Do only number 5 and thank

Answer:

cell membrane.

Explanation:

A cell can be defined as the fundamental or basic functional, structural and smallest unit of life for all living organisms. Some living organisms are unicellular while others are multicellular in nature.

A unicellular organism refers to a living organism that possess a single-cell while a multicellular organism has many (multiple) cells.

Generally, cells have the ability to independently replicate themselves. In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles. Some examples of cell organelles found in all living organisms such as trees, birds, and bacteria include; nucleus, cytoplasm, cell membrane, golgi apparatus, mitochondria, lysosomes, ribosomes, chromosomes, endoplasmic reticulum, vesicles, etc.

Cell membrane is the wall of a cell in living organisms and it typically functions as a door and window in a house by controlling what leaves and enters the cell at any given time. Also, the cell membrane opens selectively and as such it would only open at certain times and to certain chemical changes or signals.

This ultimately implies that, the part of an animal cell that is like the doors and windows in Martha's house is the cell membrane.

Answer:

give the guy above brainlist

he did a very good job.

Explanation:

Answer:

Option 1 is endothermic

Option 2 is exothermic

Explanation:

In Chemistry, Exothermic reactions are reactions whereby heat energy is transferred to the surroundings and the temperature of the surroundings increases. Endothermic reactions are those whereby heat energy from the surroundings is absorbed and thereby making the temperature of the surroundings to decrease.

This means in simple terms that endothermic reactions will have heat on the reaction side of the equation while exothermic will have heat on the product side of the equation.

Thus;

Option 1 is endothermic since it has heat absorbed on the reactant side.

Option 2 is exothermic since it gives off heat on the product side.

Answer:

a) Metres (m)

b) Kilogram (kg)

c) litres (l)

Answer:

B. When the independent variable composed of categories and does not show a relationship to the dependent variable

Explanation:

A bar graph, is a graph used for presenting data grouped into categories, which are the independent variables of the graph, and the measurement of each category, which are represented as rectangular bars having lengths proportional to the value of the category, on a chart

In the bar graph or chart, there is no direct relationship between the categories, which are the x-values and the dependent variables , which are the length of the bars, the y-values, as the length of the rectangular bar in one category, cannot be obtained from another category through a relationship

Therefore, the correct option is option is when the independent variable composed of categories and does not show a relationship to the dependent variable

Answer:

The correct answer is "20 Volts".

Explanation:

Given:

Heat,

H = 100 J

Resistance,

R = 4 Ω

As we know,

⇒ [tex]P=\frac{v^2}{R}[/tex]

By putting the values, we get

⇒ [tex]100=\frac{v^2}{4}[/tex]

⇒  [tex]v^2=100\times 4[/tex]

⇒       [tex]=400[/tex]

⇒    [tex]v=\sqrt{400}[/tex]

⇒       [tex]=20 \ volts[/tex]

Answer:

5.2 amps

Explanation:

V = I*R

I = V/R

I = 220/42

I = 5.2 amps

Answer:

5.2

Explanation:

because

[tex]i \frac{v}{r} [/tex]

220÷42=5.23

Answer:

Explanation:

Answer:

A

Explanation:

Answer:

C. 157 bar/2270 psi

Explanation:

Calculation to determine what we should head back when either of our SPGs read

SPGs=200 bar -[200 bar-(50 bar + 20 bar)]÷1/3]

SPGs=200 bar-[(200 bar-70 bar)÷1/3]

SPGs=200 bar-(130 bar÷1/3)

SPGs=200 bar-43 bar

SPGs=157 bar/2270 psi

Therefore based on the above calculation we should head back when either of our SPGs read 157 bar/2270 psi

Answer:

5.76 m/s

Explanation:

Applying,

S = d/t............... Equation 1

Where S = speed, d = distance, t = time.

For circular motion,

d = 2πr............ Equation 2

Where r = radius of the circular track, π = pie

Substitute equation 2 into equation 1

S = 2πr/t.............. Equation 3

From the question,

Given: r = 110 m, t = 2 minutes = (2×60) = 120 s

Constant: π = 3.14

Substitute these values into equation 3

S = (2×3.14×110/120)

S = 690.8/120

S = 5.76 m/s

Answer:

Explanation:

You didn't fill in the proper masses which is why you never got an answer to this. But that's ok...I got you. I happen to know what they are! We will use the universal law of gravitation and the gravitational constant to solve this.

[tex]F_g=\frac{Gm_1m_2}{r^2}[/tex] and filling in:

[tex]F_g=\frac{(6.67*10^{-11})(5.98*10^{24})(7.36*10^{22})}{(3.84*10^8)^2}[/tex] The denominator is the radius of the earth plus the radius of the moon plus the distance between their surfaces, just FYI.

That gives us that

[tex]F_g=1.99*10^{20}N[/tex] Not sure what your choices entail, but I'd have to say, taking into consideration that maybe your problem didn't figure in the distance between the surfaces, you'd be at choice B.

Answer:

The answer is A. A transistor

Answer:

a transistor

Explanation:

A P E X

Answer:

HOPE IT HEPLED U !!!!

Explanation:

i think it's (C) They have different units ....

Answer:

The ratio of the amplitudes of siren to dishwasher is 10.

Explanation:

loudness of dishwasher = 40 dB

loudness of siren = 60 dB

let the intensity of dishwasher is I an the intensity of siren is I'.

Use the formula of intensity and decibels.

[tex]dB = 10 log\frac{I}{I_o}\\\\40=10 log\frac{I}{I_o}\\\\4 = log\frac{I}{I_o}\\\\I = 10000 I_o[/tex]

And

[tex]60=10 log\frac{I'}{I_o}\\\\60 = log\frac{I'}{I_o}\\\\I' = 1000000 I_o[/tex]

The intensity if proportional to the amplitude.

[tex]\frac{A'}{A}=\sqrt\frac{1000000}{10000}\\\\\frac{A'}{A}= 10[/tex]

Answer:

Length is the unit of metre

Answer:

From the meter, several other units of measure are derived such as the: unit of speed is the meter per second (m/s).

...

Units of Length

10 millimeters (mm) = 1 centimeter (cm)

10 decimeters = 1 meter (m)

10 decimeters = 1000 millimeters

10 meters = 1 dekameter (dam)

Answer:

Explanation:

We need the power equation here, which is:

Power = (F * Δx)/time

where F * Δx is the amount of work done.

F is a force which is measured in Newtons. We are given the mass of the object, but since we need a Force measure, we need the weight of the object:

F = 2100(9.0)

F = 21000 to the correct number of sig dig.

Now we can plug in the values we have and solve for the displacement, Δx:

[tex]45000=\frac{21000x}{17.4}[/tex] and isolating x:

[tex]\frac{17.4(45000)}{21000}=x[/tex] so

x = 37 m

Answer:

Magnitude = 8.6

Angle = 324.5 degree from + X axis in counter clock  wise direction.

Explanation:

X component of B, Bx = 7

Y component of B, By = - 5

The magnitude of the resultant is  

[tex]B =\sqrt{7^{2}+(-5)^2}\\\\B =\sqrt{49+ 25}\\\\B = 8.6[/tex]

The angle is given by

[tex]tan\theta=\frac{By}{Bx}\\\\tan\theta = \frac {-5}{7}\\\\\theta = 324.5^{o}[/tex]

Answer:

Looks like its c 2x 10 m

Explanation:

i do see the question

Answer:

B . Kinetic energy increases and potential energy decreases when the velocity of an object increases.

Explanation:

The statement with best compares potential energy and kinetic energy is that only kinetic energy increases when the velocity of the object increases.

Explanation:

distance = velocity * time

d = 37.9 * 118

distance = 4472.2

0.5Ω

Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.

Using Ohm's law, the voltage across a resistor in a circuit is given by;

V = I(R + r)            -----------(i)

For the 1ohm resistor, the voltage across it is given by;

Where;

I = current passing through the 1 ohm resistor = 0.6A

R = resistance of the 1 ohm resistor = 1Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.6(1 + r)                 -------------------(ii)

For the 4.0ohm resistor, the voltage across it is given by;

Where;

I = current passing through the 4.0 ohms resistor = 0.2A

R = resistance of the 4.0 ohms resistor = 4.0Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.2(4.0 + r)                 -------------------(iii)

Now solve equations (ii) and (iii) simultaneously;

V = 0.6(1 + r)

V = 0.2(4.0 + r)

Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;

0.6(1 + r) = 0.2(4.0 + r)

Solve for r

0.6 + 0.6r = 0.8 + 0.2r

0.6r - 0.2r = 0.8 - 0.6

0.4r = 0.2

r = [tex]\frac{0.2}{0.4}[/tex]

r = 0.5

Therefore, the internal resistance of the cell is 0.5Ω

Answer:

The correct option is: (A) Both R 1 and R 2 are greater than 5 Ω. Explanation: The equivalent resistance in parallel is smaller than the smallest resistance.

Explanation:

hopefully it helps- ^^

Answer:

Quantity of charge = 0.8 Coulombs

Explanation:

Given the following data;

Current = 0.4 A

Time = 2 seconds

To find the quantity of electricity transferred;

Mathematically, the quantity of electricity (charge) passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 0.4 * 2

Quantity of charge = 0.8 Coulombs

Answer:

 ΔT = [tex]\pi \ \frac{\Delta L}{\sqrt{Lg} }[/tex]

Explanation:

In a simple harmonic motion, specifically in the simple pendulum, the angular velocity

          w = [tex]\sqrt{\frac{g}{L} }[/tex]

angular velocity and period are related

          w = 2π / T

we substitute

          2π / T = \sqrt{\frac{g}{L} }

          T = [tex]2\pi \ \sqrt{\frac{L}{g} }[/tex]

In this exercise indicate that for a long Lo the period is To, then and increase the long

          L = L₀ + ΔL

we substitute

           T = [tex]2\pi \ \sqrt{\frac{L + \Delta L}{g} }[/tex]

            T = [tex]2\pi \ \sqrt{\frac{L}{g} } \ \sqrt{1+ \frac{\Delta L}{L} }[/tex]

in general the length increments are small ΔL/L «1, let's use a series expansion

           [tex]\sqrt{1+ \ \frac{\Delta L}{L} } = 1 + \frac{1}{2} \frac{\Delta L}{L} + ...[/tex]  

we keep the linear term, let's substitute

           T = [tex]2\pi \ \sqrt{\frac{L}{g} } \ ( 1 + \frac{1}{2} \frac{\Delta L}{L} )[/tex]  

if we do

           T = T₀ + ΔT

           T₀ + ΔT = [tex]2\pi \sqrt{\frac{\Delta L}{g} } + \pi \ \sqrt{\frac{L}{g} } \ \frac{\Delta L}{L}[/tex]

            T₀ + ΔT = T₀ + [tex]\pi \sqrt{\frac{1}{Lg} } \ \Delta L[/tex]

            ΔT = [tex]\pi \ \frac{\Delta L}{\sqrt{Lg} }[/tex]

Answer:

To get to the door, the astronaut has to throw the book and pencil away from her in the direction opposite to that of the door.

Explanation:

Since no net force acts on her and she floats in the center of the room, if she throws the book and pencil away from her, since both her, the book and the pencil have an initial momentum p = 0, and since momentum is conserved, then after throwing the book and pencil away from her, the momentum of both her, the book and pencil is still zero.

The astronaut will thus develop a momentum which is opposite to that of the book and pencil. This is shown below.

Since p = p' where p = initial momentum of astronaut, book and pencil = 0 and p' = final momentum of astronaut, book and pencil = mv + m'v' where m = mass of book and pencil, v = velocity of book and pencil, m' = mass of astronaut and v' = velocity of astronaut.

So, p = p'

0 = mv + m'v'

mv = -m'v' where mv = momentum of book and pencil and m'v' = momentum of astronaut

v' = -mv/m

We see that the astronaut develops a momentum opposite in direction but equal in magnitude to that of the book and pencil and will thus develop a velocity opposite to that of the book and pencil.

Thus, to get to the door, the astronaut has to throw the book and pencil away from her in the direction opposite to that of the door.

Answer:

20 degrees

Explanation:

Because projectile has the same range on both angles which on summation gives 90 degrees as a total.

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L =  330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)  

Q = 672,000 J

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

Answer:

Ohm's law verifies that current directly varies with voltage, when resistance increases, current current decreases.

When temperature increases, the electrons gain more average kinetic energy increases and current increases as well.

In the same situation, resistance also increases because atoms of a component vibrate at higher amplitudes about their mean positions hence reducing the free path of electrons. This increases resistance, hence ohms law violated or disobeyed.

This generates the temperature coefficient of resistance