Chemistry of Life Practice Active 8 1 What type of organic compound is used for building cell parts?​

Answers

Answer 1
Carbohydrates & Lipids.

Carbs are organic compounds (examples are sugars & starches). They provide energy and form structures such as cell walls.

Lipids are organic compounds (examples are fats & oils). They store energy and help form cell membranes in addition to having other functions in organisms
Answer 2

Answer:

Carbohydrates

Explanation:


Related Questions

what are the existing evidences to support the existence of pangea?
salamat.​

Answers

Fossil evidence for Pangaea includes the presence of similar and identical species on continents that are now great distances apart.

what is the molecular geometry of c atom in ch3nh2

Answers

Answer:

compound is sp3.

Explanation:

Sp3 it is because it is trust me

PLEASE HELP!!!!

what happens when the ocean reaches it’s saturation level of carbon dioxide?

Answers

Hi!

When the ocean reaches its saturation level of carbon dioxide, a couple of things will happen:

First, more carbon dioxide will remain in the atmosphere, and second, the ocean's pH will drop.

Carbonate and bicarbonate ions in seawater act as a buffer system which keeps the ocean's pH levels stable. When CO2 dissolves in seawater, it reacts with the ocean's buffer system in such a way that it produces two hydrogen ions, which lowers the pH. As more and more CO2 reacts with the ocean's buffer system and the system becomes saturated, less atmospheric carbon dioxide will cross over into the ocean. This excess CO2 will remain in the atmosphere and contribute to global climate change.

Hope this helped!

When the ocean reaches it's saturation level of carbon dioxide  more amount of carbon dioxide remains in the atmosphere and  pH of the ocean drops.

What is saturation level?

It is defined as the level or extent up-to which a substance is soluble in a particular solvent. Due to global warming ,there is an excessive release of carbon dioxide in atmosphere. The excessive amount cannot be soluble in the ocean water which leads to ocean acidification.

As a result of ocean acidification the pH of water in the ocean drops thus there is less amount of oxygen present for aquatic organisms which is needed to survive. When carbon dioxide dissolves in water it yields carbonic acid which further reduces the pH of water  and thus making it unfit for aquatic environment.

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The rate constant for the radioactive decay of tritium 3H is 0.056 1/yr. The percentage of tritium remaining after 50 years is:_________

Answers

Answer:

6.05%

Explanation:

From the question given above, the following data were obtained:

Decay constant (K) = 0.0561 /yr

Time (t) = 50 years

We can obtain the percentage of tritium remaining after 50 years by using the following formula:

Log (N₀/N) = kt /2.303

NOTE:

N₀ is the original amount.

N is the amount remaining.

K is the decay constant.

t is the time

Log (N₀/N) = (0.0561 × 50) /2.303

Log (N₀/N) = 2.805/2.303

Log (N₀/N) = 1.218

Take the anti log of 1.218

(N₀/N) = anti log (1.218)

(N₀/N) = 1.218

N₀/N = 16.52

Invert and multiply by 100 to obtain the percentage.

N/N₀ = 1/16.52 × 100

N/N₀ = 6.05%

Thus, the percentage of tritium remaining after 50 years is 6.05%

Answer:

6.08% remains after 50 years

Explanation:

The radioactive decay follows the equation:

Ln[A] = -kt + Ln [A]₀

Where [A] is concentration of reactant after time t, [A]₀ is its initial concentration, k is rate constant and t is time.

Assuming its Initial concentration is 100%

Time is 50 yr

k is 0.056 yr⁻¹

And [A] is our incognite

Ln[A] = -0.056 yr⁻¹*50yr + Ln [100%]

ln[A] = 1.805

[A] =

6.08% remains after 50 years

A sample of 6.44 g of napthalene (C10H8) is dissolved in 80.1 g of benzene (C6H6). Calculate the percent by mass of napthalene in this solution.​

Answers

Answer:

7.44%

Explanation:

[tex]\frac{6.44}{6.44+80.1} *100=7.44[/tex]

Blood takes about 1.55 s to pass through a 2.00 mm long capillary. If the diameter of the capillary is 5.00 μm and the pressure drop is 2.45 kPa, calculate the viscosity ???? of blood. Assume laminar flow.

Answers

Answer:

The viscosity [tex]\mathbf{\eta = 7.416 \times 10^{-4} \ N.s/m^2}[/tex]

Explanation:

From the given information:

Time t = 1.55 s

The radius of capillary = 5.00 μm /2

The pressure drop ΔP = 2.45 kPa

The length of the capillary = 2.00 mm

The viscosity of the blood flow can be calculated by using the formula:

[tex]\eta = \dfrac{r^2 \Delta P }{8Lv}[/tex]

where;

v = L/t

Then;

[tex]\eta = \dfrac{r^2 \Delta P }{8L(\dfrac{L}{t})}[/tex]

[tex]\eta = \dfrac{(\dfrac{5 \times 10^{-6} \ m}{2})^2(2.45 \times 10^3 \ Pa) }{8(2.0 \times 10^{-3} \ m ) (\dfrac{2.0 \times 10^{-3} \ m }{1.55 \ s })}[/tex]

[tex]\eta = 7.416 \times 10^{-4} \ Pa.s[/tex]

To (N.s/m²)

[tex]\mathbf{\eta = 7.416 \times 10^{-4} \ N.s/m^2}[/tex]

Describe the three kinds of particles found in atoms. Where are they located in the atom and what are their charges?

Answers

Proton(positive charge), Neuron(neutral charge), electron(negative charge).

During the formation of water from hydrogen atoms and one oxygen

Answers

Answer:

B

Explanation:

hydrogen only has one electron/molecule in it's only shell so it can get together and make a bond

How many different E2 products are expected in the reaction of 3-bromo-1,1-dimethylcyclohexane with NaOCH2CH3?
A) only 1
B) 2
C) 3
D) 4

Answers

c :))))))))))) :33333333

PLease help me I am giving a lot of points for this please help me

Answers

Answer:

Under balanced its motion under motion its s = d/t under s - d/t is time d = distance s= speed

Explanation:

Answer:Under unbalanced it’s motion,and after motion it’s speed.Then after speed it’s s=d/t,and d=distance and t=time.Lastly,the last one is graph.

An ideal gas had a mass of 0.0218g and occupied a volume of 1.111L at 0oC and 0.0100atm. What is the molar mass of this gas?

Answers

Answer:

Explanation:

we shall use gas law formula to solve the problem .

P = .01 atm

V = 1.111 L

T = 273 K

mass of gas = .0218

molar mass = M

no of moles n = .0218 / M

PV = n RT

.01 x 1.111 = (.0218 / M)  x .082 x 273

.0218 / M = .000496

M = .0218 / .000496

= 43.95

You have a two-liter sample of each of the following gases, all at 25 °C and one atmosphere pressure. Which sample will weigh the most?A) Ammonia.B) Argon.C) Carbon dioxide.D) Nitrogen dioxide.E) Oxygen.

Answers

Answer: D) Nitrogen Dioxide

Explanation:

The characteristics of moles allow you to find that the correct answer for which sample weighs more is:

             D) Nitrogen Dioxide

The molecular weight of the substance is the weight of one mole of a material, where one mole is Avogadro's number of particles.

In all chemical reactions the relationships are given as a function of moles.

Let's find the molecular weight of each of the substances, we take the atomic weights from the periodic table

Element      PA (gr / mol)

   H                     1

   C                   12

   N                   14

   O                   16

   Ar                  40

A) Ammonia with NH₃ formula

     weight of a mole of molecules

           MP = 14 + 3

           PM = 17 gr / mol

B) Argon symbol Ar

    It is a noble gas and does not react

         PM = 40 gr / mol

C) Carbon dioxide formula CO₂

      Weight per mole of substance

        PM = 12 + 2 16

        Pm = 44 gr / mol

D) Nitrogen dioxide formula NO₂

       Weight per molecular

         MP = 14 + 2 16

         PM = 46 gr / mol

E) Oxygen symbol O formula O₂

      Molecular weights

         PM = 2 16

         PPM = 32 gr / mol

It indicates that we have two liters of sample, so the number of moles of each substance is the same, therefore the substance that weighs more is Nitrogen Dioxide (NO₂)

When reviewing the different answer, the correct one is:

            D) Nitrogen Dioxide

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15.0 moles of gas are in a 8.00 L tank at 22.3 ∘C∘C . Calculate the difference in pressure between methane and an ideal gas under these conditions. The van der Waals constants for methane are a=2.300L2⋅atm/mol2 a=2.300L2⋅atm/mol2 and b=0.0430L/molb=0.0430L/mol.

Answers

Answer:

[tex]\Delta P=4.10atm[/tex]

Explanation:

Hello!

In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):

[tex]P^{ideal}=\frac{nRT}{V}=\frac{15.0mol*0.08206\frac{atm*L}{mol*K}*295.45K}{8.00L}=45.5atm[/tex]

Next, since the VdW equation requires the molar volume, we proceed as shown below:

[tex]v=\frac{8.00L}{15.0mol}=0.533\frac{L}{mol}[/tex]

Now, we use its definition:

[tex]P^{VdW}=\frac{RT}{v-b} -\frac{a}{v^2}[/tex]

Thus, by plugging in we obtain:

[tex]P^{VdW}=\frac{0.08206\frac{atm*L}{mol*K}*295.45K}{0.533mol/L-0.0430L/mol} -\frac{2.300L^2*atm/mol^2}{(0.533L/mol)^2}\\\\P^{VdW}=49.44atm-8.09atm\\\\P^{VdW}=41.4atm[/tex]

Thus, the pressure difference is:

[tex]\Delta P=45.5atm-41.4atm\\\\\Delta P=4.10atm[/tex]

Best regards!

Redox reactions stand for oxidation/reduction reactions. True or false: an oxidation reaction is always paired with a reduction reaction.

Answers

Answer:

The answer is: true

Explanation:

In redox reactions, the half-reactions of oxidation and reduction always occur simultaneously in pair.

The oxidation half-reaction involved the lost of electrons from a reduced substance (A) to form a oxidized substance (A⁺):

A ⇒ A⁺ + e-

In contrapossition, during the reduction half-reaction the oxidized substance (B⁺) gains electrons to form the reduced subtance (B):

B⁺ + e- ⇒ B

The overall redox reaction is obtained by the addition of the two half-reactions:

A ⇒ A⁺ + e-

B⁺ + e- ⇒ B

-----------------

A + B⁺⇒ A⁺ + B

The electrons gained by B are provided by A, which lost the same number of electrons. Thus, the oxidation/reduction reactions are paired.

how many moles of Na2SO4 are in 0.140 m aqueous solution that was prepared with 2.30 kg of water?

Answers

Answer:

0.322 mols of NaSO4

Explanation:

Molality = Mols of Solute / kg of Solvent

Molality is given as 0.140 m = mols/kg

kg of solution is given as 2.30 kg

Mols of Solute = Molality * kg of Solvent

Mols of Solute = [tex]\frac{0.140 }{ 1 kg } *2.30 kg[/tex]

Mols of Solute = 0.322 mols

The number of mole of Na₂SO₄ required to prepare the solution is 0.322 mole

The Molality of a solution is defined as the mole of solute per Kg of water i.e

Molality = mole / mass (Kg) of water.

With the above formula, we can obtain the mole of Na₂SO₄ in the solution as follow:

Molality of Na₂SO₄ = 0.140 M

Mass of water = 2.30 Kg

Mole of Na₂SO₄ =.?

Mole = Molality × mass of water

Mole of Na₂SO₄ = 0.140 × 2.30

Mole of Na₂SO₄ = 0.322 mole

Therefore, the mole of Na₂SO₄ in the solution is 0.322 mole

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Does MgO have a structure like that of NaCl or ZnS? If the density of MgO is 3.58g/cm3, estimate the radius (in centimeters) of the O2â anions and of the Mg2+ cations.

Answers

Answer:

The radius of O^2- is  1.5*10^-8 cm and the radius of

Mg ^2+ is 6.2*10^-9 cm

Explanation:

Face centered cubic : 1/8 atoms on each edges + 1/2 atoms on each face

                                           = [tex]\frac{1}{8}* 8 + \frac{1}{2}*6[/tex]  = 4 effective atoms

MgO have a structure like NaCl forms a lattice of FCC.

density of the lattice =  [tex]\frac{ z.M}{a^3*Na}[/tex]

z : no of atoms

M: mass of the atoms

a: radius of the atom

Na: Avogadro's number

a^3(radius)  = [tex]\frac{ 4*40.3}{3.58*6.022*10^23}[/tex]

a^3 = 7.477 * 10^-23 cm^3

a = 4.21 * 10^-8 cm

Now calculating the anionic(ra O^2-) and cationic (rc Mg^2+)

in Fcc a = 2[tex]\sqrt{2} ra[/tex]

ra = 1.5*10^-8 cm

a = 2ra + 2rc

rc = a/2 -ra

rc = 6.2*10^-9 cm

The radius of O^2- is  1.5*10^-8 cm and the radius of Mg ^2+ is 6.2*10^-9 cm

A student is preparing for the titration of 20.0 mL of an approximately 0.3 M solution of NH3 using HCl . She has a 50.0 mL buret and four possible HCl solutions to fill it with. Which solution would be best for use in her titration?a. 6.00 M HCI(aq) b. 0.3 M HCI(aq) c. 0.200 M HCI(aq) d. 0.100 M HCl(aq)

Answers

Answer:

c. 0.200 M HCI(aq)

Explanation:

The titration of a base as NH3 with hydrochloric acid is:

NH3 + HCl → NH4Cl

Where 1 mole of NH3 reacts per mole of HCl

The recommended volume to read in a burette is between 60 and 80% of its capacity.

That is 60% 50.0mL = 30mL and 80% 50.0mL = 40mL must be spent.

A 6.00M HCl spend:

20mL * (0.3mol/L) * (1L/ 6.00M) = 1mL. This solution is not the ideal for the titration.

A 0.3M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.3M) = 20mL. This solution is not the ideal for the titration.

A 0.200M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.200M) = 30mL. This solution ideal for the titration.

A 0.100M HCl spend:

20mL * (0.3mol/L) * (1L/ 0.100M) = 60mL. This solution is not the ideal for the titration.

Right option is:

c. 0.200 M HCI(aq)

Phenol (C6H5OH) is often used as an antiseptic in mouthwashes and throat lozenges. If a mouthwash has a phenol concentration of 1.5 g per 100 mL of solution, what is the molarity of phenol?

Answers

Answer:

[tex]M=0.16M[/tex]

Explanation:

Hello!

In this case, since the molarity is defined as moles of solute divided by liters of solution, since we have phenol with a molar mass of 94.12 g/mol, we can first compute the moles in 1.5 g of phenol:

[tex]n=1.5g*\frac{1mol}{94.12 g}=0.016mol[/tex]

Next, since 1000 mL = 1 L, we notice that the volume of the solution is 0.100 L and therefore, the molarity of such solution turns out:

[tex]M=\frac{n}{V}=\frac{0.016mol}{0.100L}\\\\M=0.16M[/tex]

Best regards!

What does the word subcellular mean

Answers

Answer:

the word subcellular means contained within a cell. at a level of organization lower than the cellular.

Explanation:

Which two bonds are most similar in polarity? Which two bonds are most similar in polarity? O-F and Cl-F B-F and Cl-F I-Br and Si-Cl Al-Cl and I-Br C-Cl and Be-Cl

Answers

Answer:

A

Explanation:

gyx3gevedyhsdv

The branch of science which deals with chemicals and bonds is called chemistry.

The correct answer is A.

The polarity is defined as the separation of electric charge leading to a molecule or its chemical groups having an electric dipole moment, with a negatively charged end and a positively charged end.

The polar molecule has the following:-

Difference in electronegativity.

In, the first compound the polarity is the same because the compound is the same that is O-F and CL-F.

Hence, the correct answer is A.

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Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is __________.a) C2b) N2c) F2d) O2e) Ne2

Answers

Answer:

B.

Explanation:

ive done this before trust

2. If you travel 7.5 km and walk for 1.5 h. what is your average speed
Show Your Work Actual

Answers

Answer:

5km/h

Explanation:

Given parameters:

Distance  = 7.5km

Time  = 1.5h

Unknown:

Average speed   = ?

Solution:

Average speed is the distance divided by the time taken.

 Average speed  = [tex]\frac{total distance }{time taken}[/tex]  

Insert the parameters and solve;

 Average speed  = [tex]\frac{7.5}{1.5}[/tex]   = 5km/h

Of the following, which is NOT a component of the circulatory system?
A. Heart
B. Veins
ws
C. Arteries
D. Brain

Answers

Answer:

D. Brain

~PumpkinSpice1

D. Brain Bec that belongs to nervous system?

amu.
An atom with 4 protons, 5 neutrons, and 4 electrons has an atomic mass of
(Enter a whole number.)

Answers

Answer:

Explanation:

the sum of number of proton and neutron is known as atomic mass

so if number of proton is 4 and neutron is 5 then atomic mass of an atom is 9

2 or more forces that are not equal and opposite of one another can cause change in motion

A. Balanced force

B.friction

C.gravitational force

D.unbalanced force

Answers

Answer:

D unbalanced force

Explanation:

i think

Dinitrogen tetraoxide, a colorless gas, exists in equilibrium with nitrogen dioxide, a reddish brown gas. One way to represent this equilibrium is:

Answers

The question is incomplete, the complete question is shown in the image attached

Answer:

F

T

Explanation:

From the equilibrium equation;

N2O4(g) ⇄NO2(g)

We must have to remember that;

1) At equilibrium, the concentration of the species on both sides of the reaction equation may not necessarily be the same but must be held at a constant value because the rate of forward reaction equals the rate of reverse reaction.

2) The rate of forward reaction must equal the rate of reverse reaction.

If the rate of forward reaction is k1 and the rate of reverse reaction is k2. Then it follows that at equilibrium k1 = k2.

Why does water have a much higher boiling point than methane even though water (H20) and methane (CH4) molecules are approximately the same size?
A. Only metallic bonds exist between methane molecules.
B. Only Van der Waals forces exist between water molecules.
C. Only metallic bonds exist between water molecules.
D. Only Van der Waals forces exist between methane molecules.​

Answers

Answer:

Water has a higher boiling point because the hydrogen bonds that form water molecules are stronger than the Van der Waals interactions among methane molecules, therefor more energy must be provided in order to break the hydrogen bonds and allow the water molecules to escape the liquid state.

Explanation:

Water has a much higher boiling point than methane because only Van der Waals forces exist between methane molecules.

What are chemical bonds?

Chemical bonds are forces of attraction between ions, molecules, and atoms.

There are different types of bonds present

Covalent bonds are the strongest bonds.

The molecules of water are joined by a hydrogen bond, thus its boiling point is high.

The molecules of Methane are attached by the van der Waals force, and it is weaker than the hydrogen bond.

Thus, methane has a lower boiling point than water.

Weaker bonds easily get broken.

Thus, the correct option is D.

Learn more about Chemical bonds

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Why can’t you ice skate on a lake when it is not frozen?

Answers

Because you’ll fall in the water.

What is 50% of 36?
O 9
O 16
O 18
O 34

Answers

18 is 50% of 36
Like 36 divided by 2

Answer:

18

Explanation:

36 times 0.5

In the third century B.C., King Hieron of Syracuse asked the famous mathematician Archimedes to determine if his crown was made of pure gold. This was a puzzling problem for Archimedes-he knew how to measure the weight of the crown, but how could he measure the volume? Archimedes solved the problem when he got into his bath and noticed the water spilling over the sides of the tub. He realized that the volume of the displaced water must be equal to the volume of the object placed into the water. Archimedes was so excited by. his discovery that he jumped out of the bath and ran through the streets shouting "Eureka!" a. How can you tell if a crown is made of solid gold? b. Gold is one of the densest substances known, with a density of 19.3 g/mL. If the gold in the crown was mixed with a less-valuable metal like bronze or copper, how would that affect its density? c. What is the relationship between the object density, the liquid density, and the tendency of the object to float? d. From the experimental results obtained by you in the lab of the density of the liquid and the object, could the object float in that liquid? Explain.

Answers

Answer:

See explanation

Explanation:

a. I can conclusively tell if the crown was made of gold by measuring its density. First the mass of the crown is measured on a weighing balance. The crown is now put into a given volume of water and the volume of water displaced is accurately measured. The density of the crown is computed as mass/volume of fluid displaced. If the density of the crown is 19.3 g/mL, then it is made of solid gold.

b) When less valuable metals such as bronze or copper is mixed with gold in the crown, the density of the crown decreases and the crown becomes more brittle.

c) An object will float in a liquid when the density of the object is less than the density of the liquid. Hence the tendency of an object to float in a liquid depends on the density of the object and the density of the liquid.

d) Even though i do not know the results from your experiment but as regards the decision as to whether the object will float in the given liquid or not, reference must be made to the measured density of the object as well as the given density of the liquid. If the object is less dense (from values of density obtained from the experiment)  than the liquid, then the object will float in the liquid and vice versa.

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