 in the ten-thousandth place tells us to round the 4 up to a 5.

[tex]0.255 \ mol \ C[/tex]

3.06 grams of carbon is approximately 0.255 moles of carbon.

Answer:buckled railroad tracks on a hot day

Explanation: i just did it

Answer:

K = 0.0396

Explanation:

Based on the reaction:

A + 2B ⇄ 3C + 2D

Where equilibrium constant, K, is:

K = [C]³[D]² / [A] [B]²

The initial concentrations of A and B are:

[A]₀ = 0.050M * (45.0mL / 70.0mL) = 0.0321M

[B]₀ = 0.100M * (25.0mL / 70.0mL) = 0.0357M

As [C] = 0.0410M, the molar concentration of D is:

0.0410M * (2mol D / 3mol C) = 0.0273M = [D]

And the concentration of A and B that reacted was:

0.0410M * (2mol B / 3mol C) = 0.0273M B

0.0410M * (1mol A / 3mol C) = 0.0137M A

Equilibrium concentration B and A:

0.0357M - 0.0273M = 0.0084M = [B]

0.0321M - 0.0137M = 0.0184M = [A]

And K is:

K = [0.0410M]³[0.0273M]² / [0.0184M] [0.0084M]²

Answer:

2 mL.

Explanation:

From the question given above, the following data were obtained:

Volume of water = 8 mL

Volume of water + solid = 10 mL

Volume of solid =?

The volume of the solid can be obtained as follow:

Volume of solid = (Volume of water + solid) – (Volume of water)

Volume of solid = 10 – 8

Volume of solid = 2 mL

Therefore, the volume of the solid is 2 mL

Answer:

more electron deficient

Explanation:

The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.

This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.

Hence, the nitro group makes the pyrinde ring more electron deficient

Answer:

The solution with [OH-] = 3.2x10-3 M will have an [H+] of 3.09x10–12 M.Explanation:

Answer: The correct statements about thermal conductivity are:

Explanation:

The rate at which transfer of heat takes place from one object to another by conduction over a unit cross section area of a material is called thermal conductivity.

Hence, more is the distance between atoms of a substance less will be its thermal conductivity. This is because more is the space between molecules of a substance more will be their random motion due to which there will be less effective energy transport.

The thermal conductivity of metals is very high than liquids.

Also, the thermal conductivity of solids is generally higher than that of liquids.

As gases have more space between its molecules so they have less thermal conductivity.

Thus, we can conclude that the correct statements about thermal conductivity are:

Answer:

c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms.

Explanation:

The statements are:

a. There are more molecules of N2 present than atoms of Ar. FALSE. Because 1 mol of molecules of N2 = 28g and 1 mol of molecules of Ar = 40g. As there are equal MASSES, you will have more molecules of N2 than Ar molecules

b. The pressure is greater in the Ar flask. FALSE

Because pressure is directly proportional to amount of molecules. As molecules N2 > Molecules Ar. The pressure is greater in N2 flask

c. The N2 molecules collide more frequently with the walls of the flask than do the Ar atoms. TRUE

The collision probability of N2 is higher because there are more molecules presents

Answer:

11

Explanation:

becauase 5 +6

Answer:

Beta decay

Explanation:

Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.

Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.

The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.

Beta decay decreases the neutron - proton ratio.