The average temperature of coffee in the population, which is unknown.
In this problem, "mu" represents the average temperature of coffee in the population, which is unknown.
When conducting statistical analysis, it is common to use Greek letter μ (mu) to represent the population mean.
The population mean represents the average value of a variable in the entire population being studied.
In this case, the coffee company wants to ensure that the average temperature of their coffee, which is represented by μ, is at the desired level of 65 degrees Celsius.
However, the population mean is unknown to the company, and they are trying to estimate it based on a sample.
The sample mean, denoted by [tex]\bar{x}[/tex] (x-bar), is the average temperature of coffee in the sample they took. In this problem, the sample mean is reported as 70.2 degrees Celsius.
It's important to differentiate between the sample mean (70.2) and the population mean (μ).
The sample mean provides an estimate of the population mean, but it is not necessarily the same value.
In summary, in this problem, μ represents the average temperature of coffee in the population, which is unknown.
The sample mean, [tex]\bar{x}[/tex] is the average temperature of coffee in the sample and is reported as 70.2 degrees Celsius.
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Consider an RC circuit in which the resistance R = 2, the capacitance C = 0.5 F, and the electromotive force E (t) = te-2t V. What is the differential equation governing the variation of c?
The differential equation governing the variation of the charge (c) in the given RC circuit is 2(d^2q/dt^2) + (1/0.5)(dq/dt) = d(E(t))/dt, where q represents the charge, t represents time, and E(t) represents the electromotive force of the circuit. This equation describes the relationship between the charge, current, and voltage in the RC circuit.
To compute the differential equation governing the variation of the charge (c) in the given RC circuit, we can start by using Kirchhoff's voltage law (KVL) and the relationship between charge, capacitance, and voltage.
Kirchhoff's voltage law states that the sum of the voltages in a closed loop in a circuit is equal to zero. In this case, the voltage across the resistor (VR) and the voltage across the capacitor (VC) must sum up to the electromotive force (E) of the circuit.
The voltage across the resistor can be calculated using Ohm's Law: VR = IR, where I is the current flowing through the circuit.
The voltage across the capacitor can be calculated using the formula: VC = (1 / C) ∫Idt, where ∫Idt represents the integral of the current over time.
Combining these equations, we have:
E(t) = VR + VC
E(t) = IR + (1 / C) ∫Idt
Differentiating both sides of the equation with respect to time, we get:
d(E(t)) / dt = d(IR) / dt + d((1 / C) ∫Idt) / dt
Since the resistance R and the capacitance C are constant values, their derivatives with respect to time are zero.
d(E(t)) / dt = R(dI / dt) + (1 / C)(I)
Substituting I with dq / dt, where q represents the charge c, we get:
d(E(t)) / dt = R(d^2q / dt^2) + (1 / C)(dq / dt)
Simplifying the equation, we obtain the differential equation governing the variation of c:
R(d^2q / dt²) + (1 / C)(dq / dt) = d(E(t)) / dt
In summary, the differential equation governing the variation of the charge (c) in the given RC circuit is:
2(d^2q / dt²) + (1 / 0.5)(dq / dt) = d(E(t)) / dt
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I do a one-way within-subjects ANOVA with one factor and four groups. How many groups would my participants be a member of? O 3 0 1 O 2 4 Question 8 2 pts Which sums of squares is only found in a one-way within-subjects ANOVA? O Between-persons sums of squares O Interaction sums of squares O Between-groups sums of squares Total sums of squares Within-groups sums of squares Question 9 2 pts I do a one-way within-subjects ANOVA and find that my overall model is significant. What do I do next? I would look at my b-weights to see which variables are significant o I would do a post-hoc Tukey test I would do a post-hoc Bonferroni test I would do a simple main effects analysis Question 10 2 pts True or false: On average, eta-squared, partial eta squared, and R-squared are all measures of effect size that refer to the proportion of variance explained within a study. True False 11 39 2 pts When doing a two-way between subjects ANOVA, how many F-tests would I normally run? O1 O2 04 D Question 12 2 pts Which sums of squares is only found in a two-way between-subjects ANOVA? Between-groups sums of squares Between persons sums of squares Within-groups sums of squares Total sums of squares Interaction sums of square?
1. The participants would be a member of all four groups. In a within-subjects ANOVA, participants are exposed to all levels of the factor, so they experience each group.
2. The within-groups sums of squares is only found in a one-way within-subjects ANOVA. This represents the variability within each group or condition.
3. In this case, you would typically conduct a post-hoc analysis to determine which specific groups or conditions differ significantly from each other. Common post-hoc tests for within-subjects ANOVA include the Bonferroni or Tukey tests. These tests help identify pairwise differences between the groups.
4. True. Eta-squared, partial eta-squared, and R-squared are all measures of effect size that indicate the proportion of variance explained within a study. They provide information about the strength and magnitude of the effect being studied.
5. When conducting a two-way between-subjects ANOVA, you would typically run two F-tests: one for each main effect and one for the interaction effect. The main effects assess the effects of each independent variable separately, while the interaction effect examines whether the combined influence of the variables is significant.
6. The between-groups sums of squares is only found in a two-way between-subjects ANOVA. It represents the variability between the different groups or levels of the independent variables.
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Kianna says that Elena’s house is actually a reflection of her house across the y-axis.
Is Kianna right?
Answer: Kianna is incorrect, if Elena’s house was a reflection of her house across the y-axis, the coordinates would be (-4,2).
Step-by-step explanation:
Solve the following equation when x =
2 and y = 4.
3x + 2y + 4 =
Step-by-step explanation:
the answer is x=-4 ,y=-5
When approximating Sºf(x)dx using Romberg integration, R33 gives an approximation of order: h10 h8 h4 h6 Romberg integration for approximating S. f(x)dx gives R21 = 7 and R22 = 7.21 then f(1) = 4.01 3.815 1.68 -0.5
Using Romberg integration, f(1) = 4.01.
Based on the given information, we can deduce the order of approximation for [tex]R_{33}[/tex] in Romberg integration as h10, h8, h4, h6. Additionally, we are given the values [tex]R_{21} = 7[/tex] and [tex]R_{22} = 7.21[/tex].
Romberg integration typically follows the pattern R(k, m), where k represents the number of iterations and m denotes the number of function evaluations per iteration.
From [tex]R_{21} = 7[/tex], we can determine that the approximation achieved after two iterations is 7.
From [tex]R_{22} = 7.21[/tex], we can conclude that the approximation achieved after two iterations is 7.21.
Since [tex]R_{21}[/tex] and [tex]R_{22}[/tex] represent the same number of iterations (k = 2), we can directly compare the results of these two approximations.
Therefore, the final answer is: f(1) = 4.01.
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You measure 47 watermelons' weights, and find they have a mean weight of 33 ounces. Assume the population standard deviation is 7.7 ounces. Based on this, construct a 90% confidence interval for the true population mean watermelon weight. Give your answer as m (round to 2 decimal places) + ounces You measure 21 turtles' weights, and find they have a mean weight of 56 ounces. Assume the population standard deviation is 2.9 ounces. Based on this, construct a 99% confidence interval for the true population mean turtle weight. Enter your answer as #Im.Give your answers as decimals, to two places + ounces You measure 34 textbooks' weights, and find they have a mean weight of 62 ounces. Assume the population standard deviation is 9.4 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places Out of 200 people sampled, 104 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Enter your answer as p m Give your answers as decimals, to three places. + Out of 300 people sampled, 189 had kids. Based on this, construct a 99% confidence interval for the true population proportion of people with kids. Give your answers as decimals, to three places
a. The 90% confidence interval for the true population mean watermelon weight is 30.41 to 35.59 ounces.
b. The 99% confidence interval for the true population mean turtle weight is 54.56 to 57.44 ounces.
c. The 99% confidence interval for the true population mean textbook weight is 56.884 to 67.116 ounces.
d. The 99% confidence interval for the true population proportion of people with kids is 0.464 to 0.576.
e. The 99% confidence interval for the true population proportion of people with kids is 0.585 to 0.675.
a. For the watermelon weights:
Sample mean (m) = 33 ounces
Population standard deviation (σ) = 7.7 ounces
Sample size (n) = 47
Confidence level = 90%
To construct the confidence interval, we can use the formula:
Confidence Interval = m ± Z * (σ/√n)
Where Z is the z-score corresponding to the desired confidence level. For a 90% confidence level, Z = 1.645 (obtained from the standard normal distribution table).
Confidence Interval = 33 ± 1.645 * (7.7/√47)
Confidence Interval ≈ 33 ± 2.586
Confidence Interval ≈ (30.41, 35.59) ounces
The 90% confidence interval for the true population mean watermelon weight is 30.41 to 35.59 ounces.
b. For the turtle weights:
Sample mean (m) = 56 ounces
Population standard deviation (σ) = 2.9 ounces
Sample size (n) = 21
Confidence level = 99%
Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.
Confidence Interval = 56 ± 2.576 * (2.9/√21)
Confidence Interval ≈ 56 ± 1.438
Confidence Interval ≈ (54.56, 57.44) ounces
The 99% confidence interval for the true population mean turtle weight is 54.56 to 57.44 ounces.
c. For the textbook weights:
Sample mean (m) = 62 ounces
Population standard deviation (σ) = 9.4 ounces
Sample size (n) = 34
Confidence level = 99%
Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.
Confidence Interval = 62 ± 2.576 * (9.4/√34)
Confidence Interval ≈ 62 ± 5.116
Confidence Interval ≈ (56.884, 67.116) ounces
The 99% confidence interval for the true population mean textbook weight is 56.884 to 67.116 ounces.
d. For the proportion of people with kids:
Number of people with kids (p) = 104
Sample size (n) = 200
Confidence level = 99%
To construct the confidence interval for a proportion, we can use the formula:
Confidence Interval = p ± Z * √[(p(1-p))/n]
Using the z-score corresponding to a 99% confidence level (Z = 2.576), we can calculate the confidence interval.
Confidence Interval = 104/200 ± 2.576 * √[(104/200)(1 - 104/200)/200]
Confidence Interval ≈ 0.52 ± 0.056
Confidence Interval ≈ (0.464, 0.576)
The 99% confidence interval for the true population proportion of people with kids is 0.464 to 0.576.
e. For the proportion of people with kids:
Number of people with kids (p) = 189
Sample size (n) = 300
Confidence level = 99%
Using the same formula as above and considering a 99% confidence level, the z-score is Z = 2.576.
Confidence Interval = 189/300 ± 2.576 * √[(189/300)(1 - 189/300)/300]
Confidence Interval ≈ 0.63 ± 0.045
Confidence Interval ≈ (0.585, 0.675)
The 99% confidence interval for the true population proportion of people with kids is 0.585 to 0.675.
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I need help with this question
Answer:
286 Degrees
Step-by-step explanation:
A circle is 360 degrees, and from the question, we know that it is asking for ACB, so it would be 360 - 74, which is 286 degrees
Brainliest Maybe?
what is this please? i'll give u brainliest
Answer:
i dont know i just want points
Step-by-step explanation:
>;)
The cumulative frequency of the 3rd bin in a frequency distribution table represents: a. The number of data values that are less than the maximum value of the 3rd bin. b. The percentage of data that falls into the 3rd bin. C. The cumulative deviation of the 3rd bin in percent. d. The frequency of data values that are larger than the minimum value of the 3rd bin.
The cumulative frequency of the 3rd bin in a frequency distribution table represents the number of data values that are less than the maximum value of the 3rd bin. The correct option is a.
What is a frequency distribution table?A frequency distribution table, often known as a frequency table, is a table that displays the frequency or amount of occurrences of different values in a dataset. Frequencies may be written as total values or as percentages of the total (relative frequency).
What is cumulative frequency?Cumulative frequency is the total frequency of values less than or equal to a given value in a dataset. The cumulative frequency of the 3rd bin in a frequency distribution table represents the total number of data values that are less than or equal to the maximum value of the 3rd bin.
Because it is a cumulative frequency, it contains all the values that came before it as well as its own frequency. The frequency distribution table is used to compute cumulative frequency.
The calculation of cumulative frequency may be done using the data's ascending or descending order.
Thus, the correct option is a.
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4. Mark says to do the problem 12 % + 3 %, you just find 12 +3 =4 and % +3/4=1/3 to get 4- How do you respond?
Mark's approach to solving the problem is incorrect.
We have,
To find the sum of percentages, you cannot simply add the numbers together as you would with regular numbers.
Percentages represent proportions or ratios, so they must be converted to their corresponding decimal or fraction forms before adding them.
To solve 12% + 3%, you need to convert each percentage to its decimal form and then add the decimals together.
Here's the correct approach:
12% = 12/100 = 0.12
3% = 3/100 = 0.03
Now, add the decimals:
0.12 + 0.03 = 0.15
Therefore,
The value of 12% + 3% is 0.15 or 15%.
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Use the given values to complete the table. Create quantities proportional to each other and graph them.
10
9
у
8
7
6
5
4
2
4
(4,2)
3
2
1
0
0 1 2 3 4 5 6 7 8 9 10
The average American gets a haircut every 43 days. Is the average smaller for college students? The data below shows the results of a survey of 13 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 36, 42, 40, 45, 33, 31, 47, 47, 39, 41, 33, 48, 32 What can be concluded at the the α = 0.05 level of significance level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: H 0 : ? Select an answer H 1 : ? Select an answer The test statistic ? = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? α Based on this, we should Select an answer the null hypothesis. Thus, the f conclusion is that ... The data suggest the population mean number of days between haircuts for college students is not significantly lower than 43 at α = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 43. The data suggest the population mean is not significantly lower than 43 at α = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 43. The data suggest the populaton mean is significantly lower than 43 at α = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 43.
The data suggest that the population mean is not significantly different from 43 at α = 0.05.
To determine whether the average number of days between haircuts for college students is smaller than the average for the average American (43 days), we can conduct a one-sample t-test. Here are the steps and results:
Step 1: Formulate the null and alternative hypotheses:
Null hypothesis (H0): The population mean number of days between haircuts for college students is equal to 43.
Alternative hypothesis (H1): The population mean number of days between haircuts for college students is smaller than 43.
Step 2: Calculate the test statistic:
We can calculate the test statistic using the formula:
t = (x- μ) / (s / √n)
where x is the sample mean, μ is the hypothesised population mean (43), s is the sample standard deviation, and n is the sample size.
Using the given data, the sample mean x is calculated to be 39.923, the sample standard deviation s is 6.106, and the sample size n is 13.
Substituting these values into the formula, we get:
t = (39.923 - 43) / (6.106 / √13) = -0.808
Step 3: Calculate the p-value:
The p-value represents the probability of obtaining a test statistic as extreme as the observed value (or more extreme) if the null hypothesis is true. We can use the t-distribution to calculate the p-value.
Using a t-table or a statistical software, we find that the p-value for t = -0.808 with 12 degrees of freedom is approximately 0.438.
Step 4: Make a decision:
Comparing the p-value (0.438) to the significance level α (0.05), we find that the p-value is greater than α.
Therefore, we fail to reject the null hypothesis.
Based on the results, we conclude that there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is lower than 43. The data suggest that the population mean is not significantly different from 43 at α = 0.05.
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A group of adult males has foot lengths with a mean of 28.48 cm and a standard deviation of 1.41 cm. Use the range rule of thumb for identifying significant values to identify the limits separating values that are significantly low or significantly high. Is the adult male foot length of 31.6 cm significantly low or significantly high? Explain. Significantly low values are cm or lower. (Type an integer or a decimal. Do not round.)
Thus, the adult male foot length of 31.6 cm is significantly high since it falls outside the range of values considered normal for adult male foot length.
Range rule of thumb:The range rule of thumb is a formula used to calculate the range of the data that's spread around the mean. The range is the difference between the maximum and minimum data values. The range rule of thumb estimates the expected range for a normally distributed dataset by taking the difference between the maximum and minimum values, then multiplying that difference by 4. This estimate is usually only useful for datasets with more than 15 data points. Thus, using the range rule of thumb, the range of a normally distributed data set is approximately four times the standard deviation. Thus, the range of the adult male foot length is as follows:Range = 4 × Standard deviation= 4 × 1.41 cm= 5.64 cmWe can then identify the limits separating values that are significantly low or high as follows:Significantly low values are cm or lower: 28.48 - 2 x 1.41 = 25.66 cmSignificantly high values are cm or higher: 28.48 + 2 x 1.41 = 31.3 cmThus, the adult male foot length of 31.6 cm is significantly high since it falls outside the range of values considered normal for adult male foot length.
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Need help please thank you
Answer:
y = 4x+1
Step-by-step explanation:
I really need help please!!!!!
Step-by-step explanation:
area of a quadrilateral is b x h
if the base is 7 the height is x and the area is 63 then:
7x=63
divide both sides by 7
7/7x=63/7
x=9
Hope that helps :)
Please Answer!! Will give brainly!!
Answer:
480 - 12.25d = 50
Someone please help me I’ll give out brainliest please dont answer if you don’t know
Answer:
-5p+3
Step-by-step explanation:
-p-2-4p+5
-p-4p-2+5
-5p+3
question number 7 and 8 only.
What is |6 3/8 - 2| + |-8 5/8 + (-1)|?
Answer:
14
Step-by-step explanation:
help wrong answers reported
Answer:
65
Step-by-step explanation:
all triangles angles equal 180°
180-72-43=65
Suppose x’s represent solutions and y’s represent problems. S(x, y) means "x is a solution for problem y". Explain, in English, what each of these statements is saying. They do not mean the same thing.
1. ∃x∀yS(x, y)
2. ∀y∃xS(x, y)
The first statement focuses on the existence of a single solution that works for all problems, while the second statement emphasizes that for each problem, there is at least one solution available, without specifying whether it is the same solution for all problems.
1) ∃x∀yS(x, y):
This statement means "There exists at least one solution that works for all problems." In other words, there is a specific value of x that can be applied to every problem y, resulting in a solution.
2) ∀y∃xS(x, y):
This statement means "For every problem, there exists at least one solution." In other words, for any given problem y, there is at least one value of x that can be applied to it to find a solution.
The main distinction between these two statements lies in the order of quantifiers (∃ and ∀). In the first statement, the existential quantifier (∃x) appears before the universal quantifier (∀y), indicating that there is a single solution that can be applied to all problems.
In the second statement, the universal quantifier (∀y) appears before the existential quantifier (∃x), indicating that for each problem, there is at least one solution that exists.
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Please answer this I will give brainliest!!!
Perpendicular means that two lines intersect at a right angle.
D and E have perpendicular sides
(blue rectangle at the bottom left and green trapezoid all the way at the bottom right)
Which statement is true about a trend line? A regression line and a trend line are opposite terms. A regression line and trend line are equivalent terms. A trend line represents only the smallest data points. A trend line represents only the largest data points.
Answer:
A is incorrect! B. should be the correct answer
Step-by-step explanation
After some research, i found that the correct answer is most likely B. a regression line and trend line are equivalent terms
A trendline and a regression can be the same.
A regression line is based upon the best fitting curve Y= a + bX Most often it’s a least-squares fit (where the squared distances from the points to the line (along the Y-axis) is minimized).
It can be quadratic or logistic or otherwise, but most often it is linear.
A trendline is often constructed by smoothing of the results, making it less peaked. (often by using a moving average); but can also come from ARIMA projections or curve fitting techniques (such as regression).
Let me know if i helped you!
The statement that is true about a trend line is B. A regression line and trend line are equivalent terms.
It should be noted that the trend line doesn't represent only the largest data points. It can also represent the smallest data points.
The regression line and the trend line are not opposite terms but rather, the regression line and trend line are equivalent terms.
In conclusion, the correct option is B.
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For the following estimated multiple linear regression equation,
Y = 8 + 45X_1 + 16X_2
a. what is the interpretation of the estimated coefficient of X_2
b. if R^2? (Goodness of Fit Coefficient) is 0.98 in this estimated regression equation, what does that tell you?
(a) The estimated coefficient of X₂ captures the average impact of X₂ on the response variable Y, given the specified regression model. (b) a higher R² value indicates a better fit of the model to the data and a higher degree of explained variability.
(a.) The estimated coefficient of X₂ in the multiple linear regression equation (Y = 8 + 45X₁ + 16X₂) represents the expected change in the dependent variable (Y) for a one-unit increase in the independent variable X₂, while holding all other independent variables constant.
In this case, the estimated coefficient of X₂ is 16, so for every one-unit increase in X₂, the expected change in Y is an increase of 16 units, assuming X₁ and other variables remain constant.
(b.) The coefficient of determination (R²) is a measure of the proportion of the total variation in the dependent variable (Y) that can be explained by the independent variables (X₁ and X₂) in the regression model. In this case, if the R² value is 0.98, it means that approximately 98% of the total variation in Y can be explained by the linear relationship between X₁, X₂, and the constant term.
A high R² value of 0.98 indicates a very strong fit of the regression model to the data. It suggests that 98% of the variability in the dependent variable Y is accounted for by the independent variables X₁ and X₂, while the remaining 2% may be attributed to other factors or random variation.
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Please help with 1 & 2!!! Will mean a lot!! And give brainly!!! Help plz due today
1. to find angle x:
angles on a straight line add to 180º : 180-92º = 88º
to find angle y:
exterior angle equals opposite interior angles: 88+22=110º
2. to find angle x:
angles on a straight line add to 180º : 180-118 = 62º
to find angle y:
exterior angle equals opposite interior angles: 62+52 = 114º
sorry if i got any of the angles wrong, the picture was a bit blurry and I couldn't tell that well, let me know if i got it wrong and i'll fix it
Heather bought a ten-year maturity corporate bond when it was issued for $1,000. The bond has an
annual interest rate of seven percent and pays interest semi-annually. How much does she receive
every six months?
A. $90
B. $40
C. $30
D. $35
Heather receives $35 every six months from the corporate bond.
The correct answer to the given question is option D.
To calculate how much Heather receives every six months from the corporate bond, we need to determine the semi-annual interest payment.
The annual interest rate is given as seven percent. Since interest is paid semi-annually, we divide the annual interest rate by 2 to get the semi-annual interest rate:
Semi-annual interest rate = 7% / 2 = 3.5%
Next, we calculate the semi-annual interest payment by multiplying the face value of the bond ($1,000) by the semi-annual interest rate:
Semi-annual interest payment = $1,000 * 3.5% = $1,000 * 0.035 = $35
Therefore, Heather receives $35 every six months from the corporate bond.
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Choose the item that does NOT have a measurable volume.
a dollar bill
air
a box of crackers
a water bottle
Answer:
Air
Step-by-step explanation:
You can't really measure air
Answer:
Air
Step-by-step explanation:
You cannot measure air because it is invisible.
If the coefficient of determination is 0.237, what percentage of the data about the regression line is explained?
Group of answer choices
o 76.3%
o 5.63%
o 23.7%
o 46.7%
The correct option is (C) 23.7%.
If the coefficient of determination is 0.237, the percentage of the data about the regression line that is explained is 23.7%.
The coefficient of determination is used to explain how much variability in a dependent variable is due to the independent variable in a regression analysis.
It is usually represented as R², which is a fraction between 0 and 1, or expressed as a percentage between 0% and 100%.
It measures the proportion of variability in the dependent variable that can be attributed to the independent variable(s).
In this problem, the coefficient of determination is given as 0.237, which means that 23.7% of the variability in the dependent variable is explained by the independent variable(s) in the regression line. Therefore, the correct option is (C) 23.7%.
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A manufacture has been selling 1350 television sets a week at $480 each. A market survey indicates that for each $15 rebate offered to a buyer, the number of sets sold will increase by 150 per week. a) Find the demand function p(x), where x is the number of the television sets sold per week. p(x) = b) How large rebate should the company offer to a buyer, in order to maximize its revenue? $ c) If the weekly cost function is 108000 + 160x, how should it set the size of the rebate to maximize its profit?
Given that a manufacture has been selling 1350 television sets a week at $480 each. A market survey indicates that for each $15 rebate offered to a buyer, the number of sets sold will increase by 150 per week.
a) The demand function is p(x) = 480 - 15x/150, Where x is the number of television sets sold per week.
b) The company should offer a rebate of $25 to maximize its revenue.
c) The company should offer a rebate of $23 to maximize its profit.
a) Demand function:
p(x) = 480 - 15x/150, Where x is the number of television sets sold per week.
b) To maximize revenue, we need to find the point where the marginal revenue equals zero.
Marginal revenue is the derivative of the revenue function.
Revenue function is given by R(x) = x p(x), where x is the number of television sets sold and p(x) is the price per set.
R(x) = x p(x)
R(n) = (1350 + 150n)(480 - 15n/150)
R(n) = 648000 - 2250n - 45n²
R’(n) = -2250 - 90n
For marginal revenue, we need
R’(n) = 0
2250 - 90n = 0
n = -2250/90
n = -25
So, the company should offer a rebate of $25 to maximize its revenue.
c) Cost function: C(x) = 108000 + 160x
Total revenue (TR) = x p(x)
= (1350 + 150n)(480 - 15n/150)
= 648000 - 2250n - 45n²
Total cost (TC) = C(x)
= 108000 + 160n
Profit (P) = TR - TCP
P = 648000 - 2250n - 45n² - (108000 + 160n)
P = 540000 - 2090n - 45n²
For maximum profit, we need
P’(n) = 0 -2090 - 90n
P'(n) = 0
2090 - 90n = 0
n = -2090/90
n = -23.2
Since n has to be a whole number, the number of TVs sold will be
1350 + 150n = 1350 + 150(-23)
= 1020.
Therefore, the company should offer a rebate of $23 to maximize its profit.
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What is the value of x in the equation 4(2x + 10) = 0?
-5
-7
5
7
Answer:
Step-by-step explanation:
4(2x+10)=0
8x+40=0
-40 -40
8x=-40
x=-5
Answer:
-5
Step-by-step explanation:
First you have to distribute 4 to 2x and 10, giving us 8x + 40 = 0. Then subtract 40 from both sides, giving us 8x = -40. Now divide -40 by 8, which gives us -5.