Answer:
a = -3984.6 m/s²
F = 577.76 N
Explanation:
The acceleration of the ball can be calculated by using the third equation of motion:
[tex]2as = v_f^2 - v_i^2\\[/tex]
where,
a = acceleration of ball = ?
s = distance covered = recoil distance = 0.135 m
vf = final speed = 0 m/s
vi = initial speed = 38.2 m/s
Therefore,
[tex]2(0.135\ m)a = (0\ m/s)^2-(38.2\ m/s)^2\\[/tex]
a = -3984.6 m/s²
here negative sign shows deceleration.
Now, for the force applied by Brian Lara will be equal in magnitude but opposite in direction of the force required to stop the ball:
[tex]F = -ma\\F = -(0.145\ kg)(-3984.6\ m/s^2)\\[/tex]
F = 577.76 N
Help please & actually answer thank youu :)
Answer:
highest KE and lowest GPE = Dhighest GPE and lowest KE = Asome KE and some PE = BYou serve a basketball with a mass of 5 kg. If the ball leaves your hand at 30 m/s what is
the kinetic energy?
A) 150 joules
B) 2,250 joules
C) 75 joules
Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) respectively. Determine the position of the center of mass of this system?
Answer:
(1.9756, -2.1951)
Explanation:
The center of mass equation is: [tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex], where m represents the masses and x represents the position.
In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.
x-values:
[tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}[/tex] = [tex]\frac{81}{41}[/tex] = 1.9756
y-values:
[tex]y_{cm}[/tex] = [tex]\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}[/tex] = [tex]\frac{-90}{41}[/tex] = -2.1951
center of mass:
(1.9756, -2.1951)
Which of the following has no energy?"
Amoving ball
Awrecking ball
Non of the above
32. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.500 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity
Answer:
636.6 W/m²
Explanation:
From the given information:
The area of the circular spot can be calculated as:
A = πr²
A = π(0.5 × 10⁻³ m)²
A = 7.85 × 10⁻⁷ m²
The intensity can be determined by using the formula:
[tex]I = \dfrac{P}{A}[/tex]
[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]
[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]
I = 636.6 W/m²
A train has a mass of 100000 kilograms.if its kinetic energy is 3mj what velocity is it travelling at
Answer:
V = 7.75 meters per seconds.
Explanation:
Given the following data;
Mass = 100000 Kilograms
Kinetic energy = 3 Megajoules = 3 * 10⁶ Joules
To find the velocity of the train;
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;
[tex] K.E = \frac{1}{2}MV^{2}[/tex]
Where;
K.E represents kinetic energy measured in Joules.
M represents mass measured in kilograms.
V represents velocity measured in metres per seconds square.
Substituting into the formula, we have;
[tex] 3000000 = \frac{1}{2}*100000*V^{2}[/tex]
Cross-multiplying, we have;
[tex] 6000000 = 100000V^{2}[/tex]
[tex] V^{2} = \frac{6000000}{100000} [/tex]
[tex] V^{2} = 60 [/tex]
Taking the square root of both sides, we have;
[tex] V = \sqrt {60} [/tex]
V = 7.75 m/s
place the compass at one pole of the bar magnet click flip polarity in the menu what happens to the bar magnet and the compass needle
Answer:
The two poles of the bar magnet change positions. The compass needle spins a half circle.
Explanation:
Answer:
The two poles of the bar magnet change positions. The compass needle spins a half circle.
Explanation:
edmentum answer
Kinetic energy is the energy of motion and increases with the speed of the wave.
a. True
b. False
Potential energy is the energy of gravitational pull on the wave.
a. True
b. False
Half Time At 3:00 the hour hand and the minute hand of a clock point in directions that are 90.0
apart. What is the first time after 3:00 that the angle between the two hands has decreased by half to 45.0?
The first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
Angular velocity of the hour hand
The angular velocity of the hour hand for 12 hours time is calculated as follows;
[tex]\omega_h = \frac{2\pi}{12(3600 \ s)}[/tex]
Angular velocity of the minute handThe angular velocity of the minute hand for 12 hours time is calculated as follows;
[tex]\omega _m = \frac{2\pi}{3600}[/tex]
Difference in the angular velocity[tex]\Delta \omega = \frac{2\pi }{3600} - \frac{2\pi }{12(3600)} = \frac{11(2\pi)}{12(3600)} = \frac{22\pi}{12 (3600)}[/tex]
First angle between the two hands in radians[tex]45^0 = \frac{45}{180} \pi= \frac{\pi}{4}[/tex]
Time after 3:00The time after 3:00 is calculated as follows;
[tex]t =( \frac{\pi}{4}) /\frac{22\pi}{12(3600)} \\\\t = \frac{\pi }{4} \times \frac{12(3600)}{22\pi} \\\\t = 490.91 \ s\\\\t = 8 \min, \ 10.91 \ s[/tex]
[tex]t \approx 8\min, 11 \ s[/tex]
Thus, the first time after 3:00 that the angle between the two hands has decreased by half to 45.0 is 3:08:11.
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convert 1 day into seconds.(you will need to show your work to receive credit.) please help thank you
Answer:
the answer is 86400seconds.
Explanation:
1day= 24 hours
24hours to seconds =
24×60×60= 86400 seconds.
( 60 second = 1 minutes)
( 60 minutes = 1 hour)
a
Ten 2.2 v cells each having an internal
resistance of o.1ohms in are connected in series
to a load of 21ohm. Determine
pd at the battery terminals
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
40 POINTS!!! PLEASE HELPP!!!
Please select the word from the list that best fits the definition
One form of energy changes to one other form
(A.) single transformation
(B.) multiple transformation
Answer:
A
Explanation:
if it was B it would say from one to another to another
How do our attitudes help us organize our reality?
Answer:
If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.
Explanation:
Hope this helps!
When an object vibrates it goes back and forth rapidly. How would you
describe this motion?
A: it goes below its starting point and back to its starting point
B: it goes passed its starting point in both directions
C: it will go back and fourth forever
D: it actually looks like spikey waves
Answer:
B) It appears to be SHM (simple harmonic motion) which is also the projection of an object moving in a circular path on either the x or y axes.
Which of the following best describes
pollutants?
A. harmful substances in the air, water, or soil
B. radioactive particles that pass through the atmosphere
C. oxygen molecules that are released by plants
D. beneficial substances that increase overall health
Answer:
A. harmful substances in the air, water, or soil
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If a wave has a frequency of 5 hertz, the period for one wave cycle will be
Answer:
0.2 seconds
Explanation:
f=1/t
1/5=0.2
What is the angle of refraction for a beam of light moving from a prism to air if the angle of incidence is 30° and the prism’s index of refraction is 1.6?
Answer:
Refraction involves passing through a boundary (choice a) and changing speed (choice ... A ray of light in air is incident on an air-to-glass boundary at an angle of 30. ... If the index of refraction of the glass is 1.65, what is the angle of the refracted ray ... The critical angle is the angle of incidence (which is always in the more ...
Explanation:
What should stainless steel be considered when using it?
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1 E
e. 1 to 1
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is 5 to 1 C.
We have that for the Question, it can be said that the ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
Option B
From the question we are told
An empty container is filled with helium to a pressure P at a temperature T. Neon, which has atoms that are 5 times more massive than those of helium, is then added to the container until the new pressure in the container is 2P at the same temperature T. The ratio of the average speed of the helium atoms to the average speed of the neon atoms is:_________
a. 25 to 1
b. 5 to 1
c. 5to 1
d. 2to 1
e. 1 to 1
Generally the equation for the average speed of Molecules is
mathematically given as
[tex]For Helium\\\\C_h=\frac{8P_hV_h}{\pim_h}\\\\Neon gas\\\\C_n=\frac{8P_nV_n}{\pim_n}\\\\Where\\\\Ph=P_n\\\\Vh=Vn\\\\[/tex]
[tex]\frac{C_h}{C_n}=\frac{\frac{8P_hV_h}{\pim_h}}{\frac{8P_nV_n}{\pim_n}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{\frac{1}{5}}{{\frac{1}{5}}}[/tex]
[tex]\frac{C_h}{C_n}=\sqrt{\frac{5}{1}[/tex]
Therefore
The ratio of the average speed of the helium atoms to the average speed of the neon atoms is
5:1
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You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from behind the handle. You are sanding a wall in front of you. as you turn the sander towards the right, you feel a tendency in the sander to...
a. pull away from you
b. turn towards the left
c. turn downward
d. turn upward
e. push toward you
Answer:
c. turn downward
Explanation:
From the information given:
To find the tendency of the sander;
We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.
Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.
A roller coaster works by being hoisted to the top of the highest peak on the track and then released. As the roller coaster car moves along the track the energy gets converted back and forth between kinetic and gravitational potential energy. The entire time the roller coaster car is in motion air friction and friction in the wheels act to oppose the motion of the car. At which point during the ride is the total mechanical energy of the roller coaster car the greatest?
a. At the bottom of the first dip in the track when the car is moving the fastest.
b. When the car is exactly at half its original height half way through the ride.
c. At the top of the highest peak as the very start of the ride.
d. At the end of the ride as the car nears the station.
Answer:
a. At the bottom of the first dip in the track when the car is moving the fastest.
Explanation:
P.S - The exact question is -
The correct option is - a. At the bottom of the first dip in the track when the car is moving the fastest.
Reason -
From the diagram , we can see that the total mechanical energy of the roller coaster car is greatest At the bottom of the first dip in the track when the car is moving the fastest.
MY NOTES A spring with a mass of 2 kg has a damping constant 14 kg/s. A force of 3.6 N is required to keep the spring stretched 0.3 m beyond its natural length. The spring is stretched 0.6 m beyond its natural length and then released. Find the position of the mass at any time t. (Assume that movement to the right is the positive x-direction and the spring is attached to a wall at the left end.)
Two identical speakers are set some distance apart in a large open field. Both are producing sound, in unison, with a wavelength of 4 m. An observer wandering around the field notices that the sound is surprisingly loud at certain locations and unusually quiet at others. The observer concludes that this is the effect of interference between the two sources of sound waves. For each location, indicate which sort of interference would occur at that point.
Answer:
Constructive interference occurs at the surprisingly loud locations and destructive interference occurs at the unusually quiet locations.
Explanation:
This is because, constructive interference tends to combine the effects of the wave when they are in phase (that is, moving in the same direction), which thus amplifies the effect and produces surprisingly loud sounds at those locations, while destructive interference occurs when the waves are out of phase with each other(that is, move in opposite directions) and thus, their effects tend to cancel out thus producing locations of unusually quiet sounds.
If a 5-L balloon at 25 degrees celsius were gently heated to 30 degrees celsius, what new volume would the balloon have? Show all work for credi
Answer: 5.08 L.
Explation down below
Plz help, will Mark brainliest. A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. How much current flows out of the battery?
(Unit = A)
Answer: 0.1125A
Explanation:
We need to know the total resistance which will be:
R = R1+R2
where,
R1 = 20 ohm
R2 = 60 ohm
Therefore, R = 20 + 60 = 80 ohm
We should note that from Ohm's law
v = iR
i = v/R
where,
i = 9/80 = 0.1125 A
Therefore, the current that flows out of the battery is 0.1125A
Earthquakes produce two kinds of seismic
waves: he longitudinal primary waves (called
P waves) and the transverse secondary waves
(called S waves). Both S waves and P waves
travel through Earth's crust and mantle, but
at different speeds; the P waves are always
faster than the S waves, but their exact speeds
depend on depth and location. For the pur-
pose of this exercise, we assume the P wave's
speed to be 8560 m/s while the S waves travel
at a slower speed of 5760 m/s.
If a seismic station detects a Pwave and
then 30.5 s later detects an S wave, how far
away is the earthquake center?
Answer in units of km.
Mi
Answer:
d
=
s
t
Explanation:
distance = speed * time
here, the distance is from the earthquake centre to the seismic station.
both the P and S waves travel from the earthquake centre before being detected by the seismic station, so the distance is the same for both.
the speeds are given as
8740
m
/
s
for the P wave and
4100
m
/
s
for the S wave.
we also know that the P wave arrives
47.4
seconds before the S wave.
we do not know the time that the P wave takes to travel, but we can denote it as
t
P
.
the time that the S wave takes to travel can be denoted as
t
P
+
47.4
, where time is in seconds.
for the S wave, speed * time is
4100
⋅
(
t
P
+
47.4
)
for the P wave, speed * time is
8740
⋅
t
P
.
since the distances that they travel are the same, the two expressions for speed * time are equal.
4100
⋅
(
t
P
+
47.4
)
=
8740
⋅
t
P
if you expand the brackets, you can find that
4100
t
P
+
194340
=
8740
t
P
then you can subtract
4100
t
P
:
4640
t
P
=
194340
and divide by
4640
to find
t
P
, which is the time that P takes to travel:
t
P
=
41.883
...
seconds
since distance = speed * time, the distance that the P wave travels is
t
P
⋅
the speed of P.
this is
41.883
s
⋅
8740
m
/
s
, which gives
366057.42
m
.
in kilometres, this is
366
k
m
to
3
significant figures.
Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
Answer:
They require a medium to travel through.
Explanation:
PLEASE HELPPPPPP!ASAPPPPPPP
Answer:
Altitude is the height of landmass calculated from sea level. No it has no effect on weight.
Explanation:
The altitude at sea level is always assumed to be 0°, thus as you move away from altidude is calculated in increments while moving into the sea, the vice versa is true.
define the term change and state one negative change you may encounter as a student or as an employee in the future
Answer:
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The term change refers to an alteration of present conditions.
What is change?The term change refers to an alteration of present conditions. When a change occurs, things cease to be the way they were. As a student, the complexity of academic work increases with time. This is a change that has taken place.
As an employee, you are given real world tasks to accomplish rather than mere mental exercises like when you were a student, this is change that has taken place.
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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.83 ✕ 105 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 3.04 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.
Answer:
[tex]F=2.84*10^{-26}N[/tex] & -y direction
[tex]F=2.84*10^{-26}N[/tex] & +y direction
Explanation:
From the question we are told that:
Speed of electron [tex]V_e=3.83 * 10^5 m/s[/tex] +x direction
Earths magnetic field [tex]B_e=3.04 * 10^-^8[/tex] +z direction
a)
Generally the equation for magnetic force [tex]F_m[/tex] is mathematically given by
[tex]F=q(V_e*B_e)[/tex]
where
[tex]q=1.6*10^{-19}c\\\=i*\=z=-\=j[/tex]
[tex]F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]
[tex]F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]
[tex]F=-2.84*10^{-26}N \=j[/tex]
Magnitude & Direction
[tex]F=2.84*10^{-26}N[/tex] -y direction
b)
Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by
[tex]\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)[/tex]
[tex]\=F'=-2.84*10^{-26}N \=j[/tex]
Magnitude & Direction
[tex]F=2.84*10^{-26}N[/tex] & +y direction