The formula for the volume of a cylinder with a height of 5 units is v(r)-5x2 where r is the radius of the cylinder.
What is the domain and range of this function?

Answer:

Step-by-step explanation:

mag jakol

Answer:

[tex]\huge\boxed{\sf |AB|\approx 13.9 \ units}[/tex]

Step-by-step explanation:

Point 1 = (x₁, y₁) = (7, 12)

Point 2 = (x₂, y₂) = (2, -1)

So,

x₁ = 7

y₁ = 12

x₂ = 2

y₂ = -1

Using distance formula to solve the question.

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\D=\sqrt{(2-7)^2+(-1-12)^2} \\\\D=\sqrt{(-5)^2+(-13)^2} \\\\D = \sqrt{23+169} \\\\D=\sqrt{194} \\\\|AB|\approx 13.9 \ units\\\\\rule[225]{225}{2}[/tex]

Answer:

28

Step-by-step explanation:

2 30 mg pills for 60 mg

Twice a day is 4 pills and 7 days a week

So 4x7=28

Predicates are used to express statements, properties, or relationships between entities in a formal and systematic way, allowing for logical reasoning and analysis. They are an essential component of predicate calculus, which is a branch of mathematical logic.

In logic and linguistics, a predicate is a term used to describe or assert something about a subject. It is a fundamental concept in predicate logic, which is a formal system for reasoning about statements and their relationships.

In a logical statement, a predicate is typically a function or a relation that takes one or more arguments and returns a truth value (either true or false) when those arguments are substituted into it. The arguments of a predicate are usually referred to as its subjects.

For example, in the statement "Socrates is mortal," the predicate is "is mortal," which asserts the property of being mortal about the subject "Socrates." In this case, the predicate is a unary relation since it takes only one argument.

Predicates can also take multiple arguments. For instance, in the statement "John loves Mary," the predicate is "loves," which relates the subject "John" to the object "Mary." In this case, the predicate is a binary relation.

In general, predicates are used to express statements, properties, or relationships between entities in a formal and systematic way, allowing for logical reasoning and analysis. They are an essential component of predicate calculus, which is a branch of mathematical logic.

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The Mujib spent 60% of his money, while Prakash spent 20% of his money.The Mujib spent 60% of his money ($24 out of $40), and Prakash spent 20% of his money ($24 out of $120). Understanding percentages is an important skill, as it allows us to analyze and compare data in a meaningful way.

To work out the percentage of money each person has spent, we first need to determine the amount spent by each person. Both Mujib and Prakash spent $24 each. Now, let's calculate the percentage of money spent by each person.

Mujib had $40 initially and spent $24, so his total spending is $24. To find the percentage, we divide his spending by his initial amount and multiply by 100: ($24 / $40) * 100 = 60%. Therefore, Mujib spent 60% of his money.

Prakash had $120 initially and also spent $24, resulting in a total spending of $24. Similarly, we calculate the percentage of Prakash's spending by dividing his spending by his initial amount and multiplying by 100: ($24 / $120) * 100 = 20%. Hence, Prakash spent 20% of his money.

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Answer:

Step-by-step explanation:

To find out how many cuboids of dimension 5 cm x 5 cm x 3 cm are needed to form a cube, we need to calculate the volume of both the cuboid and the cube.

The volume of the cuboid is:

5 cm x 5 cm x 3 cm = 75 cubic cm

To form a perfect cube, the volume of the cube should be a multiple of the volume of the cuboid. The smallest cube that can be formed using a multiple of 75 cubic cm is a cube with a volume of 75 x 8 = 600 cubic cm.

To find the dimensions of this cube, we need to find the cube root of 600 cubic cm:

cube root of 600 = 8.66 cm

So, the dimensions of the cube are 8.66 cm x 8.66 cm x 8.66 cm.

To find how many cuboids are needed to form this cube, we need to divide the volume of the cube by the volume of the cuboid:

Volume of the cube = 8.66 cm x 8.66 cm x 8.66 cm = 658.39 cubic cm

Number of cuboids required = 658.39 cubic cm ÷ 75 cubic cm = 8.78

Since we can't use a fraction of a cuboid, Anuj will need 9 such cuboids to make a perfect cube.

The correct answer is: favorable outcomes divided by possible outcomes. The theoretical probability is a mathematical concept that represents the likelihood of an event occurring based on the ratio of favorable outcomes to the total number of possible outcomes.

The correct answer is: 1/5. Since there are five equally-sized pie shapes on the spinner, and only one of them is blue, the probability of landing on blue when you spin is 1 out of 5 or 1/5.

To predict how many out of 10,000 coffee drinkers will like the new coffee, we can use the concept of proportion. Since we know that 450 out of 1,000 coffee drinkers like the new coffee, we can set up the proportion:

450/1,000 = x/10,000

Cross-multiplying, we get:

1,000x = 450 * 10,000

Simplifying further:

1,000x = 4,500,000

Dividing both sides by 1,000:

x = 4,500

Therefore, out of 10,000 coffee drinkers, we can predict that approximately 4,500 will like the new coffee.

To determine the amount of binding Erin needs to cover the outside edges of the kite, we need to add up the lengths of all the sides of the kite.

Looking at the pattern, we can see that there are two sides with a length of 13 inches each, and two sides with a length of 15 inches each.

Therefore, the total length of the binding needed is:

13 inches + 13 inches + 15 inches + 15 inches = 56 inches.

Based on this calculation, Erin needs approximately 56 inches of binding to cover the outside edges of the kite.

Among the options given, the closest measurement to 56 inches is 52 inches.

Answer:

Step-by-step explanation:

[tex]n^{5}= 1254\\n^{5} = 2.3.11.19[/tex]

Therefore it is not possible that n is a perfect power of 5

           it is approximately 4.16

Answer:

n ≈ 4.165

Step-by-step explanation:

To solve this, you need to take the 5th root of both sides:

[tex]n^5=1,254[/tex]

[tex]\sf{\sqrt[5]{n^5} =\sqrt[5]{1254}}[/tex]

On the lhs we're only left with n as n^5 and the 5th root cancel each other out.

On the right-hand side we need to calculate:

[tex]n\approx4.165[/tex]

Step-by-step explanation:

to find f(5)   in f(x) , just put in '5' where 'x' is in the equation

f(5) = 3 (5) + 2 = 17

Answer:

f(5) = 17

Step-by-step explanation:

Let's evaluate the function for f(5)

Insert 5 everywhere x appears:

Therefore f(5) = 17

Answer:

R5096÷98people

=R52 each

There is no specific minimum amount he needs to earn on the last day to meet the goal because it has already been achieved.

We have,

To find the minimum amount Gil must earn on the last day of the week to meet his weekly goal,

We need to calculate the total earnings for the first 6 days and subtract it from the target weekly goal of $500.

Given the daily earnings for the first 6 days:

425, 515, 475, 620, 525, 415

We can calculate the total earnings:

Total earnings = 425 + 515 + 475 + 620 + 525 + 415 = 2975

Now, we subtract the total earnings from the weekly goal:

Minimum amount needed on the last day.

= 500 - 2975

= -2475

Since the calculated value is negative (-2475), it implies that Gil has already exceeded his weekly goal based on the earnings from the first 6 days.

Therefore,

There is no specific minimum amount he needs to earn on the last day to meet the goal because it has already been achieved.

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In the given triangle, we have a right triangle where one angle is 90 degrees (marked as a square symbol). To find the value of x, we can use the trigonometric ratios sine, cosine, or tangent.

Looking at the triangle, we can see that the side adjacent to the angle x is 8 cm, and the hypotenuse of the triangle is 10 cm.

Using the cosine ratio, which is defined as the adjacent side divided by the hypotenuse, we can set up the equation:

cos(x) = adjacent/hypotenuse

cos(x) = 8/10

To find the value of x, we can take the inverse cosine (arccos) of both sides:

x = arccos(8/10)

Using a calculator, we can determine the approximate value of x:

x ≈ 36.87 degrees

Therefore, the value of x in the given triangle is approximately 36.87 degrees.

Answer:

0

Step-by-step explanation:

If x ≥ 4, then the equation simplifies to x+4 = x-4, which gives 8=0, which is not true. Therefore, there are no solutions in this case.

If x < -4, then the equation becomes -(x+4) = -(x-4), which simplifies to -x-4 = -x+4. Simplifying further gives -8 = 0, which is not true. Therefore, there are no solutions in this case either.

If -4 ≤ x < 4, then the equation becomes x+4 = -(x-4), which simplifies to 2x = 0. Therefore, x = 0 is a solution.

If we plug x = 0 back into the original equation, we can see that it works:

|0+4| = |0-4|,

which simplifies to 4 = 4.

Therefore, the solution to the equation |x+4|=|x-4| is x = 0.

Answer:

x = 0

Step-by-step explanation:

Because |-4| = |4| = 4, then the only way x+4 can be -4 is if x=0, and the only way x-4 can be -4 is if x=0 as well. x can't be 4 for instance because then we have |8|≠|0|.

The number of fossils after 10 years is equal to 2333.59 fossils.

In order to determine the number of fossils on this barren land after 10 years, we would have to solve the given differential equation [tex]\frac{dN}{dt} =\frac{5000}{6\;+\;5t}[/tex] by applying an integration in order to create an equation that models N(t) with respect to the number of years or time (t) as follows.

First of all, we would rewrite the equation as follows;

[tex]dN =\frac{5000}{6\;+\;5t}dt[/tex]

By integrating both sides of the equation with respect to t, we have the following:

[tex]\int dN =\int \frac{5000}{6\;+\;5t}dt\\\\N=\frac{5000}{5} ln|6+5t|+C\\\\N=1000 ln|6+5t|+C[/tex]

Since the initial number of fossils (N) is equal to 100 when time (t) = 0, we would substitute the parameters into the equation as follows;

N = 1000ln(6 + 5t) + C

100 = 1000ln(6 + 5(0)) + C

C = 100 - 1000ln6

Next, we would rewrite the equation for the number of fossils (N) in terms of time (t) as follows;

N = 1000ln(6 + 5t) + 100 - 1000ln6

By simplifying the equation using the quotient log rule, we have:

N = 1000ln(6 + 5t) - 1000ln6 + 100

N = 1000ln[(6 + 5t)/6] + 100

Therefore, the number of fossils (N) after 10 years can be calculated as follows;

N = 1000ln[(6 + 5(10))/6] + 100

N = 1000ln[(6 + 50)/6] + 100

N = 1000ln(56/6) + 100

N = 2333.59 fossils.

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a) Population: All students who attended the college last year.

b) Population: All students who graduated from the college last year.

c) Data: 3.65, 2.80, 1.50, 3.90.

d) Sample: Group of students randomly selected from the population.

e) Variable: Cumulative GPA.

f) Sample: All students who graduated.

g) Sample: Students in the study who graduated from the college last year.

a) Population: All students who attended the college last year

Statistic: Not applicable (no specific data)

Parameter: Not applicable (no specific data)

Variable: Cumulative GPA

Data: Not applicable (no specific data)

Sample: Not applicable (no specific data)

b) Population: All students who graduated from the college last year

Statistic: Cumulative GPA of one student

Parameter: Not applicable (one student's GPA)

Variable: Cumulative GPA

Data: GPA of the specific student

Sample: Not applicable (one student)

c) Population: Not applicable (no specific population mentioned)

Statistic: Not applicable (no sample data)

Parameter: Not applicable (no population parameter)

Variable: Cumulative GPA

Data: 3.65, 2.80, 1.50, 3.90

Sample: Not applicable (no specific sample mentioned).

d) Population: All students who graduated from the college last year

Statistic: Not applicable (no specific data)

Parameter: Not applicable (no specific data)

Variable: Cumulative GPA

Data: Not applicable (no specific data)

Sample: Group of students randomly selected from the population

e) Population: All students who graduated from the college last year

Statistic: Average cumulative GPA of students

Parameter: Not applicable (no specific data)

Variable: Cumulative GPA

Data: Cumulative GPAs of students who graduated

Sample: Not applicable (no specific sample mentioned)

f) Population: All students who graduated from the college last year

Statistic: Not applicable (no specific data)

Parameter: Not applicable (no specific data)

Variable: Cumulative GPA

Data: Not applicable (no specific data)

Sample: All students who graduated

g) Population: Students in the study who graduated from the college last year

Statistic: Average cumulative GPA of students in the study

Parameter: Not applicable (no specific data)

Variable: Cumulative GPA

Data: Cumulative GPAs of students in the study

Sample: Students in the study who graduated

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Answer:

(i) x ≤ 1

(ii) ℝ except 0, -1

(iii) x > -1

(iv) ℝ except π/2 + nπ, n ∈ ℤ

Step-by-step explanation:

(i) The number inside a square root must be positive or zero to give the expression a real value. Therefore, to solve for the domain of the function, we can set the value inside the square root greater or equal to 0, then solve for x:

[tex]1-x \ge 0[/tex]

[tex]1 \ge x[/tex]

[tex]\boxed{x \le 1}[/tex]

(ii) The denominator of a fraction cannot be zero, or else the fraction is undefined. Therefore, we can solve for the values of x that are NOT in the domain of the function by setting the expression in the denominator to 0, then solving for x.

[tex]0 = x^2+x[/tex]

[tex]0 = x(x + 1)[/tex]

[tex]x = 0[/tex]     OR     [tex]x = -1[/tex]

So, the domain of the function is:

[tex]R \text{ except } 0, -1[/tex]

(ℝ stands for "all real numbers")

(iii) We know that the value inside a logarithmic function must be positive, or else the expression is undefined. So, we can set the value inside the log greater than 0 and solve for x:

[tex]x+ 1 > 0[/tex]

[tex]\boxed{x > -1}[/tex]

(iv) The domain of the trigonometric function tangent is all real numbers, except multiples of π/2, when the denominator of the value it outputs is zero.

[tex]\boxed{R \text{ except } \frac{\pi}2 + n\pi} \ \text{where} \ \text{n} \in Z[/tex]

(ℤ stands for "all integers")

Answer:

(i)  x ≤ 1

(ii)  All real numbers except x = 0 and x = -1.

(iii)  x > -1

(iv)  All real numbers except x = π/2 + πn, where n is an integer.

Step-by-step explanation:

The domain of a function is the set of all possible input values (x-values).

[tex]\hrulefill[/tex]

[tex]\textsf{(i)} \quad f(x)=\sqrt{1-x}[/tex]

For a square root function, the expression inside the square root must be non-negative. Therefore, for function f(x), 1 - x ≥ 0.

Solve the inequality:

[tex]\begin{aligned}1 - x &\geq 0\\\\1 - x -1 &\geq 0-1\\\\-x &\geq -1\\\\\dfrac{-x}{-1} &\geq \dfrac{-1}{-1}\\\\x &\leq 1\end{aligned}[/tex]

(Note that when we divide or multiply both sides of an inequality by a negative number, we must reverse the inequality sign).

Hence, the domain of f(x) is all real numbers less than or equal to -1.

[tex]\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x \leq 1\\\textsf{Interval notation:} \quad &(-\infty, 1]\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \leq 1 \right\} \end{aligned}}[/tex]

[tex]\hrulefill[/tex]

[tex]\textsf{(ii)} \quad g(x) = \dfrac{1}{x^2 + x}[/tex]

To find the domain of g(x), we need to identify any values of x that would make the denominator equal to zero, since division by zero is undefined.

Set the denominator to zero and solve for x:

[tex]\begin{aligned}x^2 + x &= 0\\x(x + 1) &= 0\\\\\implies x &= 0\\\implies x &= -1\end{aligned}[/tex]

Therefore, the domain of g(x) is all real numbers except x = 0 and x = -1.

[tex]\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x < -1 \;\;\textsf{or}\;\; -1 < x < 0 \;\;\textsf{or}\;\; x > 0\\\textsf{Interval notation:} \quad &(-\infty, -1) \cup (-1, 0) \cup (0, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq 0,x \neq -1 \right\} \end{aligned}}[/tex]

[tex]\hrulefill[/tex]

[tex]\textsf{(iii)}\quad h(x) = \log_7(x + 1)[/tex]

For a logarithmic function, the argument (the expression inside the logarithm), must be greater than zero.

Therefore, for function h(x), x + 1 > 0.

Solve the inequality:

[tex]\begin{aligned}x + 1 & > 0\\x+1-1& > 0-1\\x & > -1\end{aligned}[/tex]

Therefore, the domain of h(x) is all real numbers greater than -1.

[tex]\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &x > -1\\\textsf{Interval notation:} \quad &(-1, \infty)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x > -1\right\} \end{aligned}}[/tex]

[tex]\hrulefill[/tex]

[tex]\textsf{(iv)} \quad k(x) = \tan x[/tex]

The tangent function can also be expressed as the ratio of the sine and cosine functions:

[tex]\tan x = \dfrac{\sin x}{\cos x}[/tex]

Therefore, the tangent function is defined for all real numbers except the values where the cosine of the function is zero, since division by zero is undefined.

From inspection of the unit circle, cos(x) = 0 when x = π/2 and x = 3π/2.

The tangent function is periodic with a period of π. This means that the graph of the tangent function repeats itself at intervals of π units along the x-axis.

Therefore, if we combine the period and the undefined points, the domain of k(x) is all real numbers except x = π/2 + πn, where n is an integer.

[tex]\boxed{\begin{aligned} \textsf{Inequality notation:} \quad &\pi n\le \:x < \dfrac{\pi }{2}+\pi n\quad \textsf{or}\quad \dfrac{\pi }{2}+\pi n < x < \pi +\pi n\\\textsf{Interval notation:} \quad &\left[\pi n ,\dfrac{\pi }{2}+\pi n\right) \cup \left(\dfrac{\pi }{2}+\pi n,\pi +\pi n\right)\\\textsf{Set-builder notation:} \quad &\left\{x \in \mathbb{R}\left|\: x \neq \dfrac{\pi}{2}+\pi n\;\; (n \in\mathbb{Z}) \right\}\\\textsf{(where $n$ is an integer)}\end{aligned}}[/tex]

Answer:

number is 2

Step-by-step explanation:

let the number be n then 8 times the number is 8n, subtract 1 from this and

8n - 1 = 15 ( add 1 to both sides )

8n = 16 ( divide both sides by 8 )

n = 2

that is the number is 2

(a). Rounded to three significant figures, the length of the side of the cube is 30.0 cm.

(b). Rounded to three significant figures, the height of the trapezoidal prism is 2.75 cm.

Let's solve this problem step by step:

First, let's calculate the volume of the fish tank when it is filled with water to two-thirds of its height.

The base dimensions of the fish tank are 72 cm by 48 cm, and the height is 52 cm.

Filling it with water to two-thirds of the height means the water level is at 2/3 × 52 = 34.67 cm.

The volume of a rectangular prism (the fish tank) is given by V = length × width × height.

Plugging in the values, we have V = 72 cm × 48 cm × 34.67 cm

≈ 112,430.08 cm³.

Now, let's calculate the volume of the cube.

The cube is placed in the fish tank the water level rises to three-quarters of the height is 3/4 × 52 = 39 cm.

The volume of the water that spilled can be calculated by subtracting the volume of the fish tank before the cube was placed from the volume of the fish tank after the cube was placed.

The volume of the cube is 112,430.08 cm³ - 39 cm × 72 cm × 48 cm = 28,861.92 cm³.

Since the volume of a cube is given by V = side³, we can solve for the length of the side of the cube.

Thus, side³ = 28,861.92 cm³ and by taking the cubic root of both sides, we find side ≈ 30.042 cm.

Now, let's calculate the height of the trapezoidal prism.

We know that the volume of water spilled when the trapezoidal prism is placed is 500 cm³.

Since the volume of a trapezoidal prism is given by V = (1/2) * (a + b) * h * base a and b are the lengths of the parallel sides of the trapezoid, h is the height of the trapezoid, and base is the distance between the parallel sides, we can rearrange the formula to solve for the height:

h = (2 × V) / ((a + b) × base).

The cross-sectional area of the trapezoidal prism is 928 cm², we can find the base.

Since the area of a trapezoid is given by A = (1/2) × (a + b) × h, we can rearrange the formula to solve for the base:

base = (2 × A) / (a + b).

Plugging in the values, we have base = (2 × 928 cm²) / (72 cm + 48 cm)

≈ 9.28 cm.

Now we can calculate the height of the trapezoidal prism:

h = (2 × 500 cm³) / ((72 cm + 48 cm) × 9.28 cm)

≈ 2.754 cm.

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Answer:

To solve this problem, we can use the formula distance = rate x time.

For the first part of the trip on the highway, Jennifer travels at an average rate of 54 1/2 miles per hour for 3 hours, so the distance she covers is:

distance = rate x time

distance = (54 1/2) x 3

distance = (109/2) x 3

distance = 327/2

distance = 163.5 miles

For the second part of the trip on the smaller route, Jennifer travels at an average rate of 34.25 miles per hour for 3 hours, so the distance she covers is:

distance = rate x time

distance = 34.25 x 3

distance = 102.75 miles

The total distance Jennifer has driven after 6 hours is the sum of the distances she covered on both parts of the trip:

total distance = 163.5 + 102.75

total distance = 266.25 miles

Therefore, the answer is (A) 266.25 miles.

In the given diagram, we have two parallel lines intersected by a transversal. To determine the relationship between the angles and solve for x, we can use the properties of angles formed by parallel lines and a transversal.

From the diagram, we can observe the following angle relationships:

Angle A is corresponding to the angle (4x - 3)°.

Therefore, we can write: A = (4x - 3)°.

Angle B is alternate interior to the angle (7x + 9)°.

Therefore, we can write: B = (7x + 9)°.

Angle C is alternate interior to the angle 2x°.

Therefore, we can write: C = 2x°.

Since the sum of angles in a straight line is 180°, we can set up the equation:

A + B + C = 180°

Substituting the known values, we get:

(4x - 3)° + (7x + 9)° + 2x° = 180°

Simplifying the equation, we can solve for x:

4x - 3 + 7x + 9 + 2x = 180

13x + 6 = 180

13x = 174

x = 13.38

Therefore, the value of x is approximately 13.38.

Please note that this solution assumes the given diagram accurately represents the angle relationships.

The Separation Schema is a rule in set theory that allows us to construct a new set from an existing set based on a given property.

For example, if a set of all natural numbers, use the Separation Schema to construct a new set of all even natural numbers. The new set will contain all of the elements of the original set that satisfy the given property, in this case, the property of being even.

The property x ∉ x states that x is not a member of x. If we apply the Separation Schema to this property, we will construct a new set that contains all of the sets that are not members of themselves. This set is called the Russell set, and it is known to be paradoxical.

The Russell paradox shows that the unrestricted Comprehension Schema is inconsistent. This is because the Russell set is a set that can be constructed using the Comprehension Schema, but the Russell set also satisfies the property that it is not a member of itself. This is a contradiction, and it shows that the Comprehension Schema cannot be used to construct all sets.

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Solution of the given expression is,

 x = 6/5 or x = -4

Given that,

|2x+5| + |3x+1| = 10

Add -|3x-1| both sides,

⇒ |2x+5| + |3x+1| - |3x+1| = 10 -  |3x+1|

⇒                          |2x+5| = 10 -  |3x+1|

Either 2x+5 = -  |3x+1| + 10 or 2x + 5 = -(-|3x-1| + 10)

Proceed:

2x+5 = -  |3x+1| + 10

⇒ -|3x-1| + 10 = 2x + 5

⇒ -|3x-1| + 10 - 10 = 2x + 5 - 10             [subtract 10 both sides]

⇒                -|3x-1| = 2x - 5

⇒                -|3x-1|/-1 = (2x - 5)/-1           [ divide both sides by -1]

We know either 3x - 1 = -2x + 5 or 3x - 1 = - (-2x+5)

       3x - 1 = -2x + 5

3x - 1 + 2x = -2x + 5 + 2x                        [ adding 2x both sides]

           5x = 6

              x = 6/5

Now,

      3x - 1 = -(-2x+5)

3x - 1 - 2x = 2x - 5 - 2x                           [ subtracting 2x both sides]

             x = -4

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Answer:

24

Step-by-step explanation:

the lengths are in proportion to one another, between triangles.

(x - 4)/12  =  5/(x +7)

(x - 4)(x + 7) = 5 X 12

x² + 7x - 4x - 28 = 60

x² + 3x - 28 = 60

x² + 3x - 88 = 0.

(x + 11) (x - 8) = 0

x = -11, 8.

x cannot be -11 since both x +7 and x - 4 would be negative lengths!!

so x = 8.

AB = 12, DE = x - 4 = 8 -4 = 4. 12/4 = 3.

the lengths of triangle ABC are 3 times longer than the lengths of DEF.

we can confirm this: AC = x + 7 = 8 + 7 = 15. DF = 5

AC is 15/5 = 3 times longer than DF.

so we expect BC to be 3 times longer than x. x = 8.

so BC = 3 X 8 = 24.

The relation that represents a function is: ((- 6, 5), (- 3, 2), (1, 2), (6, 5))

A relation represents a function if each input (x-value) is associated with only one output (y-value).

1. {(0, 3), (2, 4), (0, 6)}:

This relation is not a function because the input 0 is associated with two different outputs, 3 and 6.

2. ((- 7, 5), (- 7, 1), (- 10, 3), (- 4, 3)):

This relation is not a function because the input -7 is associated with two different outputs, 5 and 1.

3. ((- 6, 5), (- 3, 2), (1, 2), (6, 5)):

This relation is a function since each input is associated with a unique output.

4. {(2, 0), (6, 2), (6, - 2)}:

This relation is not a function because the input 6 is associated with two different outputs, 2 and -2.

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The expression x² + 17 represents the sum of x squared and 17.

The sum of x squared and 17 we have to write in expression

x squared is the term x² represents x squared.

It means that the variable x is being multiplied by itself.

If x = 3, then x² would be 3 squared, which is 9.

Similarly, if x = -2, then x² would be (-2) squared, which is 4.

The term + 17 represents the constant value 17 being added to x squared. Regardless of the value of x, 17 will always be added to the result of x squared.

By combining these two terms using the addition operator (+), we express the sum of x squared and 17 as a single mathematical expression, which is x² + 17

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Hello !

2 1/4 ÷ 5/8

= 9/4 ÷ 5/8

= 9/4 x 8/5

= 9x8/4x5

= 72/20

= 18/5

= 3 3/5

Answer:

30

Step-by-step explanation:

y = ( a + b ) ( a - b )

Let a = 6.5 and b = 3.5

y = ( 6.5 + 3.5 ) ( 6.5 - 3.5 )

Simplify the terms in the parentheses.

y = (10)(3)

y= 30

Answer:

Point where the line crosses the y-axis is (0, -8)

Gradient: 3

Step-by-step explanation:

The slope-intercept form of the equation of a straight line is
y = mx + b

where m =slope or gradient

b is the y-intercept ie the y-value where the line crosses the y-axis. This is also the value of y when x = 0

Comparing the general equation with y = 3x - 8

we get the y-intercept as -8 and therefore the point (0, -8) is the point where the line crosses the y-axis

The gradient is 3 which is the coefficient of x

The gradients of the lines AB, XY and PQ are 3S, -3 and 77/3 respectively.

To find the gradient of a line, we need to use the formula: gradient = (change in y)/(change in x).

For the first question, we have two points A (C3,1) and B (C6,10S). The change in y is 10S - 1 = 9S, and the change in x is C6 - C3 = 3. Therefore, the gradient of the line AB is 9S/3 = 3S.

For the second question, we have two points X (5,-1) and Y (3,5). The change in y is 5 - (-1) = 6, and the change in x is 3 - 5 = -2. Therefore, the gradient of the line XY is 6/-2 = -3.

For the third question, we have two points P (C3,-2) and Q (6,75). The change in y is 75 - (-2) = 77, and the change in x is 6 - C3 = 3. Therefore, the gradient of the line PQ is 77/3.

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