Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below:

Collecting Site Substrate Color Number of Mice Phenotype
Light Dark
1 Dark 22 3 19
2 Light 80 74 6
3 Light 22 19 3
4 Dark 28 3 25
5 Light 58 25 33
6 Dark 65 9 56


Required:
a. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates.
b. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates.
c. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

Answers

Answer 1

Complete question

Dr. Nachman and his colleagues collected rock pocket mice across 35 kilometers of the Arizona Sonoran Desert, which included both dark, rocky lava outcrops and light, rocky, granite areas. They recorded substrate color, and coat-color frequencies for each location. Each site was separated from any of the others by at least eight kilometers. The researchers trapped a total of 275 mice. Their data are summarized below (numbers have been slightly modified for the purposes of this worksheet).

Field Data Summary

Collecting Site Substrate Color Number of Mice Phenotype Light Dark

1 Dark 22 3 19

2 Light 80 74 6

3 Light 22 19 3

4 Dark 28 3 25

5 Light 58 25 33

6 Dark 65 9 56

1. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on light-colored substrates. [to 3 decimal places]

2. Calculate the overall frequencies of light-colored mice and dark-colored mice caught on dark-colored substrates. (to 3 decimal places)

3. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the light, rocky, granite substrate. For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

4. Using the Hardy-Weinberg equation and data from the table above, determine the frequency of the three genotypes on the dark, rocky lava substrate. (to 3 decimals). For genotype frequencies use three decimal places and for calculations using the allele frequencies, you must round the allele frequencies to two decimal places.

5. Which fur color seems to have the greatest overall selective advantage? Use data collected from both dark-colored and light- colored substrates to support your answer.

6.What environmental change gave a selective advantage for one coat color over another?

7. In a separate study, 76 rock pocket mice were collected from four different, widely separated areas of dark lava rock. One collecting site was in Arizona. The other three were in New Mexico. Dr. Nachman and colleagues observed no significant differences in the color of the rocks in the four locations sampled. However, the dark-colored mice from the three New Mexico locations were slightly darker than the dark-colored mice from the Arizona population. The entire Mc1r gene was sequenced in all 76 of the mice collected. The mutations responsible for the dark fur color in the Arizona mice were absent from the three different populations of New Mexico mice. No Mc1r mutations were associated with dark fur color in the New Mexico populations. These findings suggest that adaptive dark coloration has occurred at least twice in the rock pocket mouse and that these similar phenotypic changes have different genetic bases. How does this study support the concept that natural selection is not random?

8. To determine if the rock pocket mouse population is evolving, explain why it is necessary to collect fur color frequency data over a period of many years.

Answer:

1)

frequencies of light-colored mice  ≅ 0.74 frequencies of dark-colored mice  ≅ 0.26

2)

frequencies of light-colored mice ≅ 0.13 frequencies of dark-colored mice ≅ 0.87

3)

p² ≅ 0.02 q² ≅ 0.74 2pq ≅ 0.24

4)

q² = 0.13 p² = 0.4 2pq = 0.46

5) The dark-colored fur seems to have the greatest overall selective advantage

6) Dark lava changed the color of the substrate, from light to dark.

7) Because to produce dark color, animals from the different regions suffered different mutations that drove them to have almost the same dark fur color.

8) To see if the mice population is evolving. If it is, there will be a change in the allelic and genotypic frequencies over the years. If it is not evolving, the frequencies will keep equal through the years.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files                  


Related Questions

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Answers

Answer:

Thickness and number of chlorophyll.

Explanation:

Shade-adapted plants differ from sun-adapted plants due to many characteristics such as thickness and number of chlorophyll. Sun leaves are more in thickness than shade leaves because they develop longer palisade cells. Shade leaves generally have more chlorophyll as compared to sun-adapted plants. Specific leaf area and root mass fraction of Shade-adapted plants are higher as compared sun-adapted plants due to large number of chlorophyll to harvest more sunlight for photosynthesis. Dark respiration is higher in sun-adapted plants when there is darkness as compared to shade-adapted plants which produce food in no direct sunlight.

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Answer:

macromolecules are the molecules that we can not see by the eye

Explanation:

What should I do more, that's all I know about macromolecules

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Answer:

Neither

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These are physical change examples

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Answer:

Top predator is a predator at the top of a food chain without natural predators.

Answer:

Hello There!!

Explanation:

A top predator is a predator which is at the top of the food chain and eats other consumers.

hope this helps,have a great day!!

~Pinky~

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Answer:

Predators might die out

Explanation:

Since grey squirrels can Camouflage... predators may not eat because the red squirrels die out. And grey squirrels may reproduce more because there is no competition anymore.

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Answer:

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Look at the image below.

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Y is the best graph represented
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Answer: Galvanometer

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Answer:

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Answer:

Explanation:

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Answer:

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Answer:

Explanation:

Adaptins:

Adaptor proteins, which attach the clathrin to the membrane, are required for clathrin-coated vesicles to form. Clathrin cages form in solution at strong clathrin concentrations and under the right ionic environments and parameters, but they are empty hollow shells without membranes or other proteins. The data for clathrin baskets are included in the clathrin molecules themselves, as shown by the self-assembly of clathrin into baskets. Clathrin coat cannot form or build up without adjusting to the membrane it is attached to.

Clathrin:

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Dynamin:

Clathrin-coated pits can develop and progress toward vesicle formation in the exclusion of dynamin, but the final step, known as membrane fusion, is inhibited. Consequently, in the exclusion of dynamin, strongly invaginated covered pits will be noticed. As a result, vesicles are unable to pinch the membrane.

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Explanation:

true

I hope this helps u

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susieiwiiuw7wuwiwiwiwususususu

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Answer:

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Explanation:

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Answer:

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Explanation:

In like manner, carbon dioxide passes from blood to the alveoli and exhaled after.

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Answers

Answer:

True. The atmosphere protects life on earth by shielding it from incoming ultraviolet (UV) radiation, keeping the planet warm through insulation, and preventing extremes between day and night temperatures.Greenhouse gases, such as carbon dioxide, methane, nitrous oxide, and certain synthetic chemicals, trap some of the Earth's outgoing energy, thus retaining heat in the atmosphere.

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Learn more about climate here:https://brainly.com/question/17922964

PLS HELP ME

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Answers

Answer:

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Answer:

B

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Which of the following statements correctly compares sex-linked disorders between males and females?

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Sex-linked disorders affect males more often than females because males have only one X chromosome.
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Sex-linked disorders affect males more often than females because males have only one Y chromosome.

Answers

Answer:

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Explanation:

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Answers

Answer:

B. Stage 1

Explanation:

Systolic blood pressure is less than 120 mm Hg and Diastolic less than 80 mm Hg so it is considered as normal. Pre-Hypertension occurs when the Systolic blood pressure is 120 - 139 and Diastolic pressure is 80 - 89. Stage 1 Hypertension is considered when the Systolic blood pressure is 140 - 159 and Diastolic blood pressure is 90- 99. If the Systolic blood pressure is greater than 160 it is considered as Stage 2 Hypertension.

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Answers

Answer:

The correct answer is - alternate versions of a gene.

Explanation:

In a cell, if there are two copies of each chromosome, these are called homologous chromosomes, one come from the father and the other comes from the mother, which helps in promoting the variety and stability of a species.

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Answers

Answer:

d. Species diversity

Explanation:

The species diversity can be measured by:

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Answers

Answer:

animals also have to cope i the desert, using adaptations such as being nocturnal or living under ground to survive. camels often live in deserts that are hot and dry during the day, coping with wind-blown sand and cold at night. slit-like nostrils and two rowa of eyelashes to help keep the sand out of their eyes.

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D an element with 8 valence electrons

Please help1!1

Answers

Answer:

D

Explanation:

8 valence electrons means it is stable, so it will not need to lose or gain electrons


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Answers

Answer:

Nitrogen, carbon, and phosphorus are just a few

Explanation:

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