Calculate the volume of an
object with dimensions
measuring:
9.0 mm x 2.0 mm x 2.0 mm
[ ? ] mm3

Explanation:

Have a good luck with ur exam

Answer:

25 gram

Explanation:

the minimum amount of the reactant needed is equal to the mass of the product because of the law of conservation of mass ok

Answer:

4. D sounds like the best option.

5. D is the correct answer.

Explanation:

You're Welcome

Answer:

1. Stop throwing trash and bottles in lakes because it can have our animals live longer and not have issues

2. Reducing the number of bags you use from the store because they can end up being on the ground and cause plenty of damage around us

3. probably trying not to having fires because there is alot of problems that are happening like the wildfires in californa which is leading to our animals and trees dying

hope this helps

have a good day :)

Explanation:

Answer:

Total pressure of the mixture = 1 atm

Partial pressure of He = 0.863 atm

Partial pressure of Ar  = 0.0173 atm

Partial pressure of Ne = 0.1197 atm

We confirm that the sum of partial pressure of each gas valu

Explanation:

STP conditions are:

1 atm of pressure and

273K of T°

We can also say that those value reffers to 1 mol.

We determine the moles of each:

5 g . 1mol / 4g = 1.25 moles of He

1g . 1mol / 39.9 g = 0.0250 moles of Ar

3.5g . 1mol / 20.18 g = 0.173 moles of Ne

Total pressure of a mixture can be obtained from the Ideal Gases Law.

P . V = n . R . T

Total moles: 1.25 + 0.025 + 0.173 = 1.448 moles

But now, we need the volume. We know that 1 mol is contained at 22.4L at STP.

1.448 mol . 22.4L / 1 mol = 32.4 L

That's the volume for our mixture. We replace:

32.4 L . P  = 1.448 mol . 0.082 . 273K

P = (1.448 mol . 0.082 . 273K) / 32.4L = 1 atm

Now we can obtained the partial pressure of each gas from mole fraction

Mol of gas / Total pressure = Partial pressure of gas / Total pressure

Partial pressure of He = (1.25 / 1.448) . 1 atm = 0.863 atm

Partial pressure of Ar = (0.025 / 1.448) . 1 atm = 0.0173 atm

We know that sum of partial pressure is 1 - (Mole fraction He + Mole fr. Ar)

Partial pressure of Ne = 1 - (0.863 + 0.0173) = 0.1197 atm

We confirm that the sum of partial pressure of each gas values the total pressure of the mixture: 0.863 + 0.0173 + 0.1197 = 1

Answer:

Three isomers

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

Explanation:

Complete question

How many isomers are there with the following descriptions?

a) Alcohol with formula C3H8O

Solution

There are total 3 carbon atoms in this alcohol. Hence, there will be three isomers of Alcohol with formula C3H8O .

The three isomers will comprise of alcohol group (OH) attached to the three carbon atoms one by one.

Isomer I  CH3-CHOH - CH3

Isomer 2 CH2OH-CH2-CH3

Isomer 3  CH3-CH2-CH2OH

The correct question is: 10 kg of R-134a at 300 kPa fills a rigid container whose volume is 14 L. Determine the temperature and total enthalpy in the container. The container is now heated until the pressure is 600 kPa. Determine the temperature and total enthalpy when the heating is completed.

Answer: The temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.

Explanation:

Given: Mass = 10 kg

Volume = 14 L

Final pressure = 600 K

First, convert volume from L to [tex]m^{3}/kg[/tex] as follows.

[tex]v_{1} = \frac{14 \times 10^{-3}}{10}\\= 0.0014 m^{3}/kg[/tex]

According to the R-134a tables at 300 kPa and [tex]0.0014 m^{3}/kg[/tex].

[tex]h_{1}[/tex] = 54.6 kJ/kg

[tex]T_{sat}[/tex] = 0.7 C

[tex]u_{1}[/tex] = 54.1 kJ/kg

Now, at the state 2 [tex]p_{2}[/tex] = 600 kPa and [tex]v_{2} = v_{1} = 0.0014 m^{3}/kg[/tex]

This means that the final temperature at state 2 is [tex]T_{2} = T_{sat} = 21.6^{o}C[/tex]

Hence, the change in enthalpy is calculated as follows.

[tex]\Delta H = m(h_{2} - h_{1})\\= 10(84.6 - 54.6)\\= 300 kJ[/tex]

The first law is applied to transfer the heat transfer as follows.

[tex]Q = m(u_{2} - u_{1})\\= 10(83.8 - 54.1) kJ\\= 297 kJ[/tex]

Thus, we can conclude that the temperature is [tex]21.6^{o}C[/tex] and total enthalpy when the heating is completed is 300 kJ.

Answer:

T = 246 K

Explanation:

Given that,

Number of moles, n = 0.750 mol

The volume of the cylinder, V = 6850 mL = 6.85 L

Pressure of the gas, P = 2.21 atm

We need to find the temperature of the gas stored in the cylinder. We know that,

PV= nRT

Where

R is gas constant

T is temperature

So,

[tex]T=\dfrac{PV}{nR}\\\\T=\dfrac{2.21\times 6.85}{0.75\times 0.0821}\\T=245.85\ K[/tex]

or

T = 246 K

So, the temperature of the gas is equal to 246 K.

Answer:

In all the patients with rheumatoid arthritis RF is not present. It can also be witnessed in patients with conditions like hepatitis, bacterial endocarditis, and tuberculosis. Some of the reasons that can also produce false-positive results for RF assay are lipemic, hemolyzed, or heavily contaminated serum, other rheumatic diseases like systemic lupus erythematous, reading test results post the specified time of two minutes, and due to some of the chronic infectious diseases like hepatitis, tuberculosis, and syphilis.

b. The symptoms of the oatient like inflammation and pain in joints and the results of the lab indicate that the synovial fluid is drying and formation of crystal is taking place. These are the conditions that suggests the existence of rheumatoid arthritis.

c. In the given case, the first choice diagnosis would be the blood test that would show the presence of anti-CCP antibodies and the drying of synovial fluid. The presence of anti-CCP antibodies results in wear and tear in the joints, thus showing the diseased conditions.

Answer:

When they're sleeping

Explanation:

After they've been drugged

Answer:

129

Explanation:

Answer:

32.57g

Explanation:

mass = mole x molar mass

mass of LiBr = 0.375 x 86.85

mass = 32.57g

Answer:

Explanation

i k the ansewer

Answer:

number of moles is inversely proportional to the Temperature

Explanation:

As we know

PV = nRT

where P is the pressure

V is the volume

n is the number of moles

R is the gas constant

and T is the temperature

If we see the equation, we can find that n is inversely proportional to the Temperature

Answer:

28500 years

Explanation:

Applying,

A = A'([tex]2^{x/y}[/tex])............... Equation 1

Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.

From the question,

Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.

Substitute these values into equation 1

1 = 0.0313([tex]2^{x/5700}[/tex])

[tex]2^{x/5700}[/tex] = 1/0.0313

[tex]2^{x/5700}[/tex]  = 31.95

[tex]2^{x/5700}[/tex] ≈ 32

[tex]2^{x/5700}[/tex] ≈ 2⁵

Equating the base and solve for x

x/5700 ≈ 5

x ≈ 5×5700

x ≈ 28500 years

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= [tex]Volume\times density[/tex]

= [tex]1\times 1[/tex]

= [tex]1 \ kg[/tex]

The mole of NaCl will be:

= [tex]\frac{mass}{Molar \ mass}[/tex]

= [tex]\frac{25}{58.44}[/tex]

= [tex]0.43[/tex]

hence,

The molarity will be:

= [tex]\frac{number \ of \ mole}{Volume \ of \ solution}[/tex]

= [tex]\frac{0.43}{1}[/tex]

= [tex]0.43 \ M[/tex]

The molality will be:

= [tex]\frac{mole \ of \ solute}{Weight \ of \ solvent}[/tex]

= [tex]\frac{0.43}{1}[/tex]

= [tex]0.43 \ m[/tex]

Answer:

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Answer:

Rutherford used scientific investigation to study atoms.

Scientist who used scientific investigations to study atoms is Rutherford.

Atoms are the basic fundamental or functional unit of any substance present in the nature.

Rutherford is also known as the father of nuclear physics and he did scientific investigation on the massive part of atom called nucleus he discovered that there are two types of radiation, coming from the uranium atom are alpha and beta particles.

Scientific investigation is a method in which scientist will study, perform and observe results for the experiment.

Hence Rutherford used scientific investigation.

To know more about Scientific investigation, visit the below link:
https://brainly.com/question/17216882

when you strongly heat the potassium chlorate it leaves oxygen if you'll not heat it strongly to decompose it the oxygen would not release and the compound will remain thermally unstable.

Heating of Potassium Chlorate results into decomposition of Potassium Chloride and Oxygen gas.

When KClO₃ is heated strongly, it breaks down, releasing oxygen gas and leaving behind a thermally stable (i.e., heat-insensitive) solid residue of an ionic potassium compound.

If enough heat is not provided to potassium chlorate then it will not decompose into its substituent products and also some of the potassium chloride product splattered out of the crucible during the heating process.

Learn more:

brainly.com/question/12959023

Answer:

approximately 15.1 grams.

Explanation:

The key to chemistry is to change everything to moles. Then when you have the answer in moles change the answer back to grams, liters, or whatever you want.

change 25 grams of potassium chlorate to moles.

calculate the gram molecular mass of potassium chlorate.

Chlorate is Cl with 3 oxygens. ate = saturated. Chlorine has seven valance electrons when it is saturated six of these electrons are used by oxygen ( 2 electrons per oxygen) leaving only 1 electron.

1 K x 39 grams/mole

+1 Cl x 35.4 grams/ mole

+3 O x 16 grams/ mole

= 122.4 grams / mole Potassium Chlorate

25

122.4

= moles.

2.05 moles of Potassium Chlorate.

There is a 1:1 mole ratio. 1 mole of Potassium Chlorate will produce 1 mole of Potassium Chloride.

2.05 moles of Potassium Chlorate will produce 2.05 moles of Potassium Chloride.

Find the gram molecular mass of Potassium Chloride.

1 K x 39 = 39

+1 Cl x 35.4 = 35.4

= 74.4 grams / mole.

2.05 moles x 74.4 grams/ mole = 15.2 grams

Answer:

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Given :

A compound sodium trioxocarbonate (iv) decahydrate.

To Find :

The molecular mass of sodium trioxocarbonate (iv) decahydrate.

Solution :

We know, molecular formula of sodium trioxocarbonate (iv) decahydrate is :

Na₂CO₃.10H₂O

Now, we can calculate its molecular mass :

M = ( 2 × 23 ) + 12 + ( 3 × 16 ) + 10 × ( 1 × 2 + 16)

M = 46 + 12 + 48 + ( 10 × 18 )

M = 286 gram/mol

Hence, this is the required solution.

Answer:B

15 carbon atoms

Explanation:

Take shelter in a hard wall building

Close doors and windows cut off ventilation

Answer:

the answer should be Life Cicle Difference.

Answer: Option (D) Is the correct  Life cycle difference

Explanation: Hope it helps!

Good luck!!!

Answer:

pH = 12.52

Explanation:

Given that,

The [H+] concentration is [tex]3\times 10^{-13}[/tex].

We need to find its pH.

We know that, the definition of pH is as follows :

[tex]pH=-log[H^+][/tex]

Put all the values,

[tex]pH=-log[3\times 10^{-13}]\\\\pH=12.52[/tex]

So, the pH is 12.52.

To Find :

The number of molecules of carbon tetrachloride in 0.32 mol of

carbon tetrachloride.

Solution :

We know, 1 mole of any element/compound contains [tex]6.022 \times 10^{23}[/tex] number of atoms/molecules.

So, Number of molecules in 0.32 mol are :

[tex]n = 0.32 \times 6.022 \times 10^{23}\\\\n = 1.93 \times 10^{23}[/tex]

Therefore, number of molecules of carbon tetrachloride in 0.32 mol of

carbon tetrachloride are [tex]1.93 \times 10^{23}[/tex].