danny is offering 36$ for 4 hours of swimming lessons. Martin in offering 54$ for 3 hours of swimming lessons. whose offer is better

Answers

Answer 1

Answer:

Danny's offer is cheaper

Step-by-step explanation:

Danny is offering 36$ for 4 hours meaning you would do 36÷4=9 (9$ per hour)

Martin is offering 54$ for 3 hours so 54÷3=18 (18$ per hour)

Or the faster way of finding why is Danny is offering more hours for cheaper

Hope this helps


Related Questions

In ΔMNO, \text{m}\angle M = (6x+1)^{\circ}m∠M=(6x+1) ∘ , \text{m}\angle N = (3x-10)^{\circ}m∠N=(3x−10) ∘ , and \text{m}\angle O = (x+19)^{\circ}m∠O=(x+19) ∘ . Find \text{m}\angle N.m∠N.

Answers

Applying the triangle sum theorem, m∠N = 41°

What is the Triangle Sum Theorem?

Triangle sum theorem states that the sum of the three interior angles of any triangle equals 180°.

Given the following interior angles of ΔMNO:

m∠M = (6x+1)°

m∠N = (3x-10)°

m∠O = (x+19)°

Find the value of x:

m∠M + m∠N + m∠O = 180°

Substitute

6x+1 + 3x-10 + x+19 = 180

Add like terms

10x + 10 = 180

10x = 180 - 10

10x = 170

Divide both sides by 10

x = 17

m∠N = (3x-10)°

Plug in the value of x

m∠N = 3(17) - 10

m∠N = 41°

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Mark has a certain amount budgeted for dining out each month. Last month, the difference between the amount he budgeted and the amount he actually spent on dining out was less than -20 dollars.

Which of the following best describes this situation?
A.
Mark is under his budget by less than 20 dollars.

B.
Mark is under his budget by more than 20 dollars.

C.
Mark is over his budget by less than 20 dollars.

D.
Mark is over his budget by more than 20 dollars.

Answers

A. He used 20$ under his budget because he wanted to spend less then 20$ for dinner

The function f is given by f(x)=(x^{3}+bx+6)(g(x)), where b is a constant and g is a differentiable function satisfying g(2)=3 and g′(2)=−1. For what value of b is f′(2)=0?

7
10
12
22

Answers

Answer:

[tex]\displaystyle b = -22[/tex]

Step-by-step explanation:

We are given the function:

[tex]\displaystyle f(x) = (x^3+bx+6)(g(x))[/tex]

Where b is a constant and g is a differentiable function.

And we want to determine the value of b such that f'(2) = 0.

Find f' using the product rule:

[tex]\displaystyle \begin{aligned} f'(x) & = \frac{d}{dx}\left[ (x^3+bx+6)(g(x))\right] \\ \\ & = \frac{d}{dx}\left[ x^3 + bx + 6\right] g(x) + (x^3+bx+6)\frac{d}{dx}\left[ g(x)\right] \\ \\ & = (3x^2+b)(g(x)) + (x^3 + bx + 6)(g'(x))\end{aligned}[/tex]

Substitute using known values and solve for b:

[tex]\displaystyle \begin{aligned}f'(2) = 0 & = (3(2)^2+b)(g(2)) + ((2)^3+b(2)+6)(g'(2)) \\ \\ 0 & = (12+b)(3) + (14+2b)(-1) \\ \\ 0 & = 22 +b \\ \\ b & = -22\end{aligned}[/tex]

In conclusion, the value of b is -22.

The function f is given b is a constant and g is a differentiable function the value b (-8.4),

Let's start by finding the derivative of the given function f(x) with respect to x:

f(x) = (x³ + bx + 6) × g(x)

Using the product rule for differentiation, the derivative of f(x) is:

f'(x) = (x³ + bx + 6) × g'(x) + g(x) × (3x² + b)

Now we are interested in finding the value of b for which f'(2) = 0. So, let's plug in x = 2 and use the information given about g(2) and g'(2):

f'(2) = (2³ + 2b + 6) × g'(2) + g(2) × (3 × 2² + b)

Since g(2) = 3 and g'(2) = -1,

f'(2) = (8 + 2b + 6) × (-1) + 3 × (3 × 4 + b)

= (2b + 14 - 8) + 3× (12 + b)

= 2b + 6 + 36 + 3b

= 5b + 42

Now, we want to find the value of b for which f'(2) = 0:

5b + 42 = 0

Subtracting 42 from both sides:

5b = -42

Dividing both sides by 5:

b = -8.4

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Complete question:

The function f is given by f(x)=(x^{3}+bx+6)(g(x)), where b is a constant and g is a differentiable function satisfying g(2)=3 and g′(2)=−1. For what value of b is f′(2)=0?

7

10

12

22

-8.4

Jamal wrote that 9 – 8.4 = 6.

Answers

9−8.4=6

0.6≠6

False

I don't know...

Answer:

0.6 his answer is false.

Step-by-step explanation:

...

I need help with this please​

Answers

Answer:

I’m not sure what that means but I think it’s the one with the blue

Step-by-step explanation:

Using the previous problem, what is the rate at which
the shadow changes when the person is 10 ft from the wall,
if the person is walking away from the wall at a rate of 2 ft/
sec

Answers

Answer:

It grows at a rate  

4/9 ft/second

Step-by-step explanation:

What is the value of 1/6 with an exponent of 0

Answers

The answer is 1. Anything to the 0 power is 1.

Evan is organizing textbooks on his bookshelf. He has an English textbook, a biology textbook, a physics textbook, and a writing textbook. How many different ways can he line the textbooks up on his bookshelf?

Answers

Answer:

there is many ways but he could put them side to side or top and bottom

Step-by-step explanation:

Pencils can be purchased in packages of 12 or 25. If Karl purchased 8 packages to get 135 pencils, how many packages of 12 did he buy?

Answers

Answer: 60

Step-by-step explanation:

list all of the multiples and choose the least common number

10:   10  20  30  40  50  60  70  80  90  100

12:   12  24  36  48  60  72  84  96

find a number that shares all the prime factors of the two numbers

prime factors of 10: 2, 5

prime factors or 12: 2, 2, 3

LCM = 60

how can you find 72-25? circle all the correct answers

Answers

You can find it by doing out the math and the equation

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

hello comment anything

Answers

I like anime and sleeping✌

Answer:

i like food, money, and games

Step-by-step explanation:

E

PLEASE HELP!!!
True or false
3(x-2) and 3x-6 are
equivalent

Answers

Answer:

true!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

True.

Step-by-step explanation:

They are equivalent expression because if you distribute the 3 in 3(x-2), you will get the same expression as 3x-6.

3(x-2) =

(3*x) - (3*2) =

3x - 6

Hope this helps.

Determine the center and radius of the following circle equation:
x? + y2 - 2x - 12y +36 = 0

Answers

Step-by-step explanation:  

x²+ y² -12x - 18y +17 = 0 means : (x²-12x+36)-36+(y²-18y+81)-81-27 =0

(x-6)²+(y-9)² =12²....standard form when the center is (-6 , 9) and radius 12

Answer:

The center is at (1, 6) and the radius is 1.

Step-by-step explanation:

x^2 + y^2 - 2x - 12y +36 = 0

Convert to standard form:

x^2 - 2x + y^2 - 12y = -36

(x - 1)^2 - 1 + (y - 6)^2 - 36 = -36

(x - 1)^2 + (y - 6)^2 = -36 + 36 + 1

(x - 1)^2 + (y - 6)^2 =  1

The center is at (1, 6) and the radius is 1.

Hurry!! Answer it please:))

Answers

Answer:

Option C.

Domain:

{3, 0, 2, 4}

Step-by-step explanation:

The domain is the set of all the values of x.

Answer:

C is the answer!:)

Step-by-step explanation:

Domain is all numbers on the left and range is on the right

y over 11 =8 .solve for y

Answers

Answer:

y=88

Step-by-step explanation:

uhh…maybe 88? Btw if I’m wrong sorry I’m really tired and just tryin to help

hello need help question below​

Answers

What’s the question?

Find the volume (in cubic yards) of a rectangular solid with length 3.8 yards, width 2.2 yards, and height 2.3 yards.

Answers

Answer:

19.228

Step-by-step explanation:

multiply 2.2*2.3*3.8 to get 19 yd^3

Chi is planning to put a path of paving stones through her flower garden. The flower garden is a square with sides of 15 feet. How many feet long will the path be?

Answers

80 feet long because 1x1 1 80x1 80 sooooooooooo that’s your answer!!!

[tex]\frac{\sqrt{2x} }{\sqrt{} x-1}[/tex]
For which values of x does each expression make sense?

Answers

Answer:

The expression is unclear so:

If the denominator is [tex]\sqrt{x}-1[/tex] then your set of existence is given by

[tex]\left \{ {{x\ge0} \atop {x\ne1}} \right.[/tex]

since you want the quantity inside both square roots to be positive (and it happens for both to be simply [tex]x\ge0[/tex] and you don't want a zero at the denominator so you have to rule out 1.

If the square root includes the whole denominator [tex]\sqrt{x-1}[/tex] the condition becomes [tex]\left \{ {{x\ge0} \atop {x>1}} \right.[/tex]

where you don't include the extreme in the second condition since, again, you don't want to divide by 0. The answer in this case is simply [tex]x>1[/tex] since values between 0 and 1 will give a negative root which is not a real number.

please help. one algebra question for 20 points

Answers

Answer:

f(-18) = -5

Step-by-step explanation:

Substitute−18forxiny=

1/3 x+1:

y= 1/3x+1

y= 1/3(−18)+1

y=−5(Simplify both sides of the equation)

Write the equation to the line parallel to y= 3x – 5 that goes through the point (-2, -7) using any form.

Thank you!

Answers

Answer:

y = 3x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 5 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes , then

y = 3x + c ← is the partial equation

To find c substitute (- 2, - 7 ) into the partial equation

- 7 = - 6 + c ⇒ c = - 7 + 6 = - 1

y = 3x - 1 ← equation of parallel line

If a car averages 22 miles per gallon, how many kilometers per liter is this?

Answers

We have to convert the units. 1 mile = 1.60934km, 1 gallon = 3.78541km

Since it's mile per gallon, we divide the units mentioned above.

1 mile / 1 gallon = 1 km / 1 gallon = 1.60934 / 3.78541 = 0.4251

Now multiply this result as a factor to 22

That is 22 * 0.4251 = 9.3522

So the answer is 9.3522

Can someone help me? I don't understand this

Answers

1 is 3/20 2 is 7/4 3 is 1 number 4 is 15/14

Sara earns a basic salary of 14250 every month with an additional 12% commission on her sales. If Sara sold items worth AED 22264 last month, what was her total pay?
a. AED 16921.68
b. AED 24935.68
c. AED 1710
d. AED 2671.68

Answers

Answer:

A

Step-by-step explanation:

Commission: 22264*0.12=2671.68

Total pay: 14250+2671.68=16921.68

The total pay of Sara after adding the commission is: Option A:  AED 16921.68

How to find the net income?

Sara's total pay consists of her basic salary plus the commission on her sales.

Basic salary = AED 14250

Commission on sales = 12% of AED 22264

Commission = 0.12 * 22264

Now, calculate the commission:

Commission = 0.12 * 22264 = AED 2671.68

Total pay = Basic salary + Commission

Total pay = 14250 + 2671.68 = AED 16921.68

So, Sara's total pay is AED 16921.68

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A force of 18 lb is required to hold a spring stretched 2 in. beyond its natural length. How much work W W is done in stretching it from its natural length to 7 in. beyond its natural length

Answers

Answer:

Step-by-step explanation:

Average force is (19 + 0)/2 = 9 lb

2 inches = 1/6 ft

W = Fd = 9(1/6) = 1.5 ft•lb

I need help with this question

Answers

Answer:

Go download CameraMath on playstore that how

I is get my answer

What's the missing addend 634 + =644

Answers

Answer:

10

Step-by-step explanation:

it is 10 cause 634+10=644

Answer:

10

Step-by-step explanation:

What is the missing addend?

We can fill in the blank with x

634+x=644

Now we need to get x to the other side

The rule to do this is what we do on one side we have to do the same thing to the other side

so if we subtract 634 on one side we also have to do that on the other side as well:

634-634+x=644-634

634-634 is 0

So it is

x=644-634

644-634 is 10

x=10

So the missing addend is 10

Hope this helps!

Jessica made $156 for 12 hours of work.
At the same rate, how much would she make for hours of work?

Answers

Answer:

156/12=13

so makes 13 dollars a hour

Hope This Helps!!!

Find the Value for X,Y and z using Gauss-Jordan Inversion method
2X+3Y=4
X+2Y=2

Answers

Answer:

x = 2 y = 0

Step-by-step explanation:

Answer:

Step-by-step explanation:

Please help me prove that ED is congruent to BA! I thought I had it right by proving right and vertical angles, but I’m missing something

Answers

Step-by-step explanation:

[tex]\overline{DA} \text{ bisects } \overline{EB}[/tex]     is given

[tex]\overline{BC} \cong \overline{EC}[/tex]  definition of bisect

[tex]\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}[/tex]  are both given

[tex]\angle B, \, \angle E \text{ are right angles}[/tex]  definition of perpendicular

[tex]\angle B \cong \angle E[/tex]   because all right angles are congruent

[tex]\angle{ACB} \cong \angle{DCE}[/tex]  vertical angles are congruent

[tex]\triangle{ACB} \cong \triangle{DCE}[/tex]   ASA (angle-side-angle)

[tex]\overline{ED} \cong \overline{BA}[/tex]  CPCTC (corresponding parts of congruent triangles are congruent)

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