Can someone please help? Please?

Answer:

See the answer below

Explanation:

The time Laura took to reach the post office would depend on the speed of cycling.

We know that;

 speed = [tex]\frac{distance}{time}[/tex]

hence,

time = [tex]\frac{distance}{speed}[/tex]

Since the distance from Laura's house to the post office is 4 km, the equation becomes;

time = [tex]\frac{4}{speed}[/tex]

Just ensure that the speed is in km per hour, minute, or seconds in order to obtain the time in hours, minutes, or seconds respectively.

Answer:

5.28 x 10⁻⁹N

Explanation:

Given parameters:

Mass of alien  = 71kg

Distance  = 670m

Mass of ship  = 500000kg

Unknown:

Gravitational attraction  = ?

Solution:

The gravitational attraction can be found using the Universal gravitation law proposed by Newton;

      Fg  = [tex]\frac{G x mass 1 x mass 2}{d^{2} }[/tex]  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹

 d is the distance

 Fg is the gravitational attraction

  Fg  = [tex]\frac{6.67 x 10^{-11} x 71 x 500000 }{670^{2} }[/tex]   = 5.28 x 10⁻⁹N

Answer:

Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations

Explanation:

because they are good for using and not using

also, this is a 5 point question, you are not  fooling anyone. thx for 5 points tho

Answer: It is a transverse wave ^^

Explanation:

Answer:

Approximately [tex]5.5\; \rm N[/tex], assuming that the volume of these two charged objects is negligible.

Explanation:

Assume that the dimensions of these two charged objects is much smaller than the distance between them. Hence, Coulomb's Law would give a good estimate of the electrostatic force between these two objects regardless of their exact shapes.

Let [tex]q_1[/tex] and [tex]q_2[/tex] denote the magnitude of two point charges (where the volume of both charged object is negligible.) In this question, [tex]q_1 = 20 \times 10^{-6}\; \rm C[/tex]  and [tex]q_2 = 15 \times 10^{-6}\; \rm C[/tex].

Let [tex]r[/tex] denote the distance between these two point charges. In this question, [tex]r = 0.7\; \rm m[/tex].

Let [tex]k[/tex] denote the Coulomb constant. In standard units, [tex]k \approx 8.98755\times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2}[/tex].

By Coulomb's Law, the magnitude of electrostatic force (electric force) between these two point charges would be:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\end{aligned}[/tex].

Substitute in the values and evaluate:

[tex]\begin{aligned}F &= \frac{k \cdot q_1 \cdot q_2}{r^{2}}\\ &\approx 8.98755 \times 10^{9}\; \rm kg \cdot m^{3}\cdot s^{-2}\cdot C^{-2} \\ &\quad \times 20\times 10^{-6}\; \rm C\\ &\quad \times 15\times 10^{-6}\; \rm C \\ &\quad \times \frac{1}{{(0.7\; \rm m)}^{2}}\\ &\approx 5.5\; \rm N \end{aligned}[/tex].

Figure 1= binary fission in amoeba

figure 2= budding in yeast

difference

1.Parent divides to form two daughter cells and itself gets disappeared in binary fission but in budding , a bud gets matured and detaches from the parent

Answer:

B

Explanation:

I can't explain right now, mabe later.

Answer

given :

m=1.4 kg

r/q = N

N = m(9.8)

= 1.4 kg(9.8)

= 13.72 Newton

Answer:

9.8066500286389 N

Explanation:

Answer:

20 Hz, 20000 Hz

0.0166 m, 16.6 m

Explanation:

The minimum frequency that a human ear can hear is 20 Hz

The maximum frequency that a human ear can hear is 20000 Hz.

v = Velocity of sound = 332 m/s

Wavelength is given by

[tex]\lambda=\dfrac{v}{f}\\\Rightarrow \lambda=\dfrac{332}{20}\\\Rightarrow \lambda=16.6\ \text{m}[/tex]

The longest wavelength that can be heard by the human ear is 16.6 m

[tex]\lambda=\dfrac{332}{20000}\\\Rightarrow \lambda=0.0166\ \text{m}[/tex]

The shortest wavelength that can be heard by the human ear is 0.0166 m.

Answer:

The student squeezed the clothespin less the second time because the muscles in his hand began to fatigue

Explanation:

Answer:

The new force is 2.8125 N

Explanation:

Newton’s Law of Universal Gravitation

Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.  

[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Where:

m1 = mass of object 1

m2 = mass of object 2

r     = distance between the objects' center of masses

G   = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2

Suppose two spheres have a gravitational force between them of F = 45 N. Now increase the distance to r'=4r. The new force F' is:

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(4r)^{2}}}[/tex]

[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{16r^{2}}}[/tex]

[tex]\displaystyle F'=\frac{1}{16}\ G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]

Substituting the original value of the force:

[tex]\displaystyle F'=\frac{1}{16}\ 45 N[/tex]

F' = 2.8125 N

The new force is 2.8125 N

Answer:

I’m. Nog sure

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 12 \ Newtons }}[/tex]

Explanation:

Force is equal to the product of mass and acceleration.

[tex]F=m*a[/tex]

We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.

1. Calculate Acceleration

Acceleration is the change in velocity over the change in time.

[tex]a=\frac{V_f-V_i}{t}[/tex]

The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.

[tex]V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{10 \ m/s-4 \ m/s }{1 \ s}[/tex]

Solve the numerator.

[tex]a=\frac{6 \ m/s}{1 \ s }[/tex]

Divide.

[tex]a= 6 \ m/s/s=6 \ m/s^2[/tex]

2. Calculate Force

Now we know the acceleration and the mass.

[tex]m= 2 \ kg \\a= 6 \ m/s^2[/tex]

Substitute the values into the fore formula.

[tex]F= 2 \ kg * 6 \ m/s^2[/tex]

Multiply.

[tex]F= 12 \ kg*m/s^2[/tex]

[tex]F= 12 \ N[/tex]

The force applies to the ball was 12 Newtons.

The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.

The distance between two successive troughs or crests is known as the wavelength.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The point B represent the crest of the wave. The crest is the peak of the wave. While the trough is the lowest.

Hence, option B is correct.

To learn more about the wavelength, refer to the link;

brainly.com/question/7143261

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From the principle of the conservation of energy, the velocity of the moving skater would be transferred to the stationary skater.

We know that according to the principle of the conservation of energy, energy can neither be created nor destroyed but we can be able to convert the energy from one form to the other. Given the fact that the energy of the object can be converted, we can also look at the collision as being an inelastic Collison.

Let us recall that a collsion is said to be in elastic if the momemtum and thge kinetic energy of the colliding particles is not conserved. The simple implication of this is that the objects would stick together and then move at a common velocity after the collision must have taken place in the system.

Learn more about energy conservation:https://brainly.com/question/13949051

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Answer:

Inside a femur bone found in the woods,

saliva of gum

Answer: The trip took 40 minutes average speed should be 1 mph

Explanation:  It takes aprox 12 mins to reach 20km and the trip took 40 mins. This is obviously above what it should be. Not sure if I'm 100% correct

Answer:

The force of Gravity on the ball

Explanation:

Gravity of earth pulls the ball back down to the ground.

Answer:

1.  -0.863 kgm/s 2. -1.438 kgm/s

Explanation:

1. What is the change in momentum of the bullet if it embeds in the block?

Since the block does not move, the velocity of the bullet after hitting the block , v is zero. That is v = 0 m/s

Now, the momentum change of the bullet ΔP = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = 0 m/s (since it embeds in the block and the block does not move).

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(0 m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(- 1.50 × 10² m/s)

= -8.625 × 10⁻¹ kgm/s

= -0.8625 kgm/s

≅ -0.863 kgm/s

2. What is the change in momentum of the bullet if it bounces off the block in the opposite direction with a speed of 100 m/s?

If it bounces off the block in the opposite direction with a speed of 100 m/s, then its final velocity is v = -100 m/s.

So, our momentum change ΔP' = m(v - u) where m = mass of block = 5.75 g = 5.75 × 10⁻³ kg, u = initial velocity of bullet = 1.50 × 10² m/s and v = final velocity of bullet after hitting the block = -100 m/s = -1 × 10² m/s

So, ΔP = m(v - u)

= 5.75 × 10⁻³ kg(-1 × 10² m/s - 1.50 × 10² m/s)

= 5.75 × 10⁻³ kg(-2.50 × 10² m/s)

= -14.375 × 10⁻¹ kgm/s

= -1.4375 kgm/s

≅ -1.438 kgm/s

Answer:

The planets spun in epicycles.

Explanation:

The planets were not simply attached to a mystical sphere (“deferent”) but they were actually attached to a mini-sphere (“epicycle”) which rotated on the larger one.

Answer:A

Explanation:

Answer:

b

Explanation:

Answer:

W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

Answer:

T try d add b CD c

Explanation:

Cdgffd

Answer:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Explanation:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.