1) Before the boiling point, the temperature of the water increases and it begins to boil. Boiling is the physical process by which a liquid changes to a gaseous state. It runs when the temperature of the entire liquid is equal to the boiling point of the liquid at that pressure. As the liquid continues to heat up, it absorbs heat, but without raising the temperature, it uses the heat to transform the substance from the liquid to the gaseous state, shifting the entire mass into the gaseous state. The heat that is generated in heating most of the liquid is called sensible heat, and the heat that appears during a change of state is called latent heat of boiling or vaporization.
2) Because iron is "closer" to its molecules, it can absorb more energy and, as a result, heat up faster. Instead, bricks have tiny air holes. That is, its molecules are "far away" and are not easily heated. As they conduct heat (conduction or convection), they lose energy.
3) When a piece of heated iron is placed in room temperature water, the iron gives off heat to the water (cooling) and the water receives heat (heating). Because the iron gives heat.
4) When you put a brick on top of an iron and heat it up, the iron heats up faster and starts heating the brick by conduction (because the material sticks together). In addition, the heat absorption capacity of the brick itself makes it warmer.
What is heat energy?
The term "thermal energy" is used loosely in various contexts of physics and engineering. We can refer to some well-defined physical concepts. These include the internal energy or enthalpy of matter and radiation. Heat (and thermodynamic work) defined as the mode of energy transfer. and the characteristic energies of the degrees of freedom of the system described by its microscopic particle content (where T denotes the temperature and Boltzmann constant).
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Answer:
Weight = 8.162 Newton.
Explanation:
Given the following data;
Mass = 2.2 kg
Acceleration due to gravity = 3.71 N/kg
To find the weight of the textbook;
Weight = mass * acceleration due to gravity
Weight = 2.2 * 3.71
Weight = 8.162 N
Therefore, the weight of the science textbook in mars is 8.162 Newton.
Please help The position of masses 4kg, 6kg, 7kg, 10kg, 2kg, and 12kg are (-1,1), (4,2), (-3,-2), (5,-4), (-2,4) and (3,-5) respectively. Determine the position of the center of mass of this system?
Answer:
(1.9756, -2.1951)
Explanation:
The center of mass equation is: [tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex], where m represents the masses and x represents the position.
In order to find the coordinates of the center of mass, we need to use this equation for both the x-values and the y-values.
x-values:
[tex]x_{cm}[/tex] = [tex]\frac{m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + m_{4}x_{4} + m_{5}x_{5} + m_{6}x_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(-1)+6(4)+7(-3)+10(5)+2(-2)+12(3)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(-4)+(24)+(-21)+(50)+(-4)+(36)}{41}[/tex] = [tex]\frac{81}{41}[/tex] = 1.9756
y-values:
[tex]y_{cm}[/tex] = [tex]\frac{m_{1}y_{1} + m_{2}y_{2} + m_{3}y_{3} + m_{4}y_{4} + m_{5}y_{5} + m_{6}y_{6}}{m_{1} + m_{2} + m_{3} + m_{4} + m_{5} + m_{6}}[/tex] = [tex]\frac{4(1)+6(2)+7(-2)+10(-4)+2(4)+12(-5)}{4+6+7+10+2+12}[/tex] = [tex]\frac{(4)+(12)+(-14)+(-40)+(8)+(-60)}{41}[/tex] = [tex]\frac{-90}{41}[/tex] = -2.1951
center of mass:
(1.9756, -2.1951)
40 POINTS!!! PLEASE HELPP!!!
Please select the word from the list that best fits the definition
One form of energy changes to one other form
(A.) single transformation
(B.) multiple transformation
Answer:
A
Explanation:
if it was B it would say from one to another to another
PLEASE HELP !!!!!!!!!!
Answer:
1
Explanation:
Two vectors are given as A⃗ = 2i^ + 3j^ − 3k^ and B⃗ = -1i^ + 5j^ + 3k^. Find A⃗ ⋅ B⃗
Answer:
A·B = 4
Explanation:
Given that,
Vector A = 2i+3j-3k
Vector B = -i+5j+3k
We need to find the value of A·B.
We know that,
i·i=j·j=k·k = 1 and i·j=j·k=k·i=0
So,
[tex]A\cdot B=(2i+3j-3k)\cdot (-i+5j+3k)\\\\=-2+5(3)+(-3)(3)\\\\=-3+15-9\\\\=4[/tex]
So, the value of A·B is equal to 4.
scholastic science world
CHECK FOR UNDERSTANDING: VIDEO GAME TYCOONS
a
Ten 2.2 v cells each having an internal
resistance of o.1ohms in are connected in series
to a load of 21ohm. Determine
pd at the battery terminals
Answer:
22Volts
Explanation:
The pd at the terminal is known as the emf
Since there are Ten 2.2V cells
Terminal voltage = number of cells * pd of one cell
Terminal voltage = 10 * 2.2
Terminal voltage = 22V
Hence the pd at the battery terminals is 22Volts
You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from behind the handle. You are sanding a wall in front of you. as you turn the sander towards the right, you feel a tendency in the sander to...
a. pull away from you
b. turn towards the left
c. turn downward
d. turn upward
e. push toward you
Answer:
c. turn downward
Explanation:
From the information given:
To find the tendency of the sander;
We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.
Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.
convert 1 day into seconds.(you will need to show your work to receive credit.) please help thank you
Answer:
the answer is 86400seconds.
Explanation:
1day= 24 hours
24hours to seconds =
24×60×60= 86400 seconds.
( 60 second = 1 minutes)
( 60 minutes = 1 hour)
The wireless system is operating at 2GHz. A base station and a mobile unit are separated by 16km. The maximum gain of the transmitting antenna at the base station is 20dB. The input power to the transmitter is 100W, and the power received by the antenna is 5nW. The antennas are aligned, and there are no re ections or loses. What will be the received power if the distance between the mobile unit and the base station increases to 20km?
If everything else remains constant, then the received signal power is simply an inverse-square function of its distance from the transmitter.
That is, down 6dB when distance is doubled etc.
If distance increases from 16 to 20, then received power decreases by the factor of (16/20)^2.
That's (0.8)^2 = 0.64
New receive power is 5x0.64 = 3.2 nW
=. ===== ==========
Here's how I do it at my job:
Initial RSL = 5nW ~ - 53 dBm
loss = 20log(20/16)= 20log(1.25)~1.94dB
New RSL = - 54.94 dBm or ~ 3.2 nW .
can someone please help me !!!!
Answer:
it's A subduction, deep water trench
Energy associated with moving objects or that could move later is?
How do our attitudes help us organize our reality?
Answer:
If we are upset, often our mind cannot think straight. we need to take deep breaths, and focus on reality. When we are upset we do things out of anger.
Explanation:
Hope this helps!
Niobium metal becomes a superconductor when cooled below 9K. Itssuperconductivity is destroyed when the surface magnetic fieldexceeds 0.100 T. Determine the maximum current a 2.00-mm-diameterniobium wire can carry and remain superconducting, in the absenceof any external magnetic field.
Answer:
the maximum current is 500 A
Explanation:
Given the data in the question;
the B field magnitude on the surface of the wire is;
B = μ₀i / 2πr
we are to determine the maximum current so we rearrange to find i
B2πr = μ₀i
i = B2πr / μ₀
given that;
diameter d = 2 mm = 0.002 m
radius = 0.002 / 2 = 0.001 m
B = 0.100 T
we know that permeability; μ₀ = 4π × 10⁻⁷ Tm/A
so we substitute
i = (0.100)(2π×0.001 ) / 4π × 10⁻⁷
i = 500 A
Therefore, the maximum current is 500 A
ian pushed a piano across the room with the correct amount of force. Which of newton’s laws is this?
Newton’s 1st, 2nd, 3rd, or 1st and 2nd law?
Answer:
1st and 2nd
Explanation:
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Answer:
Altitude is the height of landmass calculated from sea level. No it has no effect on weight.
Explanation:
The altitude at sea level is always assumed to be 0°, thus as you move away from altidude is calculated in increments while moving into the sea, the vice versa is true.
Which of the following has no energy?"
Amoving ball
Awrecking ball
Non of the above
A 3 kg block collides with a massless spring of spring constant 98 N/m attached to a wall. The speed of the block was observed to be 1.5 m/s at the moment of collision. The acceleration of gravity is 9.8 m/s 2 . How far does the spring compress if the surface on which the mass moves is frictionless
Answer: 0.83 m
Explanation:
Given
mass of the block is m=3 kg
spring constant k=98 N/m
The Speed at the time of collision is v=1.5 m/s
Here, the kinetic energy of the block is converted into Elastic potential energy
[tex]\Rightarrow \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2 \\\\\Rightarrow 3\times 1.5^2=98\times x^2\\\\\Rightarrow x^2=0.6887\\\\\Rightarrow x=0.829\approx 0.83\ m[/tex]
32. Assume the helium-neon lasers commonly used in student physics laboratories have power outputs of 0.500 mW. (a) If such a laser beam is projected onto a circular spot 1.00 mm in diameter, what is its intensity
Answer:
636.6 W/m²
Explanation:
From the given information:
The area of the circular spot can be calculated as:
A = πr²
A = π(0.5 × 10⁻³ m)²
A = 7.85 × 10⁻⁷ m²
The intensity can be determined by using the formula:
[tex]I = \dfrac{P}{A}[/tex]
[tex]I = \Big ( \dfrac{0.500 \ mW}{\pi (0.5 \times 10^{-3} \ m )^2} \Big) \Big( \dfrac{10^{-3} \ W}{1\ mW} \Big)[/tex]
[tex]I = \dfrac{0.500 \times 10^{-3} }{\pi(0.25 \times 10^{-6} )}[/tex]
I = 636.6 W/m²
You are trying to catch the mutated mouse and you have a rope
that both you and the mouse are pulling with a force of 500 Newtons,
but the rope does not move.
How much work is done?
PLS ANSWER ASAP! WILL MARK AS BRAINLYIST!!!!!
time left (5:00)!!
Answer:
none no work cuz no motion
Explanation:
GOOD LUCK
If a 5-L balloon at 25 degrees celsius were gently heated to 30 degrees celsius, what new volume would the balloon have? Show all work for credi
Answer: 5.08 L.
Explation down below
3) 4 electrons are placed - one electron per corner - at the corners of a square of side 1 meter. One fixed proton is placed in the middle of the square.The 4 electrons are held in place by some mechanism. The 4 electrons are released by the mechanism at the same time. They move and reach the corners of a square of side 0.8 meters, and keep on moving . Find the velocity of each electron at the corners of the square of side 0.8 meters.
Explanation:
3
i believe that they are all going at 3.2 meters each, I did 4 times 0.8
The velocity of each electron at the corners of the square is 15.92 m/s.
The given parameters;
charge of electron, q = 1.6 x 10⁻¹⁹ Clength of the square, L = 0.8 mThe diagonal length of the square is calculated as;
[tex]d^2 = 0.8^2 + 0.8^2\\\\d = \sqrt{0.8^2 + 0.8^2} \\\\d = 1.13 \ m[/tex]
The distance of each corner charge and the middle charge is calculated as;
[tex]r = \frac{1.13}{2} \\\\r = 0.565 \ m[/tex]
The force between each corner charge and the middle charge is calculated as;
[tex]F= \frac{kq^2}{r^2}[/tex]
The centripetal force on each charge moving around the square is calculated as;
[tex]F = \frac{mv^2}{r}[/tex]
solve the forces together;
[tex]\frac{mv^2}{r} = \frac{kq^2}{r} \\\\v^2 = \frac{kq^2}{m} \\\\v = \sqrt{ \frac{kq^2}{m} } \\\\v = \sqrt{ \frac{(9\times 10^9) \times (1.602\times 10^{-19})^2}{9.11 \times 10^{-31}} } \\\\v = 15.92 \ m/s[/tex]
Thus, the velocity of each electron at the corners of the square is 15.92 m/s.
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define the term change and state one negative change you may encounter as a student or as an employee in the future
Answer:
hey iam bored pls join
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Password: 1111
The term change refers to an alteration of present conditions.
What is change?The term change refers to an alteration of present conditions. When a change occurs, things cease to be the way they were. As a student, the complexity of academic work increases with time. This is a change that has taken place.
As an employee, you are given real world tasks to accomplish rather than mere mental exercises like when you were a student, this is change that has taken place.
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Plz help, will Mark brainliest. A 20.0 Ohm and 60.0 Ohm resistor are connected in series to a 9.00 V battery. How much current flows out of the battery?
(Unit = A)
Answer: 0.1125A
Explanation:
We need to know the total resistance which will be:
R = R1+R2
where,
R1 = 20 ohm
R2 = 60 ohm
Therefore, R = 20 + 60 = 80 ohm
We should note that from Ohm's law
v = iR
i = v/R
where,
i = 9/80 = 0.1125 A
Therefore, the current that flows out of the battery is 0.1125A
Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. Suppose the mass of a certain spherical neutron star is twice the mass of the Sun and its radius is 13.0 km. Determine the greatest possible angular speed the neutron star can have so that the matter at its surface on the equator is just held in orbit by the gravitational force. (The mass of the Sun is 1.99 1030 kg.)
Answer:
The required angular speed the neutron star is 10992.32 rad/s
Explanation:
Given the data in the question;
mass of the sun M[tex]_S[/tex] = 1.99 × 10³⁰ kg
Mass of the neutron star
M[tex]_N[/tex] = 2( M[tex]_S[/tex] )
M[tex]_N[/tex] = 2( 1.99 × 10³⁰ kg )
M[tex]_N[/tex] = ( 3.98 × 10³⁰ kg )
Radius of neutron star R[tex]_N[/tex] = 13.0 km = 13 × 10³ m
Now, let mass of a small object on the neutron star be m
angular speed be ω[tex]_N[/tex].
During rotational motion, the gravitational force on the object supplies the necessary centripetal force.
GmM[tex]_N[/tex] = / R[tex]_N[/tex]² = mR[tex]_N[/tex]ω[tex]_N[/tex]²
ω[tex]_N[/tex]² = GM[tex]_N[/tex] = / R[tex]_N[/tex]³
ω[tex]_N[/tex] = √(GM[tex]_N[/tex] = / R[tex]_N[/tex]³)
we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²
we substitute
ω[tex]_N[/tex] = √( ( 6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)
ω[tex]_N[/tex] = √( 2.65466 × 10²⁰ / 2.197 × 10¹²
ω[tex]_N[/tex] = √ 120831133.3636777
ω[tex]_N[/tex] = 10992.32 rad/s
Therefore, The required angular speed the neutron star is 10992.32 rad/s
A fisherman sitting on the end of a pier notices that 6 wave crests pass him in 3 seconds. What is the frequency of the waves?
9.0 Hz
18.0 Hz.
20 Hz
4.5 Hz
The frequency of the waves will be 18 Hz. Then the correct option is B.
What is the frequency?The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.
Frequency is the number that represents the number of oscillations or intervals each second. The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.
The number of finished waves produced each second is considered the wave frequency.
Six wave crests pass a fisherman sitting at the end of a pier in the span of three seconds.
The frequency of the waves is given as,
f = 6 x 3
f = 18 Hz
The waves will have a frequency of 18 Hz. Then, choice B is the best one.
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If a wave has a frequency of 5 hertz, the period for one wave cycle will be
Answer:
0.2 seconds
Explanation:
f=1/t
1/5=0.2
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Which waves can travel through space?
a. Electromagnetic waves only
b. Mechanical waves only
c. Electromagnetic and mechanical waves
d. Longitudinal and electromagnetic waves
Answer:
electromagnetic waves only
Explanation:
I just took the test, Hope it helps!
Answer:
A: Electromagnetic waves only
Explanation:
Help please & actually answer thank youu :)
Answer:
highest KE and lowest GPE = Dhighest GPE and lowest KE = Asome KE and some PE = B