The percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ is - 0.028
Coefficient of linear thermal expansion for steel, α = 1.1 * [tex]10^{-5}[/tex] / C
Let the length of the tape at 20 ℃ be L.
New length of the steel tape after cooling, L' = L ( 1 + α ΔT )
ΔL = L' - L
ΔL = L ( 1 + α ΔT ) - L
ΔL = L ( 1 + α ΔT - 1 )
ΔL = L α ΔT
ΔT = T - [tex]T_{0}[/tex]
T = Final temperature
[tex]T_{0}[/tex] = Initial temperature
ΔT = - 5 - 20
ΔT = - 25 ℃
ΔL = L * 1.1 * [tex]10^{-5}[/tex] * ( - 25 )
ΔL = - 27.5 * [tex]10^{-5}[/tex] * L
Percentage error = ΔL / L * 100
Percentage error = - 27.5 * [tex]10^{-5}[/tex] * L / L * 100
Percentage error = - 0.028
Therefore, the percentage error in the steel tape is - 0.028
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A load of 15N is placed on a scale pan attached to a spring balance. This load causes an extension of 5cm in the spring what load must be placed on the spring balance an extension of 8cm? What is the spring constant of the spring
A load of 24N must be placed on the spring balance for an extension of 8cm and the value of spring constant is calculated as 3N[tex]cm^{-1}[/tex].
How can you figure out how long a spring will extend?The lengthened portion of an object, such as a spring, is known as its extension.
F = ke
The force in newtons is F. (N)
The “spring constant” (k) is expressed in newtons per meter (N/m).
E is the length in meters (m)
This equation is valid as long as the proportionality limit is not exceeded.
What is the proportionate relationship between the spring’s length extension?The extension for a particular spring and other elastic items is inversely proportional to the applied force. For instance, the extension doubles if the force does.
Case 1Kx = 15N
K = 15/x
= 15/5
K = 3N[tex]cm^{-1}[/tex]
Case 2dx = 8cm
The value of spring constant is = 3N[tex]cm^{-1}[/tex]
So, 3(8) = 24
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When work is done by a force on an object, then which of the following are true?
O The mass of the object always increases.
O The object does negative work on the force.
O The speed of the object always increases.
O The work done will be equal to the change of the total energy of the object plus energy appearing as heat, light,
O The energy lost to friction is equal to the amount of work done by the force.
A rabbit is moving in the positive x-direction at 1.50 m/s when it spots a predator and accelerates to a velocity of 12.1 m/s along the positive y-axis, all in 2.20 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.)
Acceleration of the rabbit, moving in the positive x-direction at 1.50 m/s when it spots a predator and accelerates to a velocity of 12.1 m/s along the positive y-axis, all in 2.20 s is given by in x direction 0 m/sec² in y direction is 5.50 m/sec².
What is acceleration?The rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
Given in the question rabbit is initially moving with speed 1.50 m/sec in x direction after rabbit spot predator start accelerating in y direction to velocity 12.1 m/sec in 2.20 m. so acceleration in x direction will be zero.
Acceleration in y direction is 5.50 m/sec².
Acceleration in x direction will be zero.
Acceleration in y direction is 5.50 m/sec².
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Please help!⚠️ Find the direction of this vector: -22.2 m, 12.6 m
Answer: The direction of the resultant can be determined by finding the angle that the resultant makes with either the north-south or the east-west vector. The diagram at the right shows the angle theta (Θ) marked inside the vector addition triangle. This angle theta is the angle that the resultant makes with west.
Explanation: Hope this helps.
Answer:
Magnitude=25.5
Direction=-60.4
Explanation:
[tex]\sqr\sqrt{ x^{2} +y^{2} \\\\[/tex]=m
[tex]Tan^{-1} (y/x)[/tex] = D
A golfer strikes her tee shot with the following velocities, vx = 106 m/s & vy = 66.2 m/s. a. What is the velocity of flight? b. The time of flight? c. The horizontal distance traveled?
Answer:
a) V ≈ 125 m/s; b) Δt = 13.24 s; c) ΔS ≈ 1450 m
Explanation:
a) We have just to calculate the vector resultant.
V² = 106² + 66.2²
V² = 15618.44
V ≈ 125 m/s
b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.
In vertical:
V = V₀ + a * t
V = 66.2 - g * t
0 = 66.2 - 9.8 * t
t ≈ 6.76 s
So: Δt = 13.24 s
c) In horizontal:
V = ΔS / Δt
106 = ΔS / 13.52 ⇒ ΔS = 106 * 13.52
ΔS = 106 * 13.52
ΔS = 1433,12
ΔS ≈ 1450 m
Three point charges -Q, -Q, and +3Q are arranged along a line as shown in the sketch.
What is the electric potential at the point P?
A) +kQ/R
B) -2kQ/R
C) -1.6kQ/R
D) +1.6kQ/R
E) +4.4kQ/R
(D) The electric potential at the point P is +1.6 kQ/R.
What is electric potential?
The electric potential of a given charged body is the work done in bringing the charge from a point to a given location in the electric field.
Mathematically, electric potential is given as;
V = kq/r
where;
k is Coulomb's constantq is magnitude of the charger is radius of the chargeThe distance of each of the negative charge to point P is calculated as follows;
r = √(R² + R²)
r = √(2R²)
r = R√2
The electric potential from each negative charge to point P;
V = -kQ/(R√2)
For the two charges = - 2kQ/(R√2)
The electric potential from 3Q
V = (k3Q) / R
V = (3kQ)/R
The total electric potential;
V(net) = (3kQ)/R - 2kQ/(R√2)
V(net) = (3kQ)/R - (1.414kQ)/R
V(net) = +1.6 kQ/R
Thus, we can conclude that the sum of the sum of the electric potential at point must be positive since it is directed to the positive y-direction.
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Lisa is solving a vector problem, and the answer she arrives at is “17.4 m/s at 11°.” Why is this answer, as it is currently written, not complete?
This answer which is currently written is not complete because solving a vector problem, we should also mention the direction correctly, but here the direction is not mentioned.
A vector is a quantity or phenomenon that has two impartial houses, value and course. The term also denotes the mathematical or geometrical illustration of the sort of quantity. Examples of vectors in nature are pace, momentum, pressure, electromagnetic fields, and weight. A vector may be located in a square coordinate device, as illustrated here. The square coordinate notation for this vector.
vector, in physics, is a quantity that has each importance and course. it's far usually represented via an arrow whose direction is similar to that of the amount and whose period is proportional to the quantity's magnitude. although a vector has magnitude and direction, it does not have a function.
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Using your scientific calculator, what is the Common logarithm for the 379? What does the answer mean?
Answer:
Explanation:
In mathematics, the common logarithm is the logarithm with base 10. It is also known as the decadic logarithm and as the decimal logarithm. Natural logarithm of 379 is 5.9375362050824 Decimal logarithm of the number 379 is 2.5786392099681 Sine of 379 is 0.9055655749933. Cosine of the number 379 is -0.42420630521841. Tangent of the number 379 is -2.1347291727006
The Common logarithm for the 379 using a scientific calculator is 2.58. It means that 2.58 is the value of [tex]log_{10}[/tex] ( 379 ).
[tex]log_{a}[/tex] ( x ) = [tex]log_{10}[/tex] ( x ) / [tex]log_{10}[/tex] ( a )
This is how it should be calculated using a scientific calculator if you want to find the value of x for a different base. The commonly used base is 10 because in olden days logarithmic tables were used instead of calculators.
In order to reduce the calculations to basic formats such as addition and subtraction, base 10 was used. So calculators were designed in such a way that if you use log of any number it is the value of log with a base of 10.
Therefore, the Common logarithm for the 379 using a scientific calculator is 2.58. It means that 2.58 is the value of [tex]log_{10}[/tex] ( 379 ).
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Which has the greatest mass between a Volleyball,Basketball and Soccer ball?
difference between weight and mass.
please be honest. don't answer if you don't know
Weight is the gravitational force with which the earth pulls an object towards it whereas, Mass is a quantity representing the amount of matter in a particle or object.
hope this helps and you need a chair for sitting xD -,-
With an average acceleration of - 1.4 m/s, how long will it take a cyclist to bring a bicycle with an initial speed of 12.8 m/s to a complete stop
9.14 s long it will take a cyclist to bring a bicycle with an initial speed of 12.8 m/s to a complete stop.
What does "acceleration" mean in the example?Depending on whether an object is moving much faster, slower, or in a different direction, its speed may change. Examples of acceleration include a falling apple, the moon orbiting the earth and a car which has stopped at a stop sign.
Which four forms of acceleration are there?Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.
Briefing:a = -1.4 m/s²
v[tex]_i[/tex] = 12.8 m/s²
v[tex]_f[/tex] = 0
Δt = ?
We use formula
a = v[tex]_f[/tex] - v[tex]_i[/tex]/t
-1.4 = 0 - 12.8/t
t = 9.14 s
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Which trial has the greatest impulse?
trial 1
trial 2
trial 3
trial 4
Is it safe to stay inside a vehicle during a heavy storm?
Answer:
Like trees, houses, and people, anything outside is at risk of being struck by lightning when thunderstorms are in the area, including cars. The good news though is that the outer metal shell of hard-topped metal vehicles does provide protection to those inside a vehicle with the windows closed.
Answer: Depends
Explanation:
You should be good if you have proper shelter and protection to maintain safety.
If it's hail, it's probably best to find shelter and I recommend putting a thick blanket on the windows so they don't burst.
12. Which of the following is not a property
of metals?
13. Which of the following correctly lists
the elements in order of increasing size
(smallest to largest)?
[orange]
conduct electricity
[yellow]
Sr
[blue]
[red]
brittle
[green]
Ca
[black]
[yellow]
shiny
[purple]
Be
[purple]
Be [purple], Ca [black] and Sr [blue] are the elements in order of increasing size.
Brittle is not the property of metals.
Why brittle is not the property of metals?The strong electrostatic force of attraction that is present in metal ions when they are surrounded by a large number of electrons. It is actually very strong and flexible at the same time. So, when we apply a force on the metals, they can be transformed into flat and smooth sheets that can be drawn into wires and they are hard to break into pieces.
Beryllium is an element that is present in the second period while on the other hand, calcium element is present in the next period and Sr element is also present in the lower period of periodic table. We know that when we move down the group, the number of shells increases which ultimately leads to increase in atomic size.
So we can conclude that the elements in order of increasing size are Be [purple], Ca [black] and Sr [blue]. The property which is not present in metals is the property of metals.
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A 30.0-mg oil drop carrying a charge of +3.2 μC passes undeflected through a region in which there is a uniform, constant electric field.
Determine the Electric field Ey.
A 30.0-mg oil drop carrying a charge of +3.2 μC passes undeflected through a region in which there is a uniform, constant electric field. The Electric field is mathematically given as
98 N/C
This is further explained below.
What is the Electric field?Generally, Generally, the equation for Electric field the is mathematically given as
q E=m g
q=chargeE= electric fieldm=massg= gravityTherefore
[tex]&\left(3 \times 10^{-6} \mathrm{C}\right) E=\left(30 \times 10^{-6} \mathrm{~kg}\right)\left(9.8 \mathrm{~m} / \mathrm{s}^2\right) \\[/tex]
E=98N/C
In conclusion, The force of gravity always pulls in a downward direction; hence, the electric field will be exerted in an upward direction. As a result, the value is positive.
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A motorcyclist is traveling in the positive direction at a
velocity of 7.0 meters per second. She increases her
velocity to 9.0 meters per second. What additional
information is needed to calculate the acceleration of
the motorcycle?
The additional information needed to calculate the acceleration of the motorcycle is the time taken to complete the distance.
What is acceleration?Acceleration is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).
The acceleration of a moving body can be calculated by dividing the change in velocity of the motion (∆V) by the time taken to complete the motion as follows:
Acceleration (m/s²) = change in velocity (m/s)/time(s)
According to this question, a motorcyclist is traveling in the positive direction at a velocity of 7.0 meters per second. She then increases her velocity to 9.0 meters per second. This means that the change in velocity {∆V} is 2m/s.
However, the time taken to complete the distance is still required to compute the acceleration of the motorcycle.
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A 2.0 F capacitor is required. What should the area of the plates be if they are to be separated by a 4.5 mm air gap?
The primary of a transformer connected to 170 V has 10 turns. The secondary has 150 turns. Find the output voltage. This is a step-up transformer.
The output voltage of a step-up transformer is 2550volts.
A transformer is an electrical energy transfer device that steps up or steps down the voltage from one alternating-current circuit to one or more other circuits.
We are given that,
The primary voltage of a transformer = V₁ = 170V
The number of turns of coils of primary transformer = N₁ = 10turns
The number of turns of coils of secondary transformer = N₂ = 150 turns
Thus , to get the output voltage V₂ of a step-up transformer, we can use the formula,
[tex]\frac{V_{2} }{V_{1} } = \frac{N_{2} }{N_{1} }[/tex]
Where, V₁ is primary voltage of a transformer , V₂ is the output voltage (secondary) of a transformer , N₁ & N₂ are the number of turns of coils primary and secondary transformer.
Therefore , after putting the values in above equation we can get,
[tex]V_{2} = \frac{N_{2} }{N_{1} } V_{1}[/tex]
[tex]V_{2} =[/tex] [tex]\frac{150}{10} 170volts[/tex]
[tex]V_{2} =[/tex] [tex]2550 volts[/tex]
Therefore, the output voltage of the step-up transformer would be 2550 volts.
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While scuba diving, Alec is rising toward the surface of the water at 6.0 meters per minute. If his velocity remains constant, how much time will it take Alec to rise 8.4 meters?
Given data
*Alec is rising towards the surface of the water is u = 6.0 m/min
*The given distance is d = 8.4 m
The formula for the time taken by the Alec to rise is given as
[tex]t=\frac{d}{u}[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} t=\frac{8.4}{6.0} \\ =1.4\text{ minute} \end{gathered}[/tex]Hence, the time is taken by Alec to rise is t = 1.4 minutes
Help!! Vector V is 448 m long in a 224 direction. vector W is 336 m long in a 75.9 direction. Find the direction of their vector sum.
The Direction of the vector sum of the two vectors V and W is resulted as 240.84 m toward + x.
What is a vector?A vector is a quantity or phenomenon with independent components of magnitude and direction. The expression can also be used to describe a quantity's geometric or mathematical representation.
The following are the x and y axes for the supplied vector:
Vector V in x direction;
[tex]$$\begin{aligned}&\mathrm{V}_{\mathrm{x}}=\mathrm{V} \cos \theta \\&\mathrm{V}_{\mathrm{x}}=448 \cos \left(224^0\right) \\&\mathrm{Vx}=-322.26\end{aligned}[/tex]
Vector V in y direction;
[tex]\begin{aligned}&V_y=V \sin \theta \\&V_y=448 \times \sin 224^0 \\&V_y=-311.2\end{aligned}[/tex]
Vector W in x direction;
[tex]W_x = 336 \times cos(74.9^0)[/tex]
[tex]W_x = 81.86[/tex]
Vector W in y direction;
[tex]\begin{aligned}&\mathrm{W}_{\mathrm{y}}=336 \times \sin 75.9 \\&\mathrm{W}_{\mathrm{y}}=325.88\end{aligned}[/tex]
The resultant vector in the x direction is;
[tex]\begin{aligned}&\Sigma X=-322.26+81.86 \\&\Sigma X==-240.4\end{aligned}[/tex]
The resultant vector in the y direction is;
[tex]\begin{aligned}&\Sigma Y=-311.2+325.88 \\&\Sigma Y=14.68\end{aligned}[/tex]
The resultant vector is found as;
[tex]\begin{aligned}&\mathrm{R}=\sqrt{(-240.4)^2+(14.68)^2} \\&\mathrm{R}=240.84 \mathrm{~m}\end{aligned}[/tex]
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TRUE or FALSE: The Equator receives less solar energy than other latitudes.
Answer: False
Explanation: the equator receives the most sun light because the the equator is closest to the sun.
How would the Sun’s effect on Earth change if the Sun was half its mass?
A The pull of gravity from the Sun would only be half as strong.
B The pull of gravity from the Sun would be a quarter of what it was.
C The pull of gravity from the Sun would not change.
D The pull of gravity from the Sun would only be twice as strong.
The Sun’s effect on Earth change if the Sun was half its mass, the pull of gravity from the Sun would only be half as strong and is denoted as option A.
What is Gravity?This is referred to as the universal force of attraction which acts on all matters and is dependent on some parameters such as mass etc.
The increase in mass denotes a corresponding increase in gravity and vice versa which is therefore the reason why if the Sun was half its mass, then the pull of gravity from the Sun would only be half as strong.
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Two friends challenge each other to a race up a flight of stairs (h=4.0m) Joe, who has a mass of 150kg, makes the climb in 8.0s while mike, 120kg took 5.0s to make the climb. Use g=10m/s^2
A.) Explain why joe did more work than mike.
B.) Explain why mike was more powerful than joe.
PLEASE HELP!!!
Answer:A
Explanation: i think
WILL GIVE BRAINLIEST TO CORRECT ANSWER
Answer:
birr i am not smart i d know what to do
Explanation:
pls mark as brainliest
Compute the average acceleration during the time interval t=0 to t=10s .
Express your answer in meters per second squared to two significant figures
The average acceleration during the time interval t=0 to t=10s is 1.67 m/s².
What is average acceleration?
The average acceleration of an object is the rate of change of velocity of an object with time.
Mathematically, the average acceleration of an object is given as;
a = Δv/Δt
a = (v₂ - v₁)/(t₂ - t₁)
where;
v₂ is the final velocityv₁ is the initial velocityt₂ is the final time of motiont₁ is the initial time of motionFrom the graph,
the initial velocity at time of 0 second = 0 km/h
the final velocity at time of 10 seconds = 60 km/h = 16.67 m/s
the initial time = 0 s
the final time = 10 s
The average acceleration of the car is calculated as follows;
a = (16.67 m/s - 0 m/s) / (10 s - 0 s)
a = 1.67 m/s²
Thus, the average acceleration of the car increases with increase in the rate of change of displacement with time.
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A spacecraft orbits an unknown planet at a distance of 52 * 10 ^ 7 m from its center The period of its orbit is 52 hoursWhat is the mass of the planet ?
Answer:
m V^2 / R = G M m / R^2
M = R V^2 / G balancing forces
V = 2 pi R / T speed of craft
M = 4 pi^2 R^3 / (G * T^2) substituting for V
M = 4 pi^2 * 52E21 / (6.67E-11 * 1.30E7) = 39.5 * 52 / (6.67 * 1.3) * 10^25 kg
M = 2.37E27 kg
note mass of earth = 5.98E24 kg - should check mass obtained
A wire of length l is drawn such that its diameter is reduced to half its orginal diameter. if the initial resistance of the wire were 10 ohm, its resistance would be
a) 40 ohm
b) 60 ohm
c) 120 ohm
d) 160 ohm
Find the charge Q that requires 96J of energy to be moved through a potential difference of 16V ?
According to the given statement the charge Q is 6 coulomb that requires of energy to be moved through a potential difference .
What is an example of a potential difference?Note that whenever a voltage is stated, it refers to the difference in potential between two places. Every battery, for instance, has two terminals, and its voltage seems to be the difference in potential between them.
How is potential difference measured?The voltmeter is a tool used to measure potential difference. Some varieties, like voltmeters, feature a pointer on a dial, but digital displays are more common. To detect the potential difference across a circuit element, you must connect a voltmeter in parallel, unlike an ammeter.
Briefing:W is work done
V is potential difference
Work done
W = 96J
V = 16
W=Q×V
Q=W÷V
Q = 96 ÷ 16
Q = 6 Coulomb.
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An impulse of 24 Ns acts on a baseball from a bat. What is the force applied to the ball from bat if the ball is in contact with the ball for only 0.0007s.
The force applied to the ball from bat if the ball is in contact with the ball for only 0.0007 s is 34.29 KN
J = F * t
J = Impulse
F = Force
t = Time
J = 24 N s
t = 0.0007 s
F = J / t
F = 24 / 0.0007
F = 34.29 KN
Impulse is the rate of change of momentum in an object. It can simply be defined as force acting on an object over a period of time to change the object's momentum. So,
J = Δp = F Δt
Therefore, the force applied to the ball from bat is 34.29 KN
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module 1 question 16
A soft tennis ball is dropped onto a hard floor from a height of 1.95 m and rebounds to a height of 1.44 m. (Assume that the positive direction is upward.)
(a) Calculate its velocity just before it strikes the floor.
m/s
(b) Calculate its velocity just after it leaves the floor on its way back up.
m/s
(c) Calculate its acceleration during contact with the floor if that contact lasts 3.50 ms.
m/s2
(d) How much did the ball compress during its collision with the floor, assuming the floor is absolutely rigid?
m
The velocity of the ball just before it strikes the floor is -6.18 m/s. The velocity of the ball just after it leaves the floor is 5.3 m/s. Acceleration during contact with the floor is 3280 m/s^2. The compression of the ball during its collision with the floor is -9.42*10^-4 m
(a) The ball dropped from a height 1.95 meters. The velocity just before it strikes the floor is calculated by the kinematic equation. The initial velocity is zero.
v^2 = u^2 + 2aS
v^2 = 0 + 2*-9.8*(0-1.95)
V = -sqrt(38.22) = -6.18 m/s
(b) The velocity just after it leaves the floor on its way back up. The initial velocity is zero in this case. The ball rebounds to a height of 1.44 m.
v^2 = u^2 + 2aS
v^2 = 0 + 2*-9.8*(1.44-0)
v = sqrt(28.22) = 5.3 m/s
(c) The acceleration during contact with the floor is calculated where time is 3.50 ms.
Time in seconds = 3.5/1000 = 0.0035
a = change in velocity/time
a = (5.3 m/s - -6.18 m/s)/0.0035
a = 11.48/0.0035 = 3280 m/s^2
(d) Assuming the floor is absolutely rigid. The amount which the ball compress during its collision with the floor is given as,
v^2 = u^2 + 2aS
S = (v^2 - u^2)/2a
S = (-6.18 m/s - 0)/2*3280 m/s^2
S = -9.42*10^-4 m
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