Answer:
8 seconds = 72cm
3 seconds = 36cm
6 seconds = 96cm
Explanation:
lab assignment i just took.
Speed is the rate of distance over time. The speed of the cart is as follows:
[tex]72cms^{-1}[/tex] at 8 seconds.[tex]36cms^{-1}[/tex] at 3 seconds.[tex]96cms^{-1}[/tex] at 6 seconds.Let:
[tex]s \to[/tex] speed
[tex]d \to[/tex] distance
[tex]t \to[/tex] time
After 8 seconds
For low fan speed; the distance (d) at 8 seconds is:
[tex]d =576cm[/tex]
Speed (s) is calculated using:
[tex]s = \frac dt[/tex]
[tex]s = \frac{576cm}{8s}[/tex]
[tex]s = 72cms^{-1}[/tex]
Hence, the speed after 8 seconds is [tex]72cms^{-1}[/tex]
After 3 seconds
For medium fan speed; the distance (d) at 3 seconds is:
[tex]d = 108cm[/tex]
The speed (s) is :
[tex]s = \frac dt[/tex]
[tex]s = \frac{108cm}{3s}[/tex]
[tex]s = 36cms^{-1}[/tex]
Hence, the speed after 3 seconds is [tex]36cms^{-1}[/tex]
After 6 seconds
For high fan speed; the distance (d) at 6 seconds is:
[tex]d = 108cm[/tex]
The speed (s) is :
[tex]s = \frac dt[/tex]
[tex]s = \frac{576cm}{6s}[/tex]
[tex]s = 96cms^{-1}[/tex]
Hence, the speed at 6 seconds is [tex]96cms^{-1}[/tex]
Read more about speed at:
https://brainly.com/question/7359669
True or False: You walk across a carpet and accumulate a net negative charge on the soles of your shoes. When you touch your sister with your finger and give her a small zap, the charge that accumulated on your finger is due to charging by contact.
Answer:
True
Explanation:
Charging by conduction occurs when a charged conductor comes in contact with an uncharged conductor, leading to the sharing of charges between both conductors. Contact charging leads to a sharing and distribution of the same type of charges on the two conductors.
In this case, your entire body is charged by the sole of your feet coming in contact with the charged carpet on the floor, leading to a charge buildup all over your body.
A transmitter produces radio waves of wavelength 1500m. It takes the waves 0.025s to travel from transmitter to radio receiver.
What is the distance between the radio transmitter and the receiver?
A) 5 × 10³ m
B) 2 × 10⁵ m
C) 7.5 × 10⁶ m
D) 1.1 × 10¹⁰ m
Answer:
[tex]7.5 \times 10 {}^{6} [/tex]
Explanation:
Speed of electromagnetic waves=
[tex]3 \times 10 {}^{8} ms[/tex]
m/s
[tex] = 3 \times 10 {}^{8} ms \times 0.025[/tex]
[tex] = 3 \times 10 {}^{8} \times \frac{1}{40} [/tex]
[tex] = 7.5 \times 10 {}^{6} m[/tex]
w
Trial
х
1
75.0 72.2
2
75.1
72.3
3
75.1 72.1
4
74.9
72.2
Which set of data is most likely the result of a systematic error?
Y
75.0
80.1
69.5
72.7
Z
86.2
86.7
71.5
70.8
w
Х
Z
Answer:
75
Explanation:
w
X
y
z.86.2,86.7,70.8
how water is constructed and how the matter is built-up?
Answer:
How is water constructed ?A molecule of pure water is made of two hydrogen atoms bonded to an oxygen atomHow is matter built-up?The basic building blocks that make up matter are called atoms. (hope i could help :)Explanation:
I will give brainliest if right
Prokaryotes are structurally simple organisms that have existed for over two billion years.
Which of the following are prokaryotes?
Choose 1 answer:
(Choice A) A Animals
(Choice B) B Bacteria
(Choice C) C Plants
(Choice D) D Fungi
I will give brainliest if right
Answer:
Prokaryotic Cells are cells that lack Cell Nucleus so the answer is bacteria
Answer:
B Bacteria
Explanation:
Choice B because the prokaryotes are single-celled organism with no nucleus.
What type of microscope bends light and uses multiple lenses to magnify a cell?
Choose 1 answer:
(Choice A) A Transmission electron microscope
(Choice B) B Simple light microscope
(Choice C) C Compound light microscope
(Choice D) D Scanning electron microscope
If 2 different processes driven by heat transfer start at state 1 and end at state 2 BUT follow different paths, is the amount of energy transferred by heat the same for each path? Yes or no?
A speed skater moving to the left across frictionless ice at 8.0 m/s hits a 5.0-m-wide patch of rough ice. She slows steadily, then continues on at 6.0 m/s. What is her acceleration on the rough ice?
Answer:
Acceleration, [tex]a=-2.8\ m/s^2[/tex]
Explanation:
It is given that,
The initial speed of a speed skater, u = 8 m/s
The final speed of a speed skater, v = 6 m/s
Width of patch of rough ice, s = 5 m
We need to find the acceleration on the rough ice. Acceleration can be calculated using third equation of motion as :
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(6)^2-(8)^2}{2\times 5}\\\\a=-2.8\ m/s^2[/tex]
So, the acceleration on the rough ice is [tex]2.8\ m/s^2[/tex]. Negative sign shows that its speed is decreased.
A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. What is its acceleration?
Answer:
80/2= 40 m/s^2.
Explanation:
A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. Its acceleration is 4 m/sec².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
acceleration = change in velocity / time
acceleration = 80 / 20
acceleration = 4 m/sec²
A jet starts at rest at the end of a runway and reaches a speed of 80 m/s in 20 s. Its acceleration is 4 m/sec².
To learn more about acceleration refer to the link:
brainly.com/question/12550364
#SPJ2
A car starting from rest accelerates at a rate of 8 0 m/s/s. What is its final speed at the end of 40 seconda?
i have no idea what is if you know the answer, can you please answer it?
Answer:
you have to organize the data. a= acceleration vi=inicial velocity vf=final velocity t=time.
a=80m/s
vi=0
vf=?
t=40 s
the formula you have to use is:
vf=vi+a*t (final velocity= inicial velocity plus acceleration times time)
Explanation:
I was the best one at my class, hope it helped
Answer: 320 m/s
Explanation: V initial = 0, V final= ? Acceleration = 8m/s/s t=40s
So at the end of V 40 sec= v intial + acceleration x Δt = 0 +8m/s² x 40s = 320m/s3. Daniel stands on a bridge over a river. He drops a coin and notes that the coin takes 3 s to reach the river below.
He must be standing
above the river.
A 10 m
B. 15 m
C. 30 m
D. 45 m
Answer:
45 m
Explanation:
Initial velocity of the coin = 0 m/s (since he dropped it from his hands)
time spent in falling - 3 sec
distance s = ?
using
s = ut + [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]
where
s is the distance the stone fell
u is the initial velocity
t is the time spent falling
g is acceleration due to gravity = 10 m/s^2 (positive downwards)
substituting values, we have
s = (0 x 3) + [tex]\frac{1}{2}[/tex](10 x [tex]3^{2}[/tex])
s = 45 m
Car A of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction. After collision, the velocity of car A becomes 20 m/s. Calculate the velocity of car B after collision.
Answer:
Apparently this has been asked a few years ago, so I copied this answer from deepikakvvk06 - - all credit goes to them!
velocity of car 'B' after collision is 22.5m/s. //it's a conservation of momentum question
Explanation:
Let ,
mass = m
initial velocity = u
final velocity = v
here ,
m₁= 1500 kg
m₂=1000 kg
u₁ = 25 m/s
u₂ = 15 m/s
v₁ = 20 m/s
we have to find v₂ !!
v₂ is the velocity after collision
Here is a formula relating the values given ,
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15
= 37500 + 15000
= 52500
m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂
= 30000 + 1000v₂
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
52500 = 3000 + 1000v₂
1000v₂ = 52500 - 30000
1000 v₂ = 22500
v₂ = 22500/1000
= 22.5 m/s
Thus, velocity of car 'B' after collision is 22.5m/s.
What year was volleyball invented?
10 p
1889
1874
1895
1918
How many players are on each volleyball team?
Please help
The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to slow to a final velocity of 2.0 m/s?
Answer:
t = 2.35sExplanation:
Using one of the equation of motion expressed as v = u+at where;
v is the final velocity = 2.0m/s
u is the initial velocity = 25m/s
a is the acceleration = -a (since the acceleration is negative)
t is the time taken
Substituting the given parameters into the formula above;
2.0 = 25-9.81t
subtract 25 from both sides
2.0 - 25 = 25-9.81t - 25
-23 = -9.81t
Divide both sides by -9.81
-23/-9.81 = -9.81t/-9.81
t = 23.0/9.81
t = 2.35s
Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s
For this car, predict the shape of a graph that shows distance (x) versus time (t). Note that time is the independent variable and will be on the bottom axis.
. Air moves up and down by convection. Molecules of air are spaced farther apart in rising warm air. What must the volume of cold air have more of than the same volume of warm air?
Answer:d
Explanation:tsssss
A plant is moved from direct sunlight and placed into complete darkness.
Which structure in the plant's cells would be most affected by this change?
Choose 1 answer:
(Choice A)
A
Mitochondria
(Choice B)
B
Chloroplast
(Choice C)
C
Vacuole
(Choice D)
D
Golgi body
a,
Explanation:
because when its moved thats the sugar of it
Answer:
b. Chloroplast
Explanation:
What happens to scientific laws if new, unexpected data is discovered? a They become scientific theories. b They are revised. c Nothing, the new data is ignored.
Answer:
revised
Explanation:
6)
Calculate the area of a body which experiences a pressure of 60000 Pa by a force of 120N
Answer:
area = force by pressure
or, a = 120N by 60000 Pa
or, a= 0.002 m²
. Explain how surface waves can have characteristics of both longitudinal waves and transverse waves.
Please use 3 content related sentences. (ref: p.388-393)
Answer:
This whole concept depends on the depends on the direction of propagation of the surface wave or displacement of wave such that if its in direction of wave velocity its said to features of longitudinal wave and if its in direction at 90° to wave velocity its said to have transverse features
Help me! I need to know this for my Veterinarian unit in class. Why do cats hate water?
Another reason why cats hate water is attributed to their history. There is not much in a cat's background to recommend them for successful interactions with bodies of water, be it small or big. Cat's ancestors lived in dry arid places which means rivers or oceans weren't obstacles they had to face.
Hope this helps:)
The displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t2, where t is the time in seconds. What is the instantaneous velocity of the block when t = 2.0 s?
Answer:
0.19m/sExplanation:
velocity is the change in displacement of a body with respect to time. Given the displacement d (m) of a block sliding along a straight line is given by the equation d = -0.65 t + 0.21 t², where t is the time in seconds, instantaneous velocity is expressed by differentiating the displacement with respect to time
Velocity = dd/dt
Velocity = -0.65 + 2(0.21)t²⁻¹
Velocity = -0.65 + 0.42t
The instantaneous velocity of the block when t = 2.0 s can be gotten by substituting t = 2.0s into the expression above:
Velocity = -0.65 + 0.42(2)
Velocity = -0.65 + 0.84
Velocity = 0.19
Hence the instantaneous velocity of the block when t = 2.0 s is 0.19m/s
If a dog moves 3 meters due East and then 4 meters due North, what will be the dispalcement of the dog?
Answer:
5 mExplanation:
Displacement is the diatnce moves in a specified direction. It is the shortest distance covered by the dog. The displacement of the dog can be gotten by using the pythagoras theorem as shown;
According to the theorem, a²+b² = d² where d is the displacement
Substituting the given value into the fofrmula;
3²+4² = d²
9+16 = d²
d² = 25
square root both sides
√d² = √25
d = √25
d = 5 metres
Hence the displacement of the dog is 5metres
A 1.35 kgkg block is attached to a spring with spring constant 15.0 N/mN/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 34.0 cm/scm/s . What are
Given :
Mass of block , m = 1.35 kg .
Speed constant , k = 15 N/m .
Speed at centre , v = 34 cm/s = 0.34 m/s .
To Find :
The amplitude of oscillation .
Solution :
Now , we know total energy is conserved in SHM .
So , K.E at zero displacement :
[tex]K.E=\dfrac{mv^2}{2}\\\\K.E=\dfrac{1.35\times 0.34^2}{2}\\\\K.E=7.8\times 10^{-2}\ J[/tex]
Now , this K.E is equal to maximum P.E :
[tex]P.E=K.E=7.8\times 10^{-2}\ J[/tex] .
[tex]P.E=\dfrac{kA^2}{2}\\\\7.8\times 10^{-2}=\dfrac{kA^2}{2}\\\\A=\sqrt{\dfrac{2\times 7.8 \times 10^{-2}}{15}}\ m\\\\A=0.1019 \ m\\\\A=10.2\ cm[/tex]
Therefore , the amplitude is 10.2 cm .
Hence , this is the required solution .
The _____ optical illusion contains a horizontal line terminating in inward- or outward-pointing arrowheads.
Answer:
Muller-Lyer optical illusion
(100 POINTS AND BRAINLEIST) could you please help me with this ASAP!
The above are questions related to the formula of force F = m * a i.e. mass * accleration. It is defined by the Newton's second law of motion.
In the attachment, I can see that Question 1) and Question 2) are already done, So lemme start from Question 3[tex])[/tex]
3) Provided:-
Force applied = 7000 NOn a ball of mass = 0.5 kgTo FinD:-
Acceleration of the ball...?By using formula,
⇛ F = ma
⇛ 7000 N = 0.5 kg × a
⇛ a = 7000 / 0.5 m/s²
⇛ a = 14000 m/s²
So, the ball acclerates at the rate of 14000 m/s².
4) Provided:-
Accleration of the truck = 10 m/s²On a truck of mass = 31200 kgTo FinD:-
Force applied on the truck..?By using formula,
⇛ F = ma
⇛ F = 31200 kg × 10 m/s²
⇛ F = 312000 kg/m/s²
⇛ F = 312000 N
So, force on the truck = 312000 N
5) a) Force applied = 100 N
Mass applied = 5 kg
Then, Acceleration = 100 ÷ 5 = 20 m/s²
b) Force applied = 100 N
Mass applied = 10 kg
Then, Acceleration = 100 ÷ 10 = 10 m/s²
c) Force applied = 100 N
Mass applied = 20 kg
Then, Acceleration = 100 ÷ 20 = 5 m/s²
d) Force applied = 100 N
Mass applied = 50 kg
Then, Acceleration = 100 ÷ 5 = 2 m/s²
And we are done !!
#CarryOnLearning
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Answer: The answer are above :(
what is the momentum in Kg m/s of a 10 kg truck travelling at A) 5 m/s B) 20 cm/s C) 36 km/h?
Answer:
A) 50 kg m/s
B) 2 kg m/s
C) 100 kg m/s
Explanation:
Recall that momentum is a physical quantity defined by the product of the object's mass times its velocity. Therefore, in our case the truck's momentum (p) is:
A) p = m * v = 10 kg * 5 m/s = 50 kg m/s
B) p = m * v = 10 kg * 0.20 m/s = 2 kg m/s (notice that the velocity in cm/s was converted into m/s before multiplying)
C) the conversion from km/h to m/s is a little more involved, so we taclke it first:
since 1 km = 1000 m and 1 hour = 3600 seconds, we convert 36 km/h by replacing each unit by its m and s expression as shown below:
[tex]36 \frac{km}{h} =36\,\frac{1000\,m}{3600\,\,s}=10\,\frac{m}{s}[/tex]
Then, the momentum is: p = m * v = 10 kg * 10 m/s = 100 kg m/s
Conduction occurs when thermal energy is transferred by the movement of
a. Waves
b. molecules
c. liquids
d. fluids
Answer: Molecules
Explanation:
Answer:
B. molecules
Explanation:
got 100% on the edge quiz
A boy wishes to make
a catapults out of
a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band
he must use so that when the stretches it by 0.25
of its natural length and releases it, the velocity of the pebble of mass 0.0006kg is
30ms - Take the youngs modulus of the rubber
to be 4x10000000nm-2
what is one common electrostatic phenomenon
Answer:
There are many examples of electrostatic phenomena, from those as simple as the attraction of the plastic wrap to one's hand after it is removed from a package to the apparently spontaneous explosion of grain silos, the damage of electronic components during manufacturing, and photocopier & laser printer operation