Calculate the amount of heat (in J) needed to raise the temperature of 3.50 g of water from 22.4oC to 98.8oC.

Explanation:

Just like an independent variable, a dependent variable is exactly what it sounds like. It is something that depends on other factors. For example, a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it. Usually when you are looking for a relationship between two things you are trying to find out what makes the dependent variable change the way it does.

Answer: B

Kinetic Energy is the energy possessed by the body due to "motion".

Answer:

B- motion

Explanation:

Correct on edge 2021

️️

Answer:

0.343

Explanation:

Step 1: Given data

Step 2: Calculate the partial pressure of Kr

The total pressure of the mixture is equal to the sum of the partial pressures of the individual gases.

P = pXe + pAr + pKr

pKr = P - pXe - pAr

pKr = 6.70 atm - 1.60 atm - 2.80 atm

pKr = 2.30 atm

Step 3: Calculate the mole fraction of Kr

We will use the following expression.

X(Kr) = pKr/P

X(Kr) = 2.30 atm/6.70 atm

X(Kr) = 0.343

Considering the Dalton's partial pressure, the mole fraction of Kr is 0.34.

The pressure exerted by a particular gas in a mixture is known as its partial pressure.

So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

[tex]P_{T} =P_{1} +P_{2} +...+P_{n}[/tex] where n is the number of gases.

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

[tex]P_{A} =x_{A} P_{T}[/tex]

In this case, you know:

So, replacing in the Dalton's partial pressure law:

[tex]P_{T} =P_{Xe} +P_{Ar} +P_{Kr}[/tex]

6.70 atm= 1.60 atm + 2.80 atm + [tex]P_{Kr}[/tex]

6.70 atm- 1.60 atm- 2.80 atm= [tex]P_{Kr}[/tex]

2.30 atm=[tex]P_{Kr}[/tex]

Then: [tex]P_{Kr} =x_{Kr} P_{T}[/tex]

2.30 atm= [tex]x_{Kr}[/tex] 6.70 atm

[tex]x_{Kr}[/tex] =2.30 atm ÷6.70 atm

[tex]x_{Kr}[/tex] = 0.34  

In summary, the mole fraction of Kr is 0.34.

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Answer:

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of ammonium carbonate and chromium(III) nitrate are combined.

3 (NH₄)₂CO₃(aq) + 2 Cr(NO₃)₃(aq) ⇒ 6 NH₄NO₃(aq) + Cr₂(CO₃)₃(s)

The complete ionic equation includes all the ions and insoluble species.

6 NH₄⁺(aq) + 3 CO₃²⁻(aq) + 2 Cr³⁺(aq) + 6 NO₃⁻(aq) ⇒ 6 NH₄⁺(aq) + 6 NO₃⁻(aq) + Cr₂(CO₃)₃(s)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

3 CO₃²⁻(aq) + 2 Cr³⁺(aq) ⇒ Cr₂(CO₃)₃(s)

Answer:

A. (CH3)3C-I reacts by SN1 mechanism whose rate is independent of nucleophile reactivity.

Explanation:

We must recall that (CH3)3C-I is a tertiary alkyl halide. Tertiary alkyl halides preferentially undergo substitution reaction via SN1 mechanism.

In SN1 mechanism, the rate of reaction depends solely on the concentration of the alkyl halide (unimolecular mechanism) and is independent of the concentration of the nucleophile. As a result of this, both Br^- and Cl^- react at the same rate.

Answer:

[Ar]3d4 is the ground-state electron configuration for the Mn4 ion

but i don't know whether it is paramagnetic or daimagnetic

Answer:

use google

Explanation:

Answer:

the water cycle shows the continuous movement of water within the Earth and atmosphere. it is a complex system that includes many different processes. Beckley water evaporates into water vapor, condenses to form clouds, and precipitates back to Earth in the form of rain and snow. Water in different phases moved across the atmosphere. The Cove water flows across the land, into the ground, threw the ground. Groundwater moves into plants and evaporates from plants into the atmosphere. Solid ice and snow can turn directly into gas. It can also take place when water vapor becomes solid

Explanation:

hope this helps :]

Water can take different paths while moving through water   cycle because of it's unique property to exist in different phases.

Water cycle is one of the biogeochemical cycles which describes the movement of water above and below the surface of earth. Mass of water remains constant but it's mass in different forms varies as it exists in form of  glaciers, water and water vapor.

Water gets converted from one form to another by processes such as evaporation,transpiration, condensation,precipitation and surface run off.During this , water changes it's phases from liquid to vapor and solid . Ocean plays a major role in water cycle as it is a source of 86% global evaporation of water.

It involves change in energy leading to changes in temperature. When it evaporates,it takes energy from surroundings and while condensing, it releases energy in to the environment. The evaporation phase purifies the water and then replenishes land with freshwater.

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Answer:

work out if it's either going to sink or float

Explanation:

this can be carried out by calculating the numbers

Answer:

No

Explanation:

Nitrogen cannot be used to build the wire for a cell phone charger.

What are the elements used to build charger ?

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Answer:

1.  car traveled 30 meters per second

2. pepper traveled 10 meters per second

3. tony drove around 500 meters per minute

4. the bird traveled 200 miles

Hope this helped!

Mass of N₂ will be formed : 50.12 g

Reaction

2 NH₃(g) + 3 CuO(s) → N₂(g) + 3 Cu(s) + 3 H₂O(g)

moles NH₃ = 3.58

ratio mol NH₃ : mol N₂ = 2 : 1

so mol N₂ :

[tex]\tt \dfrac{1}{2}\times 3.58=1.79[/tex]

mass N₂ (MW=28 g/mol) :

[tex]\tt 1.79\times 28=50.12~g[/tex]

Answer:

i think it is ge

Explanation:

Two or more than two atoms with different physical or chemical properties can not combine together to form an element. Therefore, the condensed electron configurations for the given element can be written as below.

Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same.

The systematic distribution of electrons in the various atomic orbitals is called its electronic configuration. 1,2,3 represents the number of shells and s and represents the orbitals. The superscripts represents the number of electrons in each orbitals.

Electronic configuration of Mg   Ne 3s²

Electronic configuration of Ge   [Ar] 3d¹⁰ 4s² 4p²

Electronic configuration of Br    [Ar] 3d10 4s² 4p⁵

Electronic configuration of V     [Ar] 3d³ 4s²

Electronic configuration of  Y   [ Kr ]4d¹ 5s²

Electronic configuration of Lu     [Xe] 4f¹⁴ 5d¹6s²

Therefore, the condensed  electron configurations for the given element can be written as above.

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Answer:

B. 0.971 g

Explanation:

When MgCl₂(aq) reacts with Pb(NO₃)₂(aq), PbCl₂(s) and Mg(NO₃)₂(aq) are produced:

MgCl₂(aq) + Pb(NO₃)₂(aq) →, PbCl₂(s) + Mg(NO₃)₂(aq)

Thus, we need to find imiting reactant finding moles of each reactant:

Moles MgCl₂:

15.5mL = 0.0155L * (0.225 mol / L) = 3.49x10⁻³ moles

Moles Pb(NO₃)₂:

37.5mL = 0.0375L * (0.250mol / L) = 9.38x10⁻³ moles

As the ratio of the reactants is 1:1, the moles of PbCl₂ are 3.48x10⁻³ moles.

We need to convert thes moles to mass using molar mass of PbCl₂ (278.1g/mol), thus:

3.48x10⁻³ moles * (278.1g/mol) =

0.968g of PbCl₂ are precipitate

Thus, right answer is:

Answer:900j

Explanation:

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

[tex]Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}[/tex]

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

Answer:

Molarity acetate: 0.1353M

Molarity acetic acid: 0.0418M

Explanation:

When in solution you have a weak acid (Acetic acid) and its conjugate base (sodium acetate) a buffer is produced. The pH of this buffer is obtained using the H-H equation:

pH = pKa + log [A⁻] / [HA]

Where pH is pH of the solution = 5.25

pKa is pKa of acetic buffer = 4.74

[A⁻] is molarity of acetate ion - Molar mass sodium acetate: 82.03g/mol-:

11.1g * (1mol / 82.03g) = 0.1353moles A⁻ / 1.0L = 0.1353M

And [HA] are moles of acetic acid.

Solving for HA:

5.25 = 4.74 + log [0.1353] / [HA]

0.51 =  log [0.1353] / [HA]

3.236 = [0.1353] / [HA]

[HA] = 0.1353M / 3.236

[HA] = 0.0418M

Answer:

[tex]K=0.14[/tex]

Explanation:

Hello!

In this case, for the undergoing chemical reaction, we can write the equilibrium expression via:

[tex]K=\frac{[SO_2][NO_2]}{[SO_3][NO]}[/tex]

Whereas the equilibrium concentration of both SO3 and NO are 2.55 M and 1.90 M respectively, it means that the extent of reaction [tex]x[/tex] is:

[tex]x=1.90M-1.20M=0.7M[/tex]

Because the equilibrium expression in terms of the reaction extent is:

[tex]K=\frac{x*x}{([SO_3]_0-x)([NO]_0-x)}[/tex]

It means that the concentration of SO3, NO, SO2 and NO2 at equilibrium are:

[tex][SO_3]=2.55M-0.70M=1.85M[/tex]

[tex][NO]=1.20M[/tex]

[tex][SO_2]=0.70M[/tex]

[tex][NO_2]=0.70M[/tex]

Thus, the equilibrium constant for such reaction is:

[tex]K=\frac{0.70*0.70}{1.85*1.90}\\\\K=0.14[/tex]

Best regards!

Answer:

one in a billion

Explanation:

We have it known that Pure water is entirely made up of H2O molecules. Just 1 in 10⁹, that is a billion molecules are ionized when it is at room temperature.

The Ionization of water has this chemical equation:

H2O <--> H+ + OH-

When At equilibrium and at room temperature, we have the rate of forward reaction and the backward reaction to be very fast such that no water molecule would eventually remain ionized.

Therefore our answer is roughly one in a billion water.

Answer:

Concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

Note: The volume of the flask is assumed  to be 250 mL

Explanation:

Since the volume of the volumetric flask is not given, we assume the volume its volume to be 250 mL.

Mass of copper (ii) sulfate = 17.2 g; molar mass of copper (ii) sulfate = 160 g/mol

Concentration in mol/L = number of moles/volume in litres

Number of moles of copper (ii) sulfate = 17.2 g / 160 g/mol = 0.1075 moles

Volume of flask in litres = 250 mL/1000 mL * 1 L = 0.250 L

Concentration = 0.1075 moles / 0.250 L = 0.43 mol/L

Therefore, concentration of the chemist's copper(II) sulfate solution is 0.43 mol/L

Answer:

0.5000

Explanation:

We can measure the concentration of the copper sulfate solution as 1.000 mol/L. Since the tank contains one half liter, the solution contains 0.5000 moles of copper sulfate.

Answer:

The required milliliters of CsNO3 in solution 1 = 42.29 mL

Explanation:

Given that:

The molarity of CsNO3 in solution 1 M₁= 0.266 M

The Volume of CsNO3 in solution 1 V₁  =   ???

The Volume of CsNO3 in solution 2 V₂ = 150.0 mL

The molarity of CsNO3 in solution 2 M₂= 0.075 M

By the application of the titrimetric concept:

M₁V₁ = M₂V₂

We have;

0.266 M ×  V₁  = 0.075 M × 150.0 mL

V₁  = ( 0.075 M × 150.0 mL ) / 0.266 M

V₁  = (11.25 / 0.266 ) mL

V₁  = 42.29 mL

Answer:

Empirical formula is C₂H₆S

Explanation:

Given data:

Percentage of hydrogen = 9.73%

Percentage of carbon = 38.66%

Percentage of sulfur = 51.61%

Empirical formula = ?

Solution:

Number of gram atoms of H = 9.73 / 1.01 = 9.6

Number of gram atoms of S = 51.61 / 32 = 1.6

Number of gram atoms of C = 38.66 / 12 = 3.2

Atomic ratio:

             C                      :      H              :         S

           3.2/1.6               :     9.6/1.6       :       1.6/1.6

            2                      :        6             :        1

C : H : S = 2 : 6 : 1

Empirical formula is C₂H₆S.

Answer:

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH).

I hope what I just explained is enough .

Answer:

Ne is the identity of the gas

Answer:

1 oxygen and 2 hydrogen

Answer:

It changes by roughly 1 atm.

Explanation:

Hello!

In this case, since the ideal gas equation differs from the van der Waals' one by the presence of the a and b parameters which correct the assumption of no interactions into the container, they are written as:

[tex]P=\frac{nRT}{V}\\\\P=\frac{RT}{v_m-b}-\frac{a}{v_m^2}[/tex]

Thus, the pressure via the ideal gas equation is:

[tex]P=\frac{0.300mol*0.082\frac{atm*L}{mol*K}*248K}{0.200L}=30.5atm[/tex]

And the pressure via the van der Waals equation, considering the molar volume (vm=0.200L/0.300L=0.667L/mol) is:

[tex]P=\frac{0.082\frac{atm*L}{mol*K}*248K}{0.667L/mol-0.0237L/mol}-\frac{0.0342atm*L^2/mol^2}{(0.667L/mol)^2}\\\\P=31.6atm-0.0769atm\\\\P=31.5atm[/tex]

It means that the pressure change by 1 atm, which is not a significant difference for helium.

The difference in pressure calculated by the two methods is 84 atm.

The ideal gas equation is given by

PV =nRT

From the data given in the question;

P = ?

V = 0.200 L

n =  0.300 mol

T = 248K

R = 0.082 atmLK-1Mol-1

P = nRT/V

P =  0.300 mol × 0.082 atmLK-1Mol-1  × 248K/0.200 L

P = 30.5 atm

From Van der Waals equation;

P = RT/V - b - a/V^2

P =  (0.082 × 248/0.200 - 0.0237)  - (0.0342/ 0.200^2)

P = 114.5 atm

The difference in pressure calculated by the two methods is;

114.5 atm -  30.5 atm = 84 atm

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Answer:

Explanation:

1

When elements in group 2 react with Iodine, a salt MI_2 is formed

2

When they react with water, Hydrogen gas is released

3

When they react with Oxygen, an Oxide, MO is formed

4

The most vigorously reactive metal in group 2 is Barium, Ba. Reactivity increases as one moves downward in group 2

5

The most metallic element is Barium, Ba. This is because in the periodic table, metallic strength of metals increases as one moves down the table.

The thing that happens when the elements in group 2 react with iodine is:

The way these elements react with water is:

The way they react with oxygen is:

The element which reacts the most vigorously  in group 2 is:

The element in the group which is the most metallic in character is:

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Answer:

(a) 6332.812 N (b) 1469.59  pounds.

Explanation:

Given that,

The surface area of the top of yu head is 25 cm x 25 cm

Area = 625 cm² = 0.0625 m²

Atmospheric pressure on it is 101325 Pa.

(a) Pressure acting on an object is given by force acting per unit area. It can be written as :

[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=101325\ Pa\times 0.0625\ m^2\\\\F=6332.812\ N[/tex]

6332.812 N of force is acting on your head at sea level.

(b) If area, A = 100 in²

We know that,

1 atm = 14.6959 pounds/in²

[tex]P=\dfrac{F}{A}\\\\F=PA\\\\F=14.6959 \ \text{Pounds}/in^2\times 100\ in^2\\\\F=1469.59\ \text{pounds}[/tex]

So, the force is 1469.59  pounds.

A. The force required to push your head at sea level is 6332.8125 N

B. The force in pound is 1469.59 lb

A. Determination of the force required at sea level.

Pressure (P) = 101325 Nm²

Area (A) = 25 cm × 25 cm = 0.25 m × 0.25 m = 0.0625 m²

P = F / A

Cross multiply

F = PA

F = 101325 × 0.0625

Therefore, the force required to push your head at sea level is 6332.8125 N

B. Determination of the force in pounds

Area (A) = 100 in²

Pressure (P) = 14.6959 pound / in²

F = PA

F = 14.6959 × 100

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