Write the equation for the graph of the line
shown.
My answer is y= 2x-1 but I’m not sure if it’s right

Refer to the attachment

Answer:

Coordinates (0, -8/3)

Answer:

2.5

Step-by-step explanation:

The amplitude of a function is the amount by which the graph of the function travels above and below its midline.

The distance from the highest most point to the lowest point vertically is 5, meaning that the midpoint is 2.5 units from either end.

An equation is formed of two equal expressions. The number of rows in the original pattern will be 4.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Let the number of rows be represented by x. Now, the pattern has rows that are 5 tiles wide and an unknown number of rows. if you take these tiles and add one additional tile, you can create a pattern that has rows that are 3 tiles wide, with 3 more total rows than the original pattern. Therefore, we can write,

(Number of Tiles before) + 1 tile = (Number of Tiles afterward)

5x + 1 = 3(x+3)

5x + 1 = 3x + 9

5x - 3x = 9 - 1

2x = 8

x = 4

Hence, the number of rows in the original pattern will be 4.

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Answer:

(-4,-3)

Step-by-step explanation:

Answer:

(-4, -3)

Step-by-step explanation:

well, the only points possible are 3 points, a first, 2nd, and 3rd point. And the 2nd point is the mid-point.

The answer is A , for determining range look at Y-axis only from down to up .For this question we can also say

range: [1,7] , if both ends of the line are arrows it means the line goes from negative infinity to positive infinity (which means range is all real numbers) , but if the point is include just like this graph the points will be also include in range , but if the points are an empty circle the points won't be include for writing range

hope it helps

please give brainliest

The area of the target which earns 30 points on a throw.

[tex]\huge\boxed{Formula: a= \pi{r}^{2}}[/tex]

[tex]4+3[/tex]

[tex]=7[/tex]

Let's solve

We have to find the answer in terms of π so, we'll just have to multiply the radius by itself.

[tex]a={7}^{2}[/tex]

[tex]\large\boxed{a= 49 \pi\: {in}^{2}}[/tex]

Hence, the area of the target which earns 30 points on a throw is 49π square inches.

Answer= Option B

Answer:

Use given values of h and j, and find the value of k:

The equation is now:

Find the value of g when h is 2 and j is 3:

Correct choice is D

Answer:

D. 144

Step-by-step explanation:

Answer:

Not enough information to determine the area.

Step-by-step explanation:

Step-by-step explanation:

length = 2×width + 6

84 = 2×length + 2×width

now using the first in the second equation :

84 = 2×(2×width + 6) + 2×width = 4×width + 12 + 2×width

84 = 6×width + 12

72 = 6×width

width = 12 cm

length = 2×width + 6 = 2×12 + 6 = 24 + 6 = 30 cm

Answer:

Step-by-step explanation:

The profit = 150 000 - 120 000 = 30 000

………………………………………………………

The profit percentage is :

[tex]=\frac{30000}{120000} \times 100=0.25 \times 100 = 25 \%[/tex]

Answer:

Step-by-step explanation:

The inverse of the graph is (b)

To determine the inverse of the graph, we have to swap the x and the y axes.

This means that we plot the y coordinates on the x coordinates and vice versa.

The interpretation of this on the given curve is that:

The vertical curve becomes an horizontal curve (as seen in graph b)

Hence, the inverse of the graph is (b)

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Answer:

21 rounds

Step-by-step explanation:

[tex]1[/tex] [tex]round = 0.4km[/tex]

[tex]Total[/tex] [tex]distance = 8.4km[/tex]

[tex]8.4/0.4[/tex]

[tex]=21[/tex]

The number of rounds he makes, if he runs a total of 8.4 km distance.

[tex]\large\boxed{R=\frac{Total \: distance}{Distance \: covered \: in \: 1 \: round}}[/tex]

So, we'll have to divide the total distance covered by distance covered in 1 round.

Let's substitute according to the formula.

[tex]R= \frac{8.4}{0.4}[/tex]

= 21 rounds

Hence, the number of rounds he makes, if he runs a total of 8.4 km distance is 21

The car will be worth after one year is £ 5753.6.

An exponential function is defined by the formula f(x) = [tex]a^{x}[/tex], where the input variable x occurs as an exponent. The exponential curve depends on the exponential function and it depends on the value of the x.

The exponential function is an important mathematical function which is of the form

f(x) =  [tex]a^{x}[/tex]

Where a > 0 and a is not equal to 1.

x is any real number.

Given

Car cost when bought A =  £ 6200

Value of a car decreases by 7.2% each year.

n = 1

r = 7.2% or 0.072

The car will be worth after one year

[tex]y= A (1-r)^{n}[/tex]

⇒ [tex]y =6200(1-0.072)^{1}[/tex]

⇒ [tex]y = 6200(0.928)[/tex]

⇒ y = £ 5753.6

Hence, the car will be worth after one year is £ 5753.6.

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The transformation of a function may involve any change. The graph of g(x) is the graph of f(x) shifted 4 units to the right.

The transformation of a function may involve any change.

If the original function is y = f(x), assuming the horizontal axis is the input axis and the vertical is for outputs, then:

Horizontal shift (also called phase shift):

Left shift by c units, y=f(x+c) (same output, but c units earlier)

Right shift by c units, y=f(x-c)(same output, but c units late)

Vertical shift

Up by d units: y = f(x) + d

Down by d units: y = f(x) - d

Stretching:

Vertical stretch by a factor k: y = k × f(x)

Horizontal stretch by a factor k: y = f(x/k)

As per the transformation of the function, if the function g(x) = f(x-4), then the graph of g(x) will be 4 units in the right of f(x).

Hence, the graph of g(x) is the graph of f(x) shifted 4 units to the right.

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Yes all your used tiles are correct.

Let's solve the equation too

The value of variable x in the equation 2x+4=3x+(-1) is 5.

Equation is a relationship between two or more variables that are expressed in equal to form. Equation of twwo variable looks like ax+y=c. It cab be linear equation, quadratic equation and cubic equation. linear equation has a straight line curve.

We have been given equation 2x4=3x+(-1) and we have to solve the equation. Our equation has only one variable, so we have to solve for that variable only.

2x+4=3x+(-1)

2x+4=3x-1

5=x

Hence the value of x in the equation 2x+4=x+(-1) is 5.

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Answer:

15 units

Step-by-step explanation:

15.0

Answer:

8

Step-by-step explanation:

The median is the number right in the middle. Eight is in the middle of the number line making it the median.

Answer:

just solve normally as if theres no x,

1. 26x

2. -7x

The area of a regular hexagon with an apothem 18.5 inches long and a side 21 inches is 1, 165. 5 In²

The formula is given thus;

Area of hexagon = (1/2) × a × P

where a = the length of the apothem

P = perimeter of the hexagon

Given a = 18. 5 inches

Note that Perimeter, p = 6a with 'a' as side

p = 6 × 21 = 126 inches

Substitute values into the formula

Area, A = 1 ÷2 × 18. 5 × 126 = 1 ÷2 × 2331 = 1, 165. 5 In²

Thus, the area of the regular hexagon is 1, 165. 5 In²

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Work Shown:

5x-6 = 44

5x-6+6 = 44+6 ... see note 1

5x = 50

5x/5 = 50/5 ... see note 2

x = 10

Answer:

-2, 1 or 3 only

Step-by-step explanation:

just did it

Answer:

-3

Step-by-step explanation:

Given equation:

[tex]\implies (x^4y^{-3})^n=\dfrac{y^9}{x^{12}}[/tex]

[tex]\textsf{Apply exponent rule} \quad \dfrac{1}{a^n}=a^{-n}:[/tex]

[tex]\implies (x^4y^{-3})^n=x^{-12}y^9[/tex]

Rewrite -12 as (4 × -3) and 9 as (-3 × -3):

[tex]\implies (x^4y^{-3})^n=x^{(4 \times -3)}y^{(-3 \times -3)}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{bc}=(a^b)^c[/tex]:

[tex]\implies (x^4y^{-3})^n=(x^4)^{-3}(y^{-3})^{-3}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^c b^c=(ab)^c[/tex]

[tex]\implies (x^4y^{-3})^n=(x^4y^{-3})^{-3}[/tex]

Therefore, the missing value is -3

Answer:

(1.333, 0) and (3, 0)

Step-by-step explanation:

Use desmos to input your equations then click on the solutions (zeroes)

Answer:

This graph does not represent a function.

Step-by-step explanation:

The vertical line test describes how, in order to be a function, there must be only one output for every input. Remember, the input of a function is the "x" value and the output is the "y" value.

Because of the circular nature, this graph does not represent a function. As you can see, there are "x" values which could correspond with mutliple "y" values. For example, when x = 2, there are two "y" values:  y = -1 and y = -5.

Answer:

39 and 65

Step-by-step explanation:

the ratio of the two numbers is 3 : 5

sum the parts of the ratio, 3 + 5 = 8 parts

divide the sum by 8 to find the value of one part of the ratio

104 ÷ 8 = 13 ← value of 1 part of the ratio , then

3 parts = 3 × 13 = 39

5 parts = 5 × 13 = 65

the two numbers are 39 and 65

Using the hypergeometric distribution, it is found that there is a 0.1363 = 13.63% theoretical probability of 5 students from your school being selected as contestants out of 10 possible contestant​ spots.

The formula is:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

The values of the parameters are given as follows:

N = 130, k = 40, n = 10.

The theoretical probability of 5 students from your school being selected is P(X = 5), hence:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 5) = h(5,120,10,40) = \frac{C_{40,5}C_{80,5}}{C_{120,10}} = 0.1363[/tex]

0.1363 = 13.63% theoretical probability of 5 students from your school being selected as contestants out of 10 possible contestant​ spots.

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