Boron has five protons and six neutrons. What is the atomic mass of boron?
A. 11
B. 10
C. 12
D. 1
Answer:
11
Explanation:
becauase 5 +6
What is predicted to happen if the permafrost in the Arctic melts?
Answer: It is causing erosion, landslides, and craters. If this keeps up the ice in the artic will eventually be gone
Explanation:
what is the atomic mass of an element with 40 protons 40 electrons and 46 neutrons
Answer:
The 40 represents the atomic number and the number of proton in Zirconium. The "Zr" on the tile is the symbol of the elementp
If a solution has a concentration of 3.2x10-3 [OH-] what is the pOH of the solution?
Answer:
The solution with [OH-] = 3.2x10-3 M will have an [H+] of 3.09x10–12 M.Explanation:
decay mode for cesium-137
Answer:
Beta decay
Explanation:
Radioactive decay changes one nucleus to another. The type of decay that a particular nucleus undergoes depends on the number of neutrons and protons present in such nucleus.
Radioactive decay tends to lead to the attainment of a stable neutron/proton ratio.
The decay mode for cesium-137 is beta decay. The beta decay of cesium-137 yields Barium-137.
Beta decay decreases the neutron - proton ratio.
List five general properties of organic
Compound
Answer:
Five general properties of organic compounds:
Organic compounds include complex structures and high molecular weights.Organic compounds have low melting points and boiling points. They are volatile in nature. They are generally insoluble in water but soluble in organic solvents. They are poor bad conductors of electricity.Calculate the number of grams of Fe and the number of grams of Coz formed
when 0.150 kg of Fe2O3 reacts.
Answers to other questions on the sheet are appreciated!
does anyone know this??
Answer: C2H6O
Explanation: It is C2H6O with a molar mass of 46.07 g/mol.
Explain why this combination of compounds can or cannot make a buffer solution. Hint: apply definition of a buffer, mechanism of its action and consider whether the compound is acid (weak/strong) or base (weak/strong). HF (0.2 mol) and NaOH (0.1 mol)
Answer:
This combination can make a buffer
Explanation:
A buffer is defined as an aqueous mixture of a weak acid and its conjugate base, or vice versa.
In the problem, HF is a weak acid, and its conjugate base is F⁻.
When NaOH reacts with HF, F⁻, Na⁺ and H₂O are produced as follows:
NaOH + HF → F⁻ + Na⁺ + H₂O
As there are initially 0.2mol of HF and 0.1mol NaOH, after the reaction you will have:
0.1mol HF and 0.1mol F⁻. As both, the weak acic and the conjugate base are present:
This combination can make a bufferdoes the nitro group on the pyridine ring make the ring more electron rich or more electron deficient
Answer:
more electron deficient
Explanation:
The nitro group is an electron withdrawing group. It withdraws electrons from the pyridine ring by resonance.
This electron withdrawal by resonance makes the pyridine ring less electron rich or more electron deficient.
Hence, the nitro group makes the pyrinde ring more electron deficient
8. What was the original concentration in the BHL sample, if the dilution is 1:500 and the concentration 0.07 mg/ml
Answer:
The original concentration is "35 mg/ml".
Explanation:
According to the question,
The solution is diluted,
= 1:50
The initial volume,
V1 = 1 ml
Final concentration,
= 0.07 mg
then,
The final volume,
V2 = 500 ml
As we know,
⇒ [tex]V_1N_1=V_2N_2[/tex]
or,
⇒ [tex]N_1=\frac{V_2N_2}{V_1}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{500\times 0.07}{1}[/tex]
⇒ [tex]=\frac{35}{1}[/tex]
⇒ [tex]=35 \ mg/ml[/tex]
A 0.07 mg/mL BHL solution was prepared by performing a 1:500 dilution on a 35 mg/mL solution.
A 1:500 dilution was carried out to prepare a 0.07 mg/mL BHL solution. We can find the concentration of the initial solution using the dilution rule.
What is the dilution rule?It is an equation that relates the concentration and volume of a concentrated and a dilute solution. The mathematical expression is:
C₁ × V₁ = C₂ × V₂
where,
C₁ is the concentration of the concentrated solution.V₁ is the volume of the concentrated solution.C₂ is the concentration of the dilute solution.V₂ is the volume of the dilute solution.C₁ = C₂ × (V₂/V₁)
C₁ = 0.07 mg/mL × (500/1) = 35 mg/mL
A 0.07 mg/mL BHL solution was prepared by performing a 1:500 dilution on a 35 mg/mL solution.
Learn more about dilution here: https://brainly.com/question/1615979
Pick the correct statement about the pure water. Group of answer choices Pure water contains no ions. Pure water contains equal amounts of hydroxide [OH-] and hydronium [H3O ] ions. Pure water contains larger amounts of hydroxide [OH-] than hydronium [H3O ] ions. Pure water is an electrolyte. Pure water contains smaller amounts of hydroxide [OH-] than hydronium [H3O ] ions.
Answer:
Pure water contains no ions. TRUE
Pure water contains equal amounts of hydroxide [OH-] and hydronium [H3O+ ] ions. TRUE
Explanation:
This is the equilibrium for pure water:
2H₂O ⇄ H₃O⁺ + OH⁻ Kw
We see that pure water has no Ions. Pure water can not conduct electricity.
Generally ionized water comes from the water tap.
Another feature of pure water is pH.
Definetely pH of pure water is : 7
As pH = 7, [H₃O⁺] = 1×10⁻⁷
Then, [OH⁻] = 1×10⁻⁷
This is reazonable because Kw is 1×10⁻¹⁴ and Kw = [H₃O⁺] . [OH⁻]
In conclussion:
Pure water contains no ions. TRUE
Pure water contains equal amounts of hydroxide [OH-] and hydronium [H3O+ ] ions. TRUE
Pure water contains larger amounts of hydroxide [OH-] than hydronium [H3O+] ions. FALSE
Pure water is an electrolyte. FALSE
Pure water contains smaller amounts of hydroxide [OH-] than hydronium [H3O ] ions. FALSE
I dont understand this
Answer:
me too
Explanation:
200 grams of iron (III) chloride reacts with ammonium carbonate [(NH4)2CO3] in the following equation.
FeCl3 + (NH4)2CO3 ---------> NH4Cl + Fe2(CO3)3
The number of grams of iron (III) carbonate Fe2(CO3)3 that will be produced is _ grams.
a
181
b
198
c
229
d
395
Answer. First things first... Balance the Chemical Equation
2FeCl3 + 3(NH4)2CO3 ---------> 6NH4Cl + Fe2(CO3)3
Its balanced Now.
200g of FeCl3 ---Given this... We can get jts reacting Moles
Mole = Mass/Molar Mass
Molar Mass of FeCl3 = 56 + (35.5)x3=162.5gmol-¹
Mole=200/162.5 =1.231moles of FeCl3
From the equation of Reaction
When 2mole of FeCl3 reacts.... It produces 1mole of Iron III carbonate [Fe2(CO3)3]
Since Mole ratio of reaction between both is 2:1
Therefore When 1.231moles of FeCl3 react....
1.231/2 moles of Fe2(CO3)3 will be produced.
= 1.231/2 = 0.616moles.
0.616Moles of Fe2(CO3)3 will be produced
Recall MASS =MOLE X MOLAR MASS
MOLAR MASS OF FE2(CO3)3= 56(2) + (60)(3)=292gmol-¹
MASS = 0.616 x 292 =179.872g ~ 180g of Fe2(CO3)3 Will Be Produced.
OPTION A SEEMS TO BE THE CLOSEST. THAT SHOULD BE OUR ANSWER. I MAY HAVE MISSED IT A BIT BECAUSE OF SOME APPROXIMATIONS.
BYE!
Answer:
[tex]FeCl₃ + (NH₄)₂CO₃ → NH₄Cl + Fe₂(CO₃)₃[/tex]
first balance the chemical equation
first balance the chemical equation[tex]2FeCl₃ + 3(NH₄)₂CO₃ → 6NH₄Cl + Fe₂(CO₃)₃[/tex]
2FeCl₃=2*162=324g
6NH₄Cl=6*53.5=321g
324 g of FeCl₃ gives 321 g of NH₄Cl
200g of FeCl₃ gives 321/324*200=198.14 g of NH₄Cl
in nearest value it is 198g/mole
The number of grams of ammonium chloride (NH4Cl) that will be produced is C.198___ grams.
how many moles of Carbon are in 3.06 g of Carbon
Answer:
[tex]\boxed {\boxed {\sf 0.255 \ mol \ C }}[/tex]
Explanation:
If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
Look up the molar mass of carbon.
Carbon (C): 12.011 g/molSet up a ratio using the molar mass.
[tex]\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Since we are converting 3.06 grams to moles, we multiply by that value.
[tex]3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.
[tex]3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}[/tex]
[tex]3.06 * \frac{1 \ mol \ C}{12.011 }[/tex]
[tex]\frac {3.06}{12.011 } \ mol \ C[/tex]
[tex]0.25476646 \ mol \ C[/tex]
The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
0.25476646The 7 in the ten-thousandth place tells us to round the 4 up to a 5.
[tex]0.255 \ mol \ C[/tex]
3.06 grams of carbon is approximately 0.255 moles of carbon.
How many moles of solute are in a 1.50 M solution of HCl with a volume of 7.98 liters?
Answer:
[tex]\boxed {\boxed {\sf x\approx 12.0 \ moles \ HCl}}[/tex]
Explanation:
Molarity is a measure of concentration in moles per liter.
[tex]molarity= \frac{moles \ of \ solute}{liters \ of solution}[/tex]
We know the solution has a volume of 7.98 liters and it has a molarity of 1.50 M HCl.
1 molar (M) is 1 mole per liter, so the molarity is also 1.50 moles of HCl per liter.We know 2 values for the variables, but the value for moles of solute is unknown, so we use x.
molarity= 1.50 mol HCl/L moles of solute=xliters of solution = 7.98 LSubstitute the values into the formula.
[tex]1.50 \ mol \ HCl/L=\frac{x}{7.98 \ L}[/tex]
We are trying to solve for x, the moles of solute, so we must isolate the variable. It is being divided by 7.98 liters and the inverse of division is multiplication. Multiply both sides of the equation by 7.98 liters.
[tex]7.98 \ L *1.50 \ mol \ HCl/L=\frac{x}{7.98 \ L} * 7.98 \ L[/tex]
[tex]7.98 \ L *1.50 \ mol \ HCl/L=x[/tex]
The units of liters (L) cancel each other out.
[tex]7.98 *1.50 \ mol \ HCl=x[/tex]
[tex]11.97 \ mol \ HCl=x[/tex]
The original measurements of molarity and volume both have 3 significant figures, so our answer must have the same. For the number we found, that is the tenths place.
The 9 in the hundredth place tells us to round the 1 to a 2. We leave a 0 in the tenths place to ensure there are 3 significant figures.
[tex]12.0 \ mol \ HCl \approx x[/tex]
There are approximately 12.0 moles of solute in the solution.
What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat is evolved?
Answer:
The correct answer is 1.21 L.
Explanation:
Based on the given information, the reaction will be,
CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)
By using the standard values of the substances, the standard enthalpy of the reaction is,
ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol
= -285.3 kJ/mol
The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.
Now the number of moles of chlorine needed to react to produce 5.00 kJ is,
= 5.00 kJ × 3 mol Cl2/285.3 kJ
= 0.0526 mol Cl2
Now the volume of chlorine gas at 27degree C and 812 mmHg will be,
Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm
= 1.21 L
he correct statements about thermal conductivity are: A. The thermal conductivity of metals is generally higher than that of liquids. B. The thermal conductivity of solids is generally higher than that of liquids. C. The thermal conductivity of gases is generally higher than that of liquids.
Answer: The correct statements about thermal conductivity are:
The thermal conductivity of metals is generally higher than that of liquids.The thermal conductivity of solids is generally higher than that of liquids.Explanation:
The rate at which transfer of heat takes place from one object to another by conduction over a unit cross section area of a material is called thermal conductivity.
Hence, more is the distance between atoms of a substance less will be its thermal conductivity. This is because more is the space between molecules of a substance more will be their random motion due to which there will be less effective energy transport.
The thermal conductivity of metals is very high than liquids.
Also, the thermal conductivity of solids is generally higher than that of liquids.
As gases have more space between its molecules so they have less thermal conductivity.
Thus, we can conclude that the correct statements about thermal conductivity are:
The thermal conductivity of metals is generally higher than that of liquids.The thermal conductivity of solids is generally higher than that of liquids.How many moles of SO2 will be produced from 11.5 moles of O2?
Explanation:
Respuesta: La masa atómica del carbono (C) es 12 g/mol; para el oxígeno (O) es de 16 g/mol. Esto significa que 6.022 x 1023 átomos de carbono pesan 12 gramos. Según esto, el peso molecular del CO2 es: 12 g/mol [C] + 2 x 16 g/mol [O2] = 44 g/mol
Which of the following mixtures will react the fastest?
a. Iron DUST and 2 moles HCI
b. Iron DUST and 4 moles HCI
c. Solid Iron CUBE and 2 moles HCI
d. Solid Iron CUBE and 4 moles HCI
Answer:
I think the answer would be A.
ok so i need a reasoning on What evidence have you discovered to explain how the curve of Earth’s surface affects temperatures on Earth?
How many dots are drawn in a Lewis dot structure for elements in group 2 of the periodic table?
1 becasuevof one vvalence shell
A 15.67 g sample of a hydrate of magnesium carbonate was heated, without decomposing the carbonate, to drive off the water. The mass was reduced to 7.58 g. What is the name of the hydrate
Answer:
The correct answer is MgCO₃.5H₂O.
Explanation:
Based on the given information,
The mass of hydrate of magnesium carbonate given is 15.67 grams, and the mass of anhydrous magnesium carbonate given is 7.58 grams.
Now the mass of water will be,
= 15.67 grams – 7.58 grams
= 8.09 grams
The molecular mass of magnesium carbonate is 84.32 grams, the moles of MgCO₃ can be determined by using the formula,
Number of moles = Mass/Molecular mass
Moles of MgCO₃ = 7.58/84.32
= 0.0898 moles
Similarly, the number of moles of water will be,
Moles of H₂O = 8.099/18.02
= 0.4489 moles
After getting the values, there is a need to choose the smaller value and use it to divide both the values to get the ratio,
MgCO₃ = 0.0898/0.0898 = 1
H₂O = 0.4489/0.0898 = 4.9 or 5
Thus, the molecular formula for the hydrate will be MgCO₃.5H₂O.
Why Phenol is acidic in nature but benzene is not acidic in nature?
NO LINKS PLEASE
1. What are the reactants at the start of this chemical reaction? What do you start with?
2. What are the products at the end of this chemical reaction? What do you end with?
3. If the total mass of the reactants equals 150 grams, what would the total mass of the
products be?
Answer:
1.The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products
2.The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products
3.The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. For example, the mass of sodium plus the mass of chlorine that reacts with the sodium equals the mass of the product sodium chloride.
please answer all three of these questions
Answer:
I think it's 1.D
2.C
3.C
my apologies if it's incorrect
Given the reaction: N2 + O2 = 2NO for which the Keq at 2273 K is 1.2 x 10-4
a. Write the equilibrium constant expression for the reaction.
b. Write the equation that would allow you solve for the concentration of NO.
c. What is the concentration of NO if [NZ] = 0.166M and [02] = 0.145M?
Answer:
(a): The expression of equilibrium constant is [tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b): The equation to solve the concentration of NO is [tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex]
(c): The concentration of NO is 0.0017 M.
Explanation:
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term [tex]K_{eq}[/tex]
(a):
The given chemical equation follows:
[tex]N_2+O_2\rightarrow 2NO[/tex]
The expression for equilbrium constant will be:
[tex]K_{eq}=\frac{[NO]^2}{[N_2][O_2]}[/tex]
(b):
The equation to solve the concentration of NO follows:
[tex][NO]=\sqrt{K_{eq}\times [N_2]\times [O_2]}[/tex] ......(1)
(c):
Given values:
[tex]K_{eq}=1.2\times 10^{-4}[/tex]
[tex][N_2]_{eq}=0.166M[/tex]
[tex][O_2]_{eq}=0.145M[/tex]
Plugging values in equation 1, we get:
[tex][NO]=\sqrt{(1.2\times 10^{-4})\times 0.166\times 0.145}[/tex]
[tex][NO]=\sqrt{2.88\times 10^{-6}}[/tex]
[tex][NO]=0.0017 M[/tex]
Hence, the concentration of NO is 0.0017 M.
BRAINISEST & 10 POINTS
Answer:
In order from left to right, 7 (gamma), 5 (ultraviolet, now continue pattern), 4, 6, 2, 3, 1.
C. Balance these fossil-fuel combustion reactions. (1 point)
The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
In the laboratory a student finds that it takes 103 Joules to increase the temperature of 12.6 grams of solid diamond from 22.4 to 39.4 degrees Celsius. The specific heat of diamond calculated from her data is
Answer:
The correct solution is "[tex]0.480 \ J/g^{\circ}C[/tex]".
Explanation:
Given:
q = 103 J
Mass,
m = 12.6 grams
Temperature,
[tex]T_1=22.4[/tex]
[tex]T_2=39.4[/tex]
[tex]\Delta T=T_2-T_1[/tex]
[tex]=39.4-22.4[/tex]
[tex]=17^{\circ}C[/tex]
Now,
⇒ [tex]C=\frac{q}{m\times \Delta T}[/tex]
⇒ [tex]=\frac{103}{12.6\times 17}[/tex]
⇒ [tex]=\frac{103}{214.2}[/tex]
⇒ [tex]=0.480 \ J/g^{\circ}C[/tex]