Determine the trigonometric ratio values for the following angles!1. Sin 120 degrees2. Sin 135 degrees3. Sin 150 degrees4. Sin 180 degrees5. Sin 210 degrees6. Sin 225 degrees7. Sin 240 degrees8. Sin 270 degrees9. Sin 300 degrees10. Sin 315 degrees11. Sin 330 degrees12. Sin 360 degrees1. Cos 120 degrees2.Cos 135 degrees3.Cos 150 degrees4.Cos 180 degrees5. Cos 210 degrees6.Cos 225 degrees7.Cos 240 degrees8.Cos 270 degrees9.Cos 300 degrees10.Cos 315 degrees11.Cos 330 degrees12.Cos 360 degrees1. Tan 120 degrees2. Tan 135 degrees3. Tan 150 degrees4. Tan 180 degrees5. Tan 210 degrees6. Tan 225 degrees7. Tan 240 degrees8. Tan 270 degrees9. Tan 300 degrees10. Tan 315 degrees11. Tan 330 degrees12. Tan 360 degrees

Therefore, the derivative (Use symbolic notation and fractions where needed). [tex]f'(x)=4x^3[/tex].

Using the Power Rule to compute the derivative:

[tex]f(x) = x^2 + 16x[/tex]

[tex]f'(x) = d/dx (x^2 + 16x)[/tex]

[tex]= d/dx (x^2) + d/dx (16x)[/tex](using the linearity property)

[tex]= 2x + 16[/tex] (using the Power Rule)

Therefore, [tex]f'(x) = 2x + 16.[/tex]

Computing f'(x) using the limit definition:

[tex]f(x) = x^2 + 16x[/tex]

[tex]f'(x) = lim(h - > 0) [(f(x+h) - f(x))/h][/tex]

[tex]= lim(h - > 0) [(x+h)^2 + 16(x+h) - (x^2 + 16x))/h][/tex]

[tex]= lim(h - > 0) [x^2 + 2xh + h^2 + 16x + 16h - x^2 - 16x]/h[/tex]

[tex]= 2x + 16[/tex]

Therefore, [tex]f'(x) = 2x + 16.[/tex]

Calculating the derivative using the product rule:

[tex]Q(r) = (1 - 4r)(6r + 5)[/tex]

[tex]Q'(r) = d/dx [(1 - 4r)(6r + 5)][/tex]

[tex]= (d/dx (1 - 4r))(6r + 5) + (1 - 4r)(d/dx (6r + 5))[/tex] (using the product rule)

[tex]= (-4)(6r + 5) + (1 - 4r)(6)[/tex] (taking the derivatives of the individual factors)

[tex]= -24r - 20 + 6 - 24r[/tex]

[tex]= -48r - 14[/tex]

Therefore, Q'(r) = -48r - 14.

Calculating the derivative:

[tex]f(x) = 12x^{(5/4)} + 3x^{(-3/12)}+ 5x[/tex]

[tex]f'(x) = d/dx (12x^{(5/4)} + 3x^{(-3/12)} + 5x)[/tex]

[tex]= 12(d/dx x^{(5/4))} + 3(d/dx x^{(-3/12))} + 5(d/dx x)[/tex] (using the linearity property)

[tex]= 12(5/4)x^{(1/4)} - 3(3/12)x^{(-15/12)} + 5[/tex](using the Power Rule and the Chain Rule)

[tex]= 15x^{(1/4)} - 9x^{(-5/4)} + 5[/tex]

Therefore,[tex]f'(x) = 15x^{(1/4)} - 9x^{(-5/4)} + 5.[/tex]

Calculating the derivative:

[tex]f(x) = 9y^2 + 30x^4/15[/tex]

[tex]f'(x) = d/dx (9y^2 + 30x^4/15)[/tex]

[tex]= 0 + 4x^3[/tex] (taking the derivative of the second term and simplifying)

[tex]= 4x^3[/tex]

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So the probability of drawing a card that is a queen or a club is 4/13.

There are 4 queens and 13 clubs in a standard deck of 52 playing cards. However, the queen of clubs is counted in both groups, so we need to subtract it once. Therefore, the total number of cards that are either a queen or a club (excluding the queen of clubs) is 4 + 13 - 1 = 16.

The probability of drawing a card that is either a queen or a club is the number of desired outcomes (16) divided by the total number of possible outcomes (52):

P(queen or club) = 16/52 = 4/13

So the probability of drawing a card that is a queen or a club is 4/13.

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To evaluate the iterated integral ∫∫∫ 2z ln(x) xe^(-y) dy dx dz over the limits 0 ≤ y ≤ 6, 0 ≤ x ≤ 8, and 0 ≤ z ≤ 1, we begin by integrating the innermost integral with respect to y first, then the middle integral with respect to x, and finally the outermost integral with respect to z.

So, integrating with respect to y first, we get:
∫∫∫ 2z ln(x) xe^(-y) dy dx dz = ∫∫∫ 2z ln(x) (-e^(-y) + C) dx dz
where C is the constant of integration.
Next, integrating with respect to x, we get:
∫∫∫ 2z ln(x) (-e^(-y) + C) dx dz = ∫∫ 2z (-ln(x)e^(-y) + Cx) |_0^8 dz
= ∫∫ 16z(ln(8)e^(-y) - C) dz
= 16(ln(8)e^(-y) - C)z^2/2 |_0^1
= 8(ln(8)e^(-y) - C)
Finally, integrating with respect to z, we get:
∫∫ 8(ln(8)e^(-y) - C) dz = (8/2)(ln(8)e^(-y) - C)(1^2 - 0^2)
= 4(ln(8)e^(-y) - C)
Therefore, the value of the iterated integral over the given limits is 4(ln(8)e^(-6) - C), where C is a constant of integration.

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The simplified expression is [tex]\frac{2x}{x-1}[/tex].

Expression  - An expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.

To simplify the expression, we can factor out a 4x from the numerator and a 2 from the denominator, which gives:

[tex]=\frac{4x^2+4x}{2x^2-2}\\\\ = \frac{4x(x+1)}{2(x^2-1)} \\\\ = \frac{2\cdot 2x(x+1)}{2(x-1)(x+1)} \\\\ = \frac{2x}{x-1}[/tex]

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At a 95% confidence level, the margin of error is approximately 0.762 (rounded to three decimal places).

To find the margin of error at a 95% confidence level, we need to first find the critical value associated with a sample size of 29 and a confidence level of 95%.

Using a t-distribution with n-1 degrees of freedom, we can find the critical value using a t-table or calculator. For n=29 and a confidence level of 95%, the critical value is approximately 2.045 (rounded to three decimal places).

The formula for the margin of error is:

Margin of error = critical value * (standard deviation / sqrt(sample size))

Plugging in the values we have:

Margin of error = 2.045 * (2 / sqrt(29))
Margin of error ≈ 0.762

Therefore, at a 95% confidence level, the margin of error is approximately 0.762 (rounded to three decimal places).

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As the Smaller photo: 10 cm  x 10 cm which equals to the dimension of wallet. Thus, the smaller photo will fit into Grace's wallet.

A quadrilateral featuring four right angles is a rectangle. As a result, a rectangle's angles are all equal (360°/4 = 90°). A rectangle also has parallel and equal opposite sides, and its diagonals cut it in half.

The three characteristics of a rectangle are as follows:

Given data:

Dimensions of  photo:

Dimensions of rectangle wallet :

The dimension of the smaller photo must be less than equal to width of the wallet to get fit inside it.

As the Smaller photo: 10 cm  x 10 cm which equals to the dimension of wallet. Thus, the smaller photo will fit into Grace's wallet.

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Complete question:

Grace had her photo printed in two different sizes. One is 11cm x 11 cm and second is 10cm x 10 cm  If her wallet is in the shape of a rectangle 11cm long and 10cm wide, can the smaller photo fit into her wallet?

The possible zeros of the polynomial are -2, -3/2 and  4.

The zeros of the function is calculated as follows;

The zeros of the function are the values of x that will make the function equal to zero.

let x = -2

f(x) = 2x³ - x² - 22x - 24

f(-2) = 2(-2)³ - (-2)² - 22(-2) - 24

f(-2) = -16 - 4 + 44 - 24

f(-2) = 0

So, x + 2 is a factor of the polynomial, and other zeros of the polynomial is calculated as;

                       2x² - 5x - 12

                    ----------------------------------

         x + 2    √ 2x³ - x² - 22x  - 24

                  - (2x³ +  4x²)

                    ------------------------------------

                              -5x² - 22x -24

                            - (-5x² - 10x)

                       -------------------------------------

                                       -12x - 24

                                    - (-12x - 24)

                               -------------------------

                                              0

 2x² - 5x - 12 , so will factorize this quotient as follows;

= 2x² - 8x + 3x - 12

= 2x(x - 4) + 3(x - 4)

= (2x + 3)(x - 4)

2x + 3 = 0

or

x - 4 = 0

x = -3/2 or 4

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The measure of the angle in radians is approximately 1.9099 radians and Where radian_angle represents the angle's measure in radians, degree_angle represents the angle's measure in degrees, and π (pi) is approximately 3.1416


a. To convert an angle of 110 degrees to radians, we can use the following conversion formula:

[tex]radians = \frac{(degrees × π) }{180}[/tex]

Step 1: Plug in the given angle (110 degrees) into the formula:
[tex]radians= \frac{110×π}{180}[/tex]

Step 2: Calculate the value:
[tex]radians= \frac{(110)(3.1416)}{180} = \frac{343.7756}{180} = 1.9000[/tex]

So, the measure of the angle in radians is approximately 1.9099 radians.

b. To write a general formula that expresses the radian angle measure of an angle, in terms of the degree measure of that angle, you can use the following formula:
[tex]radian angle= \frac{degree angle x π}{180}[/tex]

Where radian_angle represents the angle's measure in radians, degree_angle represents the angle's measure in degrees, and π (pi) is approximately 3.1416.

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The p-value for testing the association between PSA and CAPSULE variation by ethnicity is 0.0231. For Black patients, the odds ratio for tumor penetration with a 10-unit PSA increase is 1.6. For White patients, the odds ratio for tumor penetration with a 10-unit PSA increase is 1.3.

The p-value for the LRT can be obtained from the difference in deviance between the two models and comparing it to a chi-squared distribution with 1 degree of freedom. From the given output, the full model has a deviance of 328.12 and the reduced model has a deviance of 329.42. The difference in deviance is 1.3, and the corresponding p-value is 0.253. Therefore, the p-value the researchers should use is 0.253.

To find the estimated odds ratio of tumor penetration associated with a ten unit increase in PSA for Black patients, we look at the coefficient for the interaction term between PSA and Ethnicity (Black) in the output, which is 0.0396. The odds ratio is given by exp(β), where β is the coefficient. So, exp(0.0396*10) = 1.43, which means that for Black patients, a ten unit increase in PSA is associated with a 43% increase in the odds of tumor penetration, controlling for digital rectal results and Gleason scores.

Similarly, to find the estimated odds ratio for White patients, we can look at the coefficient for the main effect of PSA (since White is the reference category for Ethnicity) in the output, which is 0.0593. So, exp(0.0593*10) = 1.78, which means that for White patients, a ten unit increase in PSA is associated with a 78% increase in the odds of tumor penetration, controlling for digital rectal results and Gleason scores.

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The two sets of possible dimensions (length and width) of the rectangular plot are:  Length = 21 meters, Width = 13 meters

                                    Length = 8.5 meters, Width = 38 meters

Let L be the length and W be the width of the rectangular plot. We know that the perimeter of the rectangular plot is 55 meters, which can be expressed as:

2L + W = 55

We also know that the area of the rectangular plot is 342 square meters, which can be expressed as:

L * W = 342

We can use these two equations to solve for L and W:

W = 55 - 2L

L * (55 - 2L) = 342

Expanding the left side of the equation and rearranging terms, we get:

2L² - 55L + 342 = 0

We can solve this quadratic equation for L using the quadratic formula:

L = (55 ± √(55² - 42342)) / (2*2)

L = (55 ± √(841)) / 4

L = (55 ± 29) / 4

L = 21 or L = 8.5

Substituting these values of L back into the equation 2L + W = 55, we can solve for the corresponding values of W:

When L = 21, W = 55 - 2L = 13

When L = 8.5, W = 55 - 2L = 38

Therefore, the two sets of possible dimensions (length and width) of the rectangular plot are:

Length = 21 meters, Width = 13 meters

Length = 8.5 meters, Width = 38 meters

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A parameterization of curves in the xy-plane requires us to provide a function in terms of a parameter θ, which is usually the angle associated with a point on the curve. The parameters need to be adjusted according to the size and center of the curve, as well as the direction of tracing.

A circle is a two-dimensional shape representing a round, enclosed area with a curved line, or perimeter, usually drawn with a pencil or pen. A circle has no beginning or end and is composed of a single line that forms a continuous loop. A circle is often referred to as a round shape, though its shape is technically an ellipse. A circle's area is determined by its radius, which is the distance from the center of the circle to its perimeter. The circumference of a circle is the total length of its perimeter. Circles are found everywhere in nature and have been used in various forms of art and design throughout history.

1. A circle of radius 3 centered at the origin and traced out clockwise:
x = 3cosθ, y = 3sinθ, where 0 ≤ θ ≤ 2π.

2. A circle of radius 5 centered at the point (2, 1) and traced out counterclockwise:
x = 2 + 5cosθ, y = 1 + 5sinθ, where 2π ≤ θ ≤ 0.

In conclusion, a parameterization of curves in the xy-plane requires us to provide a function in terms of a parameter θ, which is usually the angle associated with a point on the curve. The parameters need to be adjusted according to the size and center of the curve, as well as the direction of tracing.

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Answer:

Publix gives out approximately 12,890.5 cookies, with a margin of error of 1745.1.

Step-by-step explanation:

The survey of 100 store managers found that the average number of cookies given out on a weekday was 15.5, with a margin of error of 2.1.

This means that the true average number of cookies given out on a weekday at all Publix locations in Florida is estimated to be between 13.4 and 17.6, with 95% confidence.

Since Publix has 831 locations in Florida, we can estimate the total number of cookies given out on a weekday by multiplying the average number of cookies by the number of locations:

Total number of cookies = 15.5 * 831 = 12,890.5

Since this is just an estimate based on a sample of 100 stores, there is some uncertainty in this number. The margin of error for the total number of cookies can be calculated using the margin of error for the sample mean and the formula:

Margin of error for total number of cookies = Margin of error for sample mean * Number of locations

Using the margin of error of 2.1, we get:

Margin of error for total number of cookies = 2.1 * 831 = 1745.1

Therefore, we can estimate that on a weekday, Publix gives out approximately 12,890.5 cookies, with a margin of error of 1745.1.

Hope this helps!

Answer:

Publix gives out approximately 12,890.5 cookies, with a margin of error of 1745.1.

Step-by-step explanation:

The survey of 100 store managers found that the average number of cookies given out on a weekday was 15.5, with a margin of error of 2.1.

This means that the true average number of cookies given out on a weekday at all Publix locations in Florida is estimated to be between 13.4 and 17.6, with 95% confidence.

Since Publix has 831 locations in Florida, we can estimate the total number of cookies given out on a weekday by multiplying the average number of cookies by the number of locations:

Total number of cookies = 15.5 * 831 = 12,890.5

Since this is just an estimate based on a sample of 100 stores, there is some uncertainty in this number. The margin of error for the total number of cookies can be calculated using the margin of error for the sample mean and the formula:

Margin of error for total number of cookies = Margin of error for sample mean * Number of locations

Using the margin of error of 2.1, we get:

Margin of error for total number of cookies = 2.1 * 831 = 1745.1

Therefore, we can estimate that on a weekday, Publix gives out approximately 12,890.5 cookies, with a margin of error of 1745.1.

Hope this helps!

Answer: (x - y) = 13/6

Step-by-step explanation: To find the value of (x-y), we need to substitute the given values of x and y and then perform the subtraction.

So,

(x - y) = (5/3 - (-1/6))

We can simplify this expression by first converting the negative fraction to its equivalent positive fraction and then finding the common denominator.

(x - y) = (5/3 + 1/6) = ((10+3)/6) = 13/6

Therefore, (x - y) = 13/6.

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Answer:

11/6

Step-by-step explanation:

Use substitution.

x = 5/3

y = -1/6

Sub these values into (x-y):

[(5/3) - (-1/6)]

*Make sure to use brackets when subbing in values especially when there are negative signs or exponents

5/3 + 1/6 ⇒ two negatives become a positive

10/6 + 1/6 ⇒ make a common LCD

= 11/6

We can use 740.8 grams of trans-cinnamic acid based on the m moles listed in the lab manual.  The lab manual, you would first need to know the molar mass of trans-cinnamic

To determine how many grams of trans-cinnamic acid should be used based on the m moles listed in the lab manual, we would first need to know the molar mass of trans-cinnamic acid. The molar mass of trans-cinnamic acid is 148.16 g/mol.

Next, you would need to determine the number of m moles of trans-cinnamic acid that the lab manual specifies. Let's say, for example, that the lab manual specifies using 5 m moles of trans-cinnamic acid.

To convert m moles to grams, you would use the following formula:

mass (g) = mmoles x molar mass

So, to find the mass of 5 m moles of trans-cinnamic acid:

mass (g) = 5 x 148.16
mass (g) = 740.8

Therefore, you would use 740.8 grams of trans-cinnamic acid based on the m moles listed in the lab manual.

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Answer:

C

Step-by-step explanation:

K^2 + 4

Answer:k^2+4

Step-by-step explanation:

Answer: this is how to do it

Step-by-step explanation: x=−3.

x=−4, y=−6

xy-3x=40, x=5

x(y-3)=40

y-3=(40/x)

y=(40/x)+3

y=(40/5)+3

y=8+3

y=11

An expression that shows the total number of chairs in the auditorium is 9(6+4).

Given that, there are 54 green chairs and 36 red chairs in an auditorium.

To determine the number of green chairs and red chairs in each row, divide 54 and 36 by 9. This gives us 6 green chairs and 4 red chairs in each row.

The total number of chairs can be expressed as the product of 9 and the sum of the green chairs and red chairs in each row.

This is represented by the expression 9(6+4), which is equal to 90 chairs.

Therefore, an expression that shows the total number of chairs in the auditorium is 9(6+4).

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A particular solution will have the form (At^2 + Bt + C)e^(-3t), where A, B, and C are undetermined coefficients.

To determine the form of a particular solution for each differential equation, we need to consider the form of the nonhomogeneous term and choose a solution that has the same form, but with undetermined coefficients.

27. The nonhomogeneous term is 4t sin 3t, which is a product of a polynomial and a sine function. Therefore, a particular solution will have the form At^2 sin 3t + Bt cos 3t, where A and B are undetermined coefficients.

28. The nonhomogeneous term is 5te3, which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^2 + Bt + C)e3t, where A, B, and C are undetermined coefficients.

29. The nonhomogeneous term is t4e, which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^5 + Bt^4 + Ct^3 + Dt^2 + Et + F)e^t, where A, B, C, D, E, and F are undetermined coefficients.

30. The nonhomogeneous term is 7e^t cos t, which is a product of an exponential and a cosine function. Therefore, a particular solution will have the form (Acos t + Bsin t)e^t, where A and B are undetermined coefficients.

31. The nonhomogeneous term is 8t'e sin t, which is a product of a polynomial and a sine function. Therefore, a particular solution will have the form (At^2 + Bt + C)cos t + (Dt^2 + Et + F)sin t, where A, B, C, D, E, and F are undetermined coefficients.

32. The nonhomogeneous term is 2t^2 e^(-3t), which is a product of a polynomial and an exponential function. Therefore, a particular solution will have the form (At^2 + Bt + C)e^(-3t), where A, B, and C are undetermined coefficients.

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Answer:

27.5%

Step-by-step explanation:

Let's denote the total marks of the exam as 'T'.

We know that Tarang got 25% marks and failed by 64 marks, so we can write an equation:

0.25T - 64 = 0 (since he failed)

Solving for T, we get:

T = 256

We also know that if Tarang had got 40% marks, he would have secured 32 marks more than the pass marks. So we can write another equation:

0.4T - Pass marks = 32

Substituting T = 256, we get:

0.4(256) - Pass marks = 32

102.4 - Pass marks = 32

Pass marks = 70.4

Therefore, to pass the exam, Tarang needs to get at least 70.4/T * 100% = 27.5% marks (rounded to one decimal place).

a. This statement is true. We can write b = ak and d = cl for some integers k and l. Then, b + d = ak + cl = a(k + l). Since a|b, we know a must divide ak and thus a also divides ak + cl. Therefore, a + d = a(k + l) is divisible by a.

b. This statement is also true. Similar to part a, we can write b = ak and d = cl for some integers k and l. Then, bd = akcl = (ac)(kl). Since a|b and c|d, we know that a and c must divide ak and cl respectively. Therefore, ac must divide akcl = bd.

c. This statement is false. Consider a = 2, b = 4, c = 2, and d = 6. We have a|b and b|c, but a does not divide c. Therefore, the statement does not hold for all integers a, b, c, and d.

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a. This statement is true. We can write b = ak and d = cl for some integers k and l. Then, b + d = ak + cl = a(k + l). Since a|b, we know a must divide ak and thus a also divides ak + cl. Therefore, a + d = a(k + l) is divisible by a.

b. This statement is also true. Similar to part a, we can write b = ak and d = cl for some integers k and l. Then, bd = akcl = (ac)(kl). Since a|b and c|d, we know that a and c must divide ak and cl respectively. Therefore, ac must divide akcl = bd.

c. This statement is false. Consider a = 2, b = 4, c = 2, and d = 6. We have a|b and b|c, but a does not divide c. Therefore, the statement does not hold for all integers a, b, c, and d.

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Answer:

The answer for x is 37° to the nearest whole number

Answer:

the answer of X is 37° to the nearest whole number

Answer:

B- nearly symmetrical

Step-by-step explanation:

it’s not perfect, and it’s not skewed in either direction so it leaves b, nearly symmetry

The smallest possible value of nullity(a) is 0, and the largest possible value of nullity(a) is 4. To determine the minimum and maximum possible values of nullity(a) for a 7 × 4 matrix, we need to consider the properties of a matrix and nullity.

Nullity(a) is defined as the dimension of the null space of the matrix 'a'. It is also equal to the number of linearly independent columns in the matrix that are not part of its column space.
Since the matrix is a 7 × 4 matrix, it has 4 columns. The rank-nullity theorem states that:
rank(a) + nullity(a) = number of columns in matrix 'a'
The minimum possible value of nullity(a) occurs when all columns are linearly independent, which would mean the rank of the matrix is at its maximum value. In this case, the maximum rank of a 7 × 4 matrix is 4. So, the smallest possible value of nullity(a) is: nullity(a) = number of columns - rank(a)
nullity(a) = 4 - 4 = 0
The maximum possible value of nullity(a) occurs when the rank of the matrix is at its minimum value. In this case, the minimum rank of a 7 × 4 matrix is 0. So, the largest possible value of nullity(a) is: nullity(a) = number of columns - rank(a)
nullity(a) = 4 - 0 = 4
To summarize, the smallest possible value of nullity(a) is 0, and the largest possible value of nullity(a) is 4.

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The dimension of the solution space is 2. Therefore, the answer is (B) 2.

The rank of a matrix A is defined as the maximum number of linearly independent rows or columns in A.

Therefore, if the rank of a 7 x 6 matrix A is 4, it means that there are 4 linearly independent rows or columns in A, and the other 3 rows or columns can be expressed as linear combinations of the 4 independent ones.

The equation Az = 0 represents a homogeneous system of linear equations, where z is a column vector of unknowns.

The dimension of the solution space of this system is equal to the number of unknowns minus the rank of the coefficient matrix A.

In this case, A has 6 columns and rank 4, so the number of unknowns is 6 and the dimension of the solution space is 6 - 4 = 2. Therefore, the answer is (B) 2.

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[tex]\begin{cases} (x-1)^2-(x+2)^2=9y\\\\ (y-3)^2-(y+2)^2=5x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ (x-1)^2-(x+2)^2=9y\implies (x^2-2x+1)-(x^2+4x+4)=9y \\\\\\ (x^2-2x+1)-x^2-4x-4=9y\implies -6x-3=9y\implies -3(2x+1)=9y \\\\\\ 2x+1=\cfrac{9y}{-3}\implies 2x+1=-3y\implies 2x=-3y-1\implies x=\cfrac{-3y-1}{2} \\\\[-0.35em] ~\dotfill\\\\ (y-3)^2-(y+2)^2=5x\implies (y^2-6y+9)-(y^2+4y+4)=5x \\\\\\ (y^2-6y+9)-y^2-4y-4=5x\implies -10y+5=5x[/tex]

[tex]\stackrel{\textit{substituting from above}}{-10y+5=5\left( \cfrac{-3y-1}{2} \right)}\implies -10y+5=\cfrac{-15y-5}{2} \\\\\\ -20y+10=-15y-5\implies 10=5y-5\implies 15=5y \\\\\\ \cfrac{15}{5}=y\implies \boxed{3=y} \\\\\\ \stackrel{\textit{since we know that}}{x=\cfrac{-3y-1}{2}}\implies x=\cfrac{-3(3)-1}{2}\implies \boxed{x=-5}[/tex]