Danny and Iskander sit on a see-saw. Iskander weighs 40 N and sits 1.2 meters from the pivot. Danny sits 0.8 m from the pivot and the see-saw is balanced. How much does Danny weigh?

Answer:

Explanation:

The Law of Momentum Conservation applies, and the formula for us here specific to this problem is:

[tex][(m_bv_b)+(m_mv_m)]_b=[(m_b+m_m)v_{both}]_a[/tex] and filling in:

[(1.50*4.50)+60.0*0)] = [(1.50 + 60.0)v] and

6.75 + 0 = 61.5v so

v = .110 m/s in the same direction as the ball

Answer:

A. Stacking the cards in order of face value

Explanation:

A deck of playing cards' entropy would be reduced by being stacked in order of face value. Option C is correct.

The degree of randomness of the system is known as entropy.

If the system is organized its entropy is less. Stacking the cards in order of face value is an organized action.

Stacking the cards in order of face value is the action would decrease the entropy of a deck of playing cards.

Hence, option C is correct.

To learn more about entropy refer to;

https://brainly.com/question/13146879

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Answer:a gas at pressure of 0.8 m column of H g

Answer:

[tex]0.5\; \rm m^{3}[/tex].

Explanation:

Calculate the mass of this object:

[tex]\begin{aligned}& m(\text{object}) \\ &= \rho(\text{object}) \cdot V(\text{object}) \\ &= 500\; \rm kg \cdot m^{-3} \times 1\; \rm m^{3} = 500\; \rm kg\end{aligned}[/tex].

Multiple the mass of this object by the gravitational field strength, [tex]g[/tex], to find the weight of this object: [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].

Since this object is floating in water, the buoyancy force on it should be equal to its weight:

[tex]F(\text{buoyancy}) = W(\text{object}) = m(\text{object}) \cdot g[/tex].

By Archimedes' Principle, the weight of the water that this object displaces would be equal to [tex]F(\text{buoyancy})[/tex], the size of buoyancy force on this object,

Hence, the weight of water displaced would be [tex]W(\text{object}) = m(\text{object}) \cdot g[/tex].

Divide this weight by [tex]g[/tex] to find the mass of water displaced:

[tex]\begin{aligned} & m(\text{water displaced}) \\ &= \frac{W(\text{water displaced})}{g} \\ &= \frac{m(\text{object}) \cdot g}{g} = m(\text{object}) = 500\; \rm kg\end{aligned}[/tex].

Assume that the density of water is [tex]\rho(\text{water}) = 1000\; \rm kg \cdot m^{-3}[/tex]. The volume of water displaced would be:

[tex]\begin{aligned}& V(\text{water displaced}) \\ &= \frac{m(\text{water displaced})}{\rho(\text{water})} \\ &= \frac{500\; \rm kg}{1000\; \rm kg \cdot m^{-3}} = 0.5\; \rm m^{3}\end{aligned}[/tex].

Answer:

F = 2.45 N

Explanation:

m = 0.25 kg

a = 9.8 m/s^2

F = ma

F = (0.25)(9.8)

F = 2.45 N

Answer:

718.02N is the answer to the question

Answer:

The motorcycle daredevil does not sail across the 10-m wide pool filled with hungry crocodiles

Explanation:

The given parameters are;

The height of the ramp = 2.0 m-high

The angle of elevation of the ramp, θ = 20°

The width of the pool = 10 m

The speed with which he is going when the engine fails = 10.4 m/s

The rolling friction between the rubber tires, μ = 0.02

μ·g·cos(θ) = (1/2)·(a)

a = (μ·g·cos(θ))/(1/2)

Where;

a = The acceleration down the plane

∴ a = 0.02 × 9.81 × cos(20°)/(1/2) ≈ 0.369

The length of the ramp, l = 2.0 m/(sin(20°)) ≈ 5.8476088 m

The velocity at the end of the ramp, v² = u² - 2·a·l

∴ v² = 10.4² - 2×(0.369 + 9.81 × sin(20°))×5.8476088 ≈ 64.60446471

v ≈ √(64.60446471) ≈ 8.04

∴ The velocity at the top of the ramp, v ≈ 8.04 m/s

The time it takes the motorcycle to reach ground level from the top of the ramp, t, is given as follows;

h = h₀ + u·t + (1/2)·a·t²

h₀ = 2, u = 8.04×sin(20°), a = -9.81

When h = 0 (ground level), we have;

∴ h = 2+ 8.04×sin(20°)·t - (1/2)×9.81×t²

0 ≈ 2.75·t - 4.905·t² + 2

2.75·t - 4.905·t² + 2 = 0

By using a graphing calculator, we have, t = 0.978 or t = -0.42

At ground level, the time of flight, t ≈ 0.978 s

The horizontal distance the motorcycle travels, before landing, x = u × cos(θ) × t

∴ x = 8.04×cos(20 Degrees) × 0.978 = 7.3889

The horizontal distance the motorcycle travels, before landing, x ≈ 7.3889 m

Therefore, given that the horizontal distance the motorcycle travels in the air 7.3889 m < 10 m, therefore the motorcycle daredevil does not sail across the 10-m wide pool filled with hungry crocodiles

Answer:

Rovers, unmanned space probes, modern instruments,

Explanation:

Answer:

An egg with a thick shell.

Explanation:

Hope this helps.

Answer:

my brainly answer got deleted for no reason but its velocity thats the name of speed in 1 direction

Explanation:

Answer:

Gravitational energy and kinetic energy

Answer:

B.Converts the voltage of a current source

A transformer is an electrical apparatus designed to convert alternating current from one voltage to another. It can be designed to "step up" or "step down" voltages and works on the magnetic induction principle. ... When voltage is introduced to one coil, called the primary, it magnetizes the iron core.

MARK ME BRAINLIEST THANKS MY ANSWER PLEASE

Answer:

F=Gxy/r^2

Explanation:

F=Gm1m2/d^2

F=Gxy/r^2

Answer:

9 times

Explanation:

luminosity decreases to the square of the distance

Answer:

The proton has the same charge as the neutron.

Explanation:

Because the proton has a positive charge whereas the neutron has no charge  at all.

Answer:

A combination of two or more substances.

Answer:

no

Explanation:

Calcium chloride is a chemical compound made up of calcium ions and chlorine ions. ... Mixing calcium chloride with water is an exothermic reaction, which means that the combination of the two substances releases heat. Thus, when you add calcium chloride to water, the solution heats.

Answer:

9000 SECONDS

Explanation:3 hours=180 mins

                     180+30=210mins

                      150x60=12600secs

Answer:

Professional education as a science has been defined as a field of educational science that studies the growth of a person into a profession and the related problems. It refers to organized education aimed at the knowledge and skills needed in the profession and working life, as well as growing into active citizenship and membership of society. Professional education as a discipline studies vocational training, skills and learning related to the profession and working life.  

It enables young people and adults to pursue goal-oriented learning with the aim of acquiring and developing the necessary skills in the profession and creating the conditions for independent professional activity and continuous development in the profession.

Answer:

Power = 1800 W

Explanation:

Power = work / time

Power = 4500 / 2.5

Power = 1800 W

Answer:

Thể tích cuối cùng, V2 = 2 L

Explanation:

Cho các dữ liệu sau đây;

Khối lượng ban đầu = 10 L

Áp suất ban đầu = 10⁴ = 10000 Pa

Áp suất cuối cùng = 5 * 10⁴ = 50000 Pa

Để tìm tập mới hoặc tập cuối cùng, chúng ta sẽ sử dụng định luật Boyle;

Để tìm tập mới V2, chúng tôi sẽ sử dụng định luật Boyles.

Boyles phát biểu rằng khi nhiệt độ của khí lý tưởng được giữ không đổi, áp suất của khí tỉ lệ nghịch với thể tích mà khí chiếm giữ.

Về mặt toán học, định luật Boyles được đưa ra bởi;

[tex] PV = K[/tex]

[tex] P_{1}V_{1} = P_{2}V_{2} [/tex]

Thay vào phương trình, ta có;

[tex] 10000 * 10 = 50000V_{2} [/tex]

[tex] 100000 = 50000V_{2} [/tex]

[tex] V_{2} = \frac {100000}{50000}[/tex]

[tex] V_{2} = 2 [/tex]

Thể tích cuối cùng, V2 = 2 L

Answer:

90 A

Explanation:

Applying,

P = VI.............. Equation 1

Where P = Power, V = Supply voltage, I = current.

Make I the subject of the equation

I = P/V.............. Equation 2

From the question,

Assuming the Voltage of the main electric supply is 120 V

Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)

Substitute these values into equation 2

I = 10800/120

I = 90 A

Answer:

I think C

Explanation:

If im right give brainliest :)

Answer:

3386.23 Km

Explanation:

Without any wind interference the speed of the plane, it flies at 2.42 x 102 m/s or 242 m/s

The magnitude of the velocity of the air = 40.7-m/s

The time taken, for the plane to fly due west, tw = distance, x ÷ (speed of the plane without wind interference, up - the magnitude of the velocity of the air, ua).......... (equation 1)

The time taken, for the plane to fly due east, te = distance, x ÷ (speed of the plane without wind interference, up + the magnitude of the velocity of the air, ua).......... (equation 2)

To calculate the total time, t, the plane can fly to cover east and west distances, we add equation 1 and 2 together

t = (x ÷ (up - ua)) + (x ÷ (up + ua))

Making distance x, the subject of the formula we have:

x = t ( up²- ua²) ÷ 2up

note t = 8.0 hours which is (8 x 60 x 60) seconds = 28,800‬

So, x = 28,800‬ ((242 m/s)² - (40.7-m/s)²)÷ 2(242 m/s)

x= 1,638,936,288‬ ÷ 484

= 3386.23 Km

Answer:

B

Explanation:

4.9 eV is the correct answer

Hope it helps you ^ _ ^

Answer:

1) θ = 45,  b)  R₄₀ = R₅₀ = (v₀² / g) 0.985,  R₂₅ = R₆₅ = (v₀² / g) 0.766

3)  θ = 90º, d)   y₂₅ = (v₀ / 2g)   0.179, y₄₅ = (v₀ / 2g) 0.5, y₆₅ = (v₀ / 2g) 0.821

Explanation:

This is a projectile throwing exercise, let's use the relations

         R = [tex]\frac{v_o^2 \ sin \ 2\theta }{g}[/tex]

1) the angle for a maximum reach (R) is θ = 45

         R = v₀²/g

2) let's compare the scopes

θ = 25º

          R₂₅ = (v₀² /g) sin 2 25

          R₂₅ = (v₀² /g)  0.766

θ = 65º

         R₆₅ = (v₀² / g)  sin 2 65

         R₆₅ = (v₀² / g) 0.766

θ = 40º

        R₄₀ = (v₀²/g)  sin 2 40

        R₄₀ = (v₀²/ g) 0.985

θ = 50

        R₅₀ = (v₀²/g)  sin 2 50  

        R₅₀ = (v₀² / g) 0.985

we can see that it has the same scope

         R₄₀ = R₅₀ = (v₀² / g) 0.985

         R₂₅ = R₆₅ = (v₀² / g) 0.766

3) the maximum height is reached when the vertical speed is zero

         [tex]v_y^2 = v_{oy}^2 - 2 g y[/tex]

          v_y = 0

         y = [tex]\frac{v_{oy}^2}{2g}[/tex]

         y = (v₀² /2g) ( sin θ)²

therefore the height is maximum for θ = 90º

4) θ = 25º

         y₂₅ = (v₀ / 2g)   (sin 25)²

         y₂₅ = (v₀ / 2g)   0.179

θ = 45º

         y₄₅ = (v₀ / 2g) (sin 45)²

         y₄₅ = (v₀ / 2g) 0.5

θ = 65º

         y₆₀ = (v₀ / 2g) (sin 65)²

         y₆₅ = (v₀ / 2g) 0.821

5) It is appreciated that as the launch angle increases the height increases, the maximum is when the movement is vertical

For the launch angle, the reach has a maximum for the angle of 45º, this is due to the symmetry of the sine function around this value.

Answer:

Some galaxies are given descriptive names (e.g. "Andromeda", "Whirlpool") if they are particularly distinctive in location or appearance. But most galaxies are known from their designation in a catalogue. One of the earliest catalogues of objects in the sky was made by Charles Messier.

Answer:

106.8

Explanation:

If you multiply 6 and 17.8, you'll get 106.8.

If that's wrong, my apology's !