Carbon-14 has a half-life of 5730 years. How much of a 144 g sample of carbon-14 will remain after 100,000 years?

Answers

Answer 1

Answer:

0.001 g

Explanation:

From the question given above, the following data were obtained:

Half-life (t½) = 5730 years

Original amount (N₀) = 144 g

Time (t) = 100,000 years

Amount remaining (N) =?

Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:

Half-life (t½) = 5730 years

Time (t) = 100,000 years

Number of half-lives (n) =?

n = t / t½

n = 100,000 / 5730

n ≈ 17

Finally, we shall determine the amount remaining. This can be obtained as follow:

Original amount (N₀) = 144 g

Number of half-lives (n) = 17

Amount remaining (N) =?

N = 1/2ⁿ × N₀

N = 1/2¹⁷ × 144

N = 1/131072 × 144

N = 0.000007 × 144

N ≈ 0.001 g

Thus, the amount remaining after 100000 years is 0.001 g


Related Questions


Why would you want to slow down a chemical reaction? ​

Answers

Answer:

We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.

How many grams of carbon dioxide will be produced if 76.4 grams of
C2H3Br3 reacted with 49.1 grams of O2? How many grams of the
excess reactant will be left after the reaction is over? Consider the
equation: C2H3Br3+O2 -> CO2+H2O+Br2

Answers

Answer:

Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556 moles of C2H3Br3 are required. Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent.

Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.

Explanation:

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https://chem.libretexts.org/Bookshelves/Introductory_Chemistry/Map%3A_Introductory_Chemistry_(Tro)/08%3A_Quantities_in_Chemical_Reactions/8.04%3A_Limiting_Reactant_and_Theoretical_Yield

Step:1  When we are Assuming that all of the oxygen is used up, 1.53×4111.53×411 or 0.556  with the moles of C2H3Br3 are required. Just Because there are only 0.286 moles of C2H3Br3 available, C2H3Br3 is the limiting reagent. Step:2 When there are Limiting Reagent What is the limiting reagent if 76.4 grams of C2H3Br3 were reacted with 49.1 grams of O2? C2H3Br3 + 11O2 → 8CO2 + 6H2O + 6Br2 SOLUTION Using Approach 1: when is equal to Conclusion is that: Thus, that A. 76.4g × (1 mol/ 266.72 g) = 0.286 moles C2H3Br3 49.1g × (1 mole/ 32 g) = 1.53 moles O2 B.

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Plz help plz help me will mark Brainly

Answers

Answer:

Greenhouse gases absorb some of the energy and trap it in the lower atmosphere. Less heat radiates into space, and Earth is warmer. Many greenhouse gases occur naturally. Carbon dioxide, methane, water vapor, and nitrous oxide are naturally present in Earth's atmosphere. Since some of the extra energy from a warmer atmosphere radiates back down to the surface, Earth's surface temperature rises.

Hope this helped! :)

When looking across the periodic table from left to right, which of these groups are the first to contain nonmetals?

group 2
group 7
group 14
group 18

Answers

Answer:

The first group to contain a non-metal is Group 18.

Place the following in order of increasing entropy at 298 K.
Ne Xe He Ar Kr
A) He < Kr < Ne < Ar < Xe.
B) Xe < Kr < Ar < Ne < He.
C) Ar < He < Ar < Ne < Kr.
D) Ar < Ne < Xe < Kr < He.
E) He < Ne < Ar < Kr < Xe.

Answers

Answer:

E

Explanation:

The simple rule of thumb is that as the atomic or molar mass of an atom increases, the entropy increases. This means that more the mass more will be entropy.

The atomic mass of various elements is as follows

Ne = 20 g/mol

Xe = 131 g/mol

He = 4 g/mol

Ar = 40 g/mol

Kr = 84 g/mol

Therefore, the order of increasing entropy must be

He<Ne<Ar<Kr<Xe.

Hence, option E is the correct answer.

Answer both of these true or false correctly

brainliest if correct

Answers

Answer:

There both true.

Explanation:

Hope this helps

Answer:

The first one is True

The second one is false

Explanation:

how many moles are in 89 grams of Pb(CH3COO)4

Answers

Answer:

0.20 moles of Pb(CH3COO)4

Explanation:

89g Pb(CH3COO)4 x 1 mol Pb(CH3COO)4 / 443.376 g Pb(CH3COO)4

= 0.20 moles of Pb(CH3COO)4

One mole of lead acetate weighs 443.29 g. Then, 89 grams of lead acetate contains 0.20 moles of Pb (CH₃COO)₄.

What is one mole ?

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³  molecules. The mass of one mole of compound is called its molar mass. The number  of moles of the compound can be determined by dividing the given mass by molar mass.

Molar mass of lead acetate = 443.29 g/mol

given mass  = 89 grams

then , no.of moles = weight/molar mass

n = 89 g/ (443.29 g/mol) = 0.20 moles

Therefore, the number of moles of Pb (CH₃COO)₄ in 89 g is 0.20 moles.

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Find the % composition for each element in Zinc Chlorate

Answers

Answer:

chlorine ~ 30%

zinc ~ 28%

oxygen ~ 41%

Explanation:

For each event stated below, indicate how the concentration of each species in the chemical equation will then change to reach equilibrium.

2CO(g) + O2(g) ⇌ 2CO2(g)

a. increasing the concentration of CO
b. decreasing the amount of O2
c. decreasing the the volume of the system

Answers

Answer:

See Explanation

Explanation:

When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.

a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.

b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.

c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.

Products will form faster if___
A) temperature is decreased
B) the reaction is not stirred
C) the particle size of the reactants are larger
D) concentration of the reactants are increased

Answers

Answer:

C(btw this could be wrong)

Explanation:

Answer:

B is the answer

Explanation:

Draw a schematic diagram of a circuit with an output device, a energy source and a controller.

Answers

Answer:

ch∪pαpi munαn0?

Explanation:

You can find the speed on a distance-versus-time graph by finding the slope of the line.

True
False

Answers

true, finding the points at which speed has a given time (needed to find the slope of the graph) will give you the relationship between the variables

is this correct im just asking because my little brother not sure for his answer ​

Answers

I think it’s not right

to make a large quantity of a 5% solution of HCl but only have 25mL HCl. what volume of 5% solution can be made from this volume of HCl?

Answers

Answer:What is the volume of 37% HCl?

If however you meant to say 0.025M and assuming you want to prepare 1L solution then the volume of 37% HCl needed should be= (1000 X 0.025X 36.5)/ (37X1.19X10)=2.07 mL diluted to 1 L using DI water. Good day. If you want 0.025 mole HCl solution, you should take a 2.09 ml of your acid.

Explanation:To prepare 5% solution from this acid; simply take 5 ml. of the acid and add it to 95 ml of distilled water.You get a 5%HCl solution. By the way, Hydrogen Chloride is the name designated to the gas evolved from HCl acid

To determine the volume of a 5% solution that can be made from 25 mL of HCl, we need to use the equation: C1V1 = C2V2

Where:

C1 = Initial concentration of HCl

V1 = Initial volume of HCl

C2 = Final concentration of the solution (5% or 0.05 in decimal form)

V2 = Final volume of the solution (unknown)

What is HCl?

HCl stands for hydrochloric acid. It is a strong, highly corrosive acid that is commonly used in various industrial, laboratory, and chemical applications. In its pure form, hydrochloric acid is a colorless liquid with a pungent odor. It is composed of hydrogen (H) and chlorine (Cl) and is known for its acidic properties.

Let's plug in the known values:

C1 = 100% (since the initial HCl is undiluted)

V1 = 25 mL

C2 = 5% or 0.05

V2 = Unknown

Solving for V2:

C1V1 = C2V2

(1)(25 mL) = (0.05)(V2)

25 mL = 0.05V2

Divide both sides by 0.05 to isolate V2:

V2 = 25 mL / 0.05

V2 = 500 mL

Therefore, from 25 mL of HCl, you can make a 500 mL solution with a concentration of 5%.

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If oxygen gas at 118 °C and 10.8 atm was heated to 948 °C, what would the new
pressure be?

Answers

Answer: The new pressure is 1.34 atm.

Explanation:

Given: [tex]P_{1}[/tex] = 10.8 atm,         [tex]T_{1} = 118^{o}C[/tex]

[tex]P_{2}[/tex] = ?,                  [tex]T_{2} = 948^{o}C[/tex]

Formula used to calculate the new pressure is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{10.8 atm}{118^{o}C} = \frac{P_{2}}{948^{o}C}\\P_{2} = 1.34 atm[/tex]

Thu, we can conclude that the new pressure is 1.34 atm.

Which of the following does NOT represent a balanced reaction? ​

Answers

Answer:

letter D i think

Explanation:

correct me if im wrong

the mass concentration the mass concentration for a solution containing 45 g of calcium carbonate is 100 cm3 ​

Answers

Answer: The mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

Explanation:

Given: Mass of calcium carbonate = 45 g

Volume = [tex]100 cm^{3}[/tex]

Convert [tex]cm^{3}[/tex] into L as follows.

[tex]1 cm^{3} = 0.001 L\\100 cm^{3} = 100 cm^{3} \times \frac{0.001 L}{1 cm^{3}}\\= 0.1 L[/tex]

Moles of calcium carbonate (molar mass = 100 g/mol) is as follows.

[tex]No. of moles = \frac{45 g}{100 g/mol}\\= 0.45 mol[/tex]

Molarity is the number of moles of solute present in a liter of solution.

Hence, molarity (or mass concentration) of given solution is calculated as follows.

[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.45 mol}{0.1 L}\\= 0.045 M[/tex]

Thus, we can conclude that the mass concentration for a solution containing 45 g of calcium carbonate for 100 [tex]cm^{3}[/tex] is 0.045 M.

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Which is greater, the moon's period of rotation or its period of revolution?

They are equal.

the moon's revolution period around Earth

Neither are known.

the moon's rotational period

Answers

Answer:

B

Explanation:

What is (aq),(I), and (g) mean in H2O2(aq) -> H2O(l) + O2(g) and why is it nesesary to have (aq),(I), and (g)

Answers

Explanation:

A matter can be present in different states like solid, liquid or gas. When we write a chemical equation then states of species involved are also mentioned.

This is because it tells in what state the reactants were present and in what state the products are then formed.

For example, [tex]H_{2}O_{2}(aq) \rightarrow H_{2}O(l) + O_{2}(g)[/tex]

Now here, (aq) means aqueous, (l) means liquid and (g) means gas.

So, these states denoted are necessary as it tells that [tex]H_{2}O_{2}[/tex] in aqueous state dissociates to give [tex]H_{2}O[/tex] in liquid state and [tex]O_{2}[/tex] in gaseous state.

Phosphorus (P4) and hydrogen gas can combine to form phosphine (PH3), a toxic gas with the odor of rotting fish. Complete and balance the equation for this chemical reaction.

Answers

Answer:

P₄ + 6 H₂ ⇒ 4 PH₃

Explanation:

Let's consider the unbalanced reaction that takes place when phosphorus reacts with hydrogen to form phosphine. This is a synthesis reaction.

P₄ + H₂ ⇒ PH₃

We will balance this reaction using the trial and error method. First, we will balance P atoms by multiplying PH₃ by 4.

P₄ + H₂ ⇒ 4 PH₃

Finally, we get the balanced equation by multiplying H₂ by 6.

P₄ + 6 H₂ ⇒ 4 PH₃

Consider an electron with charge −e−e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with charge +e+e. In the classical model, the electron orbits around the nucleus, being held in orbit by the electromagnetic interaction between itself and the protons in the nucleus, much like planets orbit around the sun, being held in orbit by their gravitational interaction. When the electron is in a circular orbit, it must meet the condition for circular motion: The magnitude of the net force toward the center, FcFcF_c, is equal to mv2/rmv2/r. Given these two pieces of information, deduce the velocity vvv of the electron as it orbits around the nucleus. Express your answer in terms of eee, mmm, rrr, and ϵ0ϵ0epsilon_0, the permittivity of free space.

Answers

Answer:

Explanation:

The net force on electron is electrostatic force between electron and proton in the nucleus .

Fc = [tex]\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}[/tex]

This provides the centripetal force for the circular path of electron around the nucleus .

Centripetal force required = [tex]\frac{m\times v^2}{r}[/tex]

So

[tex]\frac{m\times v^2}{r}=\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}[/tex]

[tex]v^2=\frac{e^2}{4\pi \epsilon m r}[/tex]

[tex]v=(\frac{e^2}{4\pi \epsilon m r})^{\frac{1}{2} }[/tex]

If you have 1.82 moles of mercury (Hg), how many grams of mercury do you have?

Answers

Answer:

182

Explanation:

1 hectogram (hg) = 100 grams (g)

1.82 x 100 = 182

Which particles appear in equal numbers in all uncharged atoms? Proton, Neutron, Electron, None

Answers

Answer:

In an uncharged atom, the number of protons is always equal to the number of electrons. Apr 24, 2017

Explanation:

Neutron: An uncharged particle found in the nucleus of an atom.

There is only one stable atom that does not have neutrons. It is an isotope of the element hydrogen called protium. Protium, which contains a single proton and a single electron, is the simplest atom.


True or False: A higher vapor pressure (evaporates easily) corresponds to strong intermolecular forces.

Answers

the answer prob false

The primary structure of a protein is determined by

A. The order of amino acids in the protein.
B. The amino acid composition.
C. The hydrogen bonding that gives the protein three dimensional shape.
D. The intertwining of protein molecules to form a “functional” protein.

Answers

Answer: I believe the answer is A. The order of amino acids in the protein.

Explanation:

cómo se puede comprobar el efecto universo​

Answers

Answer:

???! huhhhjhhh no I speak English

Explanation:

?

Answer:

vifucivud UKvi uiiijhhh

Determine the type of reaction: AgNO3 + Cu --> Cu(NO3)2 + Ag

Answers

Explanation:

Cu + 2 AgNO3 → Cu(NO3)2 + 2 Ag

Cu is oxidized

Ag+ is reduced

Cu is the reducing agent

To solve such this we must know the concept of displacement reaction. The balanced reaction of silver nitrate with copper is of  displacement type of reaction.

AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

The reaction between silver nitrate and copper is example of displacement reaction. Copper displaces silver from silver nitrate. to form copper nitrate.

Therefore, the balanced equation is of displacement type of reaction.

AgNO[tex]_3[/tex] + Cu [tex]\rightarrow[/tex] Cu(NO[tex]_3[/tex])[tex]_2[/tex] + Ag

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7. What is the mass of a piece of copper (Cu) that undergoes a 25.0 °C
temperature change with the loss of 428 J of energy?

Answers

Answer:

0.0428 kg or 42.8 g

Explanation:

Applying,

Q = cmΔt.............. Equation 1

Where Q = heat lost of heat gained, c = specific heat capacity of copper, m = mass of copper, Δt = temperature change.

make m the subject of the equation above

m = Q/cΔt.................. Equation 2

From the question,

Given: Q = 428 J, Δt = 25 °C

Constant: c = 400 J/kg.°C

Substitute these values into equation 2

m = 428/(25×400)

m = 0.0428 kg

m = 42.8 g

2) Choose the best answer. Which type of reaction is this? NaOH + H2O → Na+ + OH strong base dissociation strong acid dissociation weak base dissociation neutralization weak acide dissociation​

Answers

Answer:

strong Base Dissociation

Explanation:

NaOH is baseNaOH is strong base that means strong acids ionizes almost completely when dissolved in water.

in a hypothetical element ,two energy levels are separated by an energy of 282kj mol-1 . what wavelength of light (in nma) is evolved for an electron to change between these two levels?​

Answers

Answer:

7.05 × 10⁻²² nm

Explanation:

Step 1: Given and required data

Energy evolved when a mole of electrons changes between the 2 levels (E): 282 kJPlanck's constant (h): 6.63 × 10⁻³⁴ J.sSpeed of light (c): 3.00 × 10⁸ m/s

Step 2: Calculate the wavelength (λ) of the light evolved

We will use Planck-Einstein's relation.

E = h × c/λ

λ = h × c/E

λ = (6.63 × 10⁻³⁴ J.s) × (3.00 × 10⁸ m/s)/(282 × 10³ J) = 7.05 × 10⁻³¹ m

We will convert λ to nm using the conversion factor 1 m = 10⁹ nm.

7.05 × 10⁻³¹ m × 10⁹ nm/1 m = 7.05 × 10⁻²² nm

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