Determine the volume (in mL) of water that needs to be added to 50.0 mL of a 0.600 M LiBr to produce a 0.145 M solution. Assume the volumes are additive.

Answers

Answer 1

The components MaVa=MbVb is utilized in this

dilution problem. The preliminary 50.00 mL

answer desires to be diluted from 0.six hundred M to 0.145 M through the addition of 0.597 mL.

The components MaVa-MbVb is used

Ma = 0.6M

V_ = 50ml

Mb = 0.145M

Vb = (50 + Xml)

MaVa = MbVb

(0.six hundred)(50.00)=(0.one hundred forty five)(50.00+X)

30 - 0.one hundred forty five = (50 + x)

29.85/50 = X

X = 0.597 ml.

Dilution has no impact at the solute attention in an answer. The moles of the solute do now no longer alternate while a solvent is introduced to an answer, however the attention of the answer (in molarity and in all different units) and its quantity do. Taking an answer of better attention and step by step including water till the favored attention is acquired is an average approach for growing an answer of a particular attention. This method is called.

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Related Questions


A carbon atom has a relative atomic mass of
13.3. 60% of the carbon atom has a mass
number of 12.7, 30% of the carbon atom has a
mass number of 13.6, whilst the remaining 10%
has a mass number which is not known.
Calculate the mass number of the carbon isotope
which is 10% of the Carbon 13.3 atom.
Give your answer to 1 decimal place.

Answers

According to the claim, the carbon isotope that is 10% of something like the carbon 13.3 molecule has a mass number of 15.1.

Where can you find carbon?

The majority of carbon is kept in reservoirs, or sources, such rocks and sediments; the remaining portion is kept in the atmosphere, the seas, and living things. Through the respiration of both and animals, carbon is returned to the atmosphere. Burning things like wood, oil, and gas also releases it.

Briefing:

Since all carbon isotopes have an equal atomic mass of 13.3,

(0.60 * 13.3) + (0.3 * 12.7) + (0.1 * x) = 13.3

11.79 + 0.1x = 13.3

x = 15.1

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How to recover Aluminum from brass through melting

Answers

Answer:

you can do so by pouring it into a vibrating seperator

Calculate the percent composition of H3PO4

Answers

The percent composition of hydrogen, phosphorous and oxygen in phosphoric acid is 3.06 %,31.60%,65.31 % respectively.

What is percent composition?

Percent composition is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage composition percent weight by volume and percent volume by volume .

Percent composition of hydrogen=3/97.99×100=3.06%.

Percent composition of phosphorous=30.97/97.99×100=31.60%

Percent composition of oxygen=64/97.99×100=65.31%

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