Determine whether the rational root theorem provides a complete list of all roots for the following
polynomial functions.
f(x) = 4x^2 - 25
g(x) = 4x^2 + 25
h(x) = 3x^2 - 25

Answer:

1) Yes

2) No, this polynomial has complex roots

3) No, this polynomial has irrational roots

Step-by-step explanation:

a. Rational roots theorem provide a complete list of all roots of

f (x) = 4x² - 25

b. Rational roots theorem does not provide a complete list of all roots of

g (x) = 4x² + 25

c. Rational roots theorem does not provide a complete list of all roots of

h (x) = 3x² - 25

What is Function?

A relation between a set of inputs having one output each is called a function.

Functions are given as;

f (x) = 4x² - 25

g (x) = 4x² + 25

h (x) = 3x² - 25

Now,

a. f (x) = 4x² - 25

To find the roots we can set up 0,

f (x) = 4x² - 25 = 0

4x² - 25 = 0

4x² = 25

Divide by 4,

x² = 25/4

Take square root both side,

x = √25/4

x = ±5/2

Thus, The function has rational roots.

So, Rational roots theorem provide a complete list of all roots.

b) g (x) = 4x² + 25

To find the roots we can set up 0,

4x² + 25 = 0

4x² = - 25

Divide by 4,

x² = - 25/4

Taking square root,

x = √-25/4

x = ±5i/2

Thus, The function has complex roots.

So, Rational roots theorem does not provide a complete list of all roots.

c) h (x) = 3x² - 25

To find the roots we can set up 0,

3x² - 25 = 0

3x² = 25

Divide by 3,

x² = 25/3

x² = 8.333

Take square root both sides,

x = √8.333

x = ±2.89

Thus, The function has irrational roots.

So, Rational roots theorem does not provide a complete list of all roots.

Therefore,

a. Rational roots theorem provide a complete list of all roots of

f (x) = 4x² - 25

b. Rational roots theorem does not provide a complete list of all roots of

g (x) = 4x² + 25

c. Rational roots theorem does not provide a complete list of all roots of

h (x) = 3x² - 25

Learn more about the rational root theorem visit:

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