calculate the phph of a 0.10 mm solution of hydrazine, n2h4n2h4 . kbkb for hydrazine is 1.3×10−61.3×10−6

The pH of a 1.0 L solution will be calculated after adding 0.010 mol of solid NaOH to the original buffer solution.

To determine the pH of the solution after the addition of NaOH, we need to consider the properties of the buffer solution and the effect of NaOH on its pH. A buffer solution consists of a weak acid and its conjugate base (or a weak base and its conjugate acid) and helps maintain a relatively stable pH when small amounts of acid or base are added.

When solid NaOH is added to the buffer solution, it dissociates into Na+ and OH- ions. The OH- ions will react with the weak acid component of the buffer, causing the formation of water and the conjugate base of the weak acid. This reaction reduces the concentration of the weak acid in the solution, shifting the equilibrium towards the basic side.

The addition of a small amount of NaOH to the buffer solution will result in a small change in pH. The extent of the pH change will depend on the initial buffer capacity and the amount of NaOH added. If the buffer is strong and has a high capacity, the pH change will be relatively small.

To calculate the exact pH, we need to know the initial concentrations of the weak acid and its conjugate base in the buffer solution and their dissociation constants (Ka). With this information, we can use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the concentrations of the weak acid and its conjugate base, to calculate the pH after the addition of NaOH.

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Heres the best help i can give you There is a couple different ways to determine if a bond is ionic or covalent. By definition, an ionic bond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals. So you usually just look at the periodic table and determine whether your compound is made of a metal/nonmetal or is just 2 nonmetals

Answer:

B) a substance's color and odor changed        Explanation: A signal that a chemical change has occurred is when its odor (its smell) or its appearance has changed.

The ratio between the energy and oxygen is 21.36 kJ/g of oxygen.

According to the given balanced equation:C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ. The balanced equation tells us that one molecule of C_{2}H_{5}OH reacts with two molecules of O2 to form two molecules of CO2, three molecules of H_{2}O, and 1367 kJ of energy. Therefore, to determine the ratio between energy and oxygen, we need to first find the energy released per mole of O2 reacted. To do this, we need to use the energy released by the combustion of 1 mole of C_{2}H_{5}OH, which is given as 1367 kJ. So, 1 mole of C_{2}H_{5}OH releases 1367 kJ of energy. To balance the equation, 2 moles of O2 are required for every mole of C_{2}H_{5}OH reacted. So, 2 moles of O2 is equivalent to 1367 kJ of energy. Therefore, the energy released per mole of O2 is 1367/2 = 683.5 kJ/mol. Oxygen has a molar mass of 32 g/mol and therefore the mass of one mole of oxygen is 32 g/mol. Using the molar mass of oxygen and the energy released per mole of O2, we can calculate the energy released per gram of oxygen as follows: Energy released per gram of O2 = Energy released per mole of O2 / Molar mass of O2= 683.5 / 32 = 21.36 kJ/g. Therefore, the ratio between the energy and oxygen is 21.36 kJ/g of oxygen.

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complete question: C_{2}H_{5}OH + 2O_{2} → 2CO_{2} + 3H_{2}O + 1367 kJ

What is the ratio between the energy and oxygen based on the equation?

-[?] kJ

[?]mol O2

The percent abundance of the rarest of these three isotopes of iron is 0.965%.Hence, Option (C) is correct.

Given Data:

5426Fe (53.94 amu), 5626Fe (55.93 amu), and 5726Fe (56.94 amu).

Most common isotope, 5626Fe accounts for 91.75% of iron atoms.

Average atomic mass of iron is 55.85 amu.

To find: The percent abundance of the rarest of these three isotopes of iron.

Solution:

The average atomic mass of iron is given as follows;

Average atomic mass = Σ (isotopic mass × fractional abundance)

Rearranging this equation, fractional abundance = (isotopic mass/average atomic mass) × 100%

Let's find the fractional abundance of all three isotopes of iron:

56 26 Fe (most abundant isotope)Fractional abundance = (55.93/55.85) × 100%

Fractional abundance = 1.001%54 26 Fe

Fractional abundance = (53.94/55.85) × 100%Fractional abundance = 0.965%57 26 Fe

Fractional abundance = (56.94/55.85) × 100%Fractional abundance = 1.98%

Thus, the percent abundance of the rarest of these three isotopes of iron is 0.965%.Hence, Option (C) is correct.

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Answer:

The cool people like me XD

Explanation:

Answer:

Solid – In a solid, the attractive forces keep the particles together tightly enough so that the particles do not move past each other. Their vibration is related to their kinetic energy. In the solid the particles vibrate in place. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart.

Explanation:

Hope this helped Mark BRAINLIEST!!!

The concentration of Cd2+ ion in the 0.022 M Cd(NO3)2 solution that is also 1.0 M NH3 at this temperature,

Kf for Cd(NH3)42+ is 1.0 × 10−5 M.

The given constants are:

Temperature (T) = not given

Kf (Formation constant) for

[Cd(NH3)4]2+ = 1.6 x 10^7

Kf = (4)2 / ([Cd2+][NH3]4) [Cd2+]

= (4)2 / (Kf [NH3]4)

The given values are:

Initial concentration of Cd(NO3)2 solution = 0.022 M

Initial concentration of NH3 solution = 1.0 MCd2+ is a part of complex ion, Cd(NH3)42+.

Cd2+ forms a complex ion by reacting with four NH3 molecules.  

Cd2+ + 4NH3 ⇌ Cd(NH3)42+

In this reaction, Cd2+ ion reacts with four NH3 molecules to form Cd(NH3)42+ complex ion.

Cd2+ has an equilibrium constant (Kf) of 1.6 x 107 for the complex ion formation.

Cd2+ and NH3 react to form the complex ion, Cd(NH3)42+ as follows:

[Cd2+][NH3]4 ⇌ [Cd(NH3)4]2+

We know that

Kf = ([Cd(NH3)4]2+ ) / ([Cd2+][NH3]4)

Kf = 1.6 × 107

= [Cd(NH3)4]2+ / ([Cd2+][NH3]4) [Cd2+]

= 4^2 / (Kf [NH3]4)[Cd2+]

= (4^2) / (1.6 × 107 × 1.0^4)[Cd2+]

= 1.0 × 10−5 M

Therefore, the concentration of Cd2+ ion in the 0.022 M Cd(NO3)2 solution that is also 1.0 M NH3 at this temperature,

Kf for Cd(NH3)42+ is 1.0 × 10−5 M.

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Answer: 3.09 g

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} H_2SO_4=\frac{2.70g}{98g/mol}=0.0275moles[/tex]

The balanced chemical equation is

[tex]2KOH+H_2SO_4\rightarrow 6H_2O+K_2SO_4[/tex]  

According to stoichiometry :

1 mole of [tex]H_2SO_4[/tex] require 2 moles of [tex]KOH[/tex]

Thus 0.0275 moles of [tex]H_2SO_4[/tex] will require=[tex]\frac{2}{1}\times 0.0275=0.0551moles[/tex]  of [tex]KOH[/tex]  

Mass of [tex]KOH=moles\times {\text {Molar mass}}=0.0551moles\times 56g/mol=3.09g[/tex]

Thus 3.09 g of KOH is required to react completely with 2.70 grams of

[tex]H_2SO_4[/tex]

Answer:

huh,eat wet sand b4heating iron wool??

Answer:

Please find the definition and example of neutralization reaction below

Explanation:

In chemistry, neutralization reaction is a type of reaction involving a base and an acid to form salt and water. In other words, when an acid and a base comes together chemically to form a salt and water, a neutralization reaction is said to occur.

For example; in a reaction between sodium hydroxide (NaOH) and hydrogen chloride (HCl) as follows:

HCl(aq) + NaOH(aq) → NaCl(s) + H2O(l)

In this neutralization reaction, the HCk is the acid while the NaOH is the base (reactants). For the products, the NaCl is the salt while H2O is water.

Answer : The element that is reduced in the given reaction is hydrogen (H).

Explanation: In the given reaction, Zn (s) 2 HCl (aq) → ZnCl₂ (aq) H₂ (g), Zinc (Zn) is oxidized to form Zinc chloride (ZnCl2). The reduction occurs in the other half of the reaction, where hydrogen cation (H+) from HCl is reduced to hydrogen (H2) gas. The reduction occurs because hydrogen is gaining electrons, which is the opposite of oxidation.The redox reaction in question can be broken down into two half-reactions:Zn (s) → Zn2+ (aq) + 2 e- (reduction half-reaction)2 H+ (aq) + 2 e- → H2 (g) (oxidation half-reaction)Hence, the element that is reduced in the given reaction is hydrogen (H).

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Answer:

things like hair color, eye color, skin color, size of lips, curly or straight hair, are things that could be passed down to an offspring. Things like tattoos wont be passed down.

Explanation:

things like hair color, eye color, etc. get passed down because those are inheritable traits and things like tattoo aren't.

The answer is hclo4 and naclo4

Explanation:Buffer solutions are solutions that can resist changes in pH upon addition of acid or base. They are mixtures of weak acids and their corresponding weak bases or mixtures of salts of weak acids and their corresponding strong bases.A buffer solution must have an appreciable amount of both a weak acid and its conjugate base or a weak base and its conjugate acid.

Therefore, the combination of a strong acid and a strong base cannot produce a buffer solution because they do not have the necessary weak acid or base species.hno2 and nano2 can produce a buffer solution because nitrous acid is a weak acid and sodium nitrite is its conjugate base.hcn and nacn can produce a buffer solution because hydrogen cyanide is a weak acid and sodium cyanide is its conjugate base.nh3 and (nh4)2so4 can produce a buffer solution because ammonia is a weak base and ammonium sulfate is a salt of its conjugate acid.nh3 and nh4br can produce a buffer solution because ammonia is a weak base and ammonium bromide is a salt of its conjugate acid.hclo4 and naclo4 cannot produce a buffer solution because both are strong acids and therefore, they don't have any weak acid or base species.

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Answer:

the energy levels and orbitals the electrons are in

Explanation:

i just took the test :)

The energy levels and orbitals the electrons are in. Hence, option D is correct.

An atom contains a central nucleus surrounded by one or more electrons.

The quantum numbers of electrons represent the probable distance of the electron from the nucleus. It refers to the size of the orbital and the energy level an electron is placed in.

Hence, option D is correct.

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The conversion of a carboxylic acid to an amide is accomplished by the interaction of the acid with a reagent capable of converting the carboxylate ion into the amide anion1.

Here's the mechanism for this conversion:The mechanism of this reaction is shown below:The first step is the addition of the nucleophile, which is the nitrogen in the amine, to the carbonyl carbon of the carboxylic acid. This addition causes the formation of a tetrahedral intermediate that is then protonated to form an imidic acid. The intermediate loses water to form an amide anion. When a molecule of water is removed, an amide is generated from the reaction between the carboxylic acid and the amine. Here are the structures of amide anion 1 and carbinolamine 6:Structures of amide anion 1 and carbinolamine 6 are given as follows:Image transcriptions:Image 1:Structure of amide anion 1:Image 2:Structure of carbinolamine 6:

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1. In the beginning, cobalt ions combine with six water molecules and form a complex ion, hexaaquacobalt(II) as shown below:[Co(H2O)6]2+ (aq). The hexaaquacobalt(II) ion (pink in colour) is dominant here.

After that, the hexaaquacobalt(II) ion combines with four chloride ions, forming the tetrachlorocobalt(II) ion.[CoCl4]2-(aq) + 6H2O(1)Here, the tetrachlorocobalt(II) ion (blue) is the dominant species.

2.The process of forming tetrachlorocobalt(II) is endothermic. The temperature of the solution decreases when CoCl4 is formed. It means that the energy is absorbed from the surroundings in the formation of the complex ion.

3. Le Chatelier's principle can be used to determine the effect of changing different factors on the equilibrium of this reaction. Some of the ways to shift the equilibrium of this reaction are  a. Changing the concentration of the reactants or products. b. Changing the temperature of the reaction. c. Changing the pressure of the reaction.

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Answer:

pass

Explanation:

pass

Cooking an egg is endothermic because the egg gains heat from the surrounding. The formation of snow is exothermic because water loses heat to the surroundings when it becomes snow.

The endothermic process refers to the process in which heat is absorbed, while the exothermic process refers to the process in which heat is released.

The egg receives/absorbs heat from a heat source,(e.g. the stove), which raises the temperature of the egg and causes it to cook, making it an endothermic process.

On the other hand, heat is released from the water molecule when the water vapor present in the atmosphere condenses and freezes to form snow. Therefore,  the formation of snow is exothermic.

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Cooking an egg is endothermic because the egg gains heat from the surroundings, while the formation of snow is exothermic because water loses heat to the surroundings, resulting in the formation of snow.

In terms of energy transfer, an endothermic process absorbs heat from the surroundings, while an exothermic process releases heat to the surroundings. When cooking an egg, heat is applied to the egg through methods such as boiling, frying, or baking. The egg absorbs heat from the surrounding environment to cook and undergo chemical and physical changes. As a result, cooking an egg is an endothermic process because the egg gains heat from its surroundings.

On the other hand, the formation of snow occurs when water vapor in the atmosphere condenses into ice crystals. This process is exothermic because water vapor loses heat to the surroundings, causing the water molecules to slow down and form a solid structure. The release of heat during this phase transition results in the formation of snow. Therefore, the correct explanation is that cooking an egg is endothermic because the egg gains heat from the surroundings, while the formation of snow is exothermic because water loses heat to the surroundings, leading to the formation of snow.

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The correct name for the compound N₂O₄ is dinitrogen tetroxide. The formula N₂O₄ represents the molecule dinitrogen tetroxide.

Hence, option D (dinitrogen tetroxide) is the correct answer.

The formula for nitrogen monoxide is NO, nitrogen dioxide is NO₂, and nitrogen trioxide is N₂O₃. The term "tetranitrogen dioxide" (Option B) is incorrect as it contains the prefix "tetra-," which refers to four. There are only two nitrogen atoms present in the molecule.

The term "dinitrogen quadoxide" (Option C) is also incorrect because it does not exist. The term quadoxide does not apply to any known compound.

Hence, the correct name of the compound N₂O₄ is dinitrogen tetroxide (Option D).

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The bond's yield to maturity (YTM) is 11.46%.

To calculate the bond's yield to maturity (YTM), the current yield and capital gains yield must be determined. Then, add the two yields together to get the YTM. Capital gains yield (CGY) is defined as the change in price of the bond divided by the price at the beginning of the period, all of which must be divided by the number of periods. Capital gains yield is a prediction of how much the value of an investment would rise or fall over a period of time based on the rate of return earned on the investment over that period of time.

The current yield formula is:

CY = C / P

where C is the coupon rate and P is the current price of the bond.

From this we can say that,

CY = 12% / P

where P is $1,000 / 2^9 = $389.42

CY = 12% / $389.42 = 3.08%

To determine the CGY, substitute the given values in the formula:

11.46% = CY + CGYCGY = 11.46% - 3.08% = 8.38%

Finally, we'll use the formula for yield to maturity (YTM) which is given by:

YTM = CY + CGYYTM = 3.08% + 8.38% = 11.46%

Therefore, the bond's yield to maturity (YTM) is 11.46%.

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Answer:

13.4 (w/w)% of CaCl₂ in the mixture

Explanation:

All the Cl⁻ that comes from CaCl₂ (Calcium chloride) will be precipitate in presence of AgNO₃ as AgCl.

To solve this problem we must find the moles of AgCl = Moles of Cl⁻. As 2 moles of Cl⁻ are in 1 mole of CaCl₂ we can find the moles of CaCl₂ and its mass in order to find mass percent of calcium chloride in the original mixture.

Moles AgCl - Molar mass: 143.32g/mol -:

0.535g * (1mol / 143.32g) = 3.733x10⁻³ moles AgCl = Moles Cl⁻

Moles CaCl₂:

3.733x10⁻³ moles Cl⁻ * (1mol CaCl₂ / 2mol Cl⁻) = 1.866x10⁻³ moles CaCl₂

Mass CaCl₂ -Molar mass: 110.98g/mol-:

1.866x10⁻³ moles CaCl₂ * (110.98g/mol) = 0.207g of CaCl₂ in the mixture

That means mass percent of CaCl₂ is:

0.207g CaCl₂ / 1.55g * 100 =

Molality of the solution containing 12.5 grams of ethylene glycol dissolved in 135 grams of water is 1.49 mol/kg.

The given problem can be solved by using the formula; Molality (m) = moles of solute / mass of solvent in kgThe molecular weight of ethylene glycol (C2H6O2) is (2 × 12) + (6 × 1) + (2 × 16) = 62 g/mol.The given mass of ethylene glycol is 12.5 grams.The number of moles of ethylene glycol can be calculated by dividing the given mass by the molecular weight.12.5 g = 0.2016 mol 62 g/molNow, the mass of water is 135 grams, and when converted to kg, it will be 0.135 kg.Molality (m) = 0.2016 mol / 0.135 kg = 1.49 mol/kgHence, the molality of the solution containing 12.5 grams of ethylene glycol dissolved in 135 grams of water is 1.49 mol/kg.

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In the late 1970s, proponents of rational expectations argued that (a.) the Fed should not attempt to aggressively fight inflation.

Proponents of rational expectations in the late 1970s argued that the Fed should not aggressively fight inflation because they believed that people have rational expectations and would adjust their behavior accordingly.

According to their theory, if the central bank attempted to stimulate the economy by expanding the money supply, individuals and firms would anticipate the inflationary effects and adjust their expectations, wages, and prices accordingly.

As a result, the expansionary monetary policy would be ineffective in stimulating real economic activity, but would only lead to higher inflation.

Therefore, they advocated for a more hands-off approach by the central bank and argued that monetary policy should primarily focus on maintaining price stability.

The complete question should be:

In the late 1970s, proponents of rational expectations argued that

a. the Fed should not attempt to aggressively fight inflation.

b. the sacrifice ratio was smaller than previously thought.

c. the short run was relatively long.

d. None of the above is correct

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Answer:

d.straight line motion

Answer:

d.) straight line motion

Explanation:

i just took the k12 test

Answer:

According to Boyle's Law, an inverse relationship exists between pressure and volume. Boyle's Law holds true only if the number of molecules (n) and the temperature (T) are both constant.

Answer: This is due to a dominance of political parties over ... legislative process, the influence opposition has on amending the government bills and formal and effective

Explanation: hope u get it right

To produce 6.5 moles of [tex]P_4O_{10[/tex], we would need 26 moles of [tex]PH_3[/tex].

To determine the number of moles of [tex]PH_3[/tex] required to produce 6.5 moles of [tex]P_4O_{10[/tex], we need to consider the balanced chemical equation for the reaction. The balanced equation for the combustion of phosphine ([tex]PH_3[/tex]) to form tetraphosphorus decoxide ([tex]P_4O_{10[/tex]) is:

4 PH3 + 10 O2 → P4O10 + 6 H2O

From the balanced equation, we can see that 4 moles of [tex]PH_3[/tex] react to produce 1 mole of [tex]P_4O_{10[/tex]. Therefore, the ratio of moles of [tex]PH_3[/tex] to moles of [tex]P_4O_{10[/tex] is 4:1.

If we want to produce 6.5 moles of [tex]P_4O_{10[/tex], we can calculate the number of moles of PH3 required using this ratio:

6.5 moles P4O10 × (4 moles [tex]PH_3[/tex] / 1 mole P4O10) = 26 moles PH3

Therefore, to produce 6.5 moles of [tex]P_4O_{10[/tex], we would need 26 moles of [tex]PH_3[/tex].

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