Answer:
(a) the gravitational influence on visible matter can not be explained by matter that can be seen.
The person is in motion
relative to...
Answer:
muscular force in relative to this
If you double the pressure of a constant amount of gas at a constant temperature, what happens to the volume
Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.
Explanation:
Please help! Question is attached!
Answer:
1. -6m/s
2. 0m/s
3. 3m/s
4.14.38N
5. 25.9 J
Explanation:
1. point A and C same height means velocity will be the same just in opposite direction, = -6m/s
2. at max height vertical velocity is 0
3. same as point A
4. Weight is mg = 1.438*10 = 14.38N
5. total energy is KE+PE, which never changes
so TE = 32.4 and KE =6.5J then PE = 32.4-6.5 = 25.9 J
Waves can be refracted.
Explain this term.
HELP PLSSS
Answer: By "waves can be refracted" they mean that refraction can occur with waves. To better explain, refraction is the "change in direction of a wave passing from one medium to another or from a gradual change in the medium." You probably know this best when you put a pencil inside a glass of water where the pencil bends a bit. The same can happen with sound or water waves as well!
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When is there no atmospheric pressure pjysics.
given a force of 88N and an acceleration of 4 m/s 2, what is the mass?
Answer:22kg
Explanation:
from F=ma, 88=4m, m=22kg
sports photographers often use large aperture, long focal length lenses. what limitations do these lenses impose on the photographs?
Answer:
The depth of focus achievable with those lenses is small.
Explanation:
A larger aperture makes it much harder to focus on more than one object. When using a telephoto lens (the ones the question is referring to), the depth of focus is very small. For example, using a telephoto lens to take a photo of a runner might get the runner in focus, but certainly not the track, or the audience behind them. If you look at photos, especially older photos, of Olympians in almost any sport you can see this.
Hope this helps!
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Why there has to be a driving force to keep the car moving at a constant speed?
Explanation:
For example, when a car travels at a constant speed, the driving force from the engine is balanced by resistive forces such as air resistance and friction in the car's moving parts. ... an object falling at terminal velocity experiences the same air resistance as its weight.
Is mixing mixing sugar and cinnamon a chemical or physical change?
Answer:
It is a physical
Explanation:
Question 1 of 11
The book has a mass of 2.5 kg.
What net force must act on the book to make it accelerate to the left at a rate
of 7.0 m/s2? (Hint: Use F = ma.)
O A. F = 17.5 N right
OB. F = 2.8 N right
O C. F = 2.8 N left
O D. F = 17.5 N left
Answer:
D. F= 17.5 N left
Explanation:
I just took the quiz and got it correct!
1. How much heat is released when a 25 g sample of water (c = 4.184) is cooled from 99 °C
to 75 °C?
a person weighing 500 N climbs 3 m how much power. is needed to make the climb in 5 s?
Answer:
300watts
Explanation:
Answer:
300 watts
lol hoped this helped
:)
To solve a problem using the equation for Kepler’s third law, Enrico must convert the average distance of Mars from the Sun from meters into astronomical units. How should he make the conversion? multiply the average distance by 1. 5 × 1011 multiply 1. 5 × 1011 by the average distance divide the average distance by 1. 5 × 1011 divide 1. 5 × 1011 by the average distance.
The conversion from meters to astronomical units is done by dividing the average distance by 1. 5 × 10^11.
Just as different areas of human endeavor has different units, the unit of length in astronomy is astronomical units. The astronomical unit is defined as the distance between the center of the earth and the sun.
To solve a problem using the equation for Kepler's third law, Enrico must convert the average distance of Mars from the Sun from meters into astronomical units. This is done by dividing the average distance by 1. 5 × 10^11.
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Which is larger, the sun's pull on earth or earth's pull on the sun?.
Answer:
the suns pull
Explanation:
The Sun's pull on Earth is twice as large as Earth's pull on the much larger Sun.
how does amplitude determine loudness?
Answer:
Explanation:
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder.
Answer:
Amplitude determines the loudness of a wave. Greater the amplitude, greater is the loudness.
Explanation:
Amplitude is a measure of the size of sound waves. It depends on the amount of energy that started the waves. Greater amplitude waves have more energy and greater intensity, so they sound louder. ... The same amount of energy is spread over a greater area, so the intensity and loudness of the sound is less.
I hope this helps have a great day :)
1. A 12 kilogram block is sitting on a platform 24 m high. How much Potential energy does
it contain?
The amount of potential energy the block contains is 2,822.4 Joules
Given the following data:
Mass of block = 12 kgHeight of platform = 24 meters.We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].
To determine the amount of potential energy the block contains:
Mathematically, potential energy (P.E) is given by the formula;
[tex]P.E = mgh[/tex]
Where:
m is the mass of object.g is the acceleration due to gravity.h is the height of an object.Substituting the parameters into the formula, we have;
[tex]P.E = 12 \times 9.8 \times 24[/tex]
Potential energy (P.E) = 2,822.4 Joules
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A 2 kg object has a specific heat capacity of 1,700 J/(kg \cdot⋅oC)
To raise this object's temperature from 15 Celsius to 25 Celsius, the object must absorb _______ Joules of heat.
The amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
The amount of heat absorbed by an object can be calculated by using the following expression:Q = m.c.∆TWhere;
Q = amount of heat absorbed or released (J)m = mass of objectc = specific heat capacity (J/g°C)∆T = change in temperature (°C)According to this question, 2 kg object has a specific heat capacity of 1,700J/kg°C and was raised from a temperature of 15 Celsius to 25 Celsius. The heat absorbed is calculated as follows:Q = 2 × 1700 × {25 - 15}Q = 3400 × 10Q = 34000JTherefore, the amount of heat needed to raise the temperature of a 2kg object from 15°C to 25°C is 34000J.Learn more about how to calculate heat absorbed at: https://brainly.com/question/11194034?referrer=searchResults
Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project
Answer:
Kyoto Protocol
Explanation:
Suppose cars start at a car race. In how many ways can the top 3 cars finish the race?.
Answer:
there is six ways the top three cars can finish the race
Calculate torque using angular momentum
Answer:
The equation net τ=ΔLΔt net τ = Δ L Δ t gives the relationship between torque and the angular momentum produced.
If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
the force needed to accelerated it at 2.0m/s^2 ?
Answer:
750 Newton
Explanation:
force=mass(acceleration)
State the general purpose of an experiment, using the terms dependent and independent variable
Answer:
Image result for State the general purpose of an experiment, using the terms dependent and independent variable
You can think of independent and dependent variables in terms of cause and effect: an independent variable is the variable you think is the cause, while a dependent variable is the effect. In an experiment, you manipulate the independent variable and measure the outcome in the dependent variable
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we cannot see the milky way galaxy without binocular or telescopes. true or false?
Answer:
I'm pretty sure it's false
Explanation:
.
What symbols are these?
Answer:
the bottom one is wollsiegel
The Earth system is an example of a(n)
What is the mass of an object that weighs 20N on earth? Use g=9.8 N/kg
Answer: Therefore, the mass of the object is 2.222 kg on the Earth, Moon, Saturn, Mercury and everywhere else it goes.
Explanation:
Answer:
the mass is 2.04
Explanation:
The weight of an object is calculated by: W=Mg
Solving for M: M=W/9
M=20/9.8 = 2.04
An object of mass 10 kg is moving along positive x- axis with velocity 5 m/s. At some point it breaks into two parts of 6 kg and 4 kg. 6 kg moves making 600 with x –axis and 4 kg moves making -300 with axis. What is velocity of their centre of mass after breaking?
Explanation:
Correct option is
B
−3m/s
2
Given,
m=10kg
u=10m/s
v=−2m/s
t=4sec
The acceleration is rate of change of velocity,
a=
t
v−u
a=
4
−2−10
a=
4
−12
=−3m/s
2
The correct option is B.
A block of mass m is initially at rest on a rough horizontal surface when a constant force F is exerted on it, as shown. The block accelerates to the right and is moving with speed v once it has moved a distance d. Which of the following equations can be used to solve for the force of friction exerted on the block by the surface?
The equations that can be used to solve for the force of friction exerted on the block by the surface is F- f = mv² / d
The constant force F is exerted on the block of mass and it accelerates with a speed, v and covering a distance of d in the direction of the force. The force of friction is an opposing force to the applied force.
Therefore,
using Newtons third law
F - f = ma
a = v/t
t = d/v
F - f = m × v / t
F- f = m × [tex]\frac{v}{\frac{d}{v} }[/tex]
F- f = m × v²/d
Therefore,
F- f = mv² / d
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What is the mass (in kg) of an object which accelerates at 3 m/s^2 when acted upon by a 15 N force?
[tex]\purple{\longrightarrow \sf Force = Mass \times Acceleration}[/tex]
[tex] \longrightarrow \sf Mass = \dfrac{Force}{Acceleration }[/tex]
[tex]\longrightarrow \sf Mass = \dfrac{15}{3}[/tex]
[tex]\longrightarrow \sf Mass = \cancel{\dfrac{15}{3}} [/tex]
[tex]\longrightarrow {\pink{\underline{\underline{\sf{ Mass = 5 \: Kg }}}}}[/tex]
Henceforth :-
The mass of the object is 5 kg.▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
What is the net force on a 4,000-kg car
that doubles its velocity from 15 m/s west
to 30 m/s west over 10 seconds?
Answer:
6000 N toward west
Explanation:
F = ma
a = 30-15/10 = 1.5 m/s^2 towards west
m = 4000 kg
F = 4000 x 1.5 = 6000 N towards west