Calculate the concentration (M) of arsenic acid (H3AsO4) in a solution if 25.00 mL of that solution required 35.21 mL of 0.1894 M KOH for neutralization.

Answer:

[tex]E=9.62\times 10^{-21}\ J[/tex]

Explanation:

Given that,

The wavelength of a microwave is 7.42 mm or 0.00742 m

No. of photons, n = 359

We need to find the energy produced by this no of photons. It can be given by the formula as follows :

[tex]E=\dfrac{nhc}{\lambda}\\\\E=\dfrac{359\times 6.63\times 10^{-34}\times 3\times 10^8}{0.00742}\\\\=9.62\times 10^{-21}\ J[/tex]

or

[tex]E=9.62e^{-21}\ J[/tex]

So, the required energy is [tex]9.62\times 10^{-21}\ J[/tex].

Answer:

⬆️That guy deserves brainliest

Explanation:

Answer:

(a) > (d) > (c) > (b)

Explanation:

Acidic character is based upon inductive effect of the functional group that are attached to parent chain.

1. Nitro is a -I group which makes phenol acidic due to increased resonance,  2. bromine is a -I group but it is weaker than nitro group

3. phenol is more acidic than cyclohexanol due to resonance stabilization of resonance and among halogen F>Cl>Br>I is the order of acidity

4. cyclohexanol will be weakest as  it is not associated with any -I groups here.

so the order of acidity will be

(a). 4-nitropheno >  (d). 4-bromophenol > (c). 2,6-difluorocyclohexanol  >               (b). cyclohexanol

Molarity after dilution : 0.0058 M

The number of moles before and after dilution is the same  

The dilution formula

 M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution  

V₁ = volume of the solution before dilution  

M₂ = Molarity of the solution after dilution  

V₂ = Molarity volume of the solution after dilution

M₁=0.1 M

V₁=6.11

V₂=105.12

[tex]\tt M_2=\dfrac{M_1.V_1}{V_2}=\dfrac{0.1\times 6.11}{105.12}=0.0058~M[/tex]

The sentence that has an accurate punctuation is found in (Option B).

The punctuation marks are those marks that are use to make a piece of writing to have a complete meaning. A piece of writing will be meaningless if there are no attached punctuation marks.

The sentence that is correctly punctuated is;  "I bought all the ingredients for dinner: eggs, tomatoes, macaroni, and cheese—and told Molly to preheat the oven."(Option B)

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Answer:

The answer is the second one

Answer:

(b) 2.60%

Explanation:

Partition coefficient of the organic compound in ether is:

9.5 = Concentration in ether / Concentration in water

In the first extraction, X is the amount of organic compound extracted:

9.5 = X/50mL / (1-X)/200mL

9.5 = 200X / (50-50X)

475 - 475X = 200X

475 = 675X

X = 0.7037g are extracted.

Remains = 1g - 0.7037g = 0.2963g

Second extraction:

9.5 = X/50mL / (0.2963-X)/200mL

9.5 = 200X / (14.815-50X)

140.74 - 475X = 200X

140.74 = 675X

X = 0.2085g are extracted.

Remains = 0.2963g - 0.2085g = 0.0878g

Third extraction:

9.5 = X/50mL / (0.0878g-X)/200mL

9.5 = 200X / (4.3899-50X)

41.70 - 475X = 200X

41.70 = 675X

X = 0.2085g are extracted.

Remains = 0.0878g - 0.0618g = 0.026g remains

Percentage: 0.026g / 1g * 100 =

Answer:

diastereomers

Explanation:

Enantiomers are optical isomers that are mirror images of each other. Enantiomers can not be separated by physical methods because the both compounds have almost the same physical properties such as melting points, boiling points, etc. This makes it difficult to separate enanatiomers by conventional methods.

A common method of separating enantiomers is by converting them into diasteromers which are easily separated since diasteromers often have different chemical and physical properties.

Answer:

ok  

Explanation:

Answer:

[tex]k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Explanation:

Hello!

In this case, since the differential rate law of a second-order reaction is:

[tex]\frac{dC_A}{dt}=-kC_A^2[/tex]

Whereas A stands for NOCl and the corresponding integrated rate law is:

[tex]\frac{1}{C_A} =kt+\frac{1}{C_A_0}[/tex]

Thus, since we know the concentrations and the elapsed time, we compute the rate constant as shown below:

[tex]k=( \frac{1}{C_A}-\frac{1}{C_A_0} )/t\\\\k=( \frac{1}{0.83M}-\frac{1}{0.878M} )/763,200s\\\\k=8.63x10^{-8}\frac{1}{M*s}[/tex]

Best regards!

Answer:

This question appears incomplete

Explanation:

There is no such element known as "Ballardium (Bu)" in the periodic table. However, there are elements with a bit of similarity in spellings and pronunciation such as Beryllium (Be) which is found in group 2 (meaning it is an alkali earth metal), Berkelium (Bk) which is an actinide (meaning it is radioactive) and Vanadium (V) which is found in group 5 of the periodic table (meaning it's a transition metal).

Answer:

Option D. 53 moles.

Explanation:

The following data were obtained from the question:

Number of mole of C5H10O2 = 5.3 moles

Number of mole of Hydrogen in 5.3 moles of C5H10O2 =?

From the chemical formula of propyl acetate, C5H10O2,

1 mole of C5H10O2 contains 10 moles of H.

Therefore, 5.3 moles of C5H10O2 will contain = 5.3 × 10 = 53 moles of H.

Thus, 5.3 moles of C5H10O2 contains 53 moles of H.

Answer:

6,500 gm of steam require= 3,510 kilo calories (approx)

Explanation:

Every 1 gram of water at 100° C  absorb 540 calories

So,

Total water = 6.5 kg = 6,500 gram

So,

6,500 gm of steam require = 6,500 x 540

6,500 gm of steam require= 3,510 kilo calories (approx)

According to the question,

Total water,

Temperature,

Now,

Required steam will be:

= [tex]6500\times 540[/tex]

= [tex]3510 \ kilo \ calories[/tex]

Thus the above answer is right.

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Answer:

1.3 moles of HNO₃ will be produced

Explanation:

Equation for the reaction:

3NO₂ + H₂O ----> 2HNO₃ + NO

From the equation of the reaction, 3 moles of NO₂ reacts with 1 mole of H₂O to produce 2 moles of HNO₃

Suppose there are 2 moles of NO₂  and 7.0 moles of H₂O in a reactor, the limiting reactant will be NO₂ and H₂O will be in excess since 3 moles of NO₂ reacts with every 1 mole of H₂O.

Since 3 moles of NO₂ reacts to produce  2 moles of HNO₃;

2 moles of NO₂ will react to produce 2/3 * 2 moles HNO₃ = 1.3 moles of HNO₃

Therefore, 1.3 moles of HNO₃ will be produced

The largest amount of HNO₃ produced from the reaction between 2 mole of NO₂ and 7.0 mole of H₂O in a reactor is 1.3 mole

We'll begin by determining the limiting reactant. This can be obtained as follow:

3NO₂ + H₂O —> 2HNO₃ + NO

From the balanced equation above,

3 moles of NO₂ reacted with 1 mole of H₂O.

Therefore,

2 moles of NO₂ will react with = [tex]\frac{2}{3}\\\\[/tex] = 0.67 mole of H₂O.

From the balanced equation above,

3 moles of NO₂ reacted to produce 2 moles of HNO₃.

Therefore,

2 moles of NO₂ will react to produce = [tex]\frac{2 *2 }{3} \\\\[/tex] = 1.3 mole of HNO₃.

Thus, the largest amount of HNO₃ produced from the reaction is 1.3 mole

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Answer:

• All groups (columns) have the same number of valence electrons

Explanation:

Every group or column have the same number of valence electrons as a suprise. Every column is aligned in this way.

Answer:

all members within any group

Explanation:

Answer:c

Explanation:

Answer:

ABC

Explanation:

hrdjyt

A buffer solution is often referred to as a mixture of an aqueous solution of a weak acid and its conjugate base or weak base and its conjugate acid.

Conclusively we can say that an acid or base needed for making buffer solutions and not base alone

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Answer:

273.9m/s

Explanation:

Given parameter:

Kinetic energy of the ball  = 4.5kJ

Mass of the ball  = 120g

Unknown:

Speed of the ball  = ?

Solution:

Kinetic energy of a body is the energy due to the motion of a body.

 K.E  = [tex]\frac{1}{2}[/tex] m v²

where m is the mass

           v is the speed

Convert the quantities to the appropriate units;

     4.5kJ to J  = 4.5 x 10³J

 120g to kg  = 0.12kg

Now insert the parameters and find the unknown:

       4500  = [tex]\frac{1}{2}[/tex] x 0.12 x V²  

      9000 = 0.12V²  

       V²  = [tex]\frac{9000}{0.12}[/tex]   = 75000

        V  = 273.9m/s

Explanation:

The boiling point of propanoic acid is higher than that of 1-butanol due to the prevalence of hydrogen bonding in propanoic acid.

Answer:

303.6 mg

Explanation:

Given that:

The lethal dose [tex]LD_{50}[/tex] = 1320 mg/kg

The weight of the rat = 230 g

The lethal dose is the dose of a substance likely to cause death. SO a lethal dose of 50 will cause the death of 50% of the sample of test animals.

Therefore;

The mass of 2-naphthol that would have been ingested by each rat in a sample set of rats in order to kill half the population of rats will be equal to:

[tex]=\dfrac{LD_{50}}{1000} \times wt \ of \ rat[/tex]

[tex]=\dfrac{1320}{1000}\times 230[/tex]

= 303.6 mg

Protons and neutrons are located in the nucleus of the atom while the electrons move in the trajectory of the shell

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.  

So Isotopes are elements that have the same Atomic Number (Proton)  

Isotopes of Helium : helium-3 and helium-4

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

protons = 2

electrons=protons=2

neutron=mass number-atomic number=3-2=1

protons = 2

electrons=protons=2

neutron=mass number-atomic number=4-2=2

Protons and neutron in the nucleus, electrons in the shell

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

Answer:

40 is correct

Explanation:

Your answer should be 4.

Hope this helped!

-candycchandler

How do the products of chemical reactions compare to their reactants?

Answer:

The products often have completely different properties than the reactants.

The correct answer to the question is: The products often have completely different properties than the reactants.

In a chemical reaction, the reactants and products of the reaction have different properties because during the reaction, bonds were broken and new bonds were formed which generate a new substance called the product.

However, chemical equations must be balanced in order to conform to the law of conservation of matter which states that matter can neither be created nor destroyed  during a chemical reaction but can be transferred from one form to the other.    

For example, the reaction of Hydrogen gas (H₂) and oxygen gas (O₂) to produce water (H₂O)

From the equation, we can see that the reactants are gases but the product is a liquid which has a different properties from the gaseous reactants.

Therefore, the correct answer to the question is:  The products often have completely different properties than the reactants.

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Answer:

3,686,400,000 Joules

Explanation:

Energy = 1024 kWh

To be converted to Joules.

The relationship between kwh and joules is;

1 kilowatt-hour = 3600000 J

So we have;

1 = 3600000

1024 = x

x = 1024 * 3600000

x = 3,686,400,000 Joules

Answer:

1. 4.93 = pKb of the weak base

2. pH = 12.61

Explanation:

1. When a weak base, B, is being titrated with HCl, the reaction occurs as follows:

B + HCl → BH⁺ + Cl⁻

That means the moles added of HCl are the moles of BH⁺ produced and moles of B are initial moles of B - Moles of HCl

Thus:

Moles B:

Initial moles:

0.0250L * (0.130mol / L) = 3.25x10⁻³ moles B

Moles HCl:

8.5x10⁻³L * (0.130mol / L) = 1.105x10⁻³ moles HCl

3.25x10⁻³ - 1.105x10⁻³ =

Moles BH⁺ = Moles HCl:

pH of the buffer made from B/BH⁺ is determined using H-H equation for weak bases:

pOH = pKb + log [BH⁺] / [B]

Where pOH is 14-pH = 14-9.36 = 4.64

pKb is pKb of the weak base, our unknown.

[BH⁺] could be taken as moles of BH⁺ =  1.105x10⁻³ moles

And [B] as moles of B = 2.145x10⁻³ moles B

Replacing:

pOH = pKb + log [BH⁺] / [B]

4.64 = pKb + log [1.105x10⁻³ moles] / [2.145x10⁻³ moles]

4.64 = pKb -0.288

2. When HCl and NaOH are in solution the reaction that occurs is:

HCl + NaOH → H₂O + NaCl

To find pH we need to determine, first, which reactant is in excess:

Moles HCl:

0.023L * (0.230mol / L) = 5.29x10⁻³ moles

Moles NaOH:

0.033L * (0.0230mol / L) = 7.59x10⁻³ moles

That means NaOH is in excess and after the reaction will remain:

7.59x10⁻³ moles - 5.29x10⁻³moles = 2.3x10⁻³ moles NaOH = Moles of OH⁻

In 23+33mL = 56mL = 0.056L:

2.3x10⁻³ moles OH⁻ / 0.056L = 0.0411M [OH-]

As pOH = -log [OH-]

pOH = 1.39

pH = 14 - pOH

Thank you, also what are the options then I can help!

Answer:  the cake rises as gas bubbles form in the cake

Explanation: Had a quizziz quiz on this

Answer: The cake rises as gas bubbles form in the baking cake.

Explanation: had a test, got it right.