Drag each tile to the correct location.
Match each process to where it occurs in the carbon cycle.
Ingestion
fossilization
decomposition
combustion
light
energy
oxygen
carbon
dicadde
- sugar
minerak
water
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Drag Each Tile To The Correct Location.Match Each Process To Where It Occurs In The Carbon Cycle.Ingestionfossilizationdecompositioncombustionlightenergyoxygencarbondicadde-

Answers

Answer 1

The order of the location of each process in the carbon cycle are as follows;

Ingestion → Decomposition → Fossilization → Combustion

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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Related Questions

How many neutrons are in K-37?

Answers

Answer:

18 neutrons

Explanation:

Potassium is nuimber 19 on periodic table, so when the mass equals 37, you simply subtract 37-19 to get 18

potassium usually has a mass of 39, so when we have potassium 37, it is two less neutrons than normal

A firecracker is placed in the middle of a room. When the firecracker explodes the parts of the firecracker scatter in all different directions. The total combined momentum of all the parts of the firecracker added together after the explosion must be



A.
more than before the explosion.

B.
less than before the explosion.

C.
can not tell from the given information

D.
the same as before the explosion.

Answers

Because momentum is a vector quantity, the total combined momentum of all the parts of the firecracker added together after the explosion must be the same as before the explosion. The correct answer is D

Given that a firecracker is placed in the middle of a room. This means that the firecracker is at rest. That is its momentum is equal to zero. When the firecracker is lit up, it will move in a certain velocity before it explodes. Since the total combined momentum of all the parts of the firecracker scatter in all different directions are considered, that is added up, then momentum will always be conserved. That is,

The momentum of an object before explosion will always be equal to the momentum of the object after explosion.

Because momentum is a vector quantity, in which we must consider it magnitude and direction, the best answer to this question is option D.

That is,

The total combined momentum of all the parts of the firecracker added together after the explosion must be the same as before the explosion

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A bullet of mass M1 is fired towards a block of mass m2 initially at rest at the edge of a frictionless table of height h as in the figure. The initial speed of the bullet is vi . Consider two cases, a completely inelastic one and an elastic one,where the bullet bounces off the block. inelastic case elastic case a bullet inside no bullet inside A B A' B' What is the ratio of the flight time; i.e., tAB tA′B′ ?

Answers

The ratio of time of flight for inelastic collision to elastic collision is 1:2

The given parameters;

mass of the bullet, = m₁mass of the block, = m₂initial velocity of the bullet, = u₁initial velocity of the block, = u₂

Considering inelastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\m_1u_1 + 0 = v(m_1 + m_2)\\\\v= \frac{m_1u_1}{m_1 + m_2} \ -- (1)\\\\[/tex]

The time of motion of the system form top of the table is calculated as;

[tex]v = u + gt\\\\v = 0 + gt\\\\v = gt\\\\t= \frac{v}{g} \\\\t_A = \frac{m_1u_1}{g(m_1 + m_2)} \ \ ---(2)[/tex]

Considering elastic collision, the final velocity of the system is calculated as;

[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\m_1u_1 + 0 = m_1v_1 + m_2v_2\\\\m_1 u_1 = m_1v_1 + m_2v_2[/tex]

Apply one-directional velocity

[tex]u_1 + (-v_1) = u_2 + v_2\\\\u_1 -v_1 = 0 + v_2\\\\v_1 = v_2 -u_1[/tex]

Substitute the value of [tex]v_1[/tex] into the above equation;

[tex]m_1u_1 = m_1(v_2 - u_1) + m_2 v_2\\\\m_1u_1 = m_1v_2 -m_1u_1 + m_2v_2\\\\2m_1u_1 = m_1v_2 + m_2v_2\\\\2m_1u_1= v_2(m_1 + m_2)\\\\v_2 = \frac{2m_1u_1}{m_1+ m_2} \ --(3)[/tex]

where;

[tex]v_2[/tex] is the final velocity of the block after collision

Since the bullet bounces off, we assume that only the block fell to the ground from the table.

The time of motion of the block is calculated as follows;

[tex]v_2 = v_0 + gt\\\\v_2 = 0 + gt\\\\t = \frac{v_2}{g} \\\\t_B = \frac{v_2}{g} \\\\ t_B = \frac{2m_1u_1}{g(m_1 + m_2)} \ \ ---(4)[/tex]

The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;

[tex]\frac{t_A}{t_B} = \frac{m_1u_1}{g(m_1 + m_2)} \times \frac{g(m_1 + m_2)}{2m_1u_1} \\\\\frac{t_A}{t_B} = \frac{1}{2} \\\\t_A:t_B = 1: 2[/tex]

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Other than temperature, which property also has an effect on the rates of chemical reactions?
A.Color of reactants
B.Concentration of reactants
C.Solubility of reactants
D.Volume of reactants

Answers

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants. The correct answer is B

The rate of chemical reaction means how chemical react with respect to time or as a function of time. The rate of chemical reaction tells us the speed or how fast chemicals react.

There are many factors that can affect the rate of chemical reaction. Temperature is one of them. Increase in temperature will increase the rate at which chemical react.

The color of reactants, solubility of reactants and volume of reactants have nothing to do with the rate of chemical reaction.

Other than temperature, the property that also has an effect on the rates of chemical reactions is the concentration of the reactants.

Other factors affecting the rate of chemical reaction are:

the physical state of the reactants surface area temperature and the presence of a catalyst

Therefore, the correct answer is option B

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Explain how energy changes in the spring toy below when it goes downstairs.

Answers

Given what we know, we can confirm that the spring toy uses the transfer of potential gravitational energy into kinetic energy of motion in order to fall down the stairs.

How does the toy do this?The toy stores potential energy. It does this using gravity. Once it begins to fall, it uses the momentum from each fall to continue to do so. With each fall, its stored potential energy is transferred to kinetic energy.

Therefore, we can confirm that the spring toy uses its position at the top of each stair as a source of potential energy, which using the momentum from the last fall, it transfers into the kinetic energy of motion as it falls, all through the help of gravity.

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(answer choices: applied force, normal force, friction, electrical force, magnetic force and gravitational force)

(question in picture)

Answers

Answer:

3

Explanation:

because they are pushing a body

how many kilojoules is this?

Answers

Answer:

How to convert joules to kilojoules

One joule is equal to thousandth of a kilojoule:

1J = 0.001kJ

The energy in kilojoules E(kJ) is equal to the energy in joules E(J) divided by 1000:

E(kJ) = E(J) / 1000

Example

Convert 500 joules to kilojoules.

The energy E in kilojoules (kJ) is equal to 500 joules (J) divided by 1000:

E(kJ) = 500J / 1000 = 0.5kJ

Joules to kilojoules conversion table

Energy (J) Energy (kJ)

1 J 0.001 kJ

2 J 0.002 kJ

3 J 0.003 kJ

4 J 0.004 kJ

5 J 0.005 kJ

6 J 0.006 kJ

7 J 0.007 kJ

8 J 0.008 kJ

9 J 0.009 kJ

10 J 0.01 kJ

20 J 0.02 kJ

30 J 0.03 kJ

40 J 0.04 kJ

50 J 0.05 kJ

60 J 0.06 kJ

70 J 0.07 kJ

80 J 0.08 kJ

90 J 0.09 kJ

100 J 0.1 kJ

200 J 0.2 kJ

300 J 0.3 kJ

400 J 0.4 kJ

500 J 0.5 kJ

600 J 0.6 kJ

700 J 0.7 kJ

800 J 0.8 kJ

900 J 0.9 kJ

1000 J 1 kJ

2000 J 2 kJ

3000 J 3 kJ

4000 J 4 kJ

5000 J 5 kJ

6000 J 6 kJ

7000 J 7 kJ

8000 J 8 kJ

9000 J 9 kJ

10000 J 10 kJ

100000 J 100 kJ

hope it help u

itz by Riddhi

Why does the size of a white dwarf affect its visual luminosity?

Answers

Answer:

A typical white dwarf has a carbon and oxygen mass similar to the Sun, but is much smaller in size (similar to the Earth). It is much hotter (25,000 K), but because of its small size its luminosity is low. ... Some very nearby white dwarf stars can be observed directly through telescopes, though they are extremely faint.

Explanation:

How can you use a simple model to describe a wave and its features?

Answers

Answer:

Explanation:

Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.

Describe the way that distance is changing in relation to tiMe

Answers

Answer:

DistaNcE chanGes iN relAtiOn tO TiMe Bc ThE fuRthEr yOu Go ThE mOrE TiMe goeS bY

The gravitational force on Mars is about 38% of Earth. What would a cat weighing 15 pounds on Earth weigh on Mars?

Answers

Answer: 5.7

Explanation: 38% of 15.

The weight we experience ourselves and the ability to stand in the ground is due to the gravitational pull of earth. If this pull is lower we feel weight loss. So the cat will have a weight of 5.7 pounds or 2.58 kg in mars where the gravitation is about 38% of earth.

What is gravitational force?

Gravitational force is a kind force by which a body attracts other objects into its centre of mass. Earth have strong gravitational effect on objects and thus we are all standing on the surface and everything falling from a height hits the ground.

As the mass of the object increases, gravitational effect also increases. The weight experienced by a body is the product of its mass and gravity. Thus massive body have greater weight.

Our mass is constant everywhere but weight will change according a change in gravity. Mars  have only 38% of gravity of earth. Thus the cat weighing 15 pounds on earth will loss its weight in mars by 38%.

Thus, 15 × 38/100= 5.7 pounds will be the weight of the cat in mars.

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car was moving in a straight road of length 320 km it covered 240 km with an average velocity 75 km/hr then it ran out of fuel and stopped for 0.6 hr until it was refueled and completed its journey with a velocity 100 km/hr so the average velocity during the whole journey

Answers

The average velocity of the car for the whole journey is 69.57 km/h.

The given parameters:

Length of the road, L = 320 kmDistance covered = 240 km at 75 km/htime spent refueling, t₂ = 0.6 hrFinal velocity, = 100 km/hr

The time spent by the before refueling is calculated as follows;

[tex]t = \frac{d}{v} \\\\t_1 = \frac{240}{75} \\\\t_1 = 3.2 \ hours[/tex]

The time spent by the car for the remaining journey;

[tex]t_3 = \frac{320 - 240}{100} \\\\t_3 = 0.8 \ hr[/tex]

The total time of the journey is calculated as follows;

[tex]t = t_1 + t_2 + t_3\\\\t = 3.2 \ hr \ + \ 0.6 \ hr \ + \ 0.8 \ hr\\\\t = 4.6 \ hours[/tex]

The average velocity of the car for the whole journey is calculated as follows;

[tex]v = \frac{total \ distance }{total \ time} \\\\v = \frac{320}{4.6} \\\\v = 69.57 \ km/h[/tex]

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Which element forms more com-
pounds than all the other elements
combined?

Answers

Answer:

Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.

Explanation:

Hope its helps you ✌️

I need help!
A car has a mass of 1,200 kg and the road can provide a maximum force of 24 kN on the car what is the maximum acceleration?

Answers

Answer:

The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²

Explanation:

True or false? Gas pressure is caused by molecules in a gas colliding with the walls of their container.

Answers

Answer:True

The number of molecules hitting the unit surface per unit time increasethe gas pressure increases.

Answer very true yep

write of the following does not represent electrical power in a circuit ?

(a) I²R


(b) IR²

(c)VI

(d) V²/R​

Answers

(b) IR^2 does not represent electrical power in a circuit.


The equations for electrical power are as follows:

P=I^2R

P=VI

P=V^2/R
(You can get this equation by rearranging V=IR, making I the subject to get I=V/R and substituting that into P=VI)

P=E/T

a measure of change in velocity in a measure of time is

Answers

[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{\Delta V}{t}[)tex]

In simplified form

[tex]\\ \sf\Rrightarrow Acceleration=\dfrac{dv}{dt}[/tex]

The rate of change of velocity with respect to time period is called acceleration.SI units-m/s^2

A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.

Answers

Hi there!

Recall:

Impulse = Change in momentum

I = Δp = mΔv = m(vf - vi)

Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.

Plug in the givan values:

Δp = 1.5(-10 - 12) = -33 Ns

**OR, the magnitude: |-33| = 33 Ns

A vector consists both?

Answers

Answer:

magnitude and a direction

Explanation:

i do believe that i need help

Answers

WHAT IS THAT omg Helpppp

Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)

Answers

Answer:

mass= 20kg

g=10m/s2

weight is F=mg

F=20×10

F=200N

What two things related to sedimentary rocks do you see at the Grand Canyon ?

Answers

Answer:

sandstone and mudstone

Explanation:

What is an example of bad energy efficiency but good energy conservation?

Answers

Answer:

Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.

Explanation:

hope this helps

what is the unit of measurement for expressing the intensity of sound

Answers

Decibel - the decibel is a relative unit of measurement equal to one 10th of a bel

A vertical spring stretches 9.6 cm when a 1.3 kg block is hung from its end. (a) Calculate the spring constant. This block is then displaced an additional 5.0 cm downward and released from rest. Find the (b) period, (c) freque

Answers

Answer:

F = - K x

a) K = 1.3 kg * 9.8 m/s^2 / .096 m = 133 kg/sec^2

b)  ω = (K/m)^1/2     angular frequency of SHM

ω = (133 / 1.3)^1/2 = 10.1 / sec

f = 2 π ω = 6.28 * 10.1 / sec = 63.5 / sec

P = 1/f = .0157 sec

Compare and contrast synthesis and decomposition reactions.

Answers

Answer:

Synthesis reactions are chemical reactions where two elements combine to make a product. Decomposition reactions are chemical reactions where a reactant produces another product, usually two, or even more. This is when the bonds in the compound are broken apart to make new compounds.

Explanation:

The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What must be true of the possible answers to a scientific question? A. They are popular with a majority of scientists. B. They agree with all prior experiments. O C. They can be supported by evidence. O D. They lead to increased funding of scientific research.​

Answers

Answer:

They must be supported by evidence.

Explanation:

Every scientific theory or scientifc claim must have scientific evidence.

Solve the science problem

Answers

Answer:

1.hydrogen

2.helium

3. lithium

4.beryllium

5.boron

6.carbon

7.nitrogen

8.oxygen

9.fluorine

10.neon

A payload of mass m, where m

Answers

Answer:

where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km ...

A payload of mass m, where m<M, is delivered to the space station.

What is payload?

The maximum mass that the vehicle is capable of moving is referred to as the mass's payload. The carrying capacity of a packet or other transmission data unit is referred to as a payload.

The phrase, which has military roots, is frequently used in relation to malicious code that can be executed and cause harm. A payload is a section of code that runs when hackers take advantage of a weakness. In other words, it's a module for an exploit.

It typically consists of a few commands that will execute on the targeted operating system in order to steal data and carry out other malicious deeds (such as keyloggers).

Therefore, A payload of mass m is sent to the space station, where m<M.

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Two 3.0g bullets are fired with speeds of 40.0 m/s
and 80.0 m/s, respectively. What are their kinetic
energies? Which bullet has more kinetic energy? What is the ratio of their kinetic energies?

Answers

Two 3.0g bullets are fired with speeds of 40.0 m/s and 80.0 m/s, respectively. Mass of the 1st bullet (m1) = 3 g = 0.003 KgMass of the 2nd bullet (m2) = 3 g = 0.003 KgVelocity of the 1st bullet (v1) = 40 m/sVelocity of the 2nd bullet (v2) = 80 m/sWe know, kinetic energy of a body

[tex] = \sf \frac{1}{2} m {v}^{2} [/tex]

Kinetic energy of the 1st bullet [tex] \sf = \frac{1}{2} \times m1 \times {(v1)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(40)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 1600J \\ \sf = 2.4J[/tex]Kinetic energy of the 2nd bullet [tex] \sf = \frac{1}{2} \times m2 \times {(v2)}^{2} \\ \sf= \frac{1}{2} \times 0.003 \times {(80)}^{2}J \\ \sf = \frac{1}{2} \times 0.003 \times 6400J \\ \sf = 9.6J[/tex] So, the 2nd bullet which has greater velocity has more kinetic energy.Therefore, the ratio of their kinetic energies

[tex] \sf = \frac{2.4J}{9.6J} \\ \sf= \frac{24}{96} = \frac{1}{4} \\ \sf = 1 : 4[/tex]

Answer:

The kinetic energies of the bullets are 2.4 J and 9.6 J.

The bullet having greater velocity has more kinetic energy.

The ratio of their kinetic energies is 1 : 4.

Hope you could get an idea from here

Doubt clarification - use comment section.

The kinetic energy of the two bullets are 2.4 J and 9.6 J respectively.

The ratio of the kinetic energy of the bullets is 1:4.

What is kinetic energy?

The kinetic energy of an object is the energy possessed by the object due to its motion.

The kinetic energy of the two bullets is calculated as follows;

[tex]K.E_1 = \frac{1}{2} \times 0.003 \times 40^2 = 2.4 \ J\\\\K.E_2 = \frac{1}{2} \times 0.003 \times 80^2 = 9.6 \ J[/tex]

Ratio of the kinetic energy of the bullets is calculated as follows;

[tex]K.E_1 : K.E_2 = 2.4: 9.6 \ = \ 1: 4[/tex]

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Explain how the absorption or reflection of sunlight may affect natural settings. Predict that different materials will absorb or reflect sunlight. Describe the consequences of the heat energy that is taken up by the atmosphere and what the atmosphere does with it. Explain how heat energy is transferred from the sun to Earth and the atmosphere.PREPAREApproximate lesson time is 60 minutes.MaterialsFor the Student Laboratory GuidelinesKeywords and Pronunciationspecific heat: the energy, in calories, required to raise the temperature of one gram of a substance one degreeCelsiusLEARNActivity 1: Energy Absorption/Reflection 1 (Online)Activity 2: Energy Absorption/Reflection (Online)InstructionsIntroductionFollow the Procedure below. As you complete the lab, take notes about the lab so you can participate in the discussion. In this laboratory exercise, you will design an experiment to test how different materials reflect or absorb light. ProcedurePart 1: Formulate a Hypothesis1. Keep these questions in mind as you develop your hypothesis: Do some colors absorb more light than others? Do some materials absorb or reflect more light than others? How could you indirectly measure the amount of sunlight absorbed by an object?2. Write a hypothesis, in if...then format. Part 2: Design an Experiment3. Design an experiment that tests the absorption and reflection of different materials.4. Create a list of materials and a procedure to test your hypothesis.5. Record your idea in your lab report for discussion. Note that you do not need to perform the experiment.When you have finished, you will discuss with your classmates through a threaded discussion board. Print the Grading Rubric for the Threaded Discussion Board Activity and review the contents. Your teacher will use this rubric to grade your participation in this discussion.ASSESSDiscussion: Energy Absorption/Reflection 1 (Online)Read the discussion prompt and carefully write your response. 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