Consider two events such that P(A) = equals 3/5 , P(B) = 2/3 , and P(A ∩ B) = 1/5 . Are events A and B independent events?

Yes, they are independent because P(A) ⋅ P(B) = P(A ∩ B)
No, they are dependent because P(A) ⋅ P(B) ≠ P(A ∩ B)
Yes, they are independent because P(A) ⋅ P(B) ≠ P(A ∩ B)
No, they are dependent because P(A) ⋅ P(B) = P(A ∩ B)

The n-th trianglar number is given by

[tex]T_n = \dfrac{n(n+1)}2[/tex]

Then

[tex]T_4 + T_3 = \dfrac{4\times5}2 + \dfrac{3\times4}2 = \boxed{16}[/tex]

Alternatively, the triangular numbers are defined recursively by

[tex]\begin{cases}T_1 = 1 \\ T_n = T_{n-1} + n & \text{for } n>1\end{cases}[/tex]

This means

[tex]T_1=1[/tex]

[tex]T_2 = T_1 + 2 = 3[/tex]

[tex]T_3 = T_2 + 3 = 6[/tex]

[tex]T_4 = T_3 + 4 = 10[/tex]

so that

[tex]T_3+T_4=\boxed{16}[/tex]

Answer:

the answer is π^8

Step-by-step explanation:

the math program has got some bugs in it. See your teacher and tell him or her about it

Answer:

4x + 5x = 180

9x = 180

x = 180/9

x = 180 ÷ 9

x = 20

Answer:

ITS C

Step-by-step explanation:

trust

The quotient of two fractions, (2y² - 6y - 20)/(4y + 12) and (y² + 5y + 6)/(3y² + 18y + 27), is: 3(y - 5)/2

Quotient can be described as the result you get from dividing a term by another term.

Let's find the quotient of (2y² - 6y - 20)/(4y + 12) and (y² + 5y + 6)/(3y² + 18y + 27)

Quotient = (2y² - 6y - 20)/(4y + 12) ÷ (y² + 5y + 6)/(3y² + 18y + 27)

Change the division sign to multiplication sign and turn the second fraction upside down

(2y² - 6y - 20)/(4y + 12) × (3y² + 18y + 27)/(y² + 5y + 6)

Bringing out the common terms, we would have:

2(y² - 3y - 10)/4(y + 3) × 3(y² + 6y + 9)/(y² + 5y + 6)

Factorize

2(y - 5)(y + 2)/4(y + 3) × 3(y + 3)(y + 3)/(y + 3)(y + 2)

Cancel out common factors

= 3(y - 5)/2

Quotient = 3(y - 5)/2

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Answer:b

Step-by-step explanation:

lol

Given the distance covered and the time elapsed, if the bike is at a constant rate, the speed of Bob's bikes is 16 mph.

Option C) is the correct answer.

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

Speed = Distance ÷ time

Speed = 8miles / 0.5hrs

Speed = 16 mph

Therefore, Given the distance covered and the time elapsed, if the bike is at a constant rate, the speed of Bob's bikes is 16 mph.

Option C) is the correct answer.

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Answer:

12 ft

Step-by-step explanation:

for the model is 1 and the actual is 5

conversion yards to feet

3 feet = 1 yard

20 * 3 = 60

60/5 = 12

your answers 12 ft

hope this helps:)

Answer:

52

x 6

300 6 x 5 tens

+12 6 x 2 ones

312

Answer:

If you meant 4x to the third power, than x = 1.34

Answer:

The answer is 1

Step-by-step explanation:

Answer: coeficient is 20 and the constant which is 13

Step-by-step explanation:

Based on the calculations, the measure of angle YUV is equal to 42°.

A line segment refers to a part of a line that is bounded by two (2) distinct points and it has a fixed length.

Based on the information given, we can deduce the following:

From triangle UOV, we have:

∠OUV + ∠OUV + ∠UOV  = 180°

2OUV + 84 = 180

2OUV = 180 - 84

2OUV  = 96

OUV  = 96/2

OUV  = 48°

Now, we can determine the measure of angle YUV:

∠YUV = ∠YUO - ∠OUV

∠YUV = 90 - 48

∠YUV = 42°.

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Answer:

42

Step-by-step explanation:

Step-by-step explanation:

9x²/3x + 12x/3x + 1

= 3x/1 + 4/1 + 1

= 3x + 5

I hope this is true..

Answer:

radius = 72.00 in (nearest hundredth)

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substituting the given values into the formula and solving for r:

[tex]\implies \sf 1481276.16=3.14 \cdot r^2 \cdot 91[/tex]

[tex]\implies \sf 1481276.16=285.74r^2[/tex]

[tex]\implies \sf r^2=\dfrac{1481276.16}{285.74}[/tex]

[tex]\implies \sf r^2=5184[/tex]

[tex]\implies \sf r=\sqrt{5184}[/tex]

[tex]\implies \sf r=72\:in[/tex]

Answer: radius : 72.00 inch

The following is a cylinder.

Volume of Cylinder: πr²h

Given following:

Solve for radius:

[tex]\rightarrow \sf \pi r^2h =V[/tex]

[tex]\rightarrow \sf (3.14) r^2(91) =1,481,276.16[/tex]

[tex]\rightarrow \sf r^2 =\dfrac{1,481,276.16 }{91(3.14)}[/tex]

[tex]\rightarrow \sf r^2 =5184[/tex]

[tex]\rightarrow \sf r=\sqrt{5184}[/tex]

[tex]\rightarrow \sf r=72[/tex]

Answer:

0.8x

Step-by-step explanation:

According to BODMAS,

Step 1 :

4 ÷ 5

= 4 / 5

= 0.8

Step 2 : Multiply x.

0.8 * x = 0.8x

Answer:

Step one

4 ÷ 5

= 4/5

= 0.8

Step two = 0.8 * x

= 0.8x

Step-by-step explanation:

Stephanie has spent $150

she has saved $90

and owes her brother$40

The relation between the exponential and the logarithm is used. Then the expression [tex]e^{\ln3}[/tex] is given as 3.

Exponents can also be written as logarithms. A number base logarithm is similar to some other number. It is the exact inverse of the exponent expression.

The expression is given below.

[tex]\rightarrow e^{\ln3}[/tex]

We know the formula

[tex]\rm e^{\ln x} = x[/tex]

Then the expression can be written as

[tex]e^{\ln3} = 3[/tex]

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The points at which a quadratic equation intersects the x-axis are referred to as   x intercepts or zeros or roots of quadratic equation

Given :

The points at which a quadratic equation intersects the x-axis

The points at which the any quadratic equation crosses or touches the x axis are called as x intercepts.

At x intercepts the value of y is 0.

So , the points at which a quadratic equation intersects the x-axis is also called as zeros or roots of the quadratic equation .

The points at which a quadratic equation intersects the x-axis are referred to as   x intercepts or zeros or roots of quadratic equation

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Answer:

Volume = 12 ft^3

Step-by-step explanation:

Vol = length×width×height

= 3×4×1

= 12

The volume is 12 cubic feet.

Answer:

205.03125.

Step-by-step explanation:

18/12 = 1.5

27/18 = 1.5

This is geometric with nth term = ar^(n-1)

Here first term a = 12 and common ratio r = 1.5, so

The 8th term = 12(1.5)^(8-1)

= 205.03125

Answer:

310

Step-by-step explanation:

Multiply the l/w/h x 2

Answer:

64 Ounces

Step-by-step explanation:

64 Ounces of hot dogs

Answer:

64 oz

Step-by-step explanation:

1 lb = 16 oz

4 × 1 lb = 4 × 16 oz = 64 oz

Answer:

increasing from -2 to +∞

Step-by-step explanation:

The graph starts at -2 and continues to the right which means it increases from -2.

Answer:

Increasing from -2 to positive infinity.

Step-by-step explanation: This is because this is the graph of the square root of x + 2. It will increase from -2 in the x range and eventually hit every single x value from -2 to positive infinity.

Answer:

what is P(A), the probability that the first student is a boy? 3/5

what is P(B), the probability that the second student is a girl? 3/4

what is P(A and B), the probability that the first student is a boy and the second student is a girl? 1/2

No, évents A and B are not independent events

Step-by-step explanation:

The probability that the first student is a girl P(A)= 3/4.

The probability that the second student is a girl P(B)= 3/4.

The probability that the first student is a girl and the second student is a girl P(A and B)=9/16.

Given that there are three girls (Sandra, Marta, Jane) and one boy (Franklin), and the sample space of possible outcomes is:

{SA, SM, SJ, SF, MA, MS, MJ, MF, JA, JS, JM, JF, FA, FS, FM, FJ}

P(A): Probability that the first student is a girl (Sandra, Marta, or Jane).

Number of favorable outcomes where the first student is a girl: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(A) = Number of favorable outcomes / Total outcomes = 3 / 4

P(B):

Probability that the second student is a girl (Sandra, Marta, or Jane).

Number of favorable outcomes where the second student is a girl: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(B) = Number of favorable outcomes / Total outcomes = 3 / 4

P(A and B):

Probability that the first student is a girl and the second student is a girl.

Number of favorable outcomes where both students are girls: 3 (Sandra, Marta, Jane)

Total outcomes: 4 (total number of students)

P(A and B) = P(A).P(B)

= 3/4 × 3/4

=9/16

Hence, P(A)=3/4

P(B)=3/4

P(A and B)=9/16

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Answer:

Er I think it’s 8 but not sure

Step-by-step explanation:

Answer:

1456ft²

Step-by-step explanation:

A = lw

A = 60(20)

A = 1200ft²

A = 16(16)

A = 256ft²

1200 + 256 =

1456ft²

The jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d

From the question, we are to determine the jar that weighs more

From the given information

His jar of pennies weighs 84.96 ounces

and his jar of nickels weighs 3.11 kilograms

First, we will 84.96 ounces to kilogram

From the given conversion,

There are 0.0283495 kilograms per ounce

That is, 0.0283495 kg = 1 ounce

If 1 ounce = 0.0283495 kg

Then,

84.96 ounces = 84.96 × 0.0283495 kg

∴ 84.96 ounces = 2.4086 kg

His jar of pennies weighs 2.4086 kg

Since the John's jar of nickels weighs 3.11 kg, his jar of nickels weigh more.

3.11 kg - 2.4086 kg = 0.7014 kg

Convert 0.7014 kg to pounds

1kg =  2.20462 pounds

∴ 0.7014 kg = 0.7014 × 2.20462 pounds

0.7014kg ≅ 1.55 pounds

Hence, the jar of nickels weighs 1.55 pounds more than the jar of pennies. The correct option is d.

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Answer:

if you have a graphing calculator you can just plug the whole equasion in. the anser I got was -0.1547307191

Step-by-step explanation:

to get pie you have to hit second and then ^

Answer:

x + y = 4

substitute (-A, 2B) in the equation.

-A + 2B = 4

substitute (3A-2, 3-B) in the equation

3A-2 + 3-B = 4

Use elimination method and hence multiply the first substituted equation by 3

-3A + 6B = 12

3A-2 + 3-B = 4

-2 + 3 + 5B = 16

5B = 15

B = 3

Substitute value of B in any of the equations

and hence A = 2

Answer:

[tex]CI=\{2.5053,3.2147\}[/tex]

Step-by-step explanation:

Assuming the conditions for constructing a t-confidence interval are true, we use the formula [tex]\displaystyle CI=\bar{x}\pm t^*\biggr(\frac{s}{\sqrt{n}}\biggr)[/tex] where our sample mean is [tex]\bar{x}=2.86[/tex], our sample standard deviation is [tex]s=0.78[/tex], our sample size is [tex]n=15[/tex], and a 90% confidence level is equivalent to a critical value of [tex]t^*=1.7613[/tex],

[tex]\displaystyle CI=\bar{x}\pm z^*\biggr(\frac{s}{\sqrt{n}}\biggr)\\\\CI=2.86\pm 1.761\biggr(\frac{0.78}{\sqrt{15}}\biggr)\\\\CI=2.86\pm0.3547\\\\CI=\{2.5053,3.2147\}[/tex]

Hence, we are 90% confident that the true population mean of a student's grade point average is between 2.5053 and 3.2147