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Answer:

The darts hit the same general area of the board.

Answer: C. The darts hit the same general area of the board.

Explanation: The results of a dart game were precise but not accurate. The accepted value of the game was the center of the dartboard.

Answer:

4.4.

Explanation:

Hello,

In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.

In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.

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Answer:

The car's average acceleration points due west.

Explanation:

Resolving the acceleration will give a resultant due west

the endocrine system releases hormones, and hormones impact the systems that cause changes in our behavior, including changes in what we might call biological motivations.

Answer: divergent plate

Explanation: the East African Rift Valley (EAR) is a developing divergent plate boundary in East Africa. Here the eastern portion of Africa, the Somalian plate, is pulling away from the rest of the continent, which comprises the Nubian plate.

Answer:

Lake Victoria sits between these two branches. It is thought that these rifts are generally following old sutures between ancient continental masses that collided billions of years ago to form the African craton and that the split around the Lake Victoria region occurred due to the presence of a small core of ancient metamorphic rock, the Tanzania craton, that was too hard for the rift to tear through. Because the rift could not go straight through this area, it instead diverged around it leading to the two branches that can be seen today.

Explanation:

Answer:

Distance is 13m and Displacement is 9m

Explanation:

Answer:

m = 2218.67 kg

Explanation:

It is given that,

Initial velocity, u = 7.5 m/s

Final speed of an object, v = 0 (at rest)

Force, F = 5.2 kN

Time, t = 3.2 s

We need to find the mass of the object. Force acting on an object is given by :

F = ma

m is mass, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg[/tex]

So, the mass of the object is 2218.67 kg

The force is always equal to the product of mass and acceleration. The mass of the object is 2218.7 Kg.

An object travels 7.5 m/s toward the west.

Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s.

Now,

The initial velocity of the object is 7.5 m/s.

The final velocity of the object is 0 m/s.

The object comes to the rest position in 3.2 seconds.

The formula for finding the acceleration of the object is mentioned below:

[tex]v=u+at\\0=7.5+a \times 3.2\\a= -2.34375\;\rm m/s^2[/tex]

The formula for finding the force is mentioned below:

[tex]F=ma\\-5.2 \times 10^3=m \times 2.34375\\m=2218.7 \ \;kg[/tex]

Hence, the mass of the object is 2218.7 Kg.

To know more about it, please refer to the link:

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Answer: 13.2678 kg

Explanation: Well, 13.2678 kg is 29.25 in mass and kg.

Answer:

False

Explanation:

A psychologist is a person who deals with normal and abnormal mental states, emotional, and social processes and behavior of an individual in relation to one another and to their environments.

Individuals with a master's degree in psychology can work as industrial-organizational psychologists

A psychologist is not required to obtain a medical degree to diagnose and treat people with disorders.

So, the given statement is false.

Answer:

false

Explanation:

The required value is required in SI units.

The required answer is [tex]1.94\times10^{-10}\ \text{kg m}^2/\text{s}^2[/tex]

The SI unit of mass, length and time is kg, m and s respectively.

In order to convert one unit into another it has to be multiplied or divided by the conversion factors.

A definite magnitude which has some quantity which is defined by convention or law is called a unit.

The conversion factors are

[tex]1\ \text{g}=10^{-3}\ \text{kg}[/tex]

[tex]1\ \text{cm}=10^{-2}\ \text{m}[/tex]

[tex]1\ \text{cm}^2=10^{-4}\ \text{m}^2[/tex]

1 min = 60 s

[tex]1\ \text{min}^2=60\times60\ \text{s}^2[/tex]

So,

[tex]7\ \text{g cm}^2/\text{min}^2=7\times \dfrac{10^{-3}\times 10^{-4}}{60\times 60}\\ =1.94\times10^{-10}\ \text{kg m}^2/\text{s}^2[/tex]

Learn more about SI units:

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Answer:

100 ÷ 9.58 = 10.44 (approximate answer)

Answer:

Troposphere

Explanation:

The troposphere happens to be the lowest region amongst the atmosphere. It has a length that extends from the surface to a height of about 6–10 km. And that is the lower boundary of the stratosphere among the layers of the atmosphere

The troposphere in itself is bonded on the top by a layer of air tropopause. This layer is the one which separates the troposphere from the stratosphere, and on bottom by the surface of the Earth.

Explanation:

It is given that,

Wavelength of a beam of light in vacuum, [tex]\lambda_o=620\ nm[/tex]

(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.

We know that,

Refractive index,

[tex]n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s[/tex]

(b) The wavelength of light in material,

[tex]\lambda=\dfrac{\lambda_o}{n}[/tex]

Let [tex]\lambda_1[/tex] is the wavelength of these waves in the liquid. So,

[tex]\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m[/tex]

Hence, this is the required solution.

Answer: The absolute value of a number is symbolized by two vertical lines as 3 or -3

Please pick me as brainliest please

Answer: the magnetic of a real number without regard to its sign

Explanation: In mathematics, the absolute value or modulus of a real number x, denoted |x| or, is the non-negative value of x without regard to its sign. Namely, |x| = x if x is positive, and |x| = −x if x is negative, and |0| = 0. For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3

Answer:

Average speed = 3.63 m/s

Explanation:

The average speed during any time interval is equal to the total distance travelled divided by the total time.

That is,

Average speed = distance/ time

Let d represent the distance between A and B.

Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,

5.15 = d/t1.

Make d the subject of formula

d = 5.15t1

Let t2 represent the longer time for the return trip at 2.80 m/s . That is,

2.80 = d/t2.

Then the times are t1 = d/5.15 5 and

t2 = d/2.80.

The average speed vavg is given by the following equation.

avg speed = Total distance/Total time

Avg speed = d + d/t1 + t2

Where

Total distance = 2d

Total time = t1 + t2

Total time = d/5.15 + d/2.80

Total time = (2.8d + 5.15d)/14.42

Total time = 7.95d/14.42

Total time = 0.55d

Substitute total distance and time into the formula above.

Avg speed = 2d / 0.55d

Avg Speed = 3.63 m/s

Answer:

Explanation:

check the attachment for the diagram of the set up for proper clarification.

From the diagram, the man's distance from the pole is labelled AB.

To get AB =, we need to get side CB first which is equal to ED i.e ED = CB.

From ΔCDE, opposite side = 45 feet and the adjacent is ED.

USing TOA, according to trig function SOH, CAH, TOA;

tan 16° = opp/adj = BD/ED

tan 16° = 45/ED

ED = 45/tan 16°

ED = 156.93 feet

Since ED = CB, hence CB = 156.93 feet

From ΔABC, adj = CB and hypotenuse = AB. According to CAH;

cos 12° = adj/hyp = CB/AB

cos 12° =  156.93/AB

AB =  156.93/cos 12°

AB = 160.44 feet

Hence the man's distance from the pole is 160.44 feet

Answer:

The value of m = 3.735 and the value of n = 7.

Explanation:

The equation for the momentum of the train is,

                                          P = mv  

Here, m is the mass of the train and v is the speed of the train.

Substitute [tex]4.5 \times {10^5}{\rm{ kg}} , 8.3 \times {10^1}{\rm{ m/s}}[/tex] for m and v respectively in above equation.

[tex]\begin{array}{c}\\P = \left( {4.5 \times {{10}^5}{\rm{ kg}}} \right)\left( {8.3 \times {{10}^1}{\rm{ m/s}}} \right)\\\\ = 37.35 \times {10^6}{\rm{ kg}} \cdot {\rm{m/s}}\left( {\frac{{{{10}^1}{\rm{kg}} \cdot {\rm{m/s}}}}{{10\,{\rm{kg}} \cdot {\rm{m/s}}}}} \right)\\\\ = 3.735 \times {10^7}{\rm{ kg}} \cdot {\rm{m/s}}\\\end{array}[/tex]  

According to the scientific notation, here the value of m is 3.735 and the value of n is 7 in the final answer of the momentum.

                        The value of m = 3.735 and the value of n = 7.

Answer:

1)   I_ pendulum = 2.3159 kg m² , 2)  I_pendulum = 24.683 kg m²

Explanation:

In this exercise we are asked to calculate the moment of inertia of a physical pendulum, let's start by calculating the center of mass of each elements of the pendulum and then the center of mass of the pendulum

Sphere

They indicate the density of the sphere roh = 37800 kg / m³ and its radius

r = 5 cm = 0.05 m

we use the definition of density

               ρ = M / V

               M = ρ V

the volume of a sphere is

                V = 4/3 π r³

we substitute

              M = ρ 4/3 π r³

we calculate

              M = 37800  4/3 π 0.05³

              M = 19,792 kg

Bar

the density is ρ = 32800 kg / m³ and its dimensions are 1 m,

0.8 cm = 0.0008 m and 4cm = 0.04 m

The volume of the bar is

               V = l w h

              m = ρ l w h

we calculate

              m = 32800 (1   0.008   0.04)

              m = 10.496 kg

Now we can calculate the center of mass of the pendulum, we use that the center of mass of the sphere is its geometric center, that is, its center and the center of mass of the bar is where the diagonals intersect, in this case it is a very bar. long and narrow, whereby the center of mass is about half the length. It's mass scepter of the pendulum is

               r_cm = 1 / M (M r_sphere + m r_bar)

               M = 19,792 + 10,496 = 30,288 kg

               r_cm = 1 / 30,288 (10,496 0.5 + 19.792 (1 + 0.05))

               r_cm = 1 / 30,288 (5,248 + 20,7816)

               r_cm = 0.859 m

This is the center of mass of the pendulum.

1) Now we can calculate the moment of inertia with respect to this center of mass, for this we can use the theorem of parallel axes and that the moments of inertia of the bodies are:

Sphere I = 2/5 M r2

Bar I = 1/12 m L2

parallel axes theorem

                  I = I_cm + m D²

where m is the mass of the body and D is the distance from the body to the axis of rotation

Sphere

      m = 19,792 ka

the distance D is

                D = 1.05 -0.85

                D = 0.2 m

we calculate

               I_sphere = 2/5 19.792 0.05 2 + 19.792 0.2 2 = 0.019792 +0.79168

               I_sphere = 0.811472 kg m²

Bar

m = 10.496 kg

distance D

             D = 0.85 - 0.5

             D = 0.35 m

              I_bar = 1/12 10.496 0.5 2 + 10.496 0.35 2 = 0.2186 + 1.28576

              I_bar = 1.5044 kg m²

The moment of inertia is a scalar quantity whereby the moment of inertia of the body is the sum of the moment of the parts

              I_pendulum = I_sphere + I_bar

              I_pendulum = 0.811472 +1.5044

              I_ pendulum = 2.3159 kg m²

this is the moment of inertia of the pendulum with respect to its center of mass located at r = 0.85 m

2) The moment is requested with respect to the pivot point at r = 0 m

Sphere

        D = 1.05 m

         I_sphere = 2/5 M r2 + M D2

        I_sphere = 2/5 19.792 0.05 2 + 19.792 1.05 2 = 0.019792 +21.82

        I_sphere = 21.84 kg m²

Bar

D = 0.5 m

      I_bar = 1/12 10.496 0.5 2 + 10.496 0.5 2 = 0.21866 + 2.624

      I_bar = 2,84266 kg m 2

The pendulum moment of inertia is

       I_pendulum = 21.84 +2.843

       I_pendulum = 24.683 kg m²

This moment of inertia is about the turning point at r = 0 m

Answer:

Explanation:

The attachments show the labeling of the network nodes. We found it convenient to do this so we could identify the specific nodes any given branch was attached to. Then the connections for each resistor were identified, and the list sorted to make it easier to see parallel connections.

Resistors 1 and 2 are in parallel

Resistors 5, 6, 8, 9 are in parallel

Resistors 4, 7, 11 are in parallel

No resistor has a parallel connection to resistor 3.

Answer:C: The gravity on the moon is less than the gravity on Earth.

Explanation:

Answer:

A) PARTICLES

Explanation:

VERY SMALL OBJECTS ARE BEHAVE LIKE A PARTICLES.

Answer:

The acceleration of the sled is [tex]4.6\ m/s^2[/tex].

Explanation:

It is given that,

Initial speed of sled is 0 because it was at rest.

It is placed at an angle of 28° on a frictionless hill.

We need to find the acceleration of the sled. It is placed at an incline. It means that the acceleration of the sled is given by :

[tex]a=g\sin\theta\\\\a=9.8\times \sin(28)\\\\a=4.6\ m/s^2[/tex]

So, the acceleration of the sled is [tex]4.6\ m/s^2[/tex].

The car will move in a speed of 45 meter per second

Answer: The car will move in a speed of 45 meter per second

Explanation:

Answer: A velocity-time graph shows how velocity changes over time

Explanation:

Answer:velocity

Explanation:

Answer:

10609.17miles per hr is the linear velocity

Explanation:

To arrive at Ans in miles per hr we first convert 365.25 days to hours

Which is 365.25 x24hrs per day= 8766hrs

So velocity= distance/time

So

93000000/8766= 10609.17miles per hr

Change in speed = (acceleration) x (time)

4 minutes = 240 seconds

Change in speed = (40 m/s²) x (240 seconds)

Change in speed = 9,600 m/s

What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.

The driver would definitely NOT get a speeding ticket, because nobody could catch him.

Also, his car would heat up and shoot flames from atmospheric friction.

(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)

Actually, I hope there's nobody in the car.  His experience wouldn't be pretty.

Answer:

(A) 10052.2 m/s²

(B)  0.00678 seconds

Explanation:

From the question,

(A) Applying

V² = U²+2as..................... Equation 1

Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.

make a the subject of the  equation

a = (V²-U²)/2s........................ Equation 2

Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m

Substitute these values into equation 2

a = (68²-0²)/(2×0.230)

a = 10052.2 m/s²

(B) Using,

a = (V-U)/t......................... Equation 3

Where t= time.

make t the subject of the equation

t = (V-U)/a......................... Equation 4

Given: V = 68 m/s, U = 0 m/s, a = 10052.2

Substitute into equation 4

t = (68-0)/10052.2

t = 0.00678 seconds