college professor never finishes his lecture before the end of the hour and always finishes his lectures within 2 min after the hour. Let X = the time that elapses between the end of the hour and the end of the lecture and suppose the pdf of X is as follows.
f(x) = kx^2 0 ? x ? 2
(a) Find the value of k. (Enter your answer to three decimal places.)
(b) What is the probability that the lecture ends within 1 min of the end of the hour? (Enter your answer to three decimal places.)
(c) What is the probability that the lecture continues beyond the hour for between 15 and 45 sec? (Round your answer to four decimal places.)
(d) What is the probability that the lecture continues for at least 75 sec beyond the end of the hour? (Round your answer to four decimal places.)

the electric field at a distance (r) from the center of the cylinder is approximately 0.0203 N/C, with a radial direction.

To solve this problem, let's analyze the given information step by step:

Radius of the cylinder: r = 2.00 cm = 0.02 m

Volume charge density: ρ = 18.0 μC/m²3

Now, let's find the electric field (E) at a distance (r) from the center of the cylinder using Gauss's law for a cylindrical symmetry.

Gauss's law states that the electric flux (Φ) through a closed surface is equal to the enclosed charge divided by the permittivity of free space (ε₀).

For an infinitely long cylinder, the electric field outside the cylinder will have a radial direction and a magnitude given by:

E = (ρ × r) / (2 × ε₀)

where ε₀ is the permittivity of free space, approximately equal to 8.854 × 10²-12 C²2/(N·m²2).

Substituting the given values, we can calculate the electric field:

E = (18.0 μC/m²3 × 0.02 m) / (2 × 8.854 × 10²-12 C²2/(N·m²2))

E ≈ 0.0203 N/C

Therefore, the electric field at a distance (r) from the center of the cylinder is approximately 0.0203 N/C, with a radial direction.

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Answer:

13.8cm

Step-by-step explanation:

angle A = 180 - angle B - angle C = 180 - 90 - 74 = 16°

AC/sin 90 = 3.8/sin 16

AC = (3.8 sin 90) / sin 16

= 13.786 cm

= 13.8cm (à un dixième)

The average number of trees planted by students at Arlington High School decreased by 20% when comparing the first planting session (5 trees per participant) to the upcoming session (4 trees per participant).

To calculate the percent of decrease, we can use the following formula:

Percent decrease = ((Initial value - Final value) / Initial value) * 100

For the first planting session, the initial value is 5 trees per participant, and for the upcoming session, the final value is 4 trees per participant. Plugging these values into the formula:

Percent decrease = ((5 - 4) / 5) * 100 = (1 / 5) * 100 = 20%

Therefore, the percent of decrease in the average number of trees planted is 20%. This means that the average number of trees planted per participant decreased by 20% from the first planting session to the upcoming session

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The statement that the ordered pair (-1, -1) is not a solution for the equation y = -2x - 3 is fasle.

Given a linear equation,

y = -2x - 3

We have to check whether the ordered pair (-1, -1) is a solution or not.

Substituting the point,

-1 = (-2)(-1) - 3

-1 = 2 - 3

-1 = -1

The equation holds for the given point, so (-1, -1) is a solution.

Hence the statement is false.

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The equation of the tangent line to the curve y = 6x sin(x) at the point (2, 3) is y = (12cos(2) + 6sin(2))(x - 2) + 12sin(2)

To find the equation of the tangent line to the curve y = 6x sin(x) at the point (2, 3), we need to find the slope of the tangent line and the coordinates of the point of tangency.

Let's start by finding the slope of the tangent line. The slope of the tangent line at a given point on a curve can be found using the derivative of the function.

This can be done by taking the derivative of y = 6x sin(x)  

To find the derivative, we can use the product rule and the chain rule. The derivative of 6x is 6, and the derivative of sin(x) is cos(x).

Applying the product rule, we get:

dy/dx = 6x × cos(x) + 6 × sin(x)

Now we can evaluate the derivative at x = 2 to find the slope of the tangent line at the point (2, 3):

dy/dx = 6(2) × cos(2) + 6 × sin(2)

= 12cos(2) + 6sin(2)

Next, we need to find the y-coordinate of the point of tangency,

which is y = 6(2) sin(2):

=> y = 12sin(2)

So the point of tangency is (2, 12sin(2)).

Now we have the slope of the tangent line (dy/dx) and a point on the line (2, 12sin(2)). We can use the point-slope form of a line to find the equation of the tangent line:

=> y - y₁ = m(x - x₁)

Plugging in the values, we have:

y - 12sin(2) = (12cos(2) + 6sin(2))(x - 2)

Expanding and rearranging the equation, we can find the final form of the equation of the tangent line:

y = (12cos(2) + 6sin(2))(x - 2) + 12sin(2)

Therefore,

The equation of the tangent line to the curve y = 6x sin(x) at the point (2, 3) is y = (12cos(2) + 6sin(2))(x - 2) + 12sin(2)

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The sum of the first 8 terms of the sequence is 640. The values for 1, n, and d are 10, 8, and 20, respectively.

The given sequence is an arithmetic sequence with a common difference of 20. Using the formula for the sum of n terms of an arithmetic sequence, we can find the value of n.

Let S_n be the sum of the first n terms of the sequence. Then,

S_n = n/2(2a + (n-1)d)

where a is the first term, d is the common difference.

From the given sequence, we know that a = 10 and d = 20. We need to find the value of n such that S_n = 2657200.

2657200 = n/2(2(10) + (n-1)(20))
2657200 = n/2(20n - 10)
5314400 = n(20n - 10)
1062880 = n(10n - 5)
1062880 = 5n(2n - 1)

By trial and error, we can find that n = 8 is a solution.

Thus, the finite sum equation is:

S_8 = 8/2(2(10) + (8-1)(20))
S_8 = 4(20 + 7*20)
S_8 = 4(160)
S_8 = 640

Therefore, the sum of the first 8 terms of the sequence is 640. The values for 1, n, and d are 10, 8, and 20, respectively.

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The portion of the unit circle given by the parametric equation r(s) = , where 0 ≤ s ≤ 3π/2, is a curve that starts at the point (1, 0) and moves counterclockwise until it reaches the point (-1, 0), passing through the points (0, 1) and (0, -1) along the way. Alternatively, we can write the equation of the curve as , which reflects the standard parametrization across theline y = x.

The given problem involves the portion of the unit circle represented by the parametric equation r(s) = 0, where 0  s  3/2. This means that we need to determine the curve traced by the point (x, y) as s varies over this range.

To do this, we can start by considering the unit circle with the center at the origin and a radius of 1. This circle is defined by the equation x2 + y2 = 1. The parameterization r(s) =  can be thought of as giving us the x and y coordinates of a point on the unit circle, based on the value of the parameter s.

Now, if we look at the given range of s, we see that it starts at 0 and goes up to 3/2. This means that we are looking at the portion of the unit circle that lies in the first and second quadrants and part of the third quadrant. Specifically, we start at the point (1, 0) and move in a counterclockwise direction until we reach the point (-1, 0), having passed through the points (0, 1) and (0, -1) along the way.

To get a better sense of this curve, we can plot some points. For example, when s = 0, we have r(0) = 1, 0>, which is the starting point of the curve. When s = /2, we have r(/2) = 0, 1>, which is the point on the circle where y = 1. Continuing in this way, we can plot more points and see how they connect to form the curve.

Alternatively, we can use some trigonometric identities to simplify the equation of the curve. Recall that cos(/2 - ) = sin() and sin(/2 - ) = cos(). Using these identities, we can write r(s) as:

r(s) =
    =
This tells us that the curve traced by r(s) is the same as the curve traced by the parametric equation. We can think of this as a reflection of the standard parametrization along the line y = x.

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the Laplace transform of f(t) = cosh(bt) is  [tex]s / (s^2 - b^2)[/tex], expressed in terms of b and s, under the assumption that s > |b|

To find the Laplace transform of the function f(t) = cosh(bt), we can use the property of the Laplace transform that states the transform of cosh(at) is [tex]s / (s^2 - a^2)[/tex].

Applying this property to our function, we have:

L{cosh(bt)} = [tex]s / (s^2 - b^2)[/tex]

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The monthly payment that Micaylah gives will be $189.1.

Given that:

Principal, P = $8,500

Rate, r = 0.0325 / 12 = 0.0027

Time, n = 4 x 12 = 48

The formula of monthly payment (MP) will be

[tex]\rm MP = P \times \dfrac{r(1+r)^n}{(1+r)^n - 1}\\[/tex]

Substitute the values in the above equation, then the monthly payment is calculated as,

MP = $8,500 x 0.0027 x (1 + 0.0027)⁴⁸ / [(1 + 0.0027)⁴⁸ - 1]

MP = $8500 x 0.0027 x (1.1382) / (1.1382 - 1)

MP = $8500 x 0.0027 x (1.1382) / (0.1382)

MP = $8,500 x 0.0027 x 8.2135

MP = $189.1

Thus, the monthly payment that Micaylah gives will be $189.1.

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The x-value at which the function is not continuous is [tex]x = 0.[/tex]

A continuous graph is a graph with no breaks, jumps, or holes in its plot; it represents a function or relation where there are no abrupt changes or interruptions in the values of the graph as the independent variable (typically denoted as x) changes.

Formally, a function is considered continuous if it satisfies the following criteria: The function is defined at every point in its domain. The function has no jumps, holes, or vertical asymmetries.

The formula is [tex]h(x) = 1/x^2 - 2x - 35.[/tex] We can examine the function's graph to see whether there are any x-values where the function is not continuous.

The graph of the function has a vertical asymptote at [tex]x = 0.[/tex] and is a rational function. As x gets closer to 0 from the left or right, respectively, the function will start to approach infinity or negative infinity.

The function is not defined at [tex]x = 0.[/tex] because it has a vertical asymptote; as a result, the function is not continuous at  [tex]x = 0.[/tex] Therefore, the x-value at which the function is not continuous is [tex]x = 0.[/tex]

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a) The transition matrix for the Markov chain representing the end of a volleyball game can be constructed based on the given states. The matrix will have dimensions 6x6, with each element representing the probability of transitioning from one state to another. The transition probabilities depend on the probabilities of winning rallies for each team. The resulting transition matrix is as follows:

[ 0 0 0 0 1 0 ] [ 0 0 0 0 0 1 ] [ p 0 0 0 0 1-p ] [ 0 q 0 0 1-q 0 ] [ 0 0 0 0 1 0 ] [ 0 0 0 0 0 1 ]

In this matrix, each row represents a current state, and each column represents a possible next state. The element in the i-th row and j-th column represents the probability of transitioning from state i to state j.

b) To find the probability that the game will not be finished after three rallies when team B is serving and both teams are tied 15-15, we need to calculate the probability of being in the states "tied - B serving" after three rallies. Using the given transition matrix and probabilities p = q = 0.65, we can perform matrix multiplication to obtain the state probabilities after three transitions.

Starting with an initial state vector [0 0 0 1 0 0], representing being in the state "tied - B serving," we multiply it by the transition matrix three times to find the state probabilities after three rallies. The probability of the game not being finished is the sum of the probabilities in the states "tied - B serving," "A ahead by 1 point - A serving," and "B ahead by 1 point - B serving."

Performing the calculations, the probability that the game will not be finished after three rallies is approximately 0.1721 or 17.21%.

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The transition matrix for the Markov chain representing the end of a volleyball game, considering rally point scoring, can be derived based on the six states described: 1) tied - A serving, 2) tied - B serving, 3) A ahead by 1 point - A serving, 4) B ahead by 1 point - B serving, 5) A wins the game, and 6) B wins the game.

.

(a) To construct the transition matrix for the Markov chain, we consider the possible transitions between the six states. The matrix will have dimensions 6x6, with each element representing the probability of transitioning from one state to another. For example, the probability of transitioning from state 1 (tied - A serving) to state 2 (tied - B serving) can be calculated based on the probabilities p and q mentioned in the problem statement. By considering all possible transitions, the complete transition matrix can be obtained.

(b) In this scenario, we start with state 2 (tied - B serving) and need to find the probability that the game will not be finished after three rallies. To calculate this probability, we can use the transition matrix obtained in part (a) and perform matrix multiplication. By multiplying the initial state vector (corresponding to state 2) with the transition matrix three times, we can find the probabilities of ending up in each state after three rallies. The probability of the game not being finished after three rallies would be the sum of the probabilities in states 1 and 2, which represent tied scores.

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Answer:

[tex]x= 7 + 2\sqrt{15} \\x= 7 - 2\sqrt{15}[/tex]

Step-by-step explanation:

To solve the equation (x - 7)^(2) = 60, we can start by taking the square root of both sides:

[tex]\sqrt{(x-7)^2} = \sqrt{60}[/tex]

Simplifying, we get:

x - 7 = ± [tex]\sqrt{60}[/tex]

Now we can add 7 to both sides to isolate x:

x = 7 ±  [tex]\sqrt{60}[/tex]

To simplify further, we can factor 60 into its prime factors: 60 = 2^(2) * 3 * 5.

Then, we can simplify the square root of 60:

[tex]\sqrt{60} = \sqrt{2^2*3*5} = 2\sqrt{15}[/tex]

So the final solutions are:

[tex]x= 7 + 2\sqrt{15} \\x= 7 - 2\sqrt{15}[/tex]

The expression on the left with the values of the propositional variables that make the expression true. A. P ∧ ~Q - iv. P = false, Q = false, R = true (P is false and Q is false, so P ∧ ~Q is false).

B. ~(P ∧ Q) - i. P = false, Q = true, R = false (P is false and Q is true, so ~(P ∧ Q) is true)
C. P ∨ (Q ∧ ~R) - ii. P = true, Q = false, R = true (P is true, so P ∨ (Q ∧ ~R) is true regardless of the values of Q and R)
D. ~(~P ∨ ~Q) - iii. P = true, Q = true, R = false (P and Q are both true, so ~P ∨ ~Q is false, and therefore ~(~P ∨ ~Q) is true)
A. P ∧ ~Q is true when P = true, Q = false. So, it matches with ii. P = true, Q = false, R = true
B. ~(P ∧ Q) is true when P = false, Q = true. So, it matches with i. P = false, Q = true, R = false
C. P ∨ (Q ∧ ~R) is true when P = true, Q = true, R = false. So, it matches with iii. P = true, Q = true, R = false
D. ~(~P ∨ ~Q) is true when P = true, Q = true. So, it matches with iii. P = true, Q = true, R = false

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The statement "Total surplus could be increased if the government imposed a tax on this good" is false. The graph represents a market with a positive consumption externality, and the correct statement is "I and II only."

The statement "Total surplus could be increased if the government imposed a tax on this good" is false. In a market with an externality, such as a positive consumption externality, there is a divergence between private and social costs and benefits. In this case, the graph suggests that the market quantity is already at the efficient level of 7 units. Imposing a tax would increase the cost to consumers and reduce the quantity consumed, leading to a decrease in total surplus.

The graph represents a positive consumption externality because the social benefit exceeds the private benefit at any given quantity. This can be observed by comparing the marginal social benefit (MSB) curve, which reflects the total benefit to society, with the marginal private benefit (MPB) curve, which represents the benefit to individuals. The MSB curve lies above the MPB curve, indicating the presence of a positive consumption externality.

To address the positive consumption externality and increase total surplus, the government could consider implementing policies such as subsidies, education campaigns, or regulations that encourage consumption of the good. These measures aim to close the gap between private and social benefits and help reach the socially optimal level of consumption.

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The function can be represented as a power series with coefficients [tex]C_{n}[/tex] = [tex]{-10/3}^n[/tex]. And the radius of convergence (R) is 3.

To represent the function f(x) = 10x / (3 + x) as a power series, we can use the concept of partial fraction decomposition and expand each term separately.

First, let's perform the partial fraction decomposition:

10x / (3 + x) = A + B/(3 + x),

where A and B are constants to be determined.

To find the values of A and B, we can multiply both sides by (3 + x):

10x = A(3 + x) + B.

Expanding this equation:

10x = 3A + Ax + B.

Now, we can match the coefficients of the powers of x on both sides:

For the constant term:

0 = 3A + B.

For the x term:

10 = A.

Substituting A = 10 into the first equation, we get:

0 = 30 + B,

B = -30.

Therefore, the partial fraction decomposition of the function becomes:

10x / (3 + x) = 10 - 30 / (3 + x).

Now, we can express the function as a power series:

f(x) = 10 - 30 / (3 + x)

= 10 - 30(1/3) / (1 + x/3)

= 10 - 10 / (1 + (-x/3)).

Using the geometric series formula:

1 / (1 - r) = ∑ (n=0 to ∞) [tex]r^{n}[/tex], where |r| < 1,

we can rewrite the function as:

f(x) = 10 - 10 ∑ [tex]{(-x/3)}^n[/tex], where |x/3| < 1.

From this form, we can see that the function can be represented as a power series with coefficients Cn =[tex]{-10/3}^n[/tex]. The terms C0, C1, C2, C3, ... all have the same value of [tex]{-10/3}^n[/tex].

To determine the radius of convergence (R), we need to find the range of x values for which the series converges. In this case, since x/3 must be within the range (-1, 1) for convergence, we have:

-1 < x/3 < 1,

-3 < x < 3.

Therefore, the radius of convergence (R) is 3.

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Answer:

O The amplitude of f(x) is 1 unit larger than the amplitude of g(x).

Step-by-step explanation:

The amplitude of f(x) = 5 sin(3x) is |-5 - 5|/2 = 5.

The amplitude of function g(x) is |9 - 1|/2 = 4.

Answer: O The amplitude of f(x) is 1 unit larger than the amplitude of g(x).

The total column or row in a relative frequency table provides a summary of the data and facilitates interpretation, verification, and identification of patterns or irregularities in the distribution of categories.

The presence of a total column or a total row in a relative frequency table can be helpful in interpreting the values and understanding the data within the table. Here's how it can assist in interpretation:

Proportions: A relative frequency table displays the proportions or percentages of each category relative to the total number of observations. The total column or row provides the sum of these proportions, typically represented as 100% or 1. This allows you to verify that the proportions add up correctly and provides a reference point for comparison.

Data Accuracy: By comparing the total column or row to the known total number of observations, you can assess the accuracy of the data presented in the table. If the totals match, it suggests that the data has been properly recorded and calculated.

Missing Data: If there are any missing values or incomplete rows/columns in the table, the total column or row can help identify them. If the total doesn't match the expected value, it indicates that some data might be missing or erroneously recorded.

Distribution Patterns: Analyzing the relative frequencies across different categories can reveal distribution patterns. The total column or row allows you to compare the relative sizes of various categories and identify trends or significant differences more easily.

Identifying Outliers: If there is a significant outlier in the data, it may be reflected in the total column or row. If one category has an unexpectedly high or low relative frequency compared to others, it may warrant further investigation to understand the underlying cause.

In summary, the total column or row in a relative frequency table provides a summary of the data and facilitates interpretation, verification, and identification of patterns or irregularities in the distribution of categories.

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The a(x-b)^2 form of 4x^2-24x+40 is 4[(x-3)^2 + 1].

We are given that;

The equation 4x^2-24x+40.

Form=  a(x-b)^2.

Now,

4x^2-24x+40 can be written in the form of a(x-b)^2 as follows:

4x^2-24x+40 = 4(x^2-6x+10) = 4[(x-3)^2 + 1]

Therefore, by the given equation the answer will be 4[(x-3)^2 + 1].

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Answer: 1. Boys are more likely to wear a red shirt than girls

2. Eighth graders are less likely to prefer math than 7th graders

1. We need to calculate the percentage of boys wearing red shirts, which is 10/25, or 40%

Then, we can calculate the percentage of girls wearing red shirts and compare the results.

The percentage of girls wearing red shirts is 5/20 or 25%

Since 40%>20%, we can say that boys are more likely to wear red shirts, or a positive association

2. The same can be done for the second question between the 8th graders and preferring math.

Hope this help!

[tex]|x|=x[/tex] for [tex]x > 0[/tex]

[tex]|x|=-x[/tex] for [tex]x\leq0[/tex]

[tex]\sqrt7 < \sqrt9\\\sqrt7 < 3[/tex]

Therefore

[tex]4-\sqrt7 > 0\Rightarrow |4-\sqrt7|=4-\sqrt7[/tex]

The polynomial can be expressed as P(x) = 8(x + 4)(x - 3i)(x + 3i).

The zeros of the polynomial are given as -4, 3i, and -3i. Since complex zeros occur in conjugate pairs, we can express the polynomial as P(x) = k(x + 4)(x - 3i)(x + 3i), where k is a constant.

To find the value of the constant k, we can use the given information that the polynomial has a value of 624 when x = 2. Substituting x = 2 into the polynomial equation, we have 624 = k(2 + 4)(2 - 3i)(2 + 3i). Simplifying further, we obtain 624 = k(6)(13), which gives us k = 624 / (6 * 13) = 8.

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The main limitation of a cross-sectional study design is that researchers cannot infer the temporal sequence between exposure and disease when the exposure is a changeable characteristic.

Cross-sectional studies are observational studies that measure the prevalence of a disease or health outcome at a specific point in time and assess the association between the outcome and exposure to certain risk factors. However, because the data is collected at a single time point, it is impossible to determine the order of events between exposure and outcome. This is particularly problematic when the exposure is a changeable characteristic such as diet or lifestyle habits. In such cases, it is difficult to determine whether the exposure caused the outcome or whether the outcome led to changes in exposure. Despite this limitation, cross-sectional studies can still provide valuable information about the prevalence and distribution of diseases and risk factors in a population.

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The given position function is r(t) = 3 cos(t)i + 2 sin(t)j. To find the velocity, we need to differentiate the position function with respect to time. So, v(t) = dr/dt = -3 sin(t)i + 2 cos(t)j. The velocity is a vector quantity that gives the rate of change of position with respect to time.

To find the acceleration, we need to differentiate the velocity function with respect to time. So, a(t) = dv/dt = -3 cos(t)i - 2 sin(t)j = -3v(t)/|v(t)|. The acceleration is also a vector quantity that gives the rate of change of velocity with respect to time.
Finally, to find the speed of the particle, we need to calculate the magnitude of the velocity vector at any given time. The speed is a scalar quantity that gives the rate of change of distance with respect to time. So, |v(t)| = √(9sin^2(t) + 4cos^2(t)).
In summary, the velocity vector is v(t) = -3 sin(t)i + 2 cos(t)j, the acceleration vector is a(t) = -3v(t)/|v(t)| = -3cos(t)i - 2sin(t)j, and the speed is |v(t)| = √(9sin^2(t) + 4cos^2(t)).

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To find the probabilities P(X < 2) and P(X ≥ 2), we can use the binomial probability formula. In this case, we have 9 independent trials with a probability of success of 2/5.

The probability mass function (PMF) for a binomial distribution is given by:

P(X = k) = C(n, k) * p^k * (1-p)^(n-k)

where n is the number of trials, k is the number of successes, p is the probability of success, and C(n, k) represents the combination of n choose k.

Let's calculate the probabilities:

P(X < 2)

This probability represents the sum of probabilities when X takes on the values 0 and 1.

P(X < 2) = P(X = 0) + P(X = 1)

P(X = 0) = C(9, 0) * (2/5)^0 * (3/5)^(9-0)

P(X = 1) = C(9, 1) * (2/5)^1 * (3/5)^(9-1)

Calculating these values:

P(X = 0) = 1 * 1 * (3/5)^9

P(X = 1) = 9 * (2/5) * (3/5)^8

Then, we can sum the two probabilities:

P(X < 2) = P(X = 0) + P(X = 1)

P(X ≥ 2)

This probability represents the complement of P(X < 2), which is 1 - P(X < 2).

P(X ≥ 2) = 1 - P(X < 2)

Now, we can calculate these probabilities using the formulas above and round the answers to the nearest ten-thousandth.

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The answer is False.

What is Probability ?

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one. Probability was introduced in mathematics to predict how likely events are to occur.

The meaning of probability is basically the extent to which something is likely to happen. This is a basic theory of probability that is also used in probability distributions, where you learn the possibilities of outcomes for a random experiment.

To find the probability of a single event occurring, we should first know the total number of possible outcomes.

We can use the central limit theorem to approximate the distribution of the sample mean as normal, with a mean of μ = 70 and a standard deviation of σ/√n = 10/√4 = 5. Therefore, we need to find the probability of obtaining a sample mean greater than 65:

Z = (x - μ) / (σ/√n) = (65 - 70) / (5/2) = -2

Using a standard normal distribution table or calculator, we can find that the probability of obtaining a Z-score of -2 or less is approximately 0.0228.

Therefore, the probability of obtaining a sample mean greater than 65 is 1 - 0.0228 = 0.9772, which is not equal to 0.8413. So the statement is false.

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The function s(x) = -x² + 2x² - x is neither even nor odd

From the question, we have the following parameters that can be used in our computation:

s(x) = -x² + 2x² - x

A function is said to be even if

f(x) = f(-x)

Using the above as a guide, we have the following:

s(-x) = -(-x)² + 2(-x)² + x

s(-x) = -x² + 2x² + x

A function is said to be odd if

-f(x) = f(-x)

So, we have

-s(x) = x² - 2x² + x

By comparing the functions:

s(x), -s(x)  and s(-x) are not equal

Hence, the function is neither even nor odd

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The coordinates of R' after the transformations are given as follows:

D. (10, 12).

Examples of transformations are given as follows:

The coordinates of R are given as follows:

R(2,4).

The dilation by a scale factor of 3 means that each coordinate is multiplied by 3, hence:

R'(6, 12).

The translation means that 4 is added to the x-coordinate, hence:

R''(10, 12).

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Answer:

1. The mean temperature for this sample can be found by adding up the temperatures and dividing by the sample size of 10:

98.6 + 98.5 + 98.8 + 98.2 + 98.1 + 99.0 + 98.3 + 98.5 + 98.9 + 98.7 = 986.6

986.6 / 10 = 98.66

Therefore, the mean temperature for this sample is 98.66 degrees.

2. No, we would not expect to get the exact same value for the sample if we were to take a different random sample of size 10. This is because random sampling means that each sample will be slightly different from each other, and the sample mean will vary based on the particular individuals included in each sample. However, we would expect the sample means to be similar and clustered around the true population mean of 98.6 degrees. The variability of the sample means can be quantified using the standard error of the mean, which is a measure of the average distance that the sample means are from the true population mean. The standard error of the mean decreases as the sample size increases, meaning that larger samples are more likely to provide a more accurate estimate of the population mean.

Step-by-step explanation:

The equation that can be used to solve for c in the given right triangle is the sine function: c = (3 meters) / sin(50°).

In the given right triangle ABC, we are given that angle ACB is a right angle (90°) and angle CBA is 50°. We also know the length of side AC, which is 3 meters. The length of side CB is denoted by "a," and the length of the hypotenuse AB is denoted by "c." To solve for c, we can use the trigonometric function sine (sin). In a right triangle, the sine of an acute angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. In this case, we can use the sine of angle CBA (50°) to find the ratio between side CB (a) and the hypotenuse AB (c).

The equation c = (3 meters) / sin(50°) represents this relationship. By dividing the length of side AC (3 meters) by the sine of angle CBA (50°), we can find the length of the hypotenuse AB (c) in meters. Using the given equation, we can calculate the value of c by evaluating the sine of 50° (approximately 0.766) and dividing 3 meters by this value. The resulting value will give us the length of the hypotenuse AB, completing the solution for the right triangle.

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