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Complete Question

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.

(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.

magnitude            N

direction          

   (b) What maximum force do you need to apply before the refrigerator starts to move?

Answer:

a

   The magnitude  is [tex]F_f = 339.57 \ N[/tex]

    The direction is  [negative x - axis ]

b

   The maximum force to be applied for the refrigerator to start moving is  

      [tex]F_{max} = 339.57 \ N[/tex]

Explanation:

From the question we are told that

   The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is  +ve  x-axis

   The mass of the refrigerator is  [tex]m = 63 \ kg[/tex]

    The coefficient of static friction is  [tex]\mu_s = 0.55[/tex]

Generally the frictional force exerted on the refrigerator is mathematically represented as

            [tex]F_f = \mu * m * g[/tex]

=>         [tex]F_f = 0.55 * 63 * 9.8[/tex]

=>         [tex]F_f = 339.57 \ N[/tex]

From the value obtained we see that the static force  exerted by the floor on the refrigerator  is  greater than the force (280 N ) exerted by the person and the direction is  -ve x-axis

Generally the maximum force that is to be applied by the person is mathematically  equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis  i.e

         [tex]F_{max} = F_f = 339.57 \ N[/tex]

Answer:

^ correct

Explanation:

Option A on edge 2020

Answer:

A

Explanation:

Answer:

C. transverse

Answer:

an object in motion stays in motion an object at rest stays in rest

Explanation:

Answer: here are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

Answer:

15.9k

Explanation:

The two fundamental forces that are only attractive is  A. Gravitational and strong nuclear.

The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.

Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.

Therefore, option A is correct.

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Answer:

v=v(initial)+at

45=0+15a

a= 3m/sec²

Explanation:

edge 2020

Answer:

0.2

Explanation:

3/15

Answer:

Y = 176.4 m

Explanation:

For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:

Y = V₀y*t + (0.5)gt²

where,

Y = Height = ?

V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)

t = time = 6 s

g = 9.8 m/s²

Therefore,

Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²

Y = 176.4 m

Answer:

114N

Explanation:

gravity on earth: 10m/s (exact: 9.82)

mass if chicken = 300/10 = 30Kg

weight of chicken on mercury = 3.8 x 30 = 114N (you wrote 0.38 but Mercury's gravity is about 3.7)

Answer:

113.15 g

Explanation:

That's because the planets weigh different amounts, and therefore the force of gravity is different from planet to planet. For example, if you weigh 100 pounds on Earth, you would weigh only 38 pounds on Mercury. That's because Mercury weighs less than Earth, and therefore its gravity would pull less on your body.

Answer:

C

Explanation:

Answer:

as fuel is combusted,the rocket pushes the gas is backward and the gas is pushed the rocket forward

Explanation:

hope this helps :]

Answer:

D. Sound waves

Explanation:

The following options are missing:

A. radio wave

B. X-rays

C. Light waves

D. Sound waves

There are two kinds of waves: longitudinal and transverse.

In longitudinal waves, the vibrations are parallel to the direction of wave travel. Examples of longitudinal waves include: sound waves  and ultrasound waves.

In transverse waves, the vibrations are at right angles to the direction of wave travel. All electromagnetic waves (e.g. light waves, microwaves, radio waves and X-rays) are transverse waves.

Answer:

The acceleration of the horse during this time interval is 24.286 m/min²

Explanation:

Given;

initial velocity of the horse during the gallop, u = 543 m /min

final velocity of the horse during the gallop, v = 628 m /min

time of motion, t = 3.5 minutes

The acceleration of the horse is given by the change in velocity per change in time;

[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]

Therefore, the acceleration of the horse during this time interval is 24.286 m/min²

Answer:

asd

Explanation:

Answer: the heat from the environment melts the ice cream. When it’s in the freezer it doesn’t melt because both the freezer and ice cream are the same temperature

Explanation:

Answer:

the freezer and the ice cream is at the same temp while your hand and the cone is warmer so he heat from the cone transfers to the ice cream and heat it up and its particles move faster as it changes from a solid to a liquid.

You can add an easy question and give me some points if you would like!

Answer:

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo ([tex]\Delta W[/tex]), medido en joules, que reducida a:

[tex]\Delta W = m\cdot g\cdot \Delta z[/tex] (1)

Donde:

[tex]m[/tex] - Masa del montañero, medido en kilogramos.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.

[tex]\Delta z[/tex] - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que [tex]m = 65\,kg[/tex], [tex]g = 9,807\,\frac{m}{s^{2}}[/tex] y [tex]\Delta z = 500\,m[/tex], entonces el trabajo realizado por el montañero para subir es:

[tex]\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)[/tex]

[tex]\Delta W = 318727,5\,J[/tex]

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

Answer:

The Science of Round Bubbles

But once a bubble is sealed and removed from the wand, the tension in the bubble shrinks it to the smallest possible shape for the volume of air inside of it. That's a sphere, which is the familiar round shape we see when bubbles float through the air.

Explanation:

Answer:

first page answer is B

second page answer is D

Explanation:

Answer:

0.25m/s

Explanation:

Given parameters

m₁  = 5kg

v₁ = 1.0m/s

m₂ = 15kg

v₂ = 0m/s

Unknown:

velocity after collision = ?

Solution:

Momentum before collision and after collision will be the same. For inelastic collision;

    m₁v₁ + m₂v₂  = v(m₁ + m₂)

Insert parameters and solve for v;

   5 x 1  + 15 x 0 = v (5 + 15 )

          5  = 20v

          v = [tex]\frac{5}{20}[/tex]   = 0.25m/s

Answer:

distance is how much space is between, speed is how fast they are going, velocity is money and acceleration is going

Explanation:

Answer:

I thick it's ccc not for sure

Answer:

The spiral staircase will require more work

Explanation:

This is because, work can be calculated as force (which is mass of the individual climbing the stairs in this case) multiplied by distance (or length) of the stairs. The only variable that changes in the work done while climbing any of the two (ladder or spiral staircase) is the distance and it is obvious the length of the spiral staircase will be longer; thus the spiral staircase will involve more work.

Answer:

bus , running boy etc

Explanation:

moving body is called motion .

e.g. running boy , bus, birds flying etc

Answer:

The objects meet after 2.033722438s, at a height 136.5334679m from the ground.

Explanation:

Call the object being dropped A and the object being thrown B.

When the objects meet, the time ('t') for both objects will be equal, and the sum of their distances will be equal to 156.8m.

Figure out the distance for A in terms of time, t:

s = ut + (1/2)at²

= 0t +(1/2)(9.8)t²

=4.9t²

Figure out the distance for B in terms of time, t:

s = ut + (1/2)at²

=(77.1)t + (1/2)(-9.8)t²

=77.1t - 4.9t²

We now adding the distances gives us 156.8, so can write:

(4.9t²) + (77.1t - 4.9t²) = 156.8

77.1t = 156.8

∴ t = 2.033722438s

To find the distances, plug in this value for t:

For A: 4.9t² → 20.26653209m

For B: 77.1t - 4.9t² → 136.5334679m

The objects will meet 155.2 meters below the top of the tower after 15.7 seconds.

The formula to calculate the time it takes for the object thrown upwards to return to the ground:

Time = 2 * Initial velocity / gravitational acceleration

Plugging in the values given in the question, you can calculate the time as follows:

Time = 2 * 77.1 m/s / 9.8 m/s^2 = 15.7 seconds

To determine when and where the objects meet, you can use the following formula to calculate the height of the object thrown upwards at any given time:

[tex]Height = Initial velocity * time - (1/2) * gravitational acceleration * time^2[/tex]

Plugging in the time calculated above and the initial velocity and gravitational acceleration given in the question, you can calculate the height of the object at the time it returns to the ground as follows:

Height = 77.1 m/s * 15.7 s - (1/2) * 9.8 m/s^2 * (15.7 s)^2 = -1.6 meters

This means that the object thrown upwards returns to the ground 1.6 meters below the point where it was launched. The object dropped from the top of the tower will also have fallen a distance of 156.8 meters in the same amount of time, so the two objects will meet at a point 156.8 meters - 1.6 meters = 155.2 meters below the top of the tower

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