Respuesta:
286 J
Explicación:
Paso 1: Convertir 0,01 L de Hg a cm³
Usaremos los siguientes factores de conversion.
1 L = 1000 mL
1 mL = 1 cm³
0,01 L × 1000 mL/1 L × 1 cm³/1 mL = 10 cm³
Paso 2: Calcular la masa (m) correspondiente a 10 cm³ de Hg
La densidad de Hg es 13,6 g/cm³.
10 cm³ × 13,6 g/cm³ = 136 g
Paso 3: Calcular los moles(n) correspondientes a 136 g de Hg
La masa molar de Hg es 200,6 g/mol.
136 g × 1 mol/200,6 g = 0,678 mol
Paso 4: Calcular la cantidad de calor requerido (Q)
Usaremos la siguiente fórmula.
Q = c × n × (T₂ - T₁)
donde,
c: calor específico del Hg (28,1 J/mol.K = 28,1 J/mol.K)
T₂ y T₁: temperaturas final e inicial, respectivamente
Q = (28,1 J/mol.°C) × 0,678 mol × (25°C - 10 °C) = 286 J
What mistake did Kamala make? Gamma rays should have a very high frequency, not a very low frequency. Visible light should have a low frequency and a long wavelength. Infrared light should have a short wavelength, not a long wavelength. Microwaves should have a high frequency and a short wavelength.
Answer:
The answer is "Option A".
Explanation:
Please find the complete question in the attached file.
Kamala uses Gamma radiation inside this question should be very high, not very low. Electromagnetic radiation is a penetrating type resulting from radioactive nuclear decline. Its radiation is a very high-frequency, radioactive waveform to frequencies greater than [tex]10^{19} \ Hz[/tex] usually emitted from the radioactive decline.
Answer:
A
Explanation:
edge 2022
Smaller the surface area greater the gravitational force and vice–versa yes or no? justify the statement.
Answer:
It is true that Smaller the surface area greater the gravitational force and vice versa
Explanation:
The gravitational force depends on the distance between the two objects
F=GMm/r2
where G = gravitational constant
M = mass of one object
m = mass of second object
r is the distance between the two objects
Gravitational force is inversely proportional to the square of the distance between two objects. Hence, it can be said the Gravitational force is inversely proportional to the area and hence as the area increases gravitational force will decrease or vice versa
Un movil avanza a 20 m/s y recorre una distancia de 800 km. Determinar el tiempo en horas que utiliza
Answer:
t = 11.1 hours
Explanation:
The question says that, "A mobile advances at 20 m / s and travels a distance of 800 km. Determine the time in hours you use".
Given that,
Speed of a mobile, v = 20 m/s = 72 km/h
Distance, d = 800 km
We know that,
Speed = distance/time
So,
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{800}{72}\\\\t=11.1\ h[/tex]
So, it will take 11.1 hours.
The three things to remember about gravitational forces in space are: 1. 2. 3.
Answer:
(1) The gravitational forces are inversely proportional to the square of the distance between the objects. More is the distance between the objects , less will be the gravitational force between them.
(2) The gravitational forces are the weakest of all the four fundamental forces (Nuclear forces, weak forces, electromagnetic forces, gravitational forces) in nature.
(3)Gravitational forces are always attractive . They are also conservative in nature. work done by these forces or against these forces doesn't depend on the path followed.
Explanation:
PLEASE HELP ME
Which refers to the amount of energy in a sound wave per unit of time and is also related to the loudness of a sound? period compression amplitude intensity
Answer: Thanks for the points!
Explanation: The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave. As the amplitude of the sound wave increases, the intensity of the sound increases. Sounds with higher intensities are perceived to be louder.
Answer:
Amplitude
Explanation:
One way to think about circular motion is that the object is continuously ____________.
A. Prevented from moving in a straight line.
B. Allowed to move in a straight line.
C. Forced to move in a straight line.
D. Encouraged to move in a straight line.
Answer:
A
Explanation:
circular motion means the object will follow a circular trajectory.
Answer:
the answer for the question is option A
Question- Gases the oceans exchange with the atmosphere include..
a. oxygen
b. carbon dioxide
c. water vapor
d. all of the above
What conditions would probably exist the dew point and dry bulb temperatures to be the same at the ground ?
Answer: The conditions would probably exist the drew point and dry bulb temperatures to be the same at the ground because When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.
Explanation:
Since the air is said to be saturated when the dew point temperature and air temperatures are equal, the circumstances are likely present for the dew point and dry bulb temperatures to be equal at the ground. NEVER is the dew point temperature higher than that of the air temperature. As a result, condensation is used to remove moisture from the air when it cools.
What is dew point temperature?The dew point, under the assumption of constant air pressure and water content, is the temperature at which air must be chilled to become water vapor condenses. Airborne vapor will condense to create liquid water, known as dew, when it is cooled below the dew point, thereby moisture capacity. If this occurs via coming into contact with a cooler surface, dew will grow there.
Humidity influences the dew point. The dew point rises as the amount of moisture in the atmosphere increases.
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A gas mixture has 10% O2, 50% Ar (40 gmw) and 40% Pu (244 gmw). What is the density of this mixture?
Answer: 5.39g/L
Explanation:
We need to calculate the average molar mass of the mixture which will be:
= (10 × 32) + (50 × 40) + (40 × 244) / 100
= (320 + 2000 + 9760) / 100
= 12080 / 100
= 120.8g/mol
Since the volume occupied is 22.4L and 1 mole of the gas will occupies 22.4L given the standard temperature conditions, then the density of the mixture will be:
= Mass / volume
= 120.8 / 22.4
= 5.39g/L
Therefore, the density of the mixture will be 5.39g/L.
A 50-kg copper block initially at 140°c is dropped into an insulated tank that contains 90 l of water at 10°c. Determine the final equilibrium temperature and the total entropy change for this process.
Answer:
[tex]T_f=24.71[/tex]
Explanation:
From the question we are told that:
Mass of block [tex]m=50[/tex]
Temperature of block [tex]T_b =140 \textdegree C[/tex]
Volume of water [tex]V= 90L[/tex]
Temperature of water [tex]T_w=10 \textdegree C[/tex]
Density of water [tex]\rho=1000kg/m^3[/tex]
Specific heat of water [tex]C_w=4.18KJ/kg-k[/tex]
Specific heat of copper [tex]C_p=0.96KJ/kg-k[/tex]
Generally the equation for equilibrium stage is mathematically given by
[tex]mC_p(T_b-T_f)=\rho*VV*c(T_f-T_w)[/tex]
[tex]50*0.96(140-T_f)=1000*90*10^-3*c_w(T_f-10)[/tex]
[tex]48(140-T_f)=376.2(T_f-10)[/tex]
[tex]140-T_f=7.8375(T_f-10)[/tex]
[tex]140-T_f=7.8375T_f-78.375[/tex]
[tex]-8.8375T_f=-218.375[/tex]
[tex]T_f=\frac{-218.375}{-8.8375}[/tex]
[tex]T_f=\frac{-218.375}{-8.8375}[/tex]
[tex]T_f=24.71[/tex]
7. A train 100 m long is moving with the velocity of 72 km/h. Find the time it takes to cross the bridge which is 2 km long?
a) 1050 S
b) 10500 s
c) 10.5 s
d) 105 s
Answer:
d) 105 s
Explanation:
Given the following data;
Distance A (length of train) = 100 m
Velocity = 72 km/h to meters per seconds = 72 * 1000)/3600 = 72000/3600 = 20 m/s
To find the time;
Time = distance/speed
Time = 100/20
Time = 5 seconds.
II. When the distance (bridge) is 2km;
Distance B = 2km = 2*1000 = 2000 meters
Time = distance/speed
Time = 2000/20
Time = 100 seconds
Therefore, total time = 5 + 100 = 105 seconds
You slide out of a car seat and as you touch the metal door a spark jumps between your hand and the door. Describe how the spark formed
Answer: Your body sliding against the car seat created friction, making it created potential energy. The friction is a form of electricity, and the car doors metal is a conductor of electricity. That potential energy was turned into kinetic once the metal attracted the electricity, thus making a spark.
Hope this helps ^_^
a student had rolled 114 dice and removed all those landed on the number six. the student rolled the remaining dice again and removed those that landed on a six. when the student had rolled the dice 20 times there were 9 dice left.
Calculate the most likely number of times that the student had rolled the dice before the number of dice had halved.
Answer:
4 rolls
Explanation:
The probability of rolling a 6 is 1/6 = 0.1667 (4.d.p)
This means that approx. 1/6 of the dice will land on a 6.
If the student removes a 1/6 of the dice each time, it means that the number of dice is decreasing by 1/6 each roll (or multiplying by 5/6).
114/2 = 57
By multiplying 114 by 5/6 and continuing we can see how many times it takes for us to get past 57.
Roll 1: 114 x 5/6 = 95
Roll 2: 95 x 5/6 = 79.17
Roll 3: 79.17 x 5/6 = 65.97
Roll 4: 65.97 x 5/6 = 54.98
Most likely to take 4 rolls before halving the number of dice.
You could also solve this problems by writing an equation and solving using logs but I think this method is easier to understand.
Hope this helped!
Several merchant ships reports rogue waves
which are estimated to be 25 meters high and 26 meters long. Assuming that these waves travel at
speeds of 6.5 m/s, determine the frequency and the period of these waves.
Answer:
The frequency is 0.25Hz and the period is 4s
Explanation:
To solve this we can use the formula: [tex]f = \frac{v}{\lambda}[/tex], where f=frequency, v=velocity and lambda = wavelength.
In the question, we are given the information that the velocity of the wave is 6.5m/s and the wavelength is 26 meters long. By putting these values into the formula, we can find the frequency:
[tex]f=\frac{6.5}{26} \\f= 0.25Hz[/tex]
Period is the inverse of frequency: [tex]T=\frac{1}{f}[/tex]
Therefore the period is: [tex]T = \frac{1}{0.25} \\T = 4s[/tex]
Hope this helped!
Part F
How could you add more energy to the car?
Answer:
with fuel
Explanation:
Answer:
you can add more energy to the car by launching it again.
Explanation:
nt: what is the unit of measurement for work?)
A body builder lifts a 200kg barbell up 2m into the air. How
much work does the bodybuilder do?
Answer:
The unit of measurement of work is Nm which is also called as Joule and written J.
work done by the body builder against gravity = 3920J
Explanation:
work = force x displacement
force on barrel = 200 x gravity = 200 x 9.8 = 1960 N
displacement = 2m
work done against gravity = 1960 x 2 = 3920 J
This Is Science , please help it’s due at 3 , but I dont mind if its a little late.
Answer:
uhm you can get all these answers from go ogle but just so you dot get in trouble click the tree dots at the top right of your screen (this is if your using crome) and go to history click the square and there should be a delete thing
Explanation:
Answer:
4. I and II 9. tornado
Explanation:
Which of the following is evidence that a chemical reaction has occurred?
Jim wishes to push a 100. N wood crate across a wood floor.What is the minimum horizontal force that would be required to start the crate moving?
For the wood crate to move, the force applied (minimum horizontal force) must be greater than the static friction between the wood crate and the wood floor
Given that Jim wishes to push a 100. N wood crate across a wood floor.
The weight of the wood = 100N
The weight will produce a normal reaction N which is equal in magnitude to the magnitude of the weight. That is,
N = mg = 100N
For the wood crate to move, the force applied must be greater than the static friction between the wood crate and the wood floor.
Static friction = μN
Where μ = static friction.
Therefore, the minimum horizontal force that would be required to start the crate moving depend on the nature of the surface of the wood floor.
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Haile's plane travels forward for a few feet and then begins to fall. What would explain the plane's ability to travel forward for a few feet without falling?
Answer:
Aircraft never crash because of one single issue. It's almost always a combination of factors that lead to an accident. Whilst flying is extremely safe, typical reasons why planes crash include pilot error, technical failures, bad weather, terrorism, and pilot fatigue.
Answer The force of the air pushing up on the plane is
equal to the force of gravity pulling down on the
plane.
Ali mixes 20g of Sodium Chloride in 100g of water at 15 Degree °C. Calculate the mass of the solution
Answer:
The mass of the solution is 120 g.
Explanation:
The mass of the solution is given by:
[tex] m_{sol} = m_{1} + m_{2} [/tex]
Where:
[tex]m_{sol}[/tex]: is the mass of the solution
[tex]m_{1}[/tex]: is the mass of the solvent
[tex]m_{2}[/tex]: is the mass of the solute
In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.
Hence, the mass of the solution is:
[tex] m_{sol} = m_{1} + m_{2} = 100 g + 20 g = 120 g [/tex]
I hope it helps you!
Imagine rubbing a balloon on your hair or clothes and putting extra electrons on the balloon to give it a negative charge. If you touch the balloon to a wall, it may stick to the wall. Explain why you think this happens.
Answer:
Because here is a number of electrons more applied to the balloon
A 1200 kg car accelerats from reat to 10.0 m/s in a time of 4.50 seconds. Calculate the force that thr car's tires exerted on the road.
Answer:
2667 N
Explanation:
Method 1: ImpulseWe can solve this problem by using the impulse formula.
FΔt = mΔv Δt = time interval, m = mass of the car (kg), Δv = change in velocityWe have three known variables, so we can solve for the fourth: F.
Divide Δt from both sides to isolate F.
F = (mΔv)/ΔtSubstitute known values into the equation.
F = [(1200 kg)(10 m/s - 0 m/s)] / 4.5 s F = [(1200)(10)]/4.5 F = 12000/4.5 F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
Method 2: Newton's Second LawThe force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.
We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.
F = ma F = force exerted on the car, m = mass of the car (kg), a = acceleration of the car (m/s²)We are given the mass of the car, velocity of the car, and the time in which it accelerated.
We can use this equation for acceleration:
a = Δv/Δt Δv = final velocity - initial velocity (change in velocity), Δt = time intervalThe car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.
a = (10 m/s - 0 m/s) / 4.50 s a = 10/4.5 a = 2.222... m/s²Now we have two known variables, mass and acceleration. We can solve for the force exerted on the car (and thus, the force the car exerts on the road) using the formula F = ma.
F = ma F = (1200 kg)(2.222... m/s²) F = 1200 · 2.222...F = 2666.666667 NThe force that the car's tires exert on the road is 2667 N.
will give Brianliest answer. help.
consider a collusion in one dimension that invoves two objects of masses 4.5 kg and 6.2 kg the larger mass is originally at rest, and the smaller mass has an initial velocity of 16 m/s [E]. the final velocity of the larger object is 10.0 m/s [E]. calculate the final velocity of the smaller object after the collision.
Answer:
v₁ = 1.78 m/s
Explanation:
We can use the law of conservation of momentum here, as follows:
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex]
where,
m₁ = mass of first object = 4.5 kg
m₂ = mass of second object = 6.2 kg
u₁ = initial speed of first (smaller) mass = 16 m/s
u₂ = initial speed of second (larger) mass = 0 m/s
v₁ = final speed of first (smaller) mass = ?
v₂ = final speed of second (larger) mass = 10 m/s
Therefore,
[tex](4.5\ kg)(16\ m/s)+(6.2\ kg)(0\ m/s)=(4.5\ kg)(v_1)+(6.2\ kg)(10\ m/s)\\70\ kgm/s - 62\ kgm/s = (4.5\ kg)v_1\\\\v_1 = \frac{8\ kgm/s}{4.5\ kg}\\\\[/tex]
v₁ = 1.78 m/s
Reo performed an experiment to investigate the strength of an electromagnet and the amount of force that would be affected by the size of the current flowing through its coils. Which of the following changes would increase the current flow the most?
a. Decreasing the number of paper clips being picked up
b. Decreasing the number of coils of wire wrapped around the nail
c. Increasing the voltage power supply
d. Increasing the number of nails
(WILL GIVE BRAINLIEST)
Answer:
b. Decreasing the number of coils of wire wrapped around the nail
it can cause an electrical current running through it creates a magnetic field.
which word meaning sensible has the most negative connotation
Answer:
I’d say stuffy. It has the most negative connotation of all the options .
Mark Brainlest please!
Refer to the diagram to answer the question. Which part of the eye enables it to focus? A B C D E
Answer:
what are the A B C D E
Explanation:
Studying this brochure from nasa, which explains more detail the instruments carried by the Juno spacecraft which scientific activities will jump conduct on its trip to Jupiter? Check all that apply
Answer:
Juno scientific payload includes:
A gravity/radio science system (Gravity Science) A six-wavelength microwave radiometer for atmospheric sounding and composition (MWR) A vector magnetometer (MAG) Plasma and energetic particle detectors (JADE and JEDI) A radio/plasma wave experiment (Waves) An ultraviolet imager/spectrometer (UVS) An infrared imager/spectrometer (JIRAM)Explanation:
Each mission of NASA has a specific set of instruments that it uses to perform scientific experiments on the desired heavenly body. In case of Juno, the mission for Jupiter has a series of instruments that would study domains of gravitational forces, magnetic effect, particle detection, radiation detection, UV/IR imaging, and plasma experiments.
The lens of a telescope has a diameter of 25 cm. You are using it to look at two stars that are 2 × 1017 m away from you and 6 × 109 m from each other. You are measuring light with a wavelength of 700 nm. As the light goes through the lens, it diffracts. a. Is it possible, using this telescope, to see the two stars as separate stars? b. What is the minimum possible lens diameter you would need in order to resolve these two stars?
Answer:
a)It is NOT possible using this telescope, to see the two stars as separate stars
b)[tex]d_{min} =28.466m[/tex]
Explanation:
From the question we are told that:
Diameter of lens,[tex]d = 25 cm \approx 0.25 m[/tex]
Distance from both star [tex]D_f= 2*10^{17} m[/tex]
Distance between both stars [tex]D_b= 6*10^9 m[/tex]
Wavelength of light [tex]\lambda =700 nm \approx 700*10^-9 m[/tex]
Generally the equation for angle subtended by the two stars at the lens is mathematically given by
[tex]\theta=\frac{D_f}{D_b}[/tex]
[tex]\theta=\frac{6*10^9}{2*10^{17}}[/tex]
[tex]\theta=3.0*10^{-8} rad[/tex]
Generally the equation for minimum angular separation of two object is mathematically given by
[tex]\theta_{min} = 1.22*\lambda/d[/tex]
[tex]\theta_{min}= \frac{1.22*700*10^-9}{0.25}[/tex]
[tex]\theta_{min}= 3.416*10^-^6 rad[/tex]
Therefore
[tex]\theta < \theta_{min}[/tex]
[tex]3.0*10^{-8} rad< 3.416*10^-^6 rad[/tex]
It is NOT possible using this telescope, to see the two stars as separate stars
b)
Generally the equation for minimum diameter of the lens is mathematically given by
[tex]d_{min} =\frac{ 1.22*\lambda}{\theta}[/tex]
[tex]d_{min} =\frac{ 1.22*700*10^{-9}}{3*10^{-8}}[/tex]
[tex]d_{min} =28.466m[/tex]
Which is NOT something that all green plants have in common?
1.They make their own food.
2. They reproduce.
3 .They grow.
4 .They produce flowers.
Answer:
4
Explanation:
Not all plants can grow flowers. Only the ones thay have buds can.
Not all plants produce flowers. Hence, this is the characteristic which is not common in all plants.Therefore, the correct option is 4.
What are flowers?Flowers are the structures of plants. They are responsible for producing seeds that will grow into new plants. Flowers typically consist of a colorful or ornamental part called the corolla, which attracts pollinators such as bees and butterflies, and a reproductive part called the stamen and pistil, which contain the plant's male and female organs.
Not all green plants produce flowers. Flowering plants are a type of plant that belong to the group Angiosperms, but there are also non-flowering plants like ferns and mosses that do not produce flowers. Therefore, the correct option is 4.
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