[tex] \sf \huge{ question \hookleftarrow}[/tex]


If [tex] \alpha \: and \: \beta [/tex] are roots of a equation " ax² + by + c ", then find the value of the following in terms of a , b and c ~


[tex] \boxed{ \boxed{ \sf \sqrt{ \alpha} + \sqrt{ \beta } = \: ?}}[/tex]


Answers

Answer 1

[tex]\underline{\bf{Given \:equation:-}}[/tex]

[tex]\\ \sf{:}\dashrightarrow ax^2+by+c=0[/tex]

[tex]\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.[/tex]

[tex]\sf We\:know,[/tex]

[tex]\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}[/tex]

[tex]\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}[/tex]

[tex]\underline{\large{\bf Identities\:used:-}}[/tex]

[tex]\boxed{\sf (a+b)^2=a^2+2ab+b^2}[/tex]

[tex]\boxed{\sf (√a)^2=a}[/tex]

[tex]\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}[/tex]

[tex]\boxed{\sf \sqrt{\sqrt{a}}=a}[/tex]

[tex]\underline{\bf Final\: Solution:-}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}[/tex]

[tex]\bull\sf Apply\: Squares[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}[/tex]

[tex]\bull\sf Put\:values[/tex]

[tex]\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}[/tex]

[tex]\bull\sf Simplify[/tex]

[tex]\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}[/tex]

[tex]\underline{\bf More\: simplification:-}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}[/tex]

[tex]\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}[/tex]

[tex]\underline{\Large{\bf Simplified\: Answer:-}}[/tex]

[tex]\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}[/tex]

Answer 2

The value  [tex]\sqrt{\alpha } +\sqrt{\beta }[/tex] in terms of a, b and c is [tex]\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Roots of a quadratic equation

Given the quadratic equation ax² + bx + c, the sum and product  of the roots are expressed as:

[tex]\alpha +\beta =-\frac{b}{a} [/tex][tex]\alpha \beta =\frac{c}{a} [/tex]

Get the value of the radical expression [tex]\sqrt{\alpha } +\sqrt{\beta } [/tex]

Taking the square of the expression will give:

[tex](\sqrt{\alpha } +\sqrt{\beta } )^2=(\sqrt{\alpha } )^2+(\sqrt{\beta } )^2+2\sqrt{\alpha \beta} [/tex]

Take the square root of both sides:

[tex]\sqrt{(\sqrt{\alpha } +\sqrt{\beta } )^2} =\sqrt{(\sqrt{\alpha } )^2+(\sqrt{\beta } )^2+2\sqrt{\alpha \beta} } \\ \sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(\alpha }+{\beta} )+2\sqrt{\alpha \beta} } \\[/tex]

Substitute the product and the sum values into the expression to have:

[tex]\sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(-\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\\sqrt{\alpha } +\sqrt{\beta }=\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Hence the value  [tex]\sqrt{\alpha } +\sqrt{\beta }[/tex] in terms of a, b and c is [tex]\sqrt{{(\frac{b}{a})^2 } +2\sqrt{\frac{c}{a} } } \\[/tex]

Learn more on the roots of equation here: https://brainly.com/question/25841119


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Given that,

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12 for every 2 male birds in a bird cage there are 5 females. What is the ratio of the males to females

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What is the value of y in the formula show when x=4/5

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Answer:

there is no way to solve for y, but if your solving for x then x=4/5 and in decimal form it is x=0.8    hope that helps

Step-by-step explanation:


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Answers

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Answers

f(4)= -4 and g(x)= 213

What is -10 5/6 times 8 1/2

Answers

Answer:

92 1/12      

Step by step explanation:                                

                                                     

Answer:
92 1/12
Step by step

how much coffee is in the cup, it the cup if 7 feet by 7 feet, and 1 cubic foot = 7.48052

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Answers

Answer:

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Step-by-step explanation:

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Answers

General method:

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Mean Method:

Let X = 1.333... → → →eqn(i)

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A car salesperson works 40 hours per week at a job where he has two options for being paid. Option A is an hourly wage of ​$16. Option B is a commission rate on weekly​ sales, and he averages ​$6400 in sales each week. What commission rate does he need to have to earn the same amount with the two​ options?

Answers

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Answers

Hey there!

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Answers

Answer:

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Answers

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[tex]\huge \bf༆ Answer ༄[/tex]

Let's solve for x ~

[tex] \sf9x + 1 = - 26[/tex]

[tex] \sf9x = - 26 - 1[/tex]

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Answers

Answer:  26.25 meters

=====================================================

Work Shown:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

The answer is $7.05.

Hope it helps.

Step-by-step explanation:

Okay so Amy bought 5 shirts for $10.59 EACH.

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Answers

Answer:

Step-by-step explanation:

Something missing in "noticed that of the apples."  Perhaps "that 40% of . . .?"

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Answers

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Answers

Answer:

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Hope This Helps!!!

Answer:

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Step-by-step explanation:

33y

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33 x 18 = 594

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Answers

[tex]\huge \bf༆ Answer ༄[/tex]

Let's solve ~

[tex] \sf ln(x + y) - ln(x + y) [/tex]

[tex] \sf ln( \frac{x + y}{x + y} ) [/tex]

[tex] \sf ln(1) [/tex]

[tex] \sf0[/tex]

[ Since, ln (1) = 0 ]

Therefore, the statement is true ~

Answer:

In(x+y) - In(x+y)

= In([tex] \frac{x + y}{x + y} [/tex])

= In(1)

=0

Hence, the statement is true!!

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Answers

Answer:

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

k = 3

Step-by-step explanation:

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Answers

[tex]\text{Given that,}\\\\y = -\dfrac 4{15} x + 24\\\\\text{When x = 120,}\\\\y = -\dfrac 4{15} (120) + 24\\\\\implies y = - \dfrac{480}{15} +24\\\\\implies y=-32+24 \\\\\implies y = -8[/tex]

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