Can someone please help me with my Question #29 of The Quadratic Relations for me please?
Answers
Answer:
Calculate the first differences between the y-values:
[tex]\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19[/tex]
As the first differences are not the same, we need to calculate the second differences:
[tex]\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7[/tex]
As the second differences are the same, the relationship between the variable is quadratic and will contain an [tex]x^2[/tex] term.
--------------------------------------------------------------------------------------------------
To determine the quadratic equation
The coefficient of [tex]x^2[/tex] is always half of the second difference.
As the second difference is 2, and half of 2 is 1, the coefficient of [tex]x^2[/tex] is 1.
The standard form of a quadratic equation is: [tex]y=ax^2+bx+c[/tex]
(where a, b and c are constants to be found).
We have already determined that the coefficient of [tex]x^2[/tex] is 1.
Therefore, a = 1
From the given table, when [tex]x=0[/tex], [tex]y=12[/tex].
[tex]\implies a(0)^2+b(0)+c=12[/tex]
[tex]\implies c=12[/tex]
Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:
[tex]\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}[/tex]
Therefore, the quadratic equation for the given ordered pairs is:
[tex]y=x^2+6x+12[/tex]
Related Questions
In the figure below, find the value of cose:
8
-|- -|X X|L
A. 1
О в.г
OC. 1
O D.
X
Answers
Answer:
D
Step-by-step explanation:
cosΘ = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{x}{r}[/tex]
ƒ (x) = x² − 2x – 4.
What is the average rate of change for the quadratic function from x = − 1 to x =4
Answers
[tex]\begin{array}{llll} f(x)~from\\\\ x_1 ~~ to ~~ x_2 \end{array}~\hfill slope = m \implies \cfrac{ \stackrel{rise}{f(x_2) - f(x_1)}}{ \underset{run}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \\\\[-0.35em] ~\dotfill\\\\ f(x)= x^2-2x-4 \qquad \begin{cases} x_1=-1\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(-1)}{4 - (-1)} \\\\\\ \cfrac{[(4)^2-2(4)-4]~~ - ~~[(-1)^2-2(-1)-4]}{4+1}\implies \cfrac{4~~ - ~~(-1)}{5} \\\\\\ \cfrac{4+1}{5}\implies \cfrac{5}{5}\implies 1[/tex]
Simplify the following expression:
(x+3)-[(x+2)(x³ - 1)]
O A. - x4 - 2x - x+2
OB. -x-2x³ +2x+5
OC. --2x³ +1
OD. -x-2x²+2x+5
Answers
Simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
The options are:
A) -x⁴ - 2x - x + 2
B) -x⁴ - 2x³ + 2x + 5
C) -2x³ + 1
D) -x - 2x² + 2x + 5
We have an expression:
= (x + 3) - [(x + 2)(x³ - 1)]
[tex]\rm =x+3-\left(x+2\right)\left(x^3-1\right)[/tex]
[tex]\rm =x+3-x^4+x-2x^3+2[/tex]
[tex]\rm =-x^4-2x^3+2x+3+2[/tex]
[tex]\rm =-x^4-2x^3+2x+5[/tex]
Thus, simplification form of the provided expression is -x⁴-2x³+2x+5 option (B) is correct.
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ASAP ASAP ASAP ASAP!!!!! Pls help me
I didn’t study r.I.p
Answers
Answer:
1) Scalene
2) Equilateral
3) Isosceles
4) Right
5)Obtuse
Step-by-step explanation:
The requried correct match for the given triangle and its sides and angle has been shown.
Following the given characteristic the match of the the properties of triangle is given as:
Type of Triangle: Characteristics
Scalene: all side lengths and angles are different sizes
Equilateral: all side lengths are equal and all angles are 60°
Isosceles: two sides and their base angles are equal
Right: one angle is 90°
Obtuse: one angle is greater than 90°
Thus, the required match shown above is the correct match.
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I will give BRAINLIEST
Half of the road the boy walked at a speed of 6 m / min, the other half - at a speed of 4 m / min. Calculate the average walking speed of a boy
Answers
Answer:
5
Step-by-step explanation:
6 + 4 is 10
Half of 10 is 5
A pumpkin farmer collects 20 pumpkins randomly sampled from his pumpkin patch and weighs them. the mean
weight of the pumpkins is 26 lb. he wonders whether the weight of his pumpkins follows a normal distribution.
which answers are clear signs that the pumpkin weights are not normally distributed?
select all that apply.
the median pumpkin weight is 26 lb.
the median pumpkin weight is 35 lb.
75% of pumpkins in the sample have weights higher than the me
mean.
the median pumpkin weight is 10 lb.
about 68% of pumpkin weights are within one standard deviation of the mean.
Answers
The true statement about the pumpkin include:
the median pumpkin weight is 10 lbthe median pumpkin weight is 35 lb75% of pumpkins in the sample have weights higher than the mean.What is a median?The median is a value or quantity lying at the midpoint of a frequency distribution of observed values or quantities.
Here, the median pumpkin weight is 35 lb and 75% of pumpkins in the sample have weights higher than the mean.
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let x = -5/6 and y 4/3= . select all the expressions that have a positive value. select all that apply: a. x * y b. y/x c. x/y d. x + y e. x - y f. y - x
Answers
Step-by-step explanation:
A, ×* y = -10 / 9
B, y / x = -8 / 5
C, x / y = -5 / 8
D, x+ y = 1 / 2
E, x- y = - 13 / 6
F, y- x = 13 / 6
HELP!!! 100 PNTS+BRANLIEST TO QUICK AND CORRECT ANSWER!!!!!!!!
In the small town of Middleton, there are only two restaurants that serve pizza- a small family owned Italian restaurant and a new franchise pizza restaurant. In a recent review of the franchise, a food critic reported that the pizza was delicious as promised. The only negative review that the franchise received from the critic was in reference to the inaccurate delivery time quoted during the online order process. In response to the article, the franchise owner used a program to analyze the online pizza orders that took place during the week before the review. He chose to track the orders at 6pm each day. He recorded his results in the frequency table below. Use the frequency table to create a box and whisker plot of the On Time data values. In your final answer, include all calculations necessary to create the box and whisker plot. Use the frequency table to create a box and whisker plot of the Late data values. In your final answer, include all calculations necessary to create the box and whisker plot.
Answers
Answer:
Yes
Step-by-step explanation:
1. Yes , the data franchise owner is collecting, will be helpful in order to counter the criticism from the critic. As he has a record for every delivery they are making on daily basis.
2. The scenario is that for every fifth customer , the owner cross the four lines he makes. Thus a pack of five and easy to remember. As the data on regular week days is less, As can do the same for the third customer. Crossing the 2 lines for 3rd customer.
3. With this provision of crossing the third customer, the owner can have a better check on the late delivery. As it will bring in his notice earlier as compared to fifth crossing.
4. With the data as provided in the table, we can come to the conclusion that on weekends , i.e. both on time delivery and late deliveries are high in numbers. It must be because of high demand on that days. So owner must make some provision like hiring some more delivery boys for weekend in order to reduce the late deliveries.
A container holds 50 electronic components, of which 10 are defective. if 6 components are drawn at random from the container, the probability that at least 4 are not defective is . if 8 components are drawn at random from the container, the probability that exactly 3 of them are defective is .
Answers
Answer:
See below for answers and explanations
Step-by-step explanation:
Problem 1
We know that there's a probability of [tex]p=\frac{40}{50}=\frac{4}{5}=0.8[/tex] of choosing an electronic component that is not defective and a probability of [tex]q=\frac{10}{50}=\frac{1}{5}=0.2[/tex] of choosing an electronic component that is defective:
[tex]\displaystyle P(X\geq4)=P(X=4)+P(X=5)+P(X=6)\\\\P(X\geq4)=\binom{6}{4}(0.8)^4(1-0.8)^{6-4}+\binom{6}{5}(0.8)^5(1-0.8)^{6-5}+\binom{6}{6}(0.8)^6(1-0.8)^{6-6}\\\\P(X\geq4)=\frac{6!}{4!(6-4)!}(0.8)^4(0.2)^2+\frac{6!}{5!(6-5)!}(0.8)^5(0.2)^1+\frac{6!}{6!(6-6)!}(0.8)^6(0.2)^0\\ \\P(X\geq4)=0.90112[/tex]
So, if 6 components are drawn at random from the container, the probability that at least 4 are not defective is 0.90112
Problem 2
[tex]\displaystyle P(X=3)=\binom{8}{3}(0.2)^3(1-0.2)^{8-3}\\\\P(X=3)=\frac{8!}{3!(8-3)!}(0.2)^3(0.8)^5\\ \\P(X=3)\approx0.1468[/tex]
So, if 8 components are drawn at random from the container, the probability that exactly 3 are defective is 0.1468
The probability of exactly 3 of the containers being defective is given as 0.1468
What is probability?Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.
here, we have,
to solve for the probability
We have to set p as the probability of container being non- defective
We have p as the probability of container being defective 50 - 10 = 40
p = 40/50
= 0.8
q = 10/50
= 0.2
P(3) = 8c3 * 0.2² * 0.8⁵
= 0.1468
Hence the probability that the container has exactly 3 defective containers is 0.1468
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Murat has 2/3 kg of rice that he wants to put into bags that contain 3/10 kg of rice each?
How many bags of rice can Murat fill?
Answers
Answer:
Murat can fill 6/13 kg of rice
Step-by-step explanation:
because it has 2/3 kg of rice and 3/10 each and I added 6+2 and 3+10 hope it makes your day
Answer: Murat can fill 6/13 kg of rice
find the total area of the composite figure
Answers
719ft
office area=12(20)=240ft
storage=(20-12)(40-(12+15)=8(13)=104ft
home theater=25(15)=375ft
total area= 240+104+375=719ft
Anyone mind helping me solve this inequality? Step by step
Answers
By decomposing the figure in simpler shapes, we will see that the total area is:
a = 180 cm²
How to find the area of the composite figure?
Remember that the area of a rectangle of width W and length L is:
A = L*W
And the area of a triangle with base B and height H is:
A = B*H/2.
Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.
So the area of that part is:
A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²
Now, the bottom triangle has a base of 12 cm, and a height of:
15cm - 6cm = 9cm
Then its area is:
A' = 12cm*9cm/2 = 54cm²
This means that the total area of the figure is:
total area = 54cm² + 54cm² = 108cm²
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What is the correct expanded form and value!!
Pls hurry asap
Answers
Answer:
The answer you selected is correct. Because, [tex]\frac{4}{5} ^{3\\}[/tex]is 4/5, 3 times.
Attached is more explanatory information
Step-by-step explanation:
Answer:
B. [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}=\frac{64}{125}[/tex]
Step-by-step explanation:
(4/5) is raised to a numerical power of 3.
This is NOT [tex]\frac{4}{5}(3)[/tex] and NOT [tex]\frac{4}{5}+\frac{4}{5}+\frac{4}{5}[/tex].Instead, (4/5) is being multiplied by itself 3 times.
This is correctly shown by: [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}[/tex]This can be solved by multiplying the numerators and denominators, which also looks like this: [tex]4^3=64[/tex] and [tex]5^3=125[/tex].The exact form is: [tex]\frac{64}{125}[/tex].The complete expansion is written as: [tex]\frac{4}{5}\cdot\frac{4}{5} \cdot\frac{4}{5}=\frac{64}{125}[/tex]
You have the correct option selected.
What exponential expression is equal to 2^-5 . 2^8
Answers
[tex]~~2^{-5} \cdot 2^8\\\\=2^{-5+8}~~~~~~~~~~~~~~~~~~~~~;[a^m \cdot a^n = a^{m+n}]\\\\=2^3[/tex]
Howwwww????????
Howwwww
Answers
Answer:
How?
I don't know
haha
thanks for the points
4 out of every 7 students in a school eat a packed lunch. The rest eat a school meal.
Which of the following statements is correct?
47% of students eat a school meal
The ratio of school meal to packed lunch is 7 : 4
The ratio of packed lunch to school meal is 4 : 3
56% of students eat a packed lunch
Answers
So the ratio is 4:3
Sean operates a lawn-cutting business. He charges $15 for a single lawn and $25 for a front and back lawn. Sean made $475 from 25 customers.
Write a system of equations
Answers
The system of equations that models the given situation is given as follows:
x + y = 25.15x + 25y = 475.What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, the variables are given as follows:
Variable x: Number of single lawns cut.Variable y: Number of front and back lawns cut.He had 25 customers, hence:
x + y = 25.
He charges $15 for a single lawn and $25 for a front and back lawn, and made a total of $475, hence:
15x + 25y = 475
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For the polynomial function, find the requested value: f (x) = 10x2 − 4x − 5; f (−2)
Answers
The value of f(-2) in the polynomial is 43
How to evaluate the polynomial?The polynomial function is given as:
f(x) = 10x^2 − 4x − 5;
To calculate f (−2), we substitute -2 for x in f(x).
So, we have:
f(-2) = 10(-2)^2 - 4(-2) - 5
Evaluate the expression
f(-2) = 43
Hence, the value of f(-2) in the polynomial is 43
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How would I calculate the horizontal distance of a parabola?
Answers
Find the length of AC
Find the length of DC
Answers
Step-by-step explanation:
Here is the solution...hope it helps:)
(b) Work out the value of (√2+√8)^2
Answers
[tex]~~~\left(\sqrt 2 + \sqrt 8 \right)^2\\\\=\left(\sqrt 2 \right)^2 + \left(\sqrt 8 \right)^2 +2 \sqrt 2 \sqrt 8\\\\=2+8+2\sqrt{2 \cdot 8}\\\\=10+2\sqrt{16}\\\\=10+2(4)\\\\=10+8\\\\=18[/tex]
please help with this thank you!
Answers
Answer:
A. Half of
B. Twice
C. greater than
Step-by-step explanation:
The median of the box plot is the middle line of the box, so for set a it is approximately ten and for set b it is approximately 20. 10 is half of 20 and 20 is twice as much as 10.
Hope this helps
What is the value of X and the Segment AC is
Answers
Answer:
d)14
Step-by-step explanation:
use Pythagoras
a² = b² ,+ c²
50² = 48² + c²
2500 - 2304 = c²
196 = c²
√196 = c
c=14
Determine the equation of the line with slope 3 that passes through the point M(1, 2).
3x + y = 1
3x - y = -1
3x - y = 1
Ox-3y=-1
Answers
Answer:
3x - y = 1
Explanation:
Equation formula:
y - y1 = m(x - x1)
where m is slope, (x1, y1) are coordinates
Find Equation:
⇒ y - 2 = 3(x - 1)
⇒ y = 3x - 3 + 2
⇒ -3x + y = -1
⇒ 3x - y = 1
Equation of line in point slope form
y-y1=m(x-x1)y-2=3(x-1)y-2=3x-3y=3x-13x-y=1what’s the area of the base
Answers
Answer:
16 square units
Step-by-step explanation:
16 square units
What is the value of y when the value of x is 1?
Answers
Answer: y = 60
the value of y will be 60 when the value of x is 1.
Solution set = (1 , 60)
hope that helps...
Rita is ordering 4 bags of cat food from canada. each bag has a mass of 2.5kg . to determine the shipping costs, rita needs to know the total weight in pounds. what is the weight of the cat food in pounds?
Answers
Answer:
total weight in pounds = 22 lb
Step-by-step explanation:
Let's first find out the total weight in kilograms.
total weight = 4 x 2.5 kg = 10 kg
The approximation for kilograms (kg) to pounds (lb) is 1 kg = 2.2 lb.
So if 1 kg is 2.2 lb, 10 kg is 10 times more.
10 kg = 10 x 2.2 lb = 22 lb
what is the answer to −1.4+(−1.2)
Answers
Answer:
-2.6
Step-by-step explanation:
-1.4+(-1.2)
-1.4-1.2=-2.6
Hope this helps!
If not, I am sorry.
Find the volume of the cylinders. (Use π=3.14)
A. Height= 9ft ; radius= 3ft
B. Radius=13yd; height=8yd
Answers
Question 1
h= 9 ftr= 3 ftQuestion 2
h= 8 ydr= 13 yd Note that:h= heightr= radius To find:The volume of the given cylinders.
Solution:[tex]\huge\boxed{Formula: V=\pi{r}^{2}h}[/tex]
[tex]\huge\boxed{\red \pi \red = \red 3 \red . \red 1 \red 4}[/tex]
Let's solve!
Substitute the values according to the formula.
[tex]V=3.14×{3}^{2}×9[/tex]
[tex]\large\boxed{V= 254.34 \: {ft}^{3}}[/tex]
Let's work on question 2
Substitute the values according to the formula.
[tex]V=3.14×{13}^{2}×8[/tex]
[tex]\large\boxed{V= 4245.28 \: {yd}^{3}}[/tex]
3
Select the correct answer from each drop-down menu.
A function is a relation where each input value is assigned to
The
of a function is the set of all input valu
The
of a function is the set of all output val
To write the equation y= ax + b in function notation, substitut at least
exactly
less than
one output value.
es, for which the function is defined.
ues, for which the function is defined.
or y.
Nex
Answers
The range of a function is the set of all output values.
How to illustrate the function?A function is a relation where each input value is assigned to only one output value.
The domain of a function is the set of all input values, or x-values, for which the function is defined.
The range of a function is the set of all output values, or y-values, for which the function is defined.
To write the equation y = ax + b in function notation, substitute f(x) for y.
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